Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

6151.

Question : The form and structure of growing cell are maintained because of________.

Answer»


ANSWER :TURGOR PROCESS
6152.

Question : The forest that colours in autumn is

Answer»

Temperate evergreen forest
Temperate DECIDUOUS forest
TROPICAL evergreen forest
Tropical decidous forest

Answer :B
6153.

Question : The foreskin around the glans penis is called what

Answer»


ANSWER :PREPUCE
6154.

Question : The forelimbs of higher vertebrates is the example of what?

Answer»

ANALOGOUS ORGANS
HOMOLOGOUS organs
Connecting LINK
VESTIGIAL organs

Solution :Homologous organs
6155.

Question : The forelimbs of frog, lizard,horse,man and wings of birds and bats are examples of _____organs.

Answer»


ANSWER :HOMOLOGOUS
6156.

Question : The forest conservation Act was enacted in ____________

Answer»

1972
1980
1952
1991

Answer :B
6157.

Question : The force which determines the flow of water from one cell to another is:

Answer»

T.P.
O.P.
W.P.
D.P.D

Answer :D
6158.

Question : The food chain ,in which micro -organisms break down the energy -rich compounds, is called:

Answer»

ECOSYSTEM
DETRITUS FOOD chain
Parasitic food chain
Predator food chain

Answer :B
6159.

Question : The food chain in which microbessplit energy rich compounds of the producer community is

Answer»

PARASITIC FOOD chain.
detritus food chain
Predators food chain
Producer food chain

Answer :B
6160.

Question : The fonture not present in apes is

Answer»


ANSWER :A
6161.

Question : The following transmit regulatory impulses from CNS to concerned tissue

Answer»

EFFERENT process
Reticular FIBRES
AFFERENT process
Afferent fibres

Answer :A
6162.

Question : The following tableshowsthe genotypes for bloodgroupingandthis phenotypes. Completethe tableby filling the gaps .

Answer»

SOLUTION :2)`I^(A)I^(O)`
3) `I^(A)I^(B)`
4) O
6163.

Question : The following table shows certain diseases, their causative organisms andsymptoms. Fill the gaps.

Answer»

SOLUTION :
6164.

Question : The following summaries describe some published research resutls. Research 1. Wu and Li (1985): The comparative analysis of homologous genes between human and mouse genomens suggests that the evolutionary rate of homologous genes was higher in the mouse lineage than in the human lineage. Research 2. Smith and Donohe (2008) : The plant families Caprifoliacease, Asclepiadeceae and Lamiaceae are compsed of both herbaceous and arborescent speciers. The comparative analysis of homologous genes between the herbaceous and arborescent species within a single plant family suggests that the evolutionary rate of homologous genesin herbaceous lineages were faster than of arborescent lineages in all three plant familes. Research 3. Gilman et al. (2009): The comparative analysis of 130 homologous mitochondrial genes between a sister species pari of vertebrates from the temperate region and from the tropical region indicate that the base substituion rates of homologous genes from the tropical region are 1.7 times faster than that of the temperate region. Based on these studies which of the following statements best describes the common evolutionary processes in plant and animal genes?

Answer»

The EVOLUTIONARY rates of genes are accelerated in shot-lived animals and plants.
The evolutionary rates of genes are accelerated in higher animals and plants.
The evolutionary rates of genes are accelerated in animals and plants which lived in higher temperature REGIONS.
Direct comparisons of homologous genes between animals and plants show that the plants evolve faster than animals.

Solution :Shor-lived species with quick generation replacement usually evolve at a faster rate than do LARGE, long-lived species. This is because NEW genetic variations. Normally appear in each generatin as a consequency of mutations in sex cells. Those variations may be selected for or against depending on the environment at the time. As a consequence, quickerreproductive cycles generally result in speeded up sepcies divergence. Speciation is genrally a functionof time, unlike temperate regions which were subjected to frequent glaciations in the past, tropical latitudes have remained relatively UNDISTURBED for millions of years and thus, have a long evolutionary time for species diversification.
6165.

Question : The following Table shows the genotypes for ABO blood grouping and their phenotypes. Fill the gaps left in the table:

Answer»

SOLUTION :GENOTYPE `I^A , I^B i , AB , II`
6166.

