1.

Zinc is the only metal in group -12 which shows amphoteric properties and is soluble in alkaline forming

Answer»

`Na_(2)[Zn(OH)_(4)]`
`NA[Zn(OH)_(3).(H_(2)O)_(3)]`
`Na[Zn(OH)_(3).H_(2)O]`
`Na_(4)[Zn(OH)_(6)]`

Solution :Zn reacts with NaOH to form zincate IONS and metazincate ion and `H_(2)`.
The zincate and metazincates are represented as
`[Zn(OH)_(4)]^(2-),[Zn(OH)_(3)(H_(2)O)_(3)]^(-),[Zn(OH)_(3)H_(2)O]^(-)` Hence, choce (a), (b) and (c ) are correct while (d) is INCORRECT.


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