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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1751. |
Compare the energy released during direct electronic transition from 4th orbit to lst orbit with the energy released during successive electronic transi tions between the same orbits in H-atom. Is the energy of all successive transitions between the 4th orbit and 1st orbit equal |
| Answer» expression fbr energy of electron in nth orbit | |
| 1752. |
what is the electronic configuration of `Cu^(2+)` (Z=29) of least positionA. `[Ar]4s^1 3d^8`B. `[Ar]4s^2 3d^10 4p^1`C. `[Ar] 4s^1 3d^10`D. `[Ar] 3d^9` |
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Answer» Correct Answer - D `._29Cu=[Ar]3d^10 4s^1 , Cu^(2+)=[Ar] 3d^9 . 4s^0` Ground state of `Cu^29=1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^1` `Cu^(2+)=1s^2 , 2s^2 2p^6 , 3s^2 3p^6 3d^9` |
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| 1753. |
`Cu^(2+)` will have the following electronic configuration.A. `1 s^2, 2 s^2 2p^6, 3 s^2 3 p^6 3 d^10`B. `1 s^2, 2 s^2 2p^6, 3 s^2 3 p^6 3 d^9, 4 s^1`C. `1 s^2, 2 s^2 2 p^6, 3 s^2 3p^6 3 d^9`D. `1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6 3 d^10, 4 s^1` |
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Answer» Correct Answer - C ( c) Ground state of `Cu^29 = 1 s^2 2 s^2 2 p^6 3 s^2 3p^6 3 s^10 4 s^1` `Cu^(2+) = 1 s^2 2 s^2 2p^6 3 s^2 3 p^6 3 d^9`. |
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| 1754. |
The wave number of the `H_(a)-`line in Balmer series of hydrogen spectrum isA. `5R//36`B. `3R//16`C. `21R//100`D. `3R//4` |
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Answer» Correct Answer - A `bar(v) = (1)/(lambda) = R [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` |
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| 1755. |
What is the electronic configuration of `Cu^(+)` ion |
| Answer» `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(0)3d^(10)` | |
| 1756. |
Light from a discharge tube containing H-atoms in some excited state, falls on the metallic surface of metal Na.The KE of the fastest photo-electron was found to be fastest photo-electron was found to be `10.93eV`. If `He^(+)` ions were present in the same excited state, the KE of the fastest photo-electron would have been `49.18eV`. Determine the excited state orbit number and work function of Na.A. `2,18.2ev`B. `4,1.82ev`C. `3,16ev`D. `2,1.6ev` |
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Answer» Correct Answer - B `E_(1) = E_(0) +10.93, E_(2) = E_(0) +49.18` `[13.6 xx 2^(2) - 13.6 xx 1^(2)] [(1)/(1^(2))-(1)/(n^(2))]` `= E_(2) - E_(1) = Delta E = 38.25` `:. n = 4, :. E_(1) = 12.75 & E_(0) = 1.82 eV` |
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| 1757. |
In hydrogen atom, energy of first excited state is `- 3.4 eV`. Then, `KE` of the same orbit of hydrogen atom is.A. ` + 3.4 eV`B. `+ 6.8 eV`C. `-13.6 eV`D. `+ 13.6 eV` |
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Answer» Correct Answer - A (a) `because` Total energy `(E_n) = KE + PE` In the first excited state =`(1)/(2) mv^2 + [-(Ze^2)/( r)]` =`+ (1)/(2) (Ze^2)/( r) - (Ze^2)/( r)` `- 3.4 e V = - (1)/(2) (Ze^2)/( r)` `:. KE = (1)/(2) (Ze^2)/(2) = + 3.4 eV`. |
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| 1758. |
A plot of the kinetic energy `((1)/(2)mv^(2))` of ejected electrons as a function of the frequency (v) of incident radiation for four alkali metals `(M_(1),M_(2),M_(3),M_(4))` is given below: The alkali metals `M_(1),M_(2),M_(3),M_(4)` are respectively:A. Li,Na,K and RbB. Rb,K,Na and LiC. Na, K, Li and RbD. Rb, Li, Na and K |
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Answer» Correct Answer - B Intercept on v-axis denotes `v_(0)` `v_(0)=(phi)/(h)` where `phi`=work function of the metal. Thus, greater is the value of `v_(0)`, more will be the work function of the metal. |
