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1501.

Question : The growth regulator that retards ageing of plant organs is

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auxin
gibberellin
cytokinin
abscisic acid

Answer :C
1502.

Question : The growth of pollen tubes towards ovules is the example of :

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hydrotropism
GEOTROPISM
CHEMOTROPISM
PHOTOTROPISM

Answer :C
1503.

Question : The growth of a pea plant depends on the amount of specific ……………………………..in the plant.

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ANSWER :HORMONES
1504.

Question : Fill in the blanks: (i) _____causes stomatal closure. (ii) The growth and functions of thyroid gland is controlled by_____.

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SOLUTION :HORMONE `T_3` and `T_4`
1505.

Question : The group of sepals is called :

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corolla
CALYX
androecium
gynoecium

Solution :calyx
1506.

Question : The group of organisms that reproduce through fission only is

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AMOEBA, HYDRA, Spyrogyra
Leishmania, Amoeba, Yeast
Amoeba, PLASMODIUM, Planaria
Plasmodium, Amoeba, Leishmania.

Answer :D
1507.

Question : The greatest evolutionary change enabling the land vertebrates to be completely free from water habitat is the development of

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FOUR legs
four CHAMBERED heart
internal fertilisation
lungs 

ANSWER :C
1508.

Question : The Gram's stain used to stain bacteria is

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SAFRANIN and iodine
cotton BLUE and iodine
CRYSTAL violet and iodine
crystal violet and COTON blue

Solution :N/A
1509.

Question : The Gram's stain used for bacterial staining

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SAFRANIN and iodine
crystal VIOLET and cotton blue 
cotton blue and iodine 
crystal violet and iodine 

Answer :D
1510.

Question : The golgi complex plays a major role in

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DIGESTING proteins and carbs
in trapping light and transforming it into CHEMICAL ENERGY
in GLYCOSIDATION of lipids and proteins to produce GLYCOLIPIDS and glycoproteins
as energy transferring organelles

Solution :N/A
1511.

Question : The "Golden age of Reptiles" was

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LATE Paleozoic
cenozoic
mesozoic
proterozoic

Answer :C
1512.

Question : The glass snake is a

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LIMBLESS amphibian
limbless lizard
white snake
limbless FISH 

ANSWER :B
1513.

Question :The glandular follicles of thyroid gland are filled with colloid material called……..

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SOLUTION :Thyroglobulin
1514.

Question : The given parts belong to which system ? Draw a neat labelled diagram of the system. a) Kidneys b) Ureters c) Urinary bladder

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Solution :The given PARTS belong to HUMAN EXCRETORY SYSTEM.
1515.

Question : The given figure represents

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Buds
Fragments
Seeds
Spores

Answer :D
1516.

Question : The germ cell A produced by a person X is round in shape and it fuses with another germ cell B having a long tail and produced by a person Y. The fusion of A and B produces a new cell C. The cell C divides repeatedly and grows inside the organ D of person X to form E in which the body features of the unborn baby are not much developed. E grows further to form F in which the various body features of the unborn baby (like hands, legs, eyes, and ears, etc.) can be identified. F grows further and ultimately forms a baby. What are A,B C,D E and F? Out of the two person X and Y, which one is male and which one female?

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SOLUTION :N//A
1517.

Question : The gep between two neurons is called a

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DENDRITE
SYNAPSE
axon
impulse

ANSWER :B
1518.

Question : The Geotype of female bird is,

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A+ZW
A + W
A+Z
A + ZZ

Answer :A
1519.

Question : The geographical isolation along with the variations leads to the formation of ……………………………..

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ANSWER :SPECIES
1520.

Question : The genotype of green-stemmed tomato plants is denoted by GG and that of purple-stemmed tomato plants as gg. When these two plants are crossed : (i) What colour of stem would you expect in their F_(1)progeny? (ii) Give the percentage of purple-stemmed plant if F_(1)plants are self pollinated. (iii) In what ratio would you find the green and purple colour in the F_(1)progeny?

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Solution :(i) Green COLOUR.
(II) 25%.
(III) 3:1.
1521.

Question : The genotype of green stemmed tomato plant is denoted by GG and that of purple stemmed tomato plant as gg. Hybrids of a cross between these two were selfed to obtain F2 progeny, what will be the ratio of GG, Gg and gg in this progeny ?

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GG2 : Gg1 : gg1
GG3 : Gg1 : gg0
GG1 : GGL : gg2
GG1 : Gg2 : gg1

Solution :
RATIO of the PROGENY is GG1 : Gg2: gg1.
1522.

Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: Give the % age of wrinkled seeded plants if F1 plants are self-pollinated.

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Solution :
Percentage of WRINKLED SEED PLANTS on selfing of F1 plants will be 25%.
1523.

Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: In which ratio do you find RR, Rr and rr in F2 progeny ?

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SOLUTION :
1 : 2 : 1 for RR, Rr and rr.
1524.

Question : The genotype of a round seeded pea plant is denoted as RR and that of wrinkled seeded plants as rr. When eross between them occurs: What will be the phenotype expected in F1 generation ?

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SOLUTION :
F1 PHENOTYPE will be all ROUND.
1525.

Question : The genotype of a dominant parent is determined by crossing it with the recessive parent. This cross is called

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BACK CROSS
test cross
LONG cross
out cross

Answer :B
1526.

Question : The genetic variation created during reproduction is the basis for ………………….

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ANSWER :EVOLUTION
1527.

Question : The gene ‘T’ for the character of tallness in pea plant is dominant and gene ‘t’ is recessive. Explain it on the basis of Mendel’s experiment.

