`Zn` acts as sacrifical or cathodic protect iont to prevent rusting of iron becauseA. `E_(OP)^(@)` of `ZnltE_(OP)^(@)`of `Fe`B. `E_(OP)^(@)` of `ZngtE_(OP)^(@)`of `Fe`C. `E_(OP)^(@)` of `Zn=E_(OP)^(@)`of `Fe`D. `Zn` is cheaper than iron

`Zn` acts as sacrifical or cathodic protect iont to prevent rusting of

1.	`Zn` acts as sacrifical or cathodic protect iont to prevent rusting of iron becauseA. `E_(OP)^(@)` of `ZnltE_(OP)^(@)`of `Fe`B. `E_(OP)^(@)` of `ZngtE_(OP)^(@)`of `Fe`C. `E_(OP)^(@)` of `Zn=E_(OP)^(@)`of `Fe`D. `Zn` is cheaper than iron
Answer» Correct Answer - B `Zn` is oxidised in place of iron and iron acts as cathode if `Zn` plating or galvanisation of iron is made and thus called cathodic protection. Since `Zn` is oxidised and thus also called sacrificial protection.

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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Limiting molar conductivity of `NH_(4)OH` [i.e., `Lambda_(m)^(@)(NH_(4)OH)`] is equal to:A. `Lambda_(m)^(@)(NH_(4)Cl)+Lambda_(m)^(@)(Na_(4)Cl)-Lambda_(m)^(@)(NaOH)`B. `Lambda_(m)^(@)(NaOH)+Lambda_(m)^(@)(NaCl)-Lambda_(m)^(@)(NH_(4)Cl)`C. `Lambda_(m)^(@)(NH_(4)OH)+Lambda_(m)^(@)(NH_(4)Cl)-Lambda_(m)^(@)(HCl)`D. `Lambda_(m)^(@)(NH_(4)Cl)+Lambda_(m)^(@)(NaOH)-Lambda_(m)^(@)(NaCl)`
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Based on the data given below, the correct order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt A1`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al^(-) lt Br^(-) lt Fe^(2+)`D. `Al^(-) lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

`Zn` acts as sacrifical or cathodic protect iont to prevent rusting of iron becauseA. `E_(OP)^(@)` of `ZnltE_(OP)^(@)`of `Fe`B. `E_(OP)^(@)` of `ZngtE_(OP)^(@)`of `Fe`C. `E_(OP)^(@)` of `Zn=E_(OP)^(@)`of `Fe`D. `Zn` is cheaper than iron

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