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| 1759. |
If first ionisation potential of a hypothetical atom is `16 V`, then the first excitation potential will be :A. 10.2 VB. 12 VC. 14 VD. 16 V |
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Answer» Correct Answer - B (b) `IP = 13.6 Z^2 = 16` (given) First excitation potential `= 13.6 xx (3)/(4) xx Z^2` =`16 xx (3)/(4) = 12 V`. |
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| 1760. |
The first excitation potential of a given atom is `10.2V`,then the ionisation potential isA. `10.2V`B. `13.6V`C. `30.6V`D. `20.4V` |
| Answer» Correct Answer - B | |
| 1761. |
The correct order of wavelength of Hydrogen `(._(1)H^(1))`, Deuterium `(._(1)H^(2))` and Tritium `(._(1)H^(3))` moving with same kinetic energy isA. `lambda_(H) gt lambda_(D) gt lambda_(r)`B. `lambda_(H)=lambda_(D)=lambda_(r)`C. `lambda_(H) lt lambda_(D) lt lambda_(r)`D. `lambda_(H) lt lambda_(D) gt lambda_(r)` |
| Answer» Correct Answer - 1 | |
| 1762. |
Electronic configuration of deuterium atom isA. `1s^1`B. `2s^2`C. `2s^1`D. `1s^2` |
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Answer» Correct Answer - A Atomic number of deuterium =1 , `._1D^2 to 1s^1` |
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| 1763. |
Which of the following options is not correct regarding the order of the frequency of electromagnetic radiation?A. Radio waves `lt` Microwaves `lt` X-raysB. Green light `lt` UV light `lt gamma`- radiationsC. Far infrared `gt` Radio waves `gt` Cosmic raysD. Microwaves `lt` Near infrared rays `lt` UV rays |
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Answer» Correct Answer - C |
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| 1764. |
Which of the following statements is not correct regarding electromagnetic spectrum?A. The velocity of X-rays is more than that of microwavesB. Infra-red radiations have larger wavelength than cosmic raysC. The frequency of microwaves is less than that of ultra-violet raysD. X-rays have larger wave number the micro waves |
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Answer» Correct Answer - A All types of electromagnetic radiations have same velocity |
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| 1765. |
The energy of photon is inversely proportional to itsA. WavelengthB. FrequencyC. WavenumberD. valency |
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Answer» Correct Answer - A `E = hv = (hc)/(lambda), E prop (1)/(lambda)` |
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| 1766. |
Many elements have non-integral atomic masses becauseA. they have isotopesB. their isotopes have non-integral massesC. their isotopes have different massesD. the cosstituents, neutrons, protons and electron combine to give fractional masses |
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Answer» Correct Answer - A::C At. Wt `=(P_(1)M_(1)+P_(2)M_(2)+...)/(p_(1)+p_(2)+...)` |
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| 1767. |
Which statement about cathode rays is/are correct?A. They travel in straight lines towards cathodeB. They produce fluorescent discharge through the walls of the tubeC. They produce heating effectD. They can affect photographic plate |
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Answer» Correct Answer - B::C::D Cathode rays properties |
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| 1768. |
Electromagnetic radiation with maximum wavelengths is :A. ultravioletB. radio waveC. X-rayD. infrared |
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Answer» Correct Answer - B |
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| 1769. |
The radiation with highest wave numberA. Micro wavesB. X-raysC. I.R. RadiationsD. Radiowaves |
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Answer» Correct Answer - B |X-rays|U.V rays|I.R.|Ratio `rarr lambda uarr` |
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| 1770. |