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<P>

Solution :Mendel selected garden pea plant (Pisum sativum) as an experimental material. The pea plant shows various characters and atleast two contrasting expressions for each of the characters.
Mendel selected height of the pea plant. The two contrasting expressions for the height of pea plants are tall plants and SHORT plants.
Mendel crossed the tall parent (P) plant, (TT), with another short parent (P) plant (tt), and obtained all tall plants in `F_(1)` generation. None of the short plants were produced in `F_(1)` generation. They were also not of medium height. It means that only one parental characteristic was expressed in the OFFSPRINGS.
When the plants of `F_(1)` generation were allowed to self-pollinate, about `75%` plants were tall and about `25 %` were short in the `F_(2)` generation. Thus, the genes for tallness and shortness both are capable of being inherited from the parents of `F_(1)` generation.
This INDICATES that both the tallness and shortness traits were inherited in the `F_(1)` plants, but only the tallness trait was expressed.
This led Mendel to propose that two copies of factor (gene) controlling traits are PRESENT in sexually reproducing organism.
These two may be identical or may be different.

This experiment indicates that the genes TT or genes Tt is the genetic constitution for tall plants while tt for the short plant. It means that only presence of gene T is responsible for the expression of tallness while the absence of dominant gene T and tt genes produces shortness.
Thus, tallness in pea plant is the dominant trait and shortness is the recessive trait.
1528.

Question : The gene for red hair is recessive to the gene for black hair. What will be the hair colour of a person if he inherits a gene for red hair from his mother and a gene for black hair from his father ? Form the flow chart of this cross.

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Solution :Given that
RED HAIR- Recessive `therefore` bb.
BLACK hair - DOMINANT `therefore` BB.
his person inherits one recessive gene (b) from mother and a dominant gene (B) from father ie-,

Hence, this person will have black hair as he is heterozygous for black.
1529.

Question : The gene for brown coloured hair is recessive that of gene for black coloured hair. What is the hair colour of a person who has inherited a gene for brown coloured hair from mother andblack coloured hair from father?

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SOLUTION :`{:(," BLACK",),("Black(BB)",""XX,"BROWN(bb)"),(,"Bb(Black)",):}`
1530.

Question : The gas released from vehicles exhaust arei. Carbon monoxideii. Sulphur dioxide iii. Oxides of nitrogen

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i and II
i and III
ii and iii
i, ii and iii

SOLUTION : i, ii and iii
1531.

Question : The gas-exchange surfaces of larger aquatic animals are

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tracheae
malpighian tubules
gills
book LUNGS 

ANSWER :C
1532.

Question : The gametophytes of bryophytes and pteridophytes are different from thatof gymnosperms. How ?

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Solution :Male and FEMALE gametophyte have free existence in bryophytes and PTERIDOPHYTES but not in Gymnosperms. They remain within sporangia RETAINED on sporophytes.
1533.

Question : The gamete cells, which have only one set of chromosomes is called .........

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diploid
polyploid
TRIPLOID
HAPLOID

SOLUTION :haploid
1534.

Question : The gametes and spores of phaeophyceae have a distinct morphology. Give its name.

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Solution :Pyriform (pear-shaped), bear TWO LATERALLY attached FLAGELLA.
1535.

Question : The Galapagos Islands are associated with the visit of

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JEAN Lamarck
Charles Darwin
Gregor Mendel
ALFRED Wallace

Answer :B
1536.

Question : The fungi growing on cow dung belongs to,

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ZYGOMYCETES
asidiomycetes
Qomycetes
Ascomycetes

Answer :A
1537.

Question : The functional respiratory organ of a fully formed tadpole is the

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skin
lung
gill
air bladder

Answer :C
1538.

Question : The function of vitamin K is in

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regulation of CALCIUM and PHOSPHORUS METABOLISM
blood clotting
respiration
carbohydrate metabolism 

ANSWER :C
1539.

Question : The function of kidney in mammals is to excrete

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EXTRA UREA, extra WATER and extra amino acids
extra urea, extra water and carbohydrate
extraurea, SALTS and EXCESS water
extra salts, urea and excess water

Answer :C
1540.

Question : The function of Haemoglobin is :

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To TRANSPORT `O_(2)` in the BODY
To transport `CO_(2)` in the body
Both (A) and (B)
NONE of the above.

Answer :A
1541.

Question : The fruits showing edible thalamus are

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Apple, CUSTARD, apple , GUAVA
Apple , straberry , pear
Apple , PINEAPPLE, strawberry
Jackfruit, guava, pineapple

Answer :B
1542.

Question : The fruits in which thalamus also contributes to fruit formation are called

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TRUE fruits
False fruits
Parthenocarpic fruits
Parthenogenic fruits

Answer :B
1543.

Question : The fossil remains of Archaeopteryx is a connecting link between

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amphibians
reptiles and birds
fish and amphibians
reptiles and mammals

Answer :B
1544.

Question : Theformof sugartransportedthroughthephloemis glucose .

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SOLUTION :Correct STATEMENT: The FORM of sugar transported through the phloem is SUCROSE
1545.

Question : The form and structure of growing cells are maintained because of

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osmosis
plasmolysis
turgidity
wall PRESSURE 

ANSWER :C
1546.

Question : The forest conserved in the name ot God is called……….. .

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SOLUTION :SACRED GROVE
1547.

Question : The Forest Conservation Act was enacted in ……….. .

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1980
1986
1972
1963

Solution :1980
1548.

Question : The forelimbs of bat and human are examples of. . . . . . . .organs.

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ANSWER :HOMOLOGOUS
1549.

Question : The force of attraction between the molecules of companion cells is called cohesion.

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SOLUTION :CORRECT Statement: The force of attraction between the molecules of WATER is called cohesion.
1550.

Question : The food reserve for energy in producesrs (autotrophs) is

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fat.
protein
STARCH
glycogen

Solution :FOOD RESERVES for energy purpose in plants in starch and in ANIMALS glycogen.