InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9101. |
Question : Two important processes in a cell, which take place outsidethe membrane bound organelles, are : |
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Answer» enzyme SYNTHESIS and DNA replication |
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| 9102. |
Question : Two groups (A & B) of bean plants 450nm & Group B to light of wave of similar size and same leaf area were length of 500-550nm. Compare the placed in identical conditions. Group A photosynthetic rate of the2 groups givwas exposed to light of wavelength 400 reasons. |
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Answer» Solution :Group A will show, more photosphynthesis . Chlorophyll absrobs maximumlightin the blueregion of the SPECTRUM, i.e., 400-450 nm hence , photosythetic rateeill alsohe high. Group BWILL show negligible amountof photosynthesisor no PHOTOSYNTHESIS. ChlorophyII does not absorb any LIGHTIN the greenregion, i.e, 500-550 nm, but reflectsgreen. |
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| 9103. |
Question : Two grizzled squirrel and lion tailed Macaque are endemic to _________. |
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Answer» SEMI- ARID zone |
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| 9104. |
Question : Two ganglionated solid ventral nerve cords of cockroch originate from |
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Answer» TRITOCEREBRUM |
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| 9105. |
Question : Two food chains are are given below Tree to aphid to insectivorous bird to bird of prey. Phytoplankton tozooplankton to plankton - feeding fish to carnivorous fish. Which diagram is a pyramid of energy representing both food chains |
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| 9106. |
Question : Two flagella one each on both ends of bacteria, the condition is |
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Answer» Lophotrichous |
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| 9107. |
Question : Two forces control passive transport of ions acrossmembranes: ……… and …………. |
| Answer» SOLUTION :CONCENTRATION GRADIENTS , MEMBRANE protential | |
| 9108. |
Question : Two examples of fishes are given. - Scoliodon (Dogfish) - Exocoetus (Flying fish). a) Place them in two distinct classes. b) Differentiate the above classes on the basis of two important characters. |
| Answer» SOLUTION :Chondrichthyes/Cartilaginous FISHES | |
| 9109. |
Question : Two examples in which the nitrogenous wastes are excreted from body in the form of uric acid are ………………. . |
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Answer» BIRDS and lizards |
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| 9110. |
Question : Two DNA molecule in a cell are observed but not distinct is these phases |
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Answer» S and `G_(2)` |
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| 9111. |
Question : Two counter -current systems formed in the kidney are by the _____and the __________. |
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Answer» |
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| 9112. |
Question : Two common characters found in centipede, cockroach and crab ………………. . |
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Answer» book lungs and antennae |
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| 9113. |
Question : Two characters shared by crocodiles and birds are |
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Answer» 4-chambered HEART and EXTERNAL fertilisation |
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| 9114. |
Question : Two characters shared by crocodiles and mammals are |
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Answer» 4-chambered HEART and INTERNAL fertilization |
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| 9115. |
Question : Two cells have pO_(2) of 20mm of Hg. One cell has pCO_(2) of 40 while the other has pCO_(2) of 70 mm of Hg. Which one will get more O_(2) ? |
| Answer» Solution :Cell with high `pCO_(2)` i.e. the ONE with `pCO_(2)` of 70 mm of Hg. HIGHER `pCO_(2)` LEADS to more DISSOCIATION of oxygen from hemoglobin. | |
| 9116. |
Question : Two auricles are separated by an _________in the heart of mammals. |
| Answer» SOLUTION :INTERATRIAL SEPTUM | |
| 9117. |
Question : Two adjacent cells A and B are being studied. Cell A has OP of 10 atm and TP of 6 atm. Cell B has OPof 10atm and TP of 4 atm. Movement of water will occur from |
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Answer» CELL `A`to cell `B` For cell `B:DPD=OP-TP=10-4=6atm` As water MOVES from a cell with lower DPD to cell with HIGHER DPD, therefore water will move from cell `A` to cell `B` |
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| 9118. |
Question : Twiners climb over the support with the help of |
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Answer» ADVENTITIOUS roots |
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| 9119. |
Question : Turtles are …………………. . |
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Answer» PISCES |
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| 9120. |
Question : Turpentineis obtained from ………… species . |
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Answer» CINCHONA |
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| 9121. |
Question : Turgor pressure is always equal andopposite to the |
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Answer» OSMOTIC PRESSURE |
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| 9122. |
Question : Differentiate between : Turgor pressure and wall pressure (Explain) |
| Answer» Solution :The HYDROSTATIC pressure developed inside the CELL on the cell wall due to ENDOSMOSIS is called turgor pressure. Due to turgor pressure the RIGID cell wall offers resistance. This resistance, which works in a direction opposite to the turgor pressure but is equal in strength to the turgor pressure, is called wall pressure. | |
| 9123. |
Question : Turgidity of cells helps in |
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Answer» EXTENSION growth |
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| 9124. |
Question : turbidity of water, pH hardness, salinity and dissolved O_(2). Light and temperature also play an important role in fish breeding. |
