Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

In differential encoding the _________ different between two wave forms is measured.(a) Magnitude(b) Frequency(c) Phase(d) Time periodThis question was addressed to me in an internship interview.My query is from Coherent Detection topic in division Bandpass Modulation and Detection of Digital Communications

Answer»

The correct answer is (c) Phase

The EXPLANATION is: In DIFFERENTIAL ENCODING, the phase of the present signal waveform is COMPARED with the phase of the previous signal.

2.

Matched filter is used for(a) Coherent detection(b) Non coherent detection(c) Coherent & Non coherent detection(d) None of the mentionedThe question was asked by my college director while I was bunking the class.This key question is from Coherent Detection topic in section Bandpass Modulation and Detection of Digital Communications

Answer»

The correct OPTION is (a) COHERENT detection

To EXPLAIN I WOULD say: Matched filter is used for coherent detection. It cannot be used for non coherent detection because matched filter output is a function of UNKNOWN angle α.

3.

As limit of k increases, the ratio of PB/PE becomes(a) 1:2(b) 2:1(c) 1:3(d) 3:1This question was posed to me in final exam.This key question is from M-ary Signalling and Performance topic in portion Bandpass Modulation and Detection of Digital Communications

Answer»

Correct answer is (a) 1:2

The EXPLANATION: As the LIMIT of k INCREASES, the ratio of PB/PE BECOMES 1:2.

4.

The relation between the probability of bit error and probability of symbol error in M-ary orthogonal signalling is(a) M/M-1(b) 2M/M-1(c) (M/2)/M-1(d) M/M+1The question was asked by my college professor while I was bunking the class.Question is taken from M-ary Signalling and Performance in division Bandpass Modulation and Detection of Digital Communications

Answer»

Right answer is (c) (M/2)/M-1

Easy EXPLANATION: The RELATIONSHIP between the PROBABILITY of BIT error and probability of symbol error is (M/2)/M-1 in M-ary orthogonal signalling.

5.

Energy per symbol Es is given as(a) Es=Eb(log2M)(b) Es=Eb/(log2M)(c) Es=2Eb(log2M)(d) Es=Eb/2(log2M)This question was addressed to me in an interview.I'd like to ask this question from M-ary Signalling and Performance topic in division Bandpass Modulation and Detection of Digital Communications

Answer»

The correct choice is (a) Es=Eb(log2M)

To EXPLAIN I would say: In M-ary PSK SIGNALLING, the ENERGY per symbol is given as Es=Eb(log2M).

6.

For FSK signalling, WT is equal to(a) 0(b) 1(c) 0.737(d) InfinityThe question was posed to me in class test.Origin of the question is M-ary Signalling and Performance in portion Bandpass Modulation and Detection of Digital Communications

Answer»

Right choice is (b) 1

Easy explanation: For FSK signalling the detection BANDWIDTH is typically EQUAL to SYMBOL RATE 1/T that is WT is nearly equal to 1.

7.

In orthogonal signalling with symbols containing more number of bits we need ____ power.(a) More(b) Less(c) Double(d) None of the mentionedI got this question in class test.I would like to ask this question from M-ary Signalling and Performance topic in division Bandpass Modulation and Detection of Digital Communications

Answer»

The correct OPTION is (a) More

To explain: In ORTHOGONAL signalling with SYMBOLS having more NUMBER of bits need more power but requirement PER bit is reduced.

8.

In MPSK adding new signals _______ make it vulnerable to noise and in MFSK _______ make it vulnerable.(a) Does, does not(b) Does not, does(c) Does, does(d) Does not, does notThe question was posed to me in an online quiz.The query is from M-ary Signalling and Performance in portion Bandpass Modulation and Detection of Digital Communications

Answer» CORRECT answer is (a) Does, does not

Easy explanation: In MPSK adding new signals that is on CROWDING the signals it makes it vulnerable to NOISE where as in MFSK it does not.
9.

The error performance of MPSK ______ as M or k increases.(a) Increases(b) Decreases(c) Stays constant(d) None of the mentionedThe question was posed to me in a job interview.This key question is from M-ary Signalling and Performance in section Bandpass Modulation and Detection of Digital Communications

Answer» RIGHT OPTION is (b) Decreases

Explanation: The ERROR performance of MPSK degrades as M or k increases.
10.

In which system, bit stream is portioned into even and odd stream?(a) BPSK(b) MSK(c) QPSK(d) FSKI got this question during an interview.My question comes from M-ary Signalling and Performance in division Bandpass Modulation and Detection of Digital Communications

Answer»

Correct OPTION is (c) QPSK

The best explanation: In QPSK bit stream is PORTIONED into even and ODD stream, I and Q bit STREAMS. Each new stream modulates as orthogonal COMPONENT at half bit rate.

11.

