Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)). In this reaction, which gets oxidised?

Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)). In this reacti

1.	Zn_((s)) + Cu_((aq))^(2+) to Zn_((aq))^(2+) + Cu_((s)). In this reaction, which gets oxidised?
Answer» `CU^(2+)` `Zn^(2+)` Zn `ZN,Cu^(2+)` Solution :`Zn to Zn^(2+) + 2E^(-)`(LOSS of electron = oxidation) Zn GETS oxidised