No. of visible lines when an electron returns from `5^(th)` orbit up to ground state in `H`spectrum :A. 5B. 4C. 3D. 10 |
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Answer» Correct Answer - C ( c) Visible lines `rArr` Balmer series `(5 rarr 2,4 rarr 2,3 rarr 2)`. So `3` lines. |
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| 1771. |
Which type of radiation has the highest frequency ?A. InfraredB. MicrowaveC. UltravioletD. X-rays |
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Answer» Correct Answer - D |
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| 1772. |
Quantum numbers l=2 and m=0 represent which orbital?A. `d_(xy)`B. `d_(x^(2)-y^(2))`C. `d_(z^(2))`D. `d_(zx)` |
| Answer» Correct Answer - C | |
| 1773. |
In a container a mixture is prepared by mixing of three samples of hydrogen helium ion `(He^(+))` and lithium ion `(Li^(2+)).` In sample , all the hydrogen atoms are in 1st excited state and all the `He^(+)` ions are in third excited state and all the `Li^(2+))` ions are in fifth excited state. Find the total number of spectral lines observed in the emission spectrum of such a sample when the electrons return back to the ground state. |
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Answer» Correct Answer - 20 |
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| 1774. |
A portons is accelrated to one -tenth of the velocity of light . If its velocity can be be measured with a precision `pm 1%`. wavelenght of `1 xx10^(-10)`m. |
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Answer» Correct Answer - `1.05xx10^(-13)m` `Delta"x".m.Deltage(h)/(4pi)` `Delta"x"ge(h)/(4pi.mDeltaV)=(h)/(4pim((c)/(10))xx((1)/(100)))` so `D"x"ge1.05xx10^(-13)m` |
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| 1775. |
Which statement concerning visible light is correct ?A. The product of wavelength and frequency is a constant for visible light in a vacuum.B. As the wavelength of light increases the energy of a photon increases.C. As the wavelength of light increases its amplitude also increases.D. Green light has a higher frequency than blue light . |
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Answer» Correct Answer - A |
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| 1776. |
The angular momentum of p electron isA. `sqrt( 2) h`B. `h`C. `sqrt(6) h`D. `2 h` |
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Answer» Correct Answer - A (a) Orbital angular momentum `L = sqrt(l(l + 1)) ħ` where `ħ = (h)/(2 pi)` :. `L` for `p` electron `= sqrt(1(1 + 1) ħ) = sqrt(2) ħ`. |
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| 1777. |
The work functions for metals ` A, B` and ( C) are presepctively ` 1. 92 eV` , `2, 0` eV 1 and ` 5.0 eV` According to Einstein equation , the metal which will emit photoelectron for a radistion fo wavelingth ` 4100 Å`/areA. A onlyB. (A) and (B) onlyC. A, B and ( C)D. None of these |
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Answer» Correct Answer - B `E= (12375)/(lambda_(("in "Å))) = (12375)/(4100) = 3.018 eV` Thus only (A) and (B) will eject photo electrons . |
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| 1778. |
Light of wavelength `lambda` falls on metal having work functions `hc//lambda_(0)` . Photoelectric effect will take place only if :A. `lambda ge lambda_(0)`B. `lambda ge 2 lambda_(0)`C. `lambda le lambda_(0)`D. `lambda le lambda_(0)//2` |
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Answer» Correct Answer - C |
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| 1779. |
The work function for metals X , Y and Z are respectively 1.92 eV , 2.0 eV and 5.0 eV . According to Einstein equation , the metal which will emit photoelectrons for a radiation of wavelength `4100 "Å"` is/ are :A. X onlyB. X and Y onlyC. X , Y and ZD. X and Z |
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Answer» Correct Answer - B |