Question : The following summaries describe some published research results. Research 1. Wu and Li (1985): The comparative analysis of homologous genes between human and mouse genomes suggests that the evolutionary rate of homologous genes was higher in the mouse lineage than in the human lineage. Research 2. Smith and Donohe (2008) : The plant families Caprifoliacease, Asclepiadeceae and Lamiaceae are compsed of both herbaceous and arborescent speciers. The comparative analysis of homologous genes between the herbaceous and arborescent species within a single plant family suggests that the evolutionary rate of homologous genesin herbaceous lineages were faster than of arborescent lineages in all three plant familes. Research 3. Gilman et al. (2009): The comparative analysis of 130 homologous mitochondrial genes between a sister species pair of vertebrates from the temperate region and from the tropical region indicate that the base substitution rates of homologous genes from the tropical region are 1.7 times faster than that of the temperate region. Based on these studies which of the following statements best describes the common evolutionary processes in plant and animal genes?

Answer»

The evolutionary rates of genes are accelerated in shot-lived animals and plants.
The evolutionary rates of genes are accelerated in higher animals and plants.
The evolutionary rates of genes are accelerated in animals and plants which lived in higher temperature regions.
DIRECT comparisons of HOMOLOGOUS genes between animals and plants show that the plants evolve faster than animals.

Solution :Shor-lived species with quick generation replacement usually evolve at a faster rate than do large, long-lived species. This is because NEW genetic variations. Normally appear in each generatin as a consequency of mutations in sex cells. Those variations MAY be selected for or against depending on the environment at the time. As a consequence, quickerreproductive cycles generally result in speeded up sepcies divergence. Speciation is genrally a functionof time, unlike temperate regions which were subjected to frequent glaciations in the past, tropical latitudes have remained relatively undisturbed for millions of years and thus, have a long evolutionary time for species diversification.
6167.

Question : The Following statements describe some of the steps of translation ,br (a)For chain elongation, the presence of catalyst enhances the rate of peptide bond formation.br (b) The process of translation of mRNA to protein begins when both the subunits of ribosome encounter and associate with mRNA.br(c) During chain elongation, the ribosomes moves from codon to codon along the mRNA. The correct statements are

Answer»

(a) and (B)
(b) and (C)
(a) and (c)
(a). (b) and (c)

ANSWER :C
6168.

Question : The following statements compare the process of oogenesis and spermatogensis. Which one is not true.

Answer»

Production of ovam ceases at certain age, but sperm production CONTINUES even in OLS men
Oogensis begin in the embryonic stages but spermatogensis STARTS at the ONSET of puberty.
Meiotic arrest occurs both in oogenesis and spermatogenesis.
Polar bodies are FORMED in oogenesis.

Answer :C
6169.

Question : The following statements describe the wind pollinated plants. Which one of these statements is incorrect?

Answer»


ANSWER :(I).
6170.

Question : The following statements are ture about surfactant except

Answer»

It is SECRETED by TYPE II cells of alveolar epithelium
It reduces suface tension
It decreases the efficiency of lung
It ensures stability of the alveoli

Answer :C
6171.

Question : The following sequence represents the location of genes in a chromosome . A - B - C - M - R - S - Y - Z . Which of the gene pairs will have least chance of getting inherited together ?

Answer»

A and M
S and Y
M and Z
A and Y

Answer :D
6172.

Question : The following scheme shows the fate of carbohydrates during digestion in the human alimentary canal. Identify the enzymes acting at stages indicated as A, B, C and D :-

Answer»

(A)AMYLASE(B)Maltase(C)Lactase(D)Invertase
(A)Amylase(B)Maltase(C)Invertase(D)Lactase
(A)Amylase(B)Invertase(C)Maltase(D)Lactase
(A)Amylase(B)Lactase(C)Maltase(D)Invertase

Answer :D
6173.

Question : Match the following

Answer»

(A) Fetal life, (B) Birth, ( C) Puberty, (D) ADULT REPRODUCTIVE life, (E) CHILD HOOD
(A) Fetal life , (B) Birth , ( C) Child hood , (D) Puberty , (E) Adult reproductive life
(A) Adult reproductive life , (B) Birth , ( C) Puberty , (D) Child hood , (E) Featal life
(A) Brith , (B) Child hood , ( C) Fetal life , (D) Puberty , (E) Adult reproductive life

Answer :B
6174.

