InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1501. |
Question : The growth regulator that retards ageing of plant organs is |
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Answer» auxin |
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| 1502. |
Question : The growth of pollen tubes towards ovules is the example of : |
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Answer» hydrotropism |
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| 1503. |
Question : The growth of a pea plant depends on the amount of specific ……………………………..in the plant. |
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Answer» |
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| 1504. |
Question : Fill in the blanks: (i) _____causes stomatal closure. (ii) The growth and functions of thyroid gland is controlled by_____. |
| Answer» SOLUTION :HORMONE `T_3` and `T_4` | |
| 1505. |
Question : The group of sepals is called : |
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Answer» corolla |
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| 1506. |
Question : The group of organisms that reproduce through fission only is |
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Answer» AMOEBA, HYDRA, Spyrogyra |
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| 1507. |
Question : The greatest evolutionary change enabling the land vertebrates to be completely free from water habitat is the development of |
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Answer» FOUR legs |
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| 1508. |
Question : The Gram's stain used to stain bacteria is |
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Answer» SAFRANIN and iodine |
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| 1509. |
Question : The Gram's stain used for bacterial staining |
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Answer» SAFRANIN and iodine |
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| 1510. |
Question : The golgi complex plays a major role in |
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Answer» DIGESTING proteins and carbs |
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| 1511. |
Question : The "Golden age of Reptiles" was |
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Answer» LATE Paleozoic |
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| 1512. |
Question : The glass snake is a |
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Answer» LIMBLESS amphibian |
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| 1513. |
Question :The glandular follicles of thyroid gland are filled with colloid material called…….. |
| Answer» SOLUTION :Thyroglobulin | |
| 1514. |
Question : The given parts belong to which system ? Draw a neat labelled diagram of the system. a) Kidneys b) Ureters c) Urinary bladder |
Answer» Solution :The given PARTS belong to HUMAN EXCRETORY SYSTEM.
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| 1515. |
Question : The given figure represents |
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Answer» Buds |
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| 1516. |
Question : The germ cell A produced by a person X is round in shape and it fuses with another germ cell B having a long tail and produced by a person Y. The fusion of A and B produces a new cell C. The cell C divides repeatedly and grows inside the organ D of person X to form E in which the body features of the unborn baby are not much developed. E grows further to form F in which the various body features of the unborn baby (like hands, legs, eyes, and ears, etc.) can be identified. F grows further and ultimately forms a baby. What are A,B C,D E and F? Out of the two person X and Y, which one is male and which one female? |
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Answer» |
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| 1518. |
Question : The Geotype of female bird is, |
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Answer» A+ZW |
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| 1519. |
Question : The geographical isolation along with the variations leads to the formation of …………………………….. |
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Answer» |
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| 1520. |
Question : The genotype of green-stemmed tomato plants is denoted by GG and that of purple-stemmed tomato plants as gg. When these two plants are crossed : (i) What colour of stem would you expect in their F_(1)progeny? (ii) Give the percentage of purple-stemmed plant if F_(1)plants are self pollinated. (iii) In what ratio would you find the green and purple colour in the F_(1)progeny? |
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Answer» Solution :(i) Green COLOUR. (II) 25%. (III) 3:1. |
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| 1521. |
Question : The genotype of green stemmed tomato plant is denoted by GG and that of purple stemmed tomato plant as gg. Hybrids of a cross between these two were selfed to obtain F2 progeny, what will be the ratio of GG, Gg and gg in this progeny ? |
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Answer» GG2 : Gg1 : gg1 RATIO of the PROGENY is GG1 : Gg2: gg1. |
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| 1522. |
Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: Give the % age of wrinkled seeded plants if F1 plants are self-pollinated. |
Answer» Solution : Percentage of WRINKLED SEED PLANTS on selfing of F1 plants will be 25%. |
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| 1523. |
Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: In which ratio do you find RR, Rr and rr in F2 progeny ? |
Answer» SOLUTION : 1 : 2 : 1 for RR, Rr and rr. |
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| 1524. |
Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: What will be the phenotype expected in F1 generation ? |
Answer» SOLUTION : F1 PHENOTYPE will be all ROUND. |
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| 1525. |
Question : The genotype of a dominant parent is determined by crossing it with the recessive parent. This cross is called |
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Answer» BACK CROSS |
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| 1526. |
Question : The genetic variation created during reproduction is the basis for …………………. |
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Answer» |
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| 1527. |
Question : The gene ‘T’ for the character of tallness in pea plant is dominant and gene ‘t’ is recessive. Explain it on the basis of Mendel’s experiment. |
