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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Primary and secondary amines can be distinguished by the action of:A. `CS_(2)//HgCl_(2)`B. `NaNO_(2)//HCl`C. `CHCl_(2)//KOH`D. NaOH |
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Answer» Correct Answer - A::B::C NaOH cannot distinguish amines |
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| 2. |
Which of the following can distinguish the three amines, viz…, primary , secondary and tertiary?A. Azo -dye testB. Hinsberg reagentC. Carbylamine testD. Acetyl chloric |
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Answer» Correct Answer - B `1^(@)` amine reacts with Hinsberg reagent and the product is insoluble in alkali where as `3^(@)` amine dose not react with Hinsber reagent |
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| 3. |
How many primary amines are possible for the formula `C_4 H_(11) N`A. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - D `CH_(3)-CH_(2)-CH_(2)-CH_(2)-NH_(2), CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-NH_(2)` `CH_(3)-CH_(2)-underset(NH_(2))underset(|)(CH)-CH_(3) " " CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-NH_(2)` |
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| 4. |
Primary amines can be distinguished from other amines by the following test.A. A and R are true and R is the correct explanation of AB. A and R are true and R is not the correct explanation of AC. A is true R is falseD. A is false R is true |
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Answer» Correct Answer - C `2^(@),3^(@)` amines donot give carbylamine test. |
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| 5. |
A positive carbylamine test is given byA. N,N-dimethyl anilineB. isopropyl amineC. diethyl amineD. trimethyl amine |
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Answer» Correct Answer - A `1^(@)` -amine |
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| 6. |
On heating an aliphatic primary amine with chloroform and enthanolic potassium hydrozide, the organic compound formed isA. an alkyl cyanideB. an alkyl isocyanideC. an alkanolD. an alkanediol |
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Answer» Correct Answer - B `RNH_(2)+CHCl_(3)+3KOHto RNC uarr +3KCl+3H_(2)O` |
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| 7. |
(A) Carbylamine reaction involves chemical reaction between `1^(@)` amine and chloroform in basic medium. (R) In carbylamine reaction, `-NH_(2)` group changes into-NC group.A. A and R are true and R is the correct explanation of AB. A and R are true and R is not the correct explanation of AC. A is true R is falseD. A is false R is true |
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Answer» Correct Answer - A In carbyl amine reaction, Isocyanides are formed. |
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| 8. |
Amongst the following the most basic compound is :A. BenzylamineB. AnilineC. AcetanilideD. P-nitroaniline |
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Answer» Correct Answer - A Aliphatic amines are more basic than aromatic amines |
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| 9. |
Arrange the following in increasing order of basic strength: methyl amine ,dimethylamine, aniline, N- methylaniline. |
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Answer» Correct Answer - A Increaseing order of base-strength: aniline lt N-methylaniline ltmethyl aniline lt dimethyl aniline |
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| 10. |
Considering the basec strength of amines in aqueous solution which one has the smallest `pK_b` value?A. `(CH_(3))_(3)N`B. `C_(6)H_(5)NH_(2)`C. `(CH_(3))_(2)NH`D. `CH_(3)NH_(2)` |
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Answer» Correct Answer - C Aliphatic amines are more basic than aromatic amines. `(CH_(3))_(2)NH gt CH_(3)NH_(2) gt (CH_(3))_(3)N` (among aliphatic amines in water). |
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| 11. |
There are some isomeric amines containing only one N atom. Each one of which forms a chloride salt on treatment with HCl containing `32.42%` chlorine. None of them decolorizes `Br_2` water. How many of them contains chiral carbon?A. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - A Only secodary butyl amine is chiral |
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| 12. |