Question : The following results are obtained in several dihybrid test crosses in an organism considering three genes loci Aa,Bb and Cc. a. In test cross with AaBb the number of recombinants and parental combinations are 50 and 950 respectively. b. In TC with AaCc the number of Rc and PC are 75 and 425 respectively. c. In TC with BbCc the number of RC and PC are 160 and 640 respectively. basing on the above result identify the gene loci of the three genes /prepare a genetic map of the three genes.

Answer»

Solution :First LET us calculate % of RC in each case and DISTANCE between the GENES (in map units).
% of recombination of `TC(a)=50/100xx100=5%`
`=5` map units /,CM
6175.

Question : The following reason supports that all copulations may not lead to fertilization and pregnancy

Answer»

OVUM should reach EARLIER than sperms into ampullary - isthamic junction
Sperms should reach earlier than ova into ampullary - isthamic junction
Both sperms and ova should transport SIMULTANEOUSLY to the ampullary - isthamic junction
Ovum should reach the VAGINA when sperms enter into it

Answer :C
6176.

Question : The following ratio is generally constant for a given species :

Answer»

`A+G/C+T`
`T+C/G+A`
`G+C/A+T`
`A+C/T+G`

ANSWER :C
6177.

Question : The following pictures show two personalities which biologists will not forget.a. Who are they? How did the world honour them for making this contribution? c . Briefly give details of their contribution to biology.

Answer»

Solution :a. A. Watson and B. Crick
b. By giving NOBEL Prize
c. James Watson and Francis Crick proposed the double helical structuremodel of DNA. According to them, the DNA is formed of two polynucleotide chains. The two chains are spirally coiled together to form a double helix, The two chains are formed by sugar and phosphate and are connected by nitrogen bases. The BASE pair is always Adenine with Thymine (A = T) and Cytosine with Guanine (C=G). Thus the DNA molecule looks like a spiral staircase with sugar and phosphate units along the RAILING and the hydro gen BONDED base-pairs as the steps. For this outstanding discovery thescience world honoured them by giving Nobel Prize.
6178.

Question : The following process of breeding increases homozygosity

Answer»

INBREEDING
Out BREEDING
Cross breeding
Inter-specific breeding

SOLUTION :Inbreeding
6179.

Question : The following (P through U) are the main steps of chemosynthetic ATP synthesis in the light reaction. Which answer places them in correct order? P. H^(+) concentration gradient established Q. H^(+) diffuses through ATP synthetase R. Carriers use energy from electrons to move H^(+) across the membrane S. Electrons from PSII pass along electron transport chain T. Light excites electrons in PSII U. Energy of H^(+) flow is used by ATP synthetase to make ATP

Answer»

PQTSRU
STPQRU
TSRPQU
TSRUQP

Answer :C
6180.

Question : The following pair of human blood group alleles are codominant.

Answer»

`I^(O) I^(O)`
`I^(A)I^(O)`
`I^(B)I^(O)`
`I^(A)I^(B)`

ANSWER :D
6181.

Question : The following is the illustration of the Transport of ovum, fertilisation and passage of growing embryo through fallopian tube. What are the roles of cells present in stage 'g'?

Answer»

Solution :The TROPHOBLAST layer GETS ATTACHED to the endometrium, the inner cell mass gets DIFFERENTIATED as the embryo
6182.

Question : The following is the illustration of the Transport of ovum, fertilisation and passage of growing embryo through fallopian tube. How is placenta formed?

Answer»

Solution :After implantation, finger-like PROJECTIONS appear on the trophoblast called CHORIONIC villi, which are surrounded by the uterine tissue and maternal blood, the chorionic villi and uterine tissue become interdigitated with each other and JOINTLY FORM PLACENTA.
6183.

Question : The following is the illustration of the Transport of ovum, fertilisation and passage of growing embryo through fallopian tube. Name the process represented by 'H' and the layer of maternal tissue involved in it.

Answer»

SOLUTION :.H. REPRESENTS BLASTOCYST IMPLANTATION, endometrium
6184.

Question : The following is the illustration of the sequence of ovarian events (a - i) in human female. (i) Identify the figure that illustrates ovulation and mention the stage of oogenesis it represents. (ii) Name the ovarian hormone and the pituitary hormone that have caused the above mentioned event. (iii) Explain the changes that occur in the uterus simultaneously in anticipation. (iv) Write the difference between 'c' and 'h' (v) Draw a labelled sketch of the structure of a human ovum prior to fertilization.

