Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)) . In this reaction, which gets oxidised ?

Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)) . In this react

1.	Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)) . In this reaction, which gets oxidised ?
Answer» `Cu^(2+)` `Zn^(2+)` Zn `Zn, Cu^(2+)` SOLUTION :`Zn to Zn^(2+)+2E^(-)` (LOSS of electron = oxidation) Zn gets oxidised