Aniline on heating with fumig sulphuric acid gives.A. aniline disulphateB. sulphanilic acidC. aniline sulphateD. aniline-2,4-disulphonic acid |
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Answer» Correct Answer - B Electrophilic substitution |
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| 13. |
Aromatic diazonium group can be replaced by various groups. Identify the correct reagent and groupA. `H_(3)PO_(2),H`B. boiling with water. OHC. KI,ID. Cul/HI,I |
| Answer» Correct Answer - A::B::C | |
| 14. |
Which of the following compounds will dissolve in an alkali solution after it has undergone reaction with Hinsberg reagent?A. `(C_(2)H_(5))_(2)NH`B. `(CH_(3))_(3)N`C. `CH_(3)NH_(2)`D. `C_(6)H_(5)NHC_(6)H_(5)` |
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Answer» Correct Answer - C `1^(@)` amine |
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| 15. |
Ethyl amine reacts with NOCl in polar aprotic solvent to formA. ethyl chlorideB. EthylnitrateC. Ethyl alcoholD. Nitro ethane |
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Answer» Correct Answer - A Reaction of amines with nitrosonium ion. |
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| 16. |
Reaction involves isocyanate as intermediate productA. Curtuis rearrangementB. Lossen rearrangementC. Schmidt reactionD. Hofmann rearragement |
| Answer» Correct Answer - A::B::C::D | |
| 17. |
How many of below listed compounds are soluble in aq. NaOH but insoluble in aq. `NaHCO_3`. |
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Answer» Correct Answer - D All sulphonic acids, carboxylic acids and trinitrophenols are soluble in NaOH & `Na_(2)CO_(3)` |
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| 18. |
Identify the correct statement.A. Hoffmann elimination is syn eliminationB. Sulphonamides can be used to prepare `2^(@)`-aminesC. Benzene diazonium ion does not couple with all aromatic ringsD. Hoffmann rearrangements is limited to amide of the type `RCONH_(2)` |
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Answer» Correct Answer - B::C::D Hoffmann elimination is antielimination |
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| 19. |
How many of the below listed compounds on treatment with `HNO_2` would go for ring expansion? |
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Answer» Correct Answer - C Cyclic compounds with `-CH_(2)-NH_(2)` group on the ring undergo ring expansion. |
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| 20. |
An optically active compound with molecular formula `C_6 H_(11) N` dissolves in dilute aqueous HCl and releases `N_2` on treatment with `HNO_2`. The compound on Hofmann eliminatioon givesA. B. C. D. no reaction |
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Answer» Correct Answer - B Cyclohexenamine fullfills the given reaction |
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| 21. |
Which of the following is not formed in the reaction? A. B. C. D. |
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Answer» Correct Answer - A Diazotisation |
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| 22. |
Electron releasing group pushes electrons to ward nitrogen and hence increases the availability of lone pair of electrons and thus increases its basicity on the other hand, electron with drawing group decreases the availability hence makes the amine less basic Which of the following is the strongest base?A. B. C. D. |
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Answer» Correct Answer - B Aliphatic amines are stronger bases than aromatic amines |
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| 23. |
Electron releasing group pushes electrons to ward nitrogen and hence increases the availability of lone pair of electrons and thus increases its basicity on the other hand, electron with drawing group decreases the availability hence makes the amine less basic Which of the following has maximum `pK_b` value?A. `CH_(3)CH_(2)NH_(2)`B. C. `(CH_(3)CH_(2))_(2)NH`D. |
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Answer» Correct Answer - D `C_(6)H_(5)NH_(2)` is a weak base. |
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| 24. |
Electron releasing group pushes electrons to ward nitrogen and hence increases the availability of lone pair of electrons and thus increases its basicity on the other hand, electron with drawing group decreases the availability hence makes the amine less basic Among the following which is more basicA. B. C. D. |