Answer»

Solution :(i) Stage of Oogenesis is represented by (D Mature Graafian follicle.
(ii) Ovarian hormone - Estrogen.
Pituitary hormone - Luteinsing hormone (LH)
(iii) Endometrium PROLIFERATE (glands become cork-screw shaped) highly vascularised with high DEGREE of REGENERATION anticipating IMPLANTATION of the fertilised ovum.
(IV) c-developing follicle, h-regressing corpus luteum. (v)
6185.

Question : The following is the illustration of the Transport of ovum, fertilisation and passage of growing embryo through fallopian tube. Identify and draw the stages labelled 'e' and 'g'.

Answer»

SOLUTION : .e. is Morula, .G. is blastocyst (Correct DIAGRAM and NAME of stage)
6186.

Question : The following is the illustration of the sequence of ovarian events ''a'' to ''I'' in a human female : (a) Identify the figure that illustrates corpus luteum and name the pituitar) hormone that inhuences its formation. (b) Specify the endocrine function of corpus luteum. How does it influence the uterus? Why is it essential? (c) What is the difference between “d” and “e”? (d) Draw a neat labelled sketch of Graafian follicle.

Answer»

SOLUTION :(a) g to i are CORPUS luteum pituitary hormone-Luteinising hormone.
(b) Corpus luteum secretes large amount of progesterone hormone that is essential for maintenance of the endometrium required for implantation of blastocyst leading to pregnancy.
(c) ‘d’ REPRESENTS the TERTIARY follicle which has a fluid filled cavity called the antrum.
‘e’ represents the Graafian follicle. This is actually a large tertiary follicle ready for ovulation.
(d)
6187.

Question : The following is the illustration of the sequence of ovarian events (a-i) in a human female. (a) Identify the figure that illustrates ovulation and mention the stage of oogenesis it represents. (b) Name the ovarian hormone and the pituitary hormone that have caused the above mentioned events. (c) Explain the changes that occurs in the uterus simultaneously in anticipation. (d) Write the difference between C and H.

Answer»

Solution :(a) A- Primordial follicle, B- Primary follicle, C- Secondary follicle, D-Tertiary follicle, E- MATURE graafian follicle, F- Ovulation (release of egg), G- Empty Graafian follicle, H-Corpus luteum, I - Corpus albicans.
(b) Pituitary hormones: Follicle Stimulating Hormones (FSH) and Lutenizing Hormone (LH). Ovarian hormones: Estrogen and Progesterone.
(c) At the start of menstrual cycle, the endometrium of uterus starts REGENERATING through proliferation of cells induced by FSH and CH. After ovulation, the progesterone secreted by corpus luteum prepares the endometrium (uterine wall) to receive the egg if it is fertilized.
(d) C- Secondary follicle
H - Corpus luteum During development of ovum, the primary follicle gets surrounded by many layers of granular cells and forms a NEW layer called secondary follicle.
Corpus luteum is the empty graafian follicle that remains after ovulation. It acts as a transitory endocrine GLAND secreting progesterone to maintain pregnancy.
6188.

Question : The following is not relate to C_4 plant

Answer»

WATER USE efficiency is more
Photorespiration is not detectable
`CO_2` compensation points is high
The PRIMARY ACCEPTOR of `CO_2` is a 3C compound

ANSWER :C
6189.

Question : The following graph shows the species area relationship. Answers the Questions as directed. (a) Name the naturalist who studied the kind of relationship shown in the graph. Write the observations made by him. (b) Write the situations as discovered by the ecologists when the value of 'Z'(slope of the line) lies between (i) 0.1 and 0.2, (ii) 0.6 and 1.2 What does 'Z' stand for ? (c ) When would the slope of the line 'b' become steeper ?

Answer»

Solution :(a) Alexander VON Humboldt : He observed that within the region species richness increased with increasing explored area but only upto a limit.
(b) i-The slope of regression lines is similar, unaffected by the region or taxa and VALUE of Z lies between 0.1-0.2.
(ii) The slope of regression is steeper when we ANALYSE the species area RELATIONSHIP AMONG very large areas like entire continent. (slope of the line) regression co-efficient between 0.6-1.2. Z-slope of line (regression coefficent).
(c) If species richness is more, the slope of the will become steeper Z values 0.6-1.2 for large areas with rich species diversity, such us mammals in the tropical forests.
6190.

Question : The following graph shows two types of population growth curves: Name the growth cureves.

