InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 18251. |
Sorth the following into actively or passively transported substances during reabsorption of GFR. e.g., glucose, amino acids, nitrogenous wastes, Na+ water. |
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Answer» Sorth the following into actively or passively transported substances during reabsorption of GFR. e.g., glucose, amino acids, nitrogenous wastes, Na+ water. |
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| 18252. |
Given below are a few floral formulae of some well known plants. Draw floral diagrams from these formulae. (i) ⨁ K(5) C(5) A(5) G(2)− (ii) K(5) C1+2+2 A(9)+1 G1− (iii) ⨁ K5 C5 A5+5 G(5) |
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Answer» Given below are a few floral formulae of some well known plants. Draw floral diagrams from these formulae. (i) ⨁ K(5) C(5) A(5) G(2)− (ii) K(5) C1+2+2 A(9)+1 G1− (iii) ⨁ K5 C5 A5+5 G(5) |
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| 18253. |
A structure used by bryophytes to produce spores is called _______ |
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Answer» A structure used by bryophytes to produce spores is called _______ |
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| 18254. |
Lignin and cellulose present in xylem vessels shows affinity for water due to |
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Answer» Lignin and cellulose present in xylem vessels shows affinity for water due to |
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| 18255. |
Conjoint, collateral, open and endarch vascular bundles are found in |
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Answer» Conjoint, collateral, open and endarch vascular bundles are found in |
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| 18256. |
How much percentage of pollen grains do angiosperms sheds at 2- celled stage? |
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Answer» How much percentage of pollen grains do angiosperms sheds at 2- celled stage? |
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| 18257. |
A cross is made between true breeding lines of pea plants with axillary (A) and terminal (a) flowers. What is the ratio between the number of possible genotypes of homozygous and heterozygous plants in F2 progeny? |
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Answer» A cross is made between true breeding lines of pea plants with axillary (A) and terminal (a) flowers. What is the ratio between the number of possible genotypes of homozygous and heterozygous plants in F2 progeny? |
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| 18258. |
How does secondary growth takes place in dicot stem? |
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Answer» How does secondary growth takes place in dicot stem? |
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| 18259. |
Metanephros kidney occurs is |
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Answer» Metanephros kidney occurs is |
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| 18260. |
A lymphocytes is most likely to encounter it's specific antigen when it is in the 1.bone marrow 2.spleen 3.thymus 4.cardiac muscle |
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Answer» A lymphocytes is most likely to encounter it's specific antigen when it is in the 1.bone marrow 2.spleen 3.thymus 4.cardiac muscle |
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| 18261. |
The epithelial lining of the inner wall of trachea bears cilia. What may be the purpose of this? |
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Answer» The epithelial lining of the inner wall of trachea bears cilia. What may be the purpose of this? |
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| 18262. |
The carbohydrates on the extracellular membrane forms |
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Answer» The carbohydrates on the extracellular membrane forms |
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| 18263. |
A woman with regular menstrual cycle is not menstruating. Which one of the following is the most likely root cause of this? |
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Answer» A woman with regular menstrual cycle is not menstruating. Which one of the following is the most likely root cause of this? |
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| 18264. |
If in a pond there were 40 lotus plants last year and through reproduction 16 new plants are added, taking the current population to 56, now the birth rate will be |
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Answer» If in a pond there were 40 lotus plants last year and through reproduction 16 new plants are added, taking the current population to 56, now the birth rate will be |
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| 18265. |
A student looking through a light microscope saw this cell in cytokinesis. This cell is most likely from |
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Answer» A student looking through a light microscope saw this cell in cytokinesis. This cell is most likely from |
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| 18266. |
Match the following columns. Column I Column IIA. Cuticle1. Guard cellsB. Bulliform cells2. Single layerC. Stomata3. Waxy layerD. Epidermis4. Empty colourless cell Codes A B C D (a) 3 4 1 2 (b) 1 2 3 4 (c) 3 2 4 1 (d) 3 2 1 4 |