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| 1780. |
The positive charge of an atom is.A. spread all over the atomB. distributed around the nucleusC. concentrated at the nucleusD. all of these |
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Answer» Correct Answer - C ( c) Positive charge of an atom is present in nucleus. |
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| 1781. |
Which of the following best explains light both as a stream of particles and wave motion ?A. DiffractionB. `lamda = h//p`C. InterferenceD. Photoelectric effect. |
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Answer» Correct Answer - B (b) `lamda = (h)/(p)` or `(h)/(mv)` or `(h)/(mc)` de-Broglie equation. |
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| 1782. |
The uncertainty in position and velocity of the particle are 0.1 nm and `5.27xx10^(-24) ms^(-1)` respectively then find the approximate integral mass of the particle (in g ) . `(h=6.625xx10^(-34) Js)` |
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Answer» Correct Answer - 100 |
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| 1783. |
The uncertainty in position and velocity of the particle are `0.1 nm` and `5.27 xx 10^-27 ms^-1` respectively. Then the mass of the particle is : `(h = 6.625 xx 10^-34 J s)`.A. 200gB. 300 gC. 100 gD. 1000 g |
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Answer» Correct Answer - C |
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| 1784. |
The uncertainty in position and velocity of the particle are `0.1 nm` and `5.27 xx 10^-27 ms^-1` respectively. Then the mass of the particle is : `(h = 6.625 xx 10^-34 J s)`.A. 200 gB. 300 gC. 100 gD. 1000 g |
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Answer» Correct Answer - C ( c) `Delta x = 0.1 xx 10^-9 m` `Delta V = 5.27 xx 10^-27 ms^-1` `:. Delta x xx m Delta V = (h)/(4 pi)` :. `0.1 xx 10^-9 xx m xx 5.27 xx 10^-27 = 0.527 xx 10^-34` `:. m = 0.1 kg = 100 g`. |
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| 1785. |
The uncertainty in position and velocity of the particle are `0.2mm` and `10.54xx10^(-27)ms^(-1)` respectively then the mass of the particle is `: ( h=6.625xx10^(-34)Js)`A. `48.86g`B. `30.86g`C. `24.86gm`D. `100g` |
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Answer» Correct Answer - 3 `Deltax=0.2 xx10^(-9)m`. `DeltaV=10.54xx10^(-27)ms^(-1)` `:. " "Deltax xxmDeltaV=(h)/(4pi)` `:." "0.2xx10^(-3)xxmxx10.54xx10^(-27)=0.527xx10^(-34)` `m=24.86gm` |
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| 1786. |
If wavelength is equal to the distance travelled by the electron in one second thenA. `lambda = h//p`B. `lambda = h//m`C. `lambda = sqrt(h//p)`D. `lambda = sqrt(h//m)` |
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Answer» Correct Answer - D `lambda = (h)/(mv)` distance travelled in one second by velocity `bar V = vcm = olambda` `lambda = (h)/(m lambda) rArr lambda^(2) = (h)/(m) rArr lambda = sqrt((h)/(m))` |
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| 1787. |
If wavelength is equal to the distance travelled by the electron in one second, thenA. `lambda=(h)/(p)`B. `lambda=(h)/(m)`C. `lambda=sqrt((h)/(p))`D. `lambda=sqrt((h)/(m))` |
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Answer» Correct Answer - D Acc to schrodinger model `e^(-)` behave as wave only. |
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| 1788. |
If wavelength is equal to the distance travelled by the electron in one second , then :A. `lambda = (h)/(p)`B. `lambda =(h)/(m)`C. `lambda = sqrt((h)/(p))`D. `lambda = sqrt((h)/(m)` |
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Answer» Correct Answer - D |
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| 1789. |
The mass number of three isotopes of an element are 10,12,14 units. Their percentage aboundance is 80,15 and 5 units respectively. What is the atomic weight of the element? |