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Answer» <P> Solution :Mendel selected garden pea plant (Pisum sativum) as an experimental material. The pea plant shows various characters and atleast two contrasting expressions for each of the characters.Mendel selected height of the pea plant. The two contrasting expressions for the height of pea plants are tall plants and SHORT plants. Mendel crossed the tall parent (P) plant, (TT), with another short parent (P) plant (tt), and obtained all tall plants in `F_(1)` generation. None of the short plants were produced in `F_(1)` generation. They were also not of medium height. It means that only one parental characteristic was expressed in the OFFSPRINGS. When the plants of `F_(1)` generation were allowed to self-pollinate, about `75%` plants were tall and about `25 %` were short in the `F_(2)` generation. Thus, the genes for tallness and shortness both are capable of being inherited from the parents of `F_(1)` generation. This INDICATES that both the tallness and shortness traits were inherited in the `F_(1)` plants, but only the tallness trait was expressed. This led Mendel to propose that two copies of factor (gene) controlling traits are PRESENT in sexually reproducing organism. These two may be identical or may be different. This experiment indicates that the genes TT or genes Tt is the genetic constitution for tall plants while tt for the short plant. It means that only presence of gene T is responsible for the expression of tallness while the absence of dominant gene T and tt genes produces shortness. Thus, tallness in pea plant is the dominant trait and shortness is the recessive trait. |
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| 1528. |
Question : The gene for red hair is recessive to the gene for black hair. What will be the hair colour of a person if he inherits a gene for red hair from his mother and a gene for black hair from his father ? Form the flow chart of this cross. |
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Answer» Solution :Given that RED HAIR- Recessive `therefore` bb. BLACK hair - DOMINANT `therefore` BB. his person inherits one recessive gene (b) from mother and a dominant gene (B) from father ie-, Hence, this person will have black hair as he is heterozygous for black. |
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| 1529. |
Question : The gene for brown coloured hair is recessive that of gene for black coloured hair. What is the hair colour of a person who has inherited a gene for brown coloured hair from mother andblack coloured hair from father? |
| Answer» SOLUTION :`{:(," BLACK",),("Black(BB)",""XX,"BROWN(bb)"),(,"Bb(Black)",):}` | |
| 1530. |
Question : The gas released from vehicles exhaust arei. Carbon monoxideii. Sulphur dioxide iii. Oxides of nitrogen |
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Answer» i and II |
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| 1531. |
Question : The gas-exchange surfaces of larger aquatic animals are |
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Answer» tracheae |
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| 1532. |
Question : The gametophytes of bryophytes and pteridophytes are different from thatof gymnosperms. How ? |
| Answer» Solution :Male and FEMALE gametophyte have free existence in bryophytes and PTERIDOPHYTES but not in Gymnosperms. They remain within sporangia RETAINED on sporophytes. | |
| 1533. |
Question : The gamete cells, which have only one set of chromosomes is called ......... |
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Answer» diploid |
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| 1534. |
Question : The gametes and spores of phaeophyceae have a distinct morphology. Give its name. |
| Answer» Solution :Pyriform (pear-shaped), bear TWO LATERALLY attached FLAGELLA. | |
| 1535. |
Question : The Galapagos Islands are associated with the visit of |
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Answer» JEAN Lamarck |
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| 1536. |
Question : The fungi growing on cow dung belongs to, |
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Answer» ZYGOMYCETES |
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| 1537. |
Question : The functional respiratory organ of a fully formed tadpole is the |
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Answer» skin |
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| 1538. |
Question : The function of vitamin K is in |
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Answer» regulation of CALCIUM and PHOSPHORUS METABOLISM |
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| 1539. |
Question : The function of kidney in mammals is to excrete |
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Answer» EXTRA UREA, extra WATER and extra amino acids |
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| 1540. |
Question : The function of Haemoglobin is : |
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Answer» To TRANSPORT `O_(2)` in the BODY |
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| 1541. |
Question : The fruits showing edible thalamus are |
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Answer» Apple, CUSTARD, apple , GUAVA |
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| 1542. |
Question : The fruits in which thalamus also contributes to fruit formation are called |
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Answer» TRUE fruits |
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| 1543. |
Question : The fossil remains of Archaeopteryx is a connecting link between |
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Answer» amphibians |
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| 1544. |
Question : Theformof sugartransportedthroughthephloemis glucose . |
| Answer» SOLUTION :Correct STATEMENT: The FORM of sugar transported through the phloem is SUCROSE | |
| 1545. |
Question : The form and structure of growing cells are maintained because of |
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Answer» osmosis |
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| 1546. |
Question : The forest conserved in the name ot God is called……….. . |
| Answer» SOLUTION :SACRED GROVE | |
| 1547. |
Question : The Forest Conservation Act was enacted in ……….. . |
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Answer» 1980 |
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| 1548. |
Question : The forelimbs of bat and human are examples of. . . . . . . .organs. |
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Answer» |
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| 1549. |
Question : The force of attraction between the molecules of companion cells is called cohesion. |
| Answer» SOLUTION :CORRECT Statement: The force of attraction between the molecules of WATER is called cohesion. | |
| 1550. |
Question : The food reserve for energy in producesrs (autotrophs) is |
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Answer» fat. |
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