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Answer» SOLUTION :Natural breeding (Bundh breeding) These are special types of PONDS where natural RIVERINE conditions or any natural water RESOURCES are managed for breeding of culturable fishes. These bundhs are constructed in large low-lying areas that can accommodate large quantity of rain water. The shallow area of such bundhs is USED as spawning ground. |
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| 9125. |
Question : "Turbellarians" are free living …………………… . |
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Answer» FLATWORMS |
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| 9126. |
Question : Turbellarians are free living ............ . |
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Answer» Flatworms |
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| 9127. |
Question : Tunica-corpus theory was proposed by |
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Answer» Hanstein |
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| 9128. |
Question : Tubers store food materials in ………….. |
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Answer» OEDOGONIUM |
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| 9129. |
Question : Tuberculosis is caused by the bacterium ________. |
| Answer» SOLUTION :MYCOBACTERIUM tuberculae | |
| 9130. |
Question : Tube -in - tube organization is absent in |
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Answer» FLATWORMS |
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| 9131. |
Question : Tube feet are the locomotory organs of …………………. . |
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Answer» PLATYHELMINTHES |
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| 9132. |
Question : Tube feet are characteristic structures(a) star fish(b) cuttle fish(c) cray fish(d) jelly fish |
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| 9133. |
Question : Tube feet are the characteristic structures of ……………….. . |
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Answer» JELLYFISH |
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| 9134. |
Question : TSH (thyroid stimulating hormone) is produced by |
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Answer» adrenal cortex |
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| 9135. |
Question : Trypsinogen is an inactive enzyme of pancreatic juice. An enzyme enterokinase activates it. Which tissue/cell secretes this enzyme ? How is it activated ? |
| Answer» Solution :TRYPSINOGEN GETS CONVERTED into active Trypsin by ENTEROKINASE. Intestinal mucosa secretes this ENZYME. | |
| 9136. |
Question :Trypsin changes…….. . |
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Answer» Proteins into peptones |
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| 9137. |
Question : Write down the two actions of trypsin. |
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Answer» |
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| 9138. |
Question : Trypsin acts on |
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Answer» proteins in ACIDIC MEDIUM |
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| 9139. |
Question : Try to explain the following observations: If ATP is introduced into cells, Na^+ efflux is stimulated. |
| Answer» SOLUTION :ATP is a source of ENERGY for ACTIVE TRANSPORT of `Na^+` ions. | |
| 9140. |
Question : Try to explain the following observations:When K^+ ions are removed from the mediumsurrounding red blood cells, sodium influxinto the cells and potassium efflux increase dramatically. |
| Answer» Solution :A `Na^(+) // K^(+)` pump operates WHEREBY efflux of `Na^+` is linked to influx of `K^+` without `K^+` , no `Na^+` efflux can OCCUR , so `Na^+` ACCUMULATES within the cells by DIFFUSIONAND `K^+` leaves the cells by DIFFUSION. | |
| 9141. |
Question : Try to collect all the currently accepted meanings for the word 'Species'. Discuss with your teacher the meaning of species in case of higher plants and animals on one hand, and bacteria on the other hand. |
| Answer» Solution :Taxonomic studies consider a group of individual organisms with fundamental SIMILARITIES as a species. One should be able to distinguish one species from the other closely related species based on the distinct morphological differences. For example, Solanum includes species like Nigrum and Tuberosum. Both are different species of potato. In CASE of higher PLANTS one genus MAY have one or more than one species. In case of bacteria their SHAPE is consider. These are spherical, coccus, rod-shaped, comma and spiral - shaped. | |
| 9142. |
Question : Trunks of some of the aged tree species appear to be composed of several fused trunks. Is it a physiological or anatomical abnormality ? Explain in detail. |
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Answer» Solution :It is internal structural irregularity. It is an irregular type of secondary growth where regular fascicular cambium or cork cambium does not occur under normal conditions. In CASE of old tree barks irregular secondary growth is produced by cortex and pith vascular bundles. Hence extra or subsidiary vascular bundles produce APPEARANCE such that it OCCURRED by combination of many barks. |
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| 9143. |
Question : True species are ……………….. . |
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Answer» INTERBREEDING |
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| 9144. |
Question : True segmentation of body is first observed in the |
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Answer» Platyhelminthes |
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| 9145. |
Question : True species are ………….. . |
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Answer» Interbreeding |
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| 9146. |
Question : True of false : Insulin resisitance results in a disease called diabetes mellitus. |
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| 9147. |
Question : True of false : Pars distalis produces six trophic hormones. |
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| 9148. |
Question : True of false : Gastrointestinal tract, kidney and heart also produce hormones |
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| 9149. |
Question : True of false : B-lymphocytes provide cell - mediated immunity. |
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| 9150. |
Question : True nucleus is not found in : |
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Answer» GREEN algae |
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