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Answer» Correct Answer - A `CH_(3)O` group is electron releasing group |
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| 25. |
Which of the following pair is correctly matched.A. Cirtuis reaction, carboxylic acidB. Hoffmann rearragement -acid azideC. Schmidt reaction-carboxylic acidD. Lossen rearragements-acid chloride |
| Answer» Correct Answer - C | |
| 26. |
The correct matching isA. A-3 B-1 C-4 D-3B. A-5 B-4 C-1 D-2C. A-2 B-5 C-1 D-3D. A-1 B-2 C-4 D-5 |
| Answer» Correct Answer - B | |
| 27. |
The correct matching isA. A-2 B-3 C-4 D-1B. A-4 B-3 C-2 D-1C. A-1 B-2 C-3 D-4D. A-3 B-1 C-2 D-4 |
| Answer» Correct Answer - A | |
| 28. |
Cyanide is an:A. Zwitter ionB. CationC. Ambident nucleophileD. Electrophile |
| Answer» Correct Answer - C | |
| 29. |
Gabriel phthalimide reaction can be out lined as follows How many of the following amines can be prepared by this method |
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Answer» Correct Answer - D Onluy `1^(@)` amine of aliphatic series and `1^(@)` aromatic amine with ring deactivating substituents can be synthesized. Not that the step II is `S_(N)2`. |
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| 30. |
Which of the following amines cannot be prepared by Gabriel phthalimide reaction?A. BenzylamineB. AnilineC. EthylamineD. Methalylamine |
| Answer» Correct Answer - B | |
| 31. |
N-ethyl formamide on dehydration with `POCl_(3)` in presence of pyridine gives:A. Ethyl amineB. Ethyl cyanideC. Ethyl isocynideD. Methyl isocyanide |
| Answer» Correct Answer - C | |
| 32. |
Schiffs base is used as aA. oxidantB. hydrolysing agentC. antichlorD. antioxidant |
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Answer» Correct Answer - D In order industry it is used as anti oxidant |
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| 33. |
Towards electrophilic substitution, the most reactive isA. anilinium chlorideB. anilineC. N-acetylanilineD. nitrobenzene |
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Answer» Correct Answer - B `-NH_(2)` group is electron releasing group |
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| 34. |
Which is/are correct reaction(s) w.r.t major productA. B. C. D. |
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Answer» Correct Answer - C::D A gives subtitution and B gives predominantly elimination |
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| 35. |
The IUPAC name of `CH_3 NH_2` isA. methylamineB. amino ethaneC. methanamineD. Ethylamine |
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Answer» Correct Answer - C `1^(@)` amine |
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| 36. |
The pyramidal inversion from one invertomer of chiral tetrahedral amine to another takes place viaA. Carbocationic intermediateB. Anionic nitrogen intermediateC. Cationic nitrogen intermediateD. Planar nitrogen |
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Answer» Correct Answer - D Amines are in equilibrium of two enantiomers. |
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| 37. |
Aniline reacts with excess alkyl halide to giveA. amino compoundB. tertiary compoundC. azomethaneD. quaternary ammonium compound |
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Answer» Correct Answer - D `C_(6)H_(5)NH_(2)overset(3RX)to[C_(6)H_(5)NR_(3)]^(+)X^(-)` |
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| 38. |
Bromine water reacts with aniline to giveA. o-bromoanilineB. p-bromoanilineC. m-bromoanilineD. symmetric tribromoaniline |
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Answer» Correct Answer - D Electrophilic substitution |
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| 39. |
The compound `C_5 H_(13) N` is optically active and reacts with HONO to give `C_5 H_(11) OH`. The compound isA. N-methylbutanamineB. 2-AminopentaneC. 1-AminopentaneD. N,N-Dimethylpropanamine |
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Answer» Correct Answer - B `H_(3)^(5)C-CH_(2)^(4)-CH_(2)^(3)-underset(NH_(2))underset(|)(C)overset(2)(H)-Coverset(1)(H)_(3)` |
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| 40. |
The correct order of basicities of the following compounds is , `" "underset((2))(CH_(3)CH_(2)NH_(2))` `underset((3))((CH_(3))_(2)NH)" "underset((4))(CH_(3)CONH_(2))`A. 2gt1gt3gt4B. 1gt3gt2gt4C. 3gt1gt2gt4D. 1gt2gt3gt4 |