Answer»

SOLUTION :(a) a -EXPONENTIAL GROWTH model
b - LOGISTIC growth model
6191.

Question : The following graph represents the concentrations of the four hormones present in the blood plasma of an woman during her menstrual cycle. Identify the hormones.

Answer»


ANSWER :C
6192.

Question : The following graph illustrates several phenomena that develop while a muscel is being repetitively stimulated : ______ (a)Treppe or staircase phenomenon

Answer»


ANSWER :B
6193.

Question : The following graph illustrates several phenomena that develop while a muscel is being repetitively stimulated : (c )Physiological contracture

Answer»


Solution :The staircasephenomenon or treppe is due to a gradual increase in the extent of MUSCLE CONTRACTION, a limit will be REACHED after rapid REPEATED stimuli. Fatigue is the decreased response of the nerve to stimulation.
6194.

Question : The following graph illustrates several phenomena that develop while a muscel is being repetitively stimulated : ____ (b)Fatigue

Answer»


ANSWER :A
6195.

Question : The following graph depicts changes in two populations A and B of herbivores in a grassy field. A possible reason for these changes is that

Answer»

Population A produced more offspring than population B
Population A CONSUMED the members of population B
Both PLANT populations in this habitat DECREASES
Population B competed more successfully for food than population A

Answer :D
6196.

Question : The following figure is of an eminent environmentalist. a. Name the personality. b. Mention his contribution in this regard. c. To which state does he belong?

Answer»

Solution :a. Sundarlal BAHUGUNA
b. He is the leader of .CHIPKO Movement.. He coined the Chipko slogan .ECOLOGY is PERMANENT economy..
c. Uttarakhand
6197.

Question : The following features occur during protein synthesis: (i) Movement of m-RNA from the nucleus into theCytoplasm, where it binds to the ribosomes (ii) Formation of amino acyl t-RNA complex (iii) Transcription of specific segments of DNA into m-RNA molecules in the nucleus (iv) Binding of N-terminal amino acid, methionine t-RNA to the 'P' site of the ribosome. The t-RNA anticodon "pairs with AUG on m-RNA" (v) Formation of peptide bond between first and second amino acids at the 'A' site (vi) Release of the completed polypeptide chain from ribosomes (vii) Migration of dipeptide to form a tripeptide and then a polypeptide The correct order of events is

Answer»

(III) – (II) – (i) – (iv) – (v) – (vi) – (VII)
(i) – (ii) – (iii) – (iv) – (v) – (vi) – (vii)
(iii) – (i) – (ii) – (iv) – (v) – (vi) – (vii)
(iii) – (i) – (ii) – (iv) – (v) – (vii) – (vi)

ANSWER :D
6198.

Question : The following experiment was performed to test the effect of auxin on the plant growth . Five plant seedlings ( all growing actively ) were prepared as below , they were unilaterally illuminated ,and growth was measured after 10 days. Treatments : Plant A : Tip not removed , nothing applied Plant B : Tip removed , nothing applied PlantC : Tip removed , gelation block with cytokinin was placed on the cut edge Plant D : Tip removed gelation block with auixn placed on the cut edge.

Answer»

A and B
A and D
B and C
A, B, C and D

Answer :B
6199.

Question : The followingDNA Sequence(5' rarr 3')specifies part of a protein coding sequence, starting fromposition I. Which of the followingmutantionswill giverise to a proteinthat is shorter tha the full-lengthprotein ?

Answer»

DELETION of NUCLEOTIDE 13
Deletion of nucleotide 8
Insertion ofa singlenucleotide between 3 and 4
Inserationof a single nucleotidebetween 10 and 11

Solution :N//A
6200.

Question : The following diagrams are the age pyramids of different populations. Comment on the status of these populations.

Answer»

Solution :• FIG. A: It is a pyramid shaped age pyramid. In this figure, the base, i.e., PRE-reproductive STAGE is very large when compared with the reproductive and post reproductive stages of the population. This type of age structure INDICATES that the population would increase rapidly.
• Fig. B : It is an inverted bell shaped pyramid. In this figure, the pre- reproductive and reproductive stages are same. This type of age structure indicates that the population is stable.
•Fig. C: It is .URN. shaped pyramid. In this figure, the pre-reproductive and reproductive stages are less than the post reproductive stage of this population. In this population, more older people are present. This type of age structure indicates that the population definitely is declining.