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Answer» Match the following columns. Column I Column IIA. Cuticle1. Guard cellsB. Bulliform cells2. Single layerC. Stomata3. Waxy layerD. Epidermis4. Empty colourless cell Codes A B C D (a) 3 4 1 2 (b) 1 2 3 4 (c) 3 2 4 1 (d) 3 2 1 4 |
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| 18267. |
Removal of the ring of tissue outside the vascular cambium from the tree trunk kills it because. |
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Answer» Removal of the ring of tissue outside the vascular cambium from the tree trunk kills it because. |
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| 18268. |
Which one of the following statements is incorrect regarding IUDs? |
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Answer» Which one of the following statements is incorrect regarding IUDs? |
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| 18269. |
a decimolar solution of potassium ferrocyanide is 5% dissociated at 300 Kelvin calculate Osmotic pressure of solution |
| Answer» a decimolar solution of potassium ferrocyanide is 5% dissociated at 300 Kelvin calculate Osmotic pressure of solution | |
| 18270. |
what is the figure given below showing in particular? |
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Answer» what is the figure given below showing in particular? |
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| 18271. |
The smallest animal egg is that of |
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Answer» The smallest animal egg is that of |
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| 18272. |
Which one of the following is not a poisonous snake? (a) Cobra (b) Viper (c) Python (d) Krait |
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Answer» Which one of the following is not a poisonous snake? (a) Cobra (b) Viper (c) Python (d) Krait |
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| 18273. |
Consider the following statements: (a) The portion of the spectrum between 500 nm and 800 nm is also referred to as photosynthetically active radiation (PAR). (b) Magnesium, calcium and chloride ions play prominent roles in the photolysis of water. (c) In cyclic photophosphorylation, oxygen is not released (as there is no photolysis of water) and NADPH is also not produced. Of these statements given above, |
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Answer» Consider the following statements: (a) The portion of the spectrum between 500 nm and 800 nm is also referred to as photosynthetically active radiation (PAR). (b) Magnesium, calcium and chloride ions play prominent roles in the photolysis of water. (c) In cyclic photophosphorylation, oxygen is not released (as there is no photolysis of water) and NADPH is also not produced. Of these statements given above, |
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| 18274. |
Match the following columns and choose the correct option. Column−IColumn−III. Mutational BreedingP. Laborious and expensive process to obtain gene variation.II. SelectionQ. Hybrid vigour can be maintained for several generation.III. HybridizationR. Simplest and easiest method of plant improvement.IV. IntroductionS. Oldest breeding method T Quick method to obtain gene variation |
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Answer» Match the following columns and choose the correct option. Column−IColumn−III. Mutational BreedingP. Laborious and expensive process to obtain gene variation.II. SelectionQ. Hybrid vigour can be maintained for several generation.III. HybridizationR. Simplest and easiest method of plant improvement.IV. IntroductionS. Oldest breeding method T Quick method to obtain gene variation |
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| 18275. |
A monohybrid cross between two plants, one having 22 cm long internodes and the other having 12 cm long internodes, produced F1 hybrids all of 18 cm long internodes. This is a case of |
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Answer» A monohybrid cross between two plants, one having 22 cm long internodes and the other having 12 cm long internodes, produced F1 hybrids all of 18 cm long internodes. This is a case of |
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| 18276. |
This graph is a typical cell cycle representing DNA content of various phases (1 to 4). Identify the phases based on changes in the DNA content and select the correct option. |
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Answer» This graph is a typical cell cycle representing DNA content of various phases (1 to 4). Identify the phases based on changes in the DNA content and select the correct option. |
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| 18277. |
Chief function of crista and macula is: |
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Answer» Chief function of crista and macula is: |
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| 18278. |
A population will not exist in Hardy-Weinberg equilibrium if: |
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Answer» A population will not exist in Hardy-Weinberg equilibrium if: |
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| 18279. |
Give two examples each of sample, population and variable. |
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Answer» Give two examples each of sample, population and variable. |
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