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Answer» Correct Answer - B Order of basic nature of amines |
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| 41. |
Cyclohexyl amine and pyrrolidine are distingsuished byA. `NANO_(2)//HCl`B. Benzene sulphonyl chlorideC. RCOCl/pyridineD. Carbyl amine reaction |
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Answer» Correct Answer - A::B::D Acylation is not a distinction test |
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| 42. |
Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by `OH^(-)` because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as `alpha` carbon. When the hydroxide ion starts to remove a `beta` H form from a quarternary ammonium ion, the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result, a partial negative charge bulds up on the carbon from which the proton is removed. Which compounds of question number 31 are optically activeA. A and BB. B and CC. A,B and CD. All are inactive |
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Answer» Correct Answer - A C is not optically active |
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| 43. |
There are some isomeric amines containing only one N atom. Each one of which forms a chloride salt on treatment with HCl containing `32.42%` chlorine. None of them decolorizes `Br_2` water. How many of them can evolve `N_2` on reaction with `HNO_2`?A. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - C The compound is `C_(4)H_(11)N` and only primary amines release nitrogen gas with `HNO_92)` |
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| 44. |
Which of the following shows optical acivity?A. butanamine-IB. butanamine-2C. isopropylamineD. etyl methyl amine |
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Answer» Correct Answer - B It contain chiral carbon |
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| 45. |
Which of the following statements is/are correct?A. In gas phase the basic strength order among the three types of amines is `3^(@) gt 2^(@) gt 1^(@)`B. Among the isomeric amines boiling points order is `3^(@) gt 2^(@) gt 1^(@)`C. Alcohols are more water soluble than amines (of comparable molecular weight)D. The C-N bond in aromatic amines is shorter than that of in aliphatic amines |
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Answer» Correct Answer - A::C::D The order of boiling points is `1^(@) gt 2^(@) gt 3^(@)`. |
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| 46. |
Which of the following statements is/are correct?A. Primary amines show intermolecular hydrogen bondingB. Secondary amines shown interamolecular hydrogen bondingC. Tertiary amines show intermolecular hydrogen bondingD. Amines have lower boiling points as compared to those of alcohols and carboxylic acid of comparable molar masses. |
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Answer» Correct Answer - A::B::D Hydrogen bonds are absent in tertiary amines |
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| 47. |
Which of the following would not react with benzene sulphonyl chloride in aqueous NaOH?A. anilineB. methylamineC. N,N-dimethyl anilineD. N-methyl aniline |
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Answer» Correct Answer - C `3^(@)`-amine |
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| 48. |
`CH_3 CH_2 Cl overset ("NaOH")to X overset ("Ni//H_2") to Y overset("Acetic") underset("anhydride") to Z` Z in the above sequence isA. `CH_(3)CH_(2)CH_(2)NHCOCH_(3)`B. `CH_(3)CH_(2)CH_(2)NH_(2)`C. `CH_(3)CH_(2)CH_(2)CONHCH_(3)`D. `CH_(3)CH_(2)CH_(2)CONHCOCH_(3)` |
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Answer» Correct Answer - A `x=CH_(3)CH_(2)CN " " Y=CH_(3)CH_(2)CH_(2)NH_(2)` |
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| 49. |
Aniline is more basic thanA. `NH_(3)`B. `CH_(3)NH_(2)`C. N-Methyl anilineD. P-nitroaniline |
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Answer» Correct Answer - D Nitro group is electron with drawing group |
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| 50. |
In the given reaction `CH_(3)-CH_(2)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-NH_(2) overset(NaNO_(3))underset(Conc. HCl)to` product(s). Product(s) will beA. `CH_(3)-CH_(2)-overset(OH)overset(|)underset(CH_(3))underset(|)(C)-CH_(3)`B. `CH_(3)-CH=underset(CH_(3))underset(|)(C)-CH_(3)`C. `CH_(3)-CH_(2)-overset(Cl)overset(|)underset(CH_(3))underset(|)(C)-CH_(3)`D. All |
| Answer» Correct Answer - D | |