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Answer» Percentage abundances of Isotopes =80,15,5 ratio of percentage abundances of Isotopes =16:3:1 The total ratio `= 16 +3 +1 = 20` avg. Awt `=(sum "ratio of % abundance" xx "Atomic weights")/("Total ratio")` `= (10 xx 16 +12 xx 3 +14 xx 1)/(20) = 10.5` The average Atomic weight `=10.5` |
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| 1790. |
The value of the spin only magnetic moment of a particular ion is 2.83 Bohr magneton. The ion isA. `Fe^(2+)`B. `Ni^(2+)`C. `Mn^(2+)`D. `Co^(3+)` |
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Answer» Correct Answer - B `mu = sqrt(n(n+2))` Where `n = 2` |
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| 1791. |
Which of the following ion is not isoelectronic with `O^(2-)` ?A. `N^(3-)`B. `F^-`C. `TI^(+)`D. `Na^(+)` |
| Answer» Correct Answer - C | |
| 1792. |
Calculate the minimum uncertainty in velocity of a particle of mass `1.1 xx 10^-27 kg` if uncertainty in its position is `3 xx 10^-10 cm`.A. `1.5 xx 10^-4 m`B. `2.5 xx 10^-4 m`C. `3.5 xx 10^-4 m`D. `4.5 xx 10^-4 m` |
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Answer» Correct Answer - A (a) `Delta x, Delta v ge (h)/(4 pi m)` `Delta v ge (h)/(Delta x. 4 pi. M)` =`(6.6 xx 10^-34)/(3 xx 10^-10 xx 10^-2 m xx 4 xx 3.14 xx 1.1 xx 10^-27)` =`1.5 xx 10^-4 m`. |
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| 1793. |
If wavelength is equal to the distance travelled by the electron in one second, thenA. `lamda = (h)/(p)`B. `pi = (h)/(m)`C. `lamda = sqrt((h)/(p))`D. `lamda = sqrt((h)/(m))` |
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Answer» Correct Answer - D (d) `lamda = v` then `lamda = (h)/(mV)` or `lamda^2 = (h)/(m)` So, `lamda = sqrt((h)/(m))`. |
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| 1794. |
The relative atomic mass of an element A is 16.2 . There are two isotopes `""_(8)^(16)A` and `""_(8)^(18)A` of the element. Calculate the percentage of these two isotopes present in the element . |
| Answer» `""_(8)^(16)A=90%, ""_(8)^(18)A=10%` | |
| 1795. |
A naturally occuring sample of lithium contains 7.42% of `""^(6)Li` and 92.58% `""^(7)Li`. The relative atomic mass of `""^(6)Li` is 6.015 and that of `""^(7)Li` is 7.016. Calculate the atomic mass of a naturally occuring sample of lithium. |
| Answer» Atomic mass `=((6.015xx7.42)(7.016xx92.58))/(100)=6.94` | |
| 1796. |
The hydride ions `(H^-)` are isoelectronic withA. `L i`B. `He^+`C. `He`D. `Be` |
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Answer» Correct Answer - C ( c) `H^- = 1 s^2 and He = 1 s^2`. |
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| 1797. |
The hydride ion is isoelectronic with Electromagnetic RadiationA. `H^(+)`B. `He^(+)`C. HeD. Be |
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Answer» Correct Answer - C Hydride ion `(H^(-))` have 2 electrons |
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| 1798. |
Which combinations of quantum number `n,l,m,s` for the electron in an atom does not provide a permission solution of the wave equation ?A. `3,2,-2,1//2`B. `3,3,1,-1//2`C. `3,2,1,1//2`D. `3,1,1,-1//2` |
| Answer» Correct Answer - B | |
| 1799. |
The ratio of the atomic numbers of two elements A and B is `2:3` A is an intery gas the first 3 orbits completely filled. Identify A and B and write their electronic configurations. |
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Answer» `Ato` electronic configuration `-2,8,18,8`. Thus, the atomic number `=36`. `A:B=2:3` `therefore B=(36xx3)/(2)=54` The electronic configuration of `B=2,8,18,18,8` |
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| 1800. |
The hydride ions `(H^-)` are isoelectronic withA. LiB. `He^+`C. HeD. Be |
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Answer» Correct Answer - C `H^- =1s^2` and `He^+ =1s^2` |
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