M-ary signalling produces _______ error performance with orthogonal signalling and _______ error performance with multiple phase signalling.(a) Degraded, improved(b) Improved, degraded(c) Improved, improved(d) Degraded, degradedThe question was posed to me in class test.The origin of the question is M-ary Signalling and Performance topic in section Bandpass Modulation and Detection of Digital Communications

Answer»

Correct OPTION is (b) Improved, degraded

The best EXPLANATION: In M-ary signalling as K increases, the curve moves towards the degraded ERROR performance. It produces improved error performance in CASE of orthogonal signalling and degraded error performance in case of multiple phase signalling.

12.

Which is more vulnerable to noise?(a) 2-ary system(b) 4-ary system(c) Binary system(d) None of the mentionedThe question was posed to me during an online interview.My question comes from M-ary Signalling and Performance in section Bandpass Modulation and Detection of Digital Communications

Answer»

The CORRECT answer is (b) 4-ary system

Best explanation: The MINIMUM energy noise vector for 4-ary system is SMALLER than 2-ary system. So 4-ary system is more VULNERABLE to noise.

13.

The limit which represents the threshold Eb/N0 value below which reliable communication cannot be maintained is called as(a) Probability limit(b) Error limit(c) Shannon limit(d) Communication limitThe question was asked in a job interview.My enquiry is from M-ary Signalling and Performance in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

Right choice is (C) Shannon limit

To EXPLAIN: Eb/N0 curve has waterfall shape. Shannon limit GIVES the THRESHOLD value below which reliable COMMUNICATION cannot be maintained.

14.

The error probability of DPSK is ________ worse than PSK.(a) Twice(b) 3 db(c) Twice (3db)(d) None of the mentionedI have been asked this question in an online interview.The question is from Coherent Detection in section Bandpass Modulation and Detection of Digital Communications

Answer» RIGHT option is (c) Twice (3db)

EASIEST EXPLANATION: DPSK has twice as much as NOISE than in PSK. The error probability in DPSK is twice (3db) worse than PSK.
15.

The minimum tone separation corresponds to(a) T(b) 1/T(c) 2T(d) T/2This question was posed to me by my college professor while I was bunking the class.My enquiry is from Coherent Detection topic in division Bandpass Modulation and Detection of Digital Communications

Answer»

The CORRECT ANSWER is (B) 1/T

To explain I would say: In non COHERENT detection the minimum tone separation CORRESPONDS to 1/T.

16.

The minimum required spacing is the difference between the(a) Center of the spectral main lobe and first zero crossing(b) First and second zero crossing(c) First and last zero crossing(d) None of the mentionedThe question was posed to me in an interview for internship.I'd like to ask this question from Coherent Detection in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

Right OPTION is (a) Center of the spectral main lobe and first ZERO CROSSING

The explanation is: The frequency difference between the center of the spectral main lobe and the first zero crossing is CALLED as the minimum REQUIRED spacing in non coherent detection.

17.

Envelope detector consists of(a) Rectifier and high pass filter(b) Rectifier and low pass filter(c) Amplifier and low pass filter(d) Amplifier and high pass filterThis question was posed to me in an online quiz.I would like to ask this question from Coherent Detection in portion Bandpass Modulation and Detection of Digital Communications

Answer»

Right choice is (B) Rectifier and LOW pass filter

The EXPLANATION: An envelope detector consists of a rectifier and a low pass filter. The detectors are MATCHED to the envelopes and not to the SIGNAL themselves.

18.

In differential PSK the date is(a) Encoded differentially(b) Decoded differentially(c) Encoded & Decoded differentially(d) None of the mentionedI got this question at a job interview.My question is from Coherent Detection topic in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

Correct CHOICE is (a) Encoded differentially

For explanation I would say: In this method, the data is encode deferentially that is the presence of binary zero or one is MANIFESTED by symbol’s similarity or DIFFERENCE when COMPARED to that of the previous symbol.

19.

Phase-locked loop circuitry is used for(a) Carrier wave recovery(b) Phase estimation(c) Carrier wave recovery & Phase estimation(d) None of the mentionedI got this question in a national level competition.The doubt is from Coherent Detection in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

The correct ANSWER is (C) Carrier wave recovery & Phase estimation

Explanation: The phase locked loop circuitry locks on the ARRIVING carrier wave and ESTIMATES its phase.

20.

The minimum nyquist sampling rate is given as, fs =(a) 1/T(b) T(c) 2/T(d) 2TI had been asked this question during an online exam.I'd like to ask this question from Coherent Detection in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

Correct ANSWER is (a) 1/T

Explanation: The input signal comprises of a PROTOTYPE signal plus NOISE and the bandwidth is 1/2T where T is the symbol TIME and minimum nyquist sampling rate can be GIVEN as 2W or 1/T.

21.

