Zinc and hydrochloric acid react according to the equation Zn(s)+2HCl( – InterviewSolution

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1.	Zinc and hydrochloric acid react according to the equation Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) 0.30 mole of Zn is added to 0.52 mole of HCl. Which of the two reactants is the limiting reagent and how many moles of H2 is produced?
Answer» Zinc and hydrochloric acid react according to the equation $Z n (s) + 2 H C l (a q) \to Z n C l_{2} (a q) + H_{2} (g)$ 0.30 mole of $Z n$ is added to 0.52 mole of $H C l$ . Which of the two reactants is the limiting reagent and how many moles of $H_{2}$ is produced?

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