The correlating detector is also known as(a) Maximum likelihood detector(b) Minimum likelihood detector(c) Maximum & Minimum likelihood detector(d) None of the mentionedThe question was posed to me in homework.My question is taken from Coherent Detection in portion Bandpass Modulation and Detection of Digital Communications

Answer»

Correct CHOICE is (a) MAXIMUM LIKELIHOOD detector

The best I can explain: Coherent detector considers PHASE as the most IMPORTANT parameter. This coherent detector is also known as maximum likelihood detector.

22.

The transformation of the waveform into a single point in signal space is called as(a) Vector point(b) Predetection point(c) Preamplification point(d) Transformation pointI got this question in a job interview.The above asked question is from Digital Bandpass Modulation Techniques topic in division Bandpass Modulation and Detection of Digital Communications

Answer»

Right answer is (B) Predetection point

Easy explanation: The first step of the DETECTION process is to reduce waveform into a single or GROUP of random variable. This first step in the transformation of waveform into a point in signal space. This point is CALLED as predetection point.

23.

Which modulation scheme is also called as on-off keying method?(a) ASK(b) FSK(c) PSK(d) GMSKI had been asked this question during an interview.The origin of the question is Digital Bandpass Modulation Techniques topic in section Bandpass Modulation and Detection of Digital Communications

Answer»

Correct choice is (a) ASK

The best explanation: In ASK modulation scheme the SIGNAL attains either maximum AMPLITUDE or ZERO point. Thus it is ALSO called as on-off keying.

24.

In amplitude phase keying each phase vector is separated by(a) 90(b) 0(c) 45(d) 180The question was posed to me at a job interview.I need to ask this question from Digital Bandpass Modulation Techniques topic in division Bandpass Modulation and Detection of Digital Communications

Answer» CORRECT option is (c) 45

Explanation: The COMBINATION of ASK and PSK is CALLED as APK. In APK each vector is separated by 45.
25.

The FSK signal which has a gentle shift from one frequency level to another is called as(a) Differential PSK(b) Continuous PSK(c) Differential & Continuous PSK(d) None of the mentionedThe question was posed to me by my college director while I was bunking the class.The question is from Digital Bandpass Modulation Techniques topic in section Bandpass Modulation and Detection of Digital Communications

Answer»
26.

Antipodal signal sets are those vectors that can be illustrated as(a) Two 180 opposing vector(b) Two 90 opposing vector(c) Two 360 opposing vector(d) None of the mentionedI have been asked this question in an online quiz.My question is based upon Digital Bandpass Modulation Techniques topic in portion Bandpass Modulation and Detection of Digital Communications

Answer»

Right option is (a) Two 180 opposing vector

Best explanation: In BPSK the two VECTORS, the signal SET can be ILLUSTRATED as two 180 opposing vector which is called as ANTIPODAL signal sets.

27.

The real part of a sinusoid carrier wave is called as(a) Inphase(b) Quadrature(c) Inphase & Quadrature(d) None of the mentionedI got this question during an interview.The above asked question is from Digital Bandpass Modulation Techniques in division Bandpass Modulation and Detection of Digital Communications

Answer»

Right answer is (a) INPHASE

The BEST I can explain: The TWO main PARTS of sinusoid carrier wave – REAL part is called as inphase and the imaginary part is called as quadrature.

28.

The coherent modulation techniques are(a) PSK(b) FSK(c) ASK(d) All of the mentionedI have been asked this question in class test.I want to ask this question from Digital Bandpass Modulation Techniques topic in portion Bandpass Modulation and Detection of Digital Communications

Answer»

The correct answer is (d) All of the mentioned

The explanation is: Some of the examples of COHERENT modulation techniques are phase SHIFT KEYING, AMPLITUDE shift keying, FREQUENCY shift keying and continuous phase modulation.

29.

The detection method where carrier’s phase is given importance is called as(a) Coherent detection(b) Non coherent detection(c) Coherent detection & Non coherent detection(d) None of the mentionedThis question was addressed to me during a job interview.The origin of the question is Digital Bandpass Modulation Techniques in chapter Bandpass Modulation and Detection of Digital Communications

Answer»

Right choice is (a) COHERENT detection

The best I can explain: When the receiver USES CARRIER’s phase as major factor for detection then it is called as coherent detection and when carrier is not given importance it is called as NON coherent detection.

30.

Wavelength and antenna size are related as(a) λ/2(b) λ/4(c) 2λ(d) 4λThe question was posed to me in a job interview.The origin of the question is Digital Bandpass Modulation Techniques topic in portion Bandpass Modulation and Detection of Digital Communications

Answer» CORRECT CHOICE is (b) λ/4

Easy explanation: The transmission of EM field in space is done with the help of ANTENNAS. Antenna size depends of the wavelength. The length of the antenna is EQUAL to λ/4.