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4851.

Question : The reactant reduced during photosynthesis _____

Answer»


ANSWER :CARBON DIOXIDE
4852.

Question : The ratio of various genotypes of a recombinant phenotype of F_(2) dihybrid cross

Answer»

`1:2:1`
`1:2`
`1:2:1:2`
`1:2:2:4`

ANSWER :C
4853.

Question : The ration of chlorophyll a to chlorphyll b in flowering plants is

Answer»

`1.5:1`
`0.5:1.5`
`2.5-3.5:1`
`5.5:1`

ANSWER :C
4854.

Question : The ratio of the number of kinds of double homozygous to double heterozygous to single homozygous genotypes of F_(2) generation of a Mendelian dihybrid cross is

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`1:4:4`
`4:4:1`
`4:1:4`
`4:2:3`

ANSWER :C
4855.

Question : The ratio of various genotypes of adouble dominant phenotype of F_(2) dihybrid cross

Answer»

`1:2:1`
`1:2`
`1:2:1:2`
`1:2:2:4`

ANSWER :D
4856.

Question : the ratio of monohybrid test cross is

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`12:3:1`
`1:1`
`9:3:4`
`9:6:1`

ANSWER :B
4857.

Question : The ratio of homozygous violet color flower pea plants and hetrozygous violet coour flower pea plants obtained in the F_(2) generation of a typical Mendelian monohybrid cross is

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`3:1`
`1:1`
`1:2`
`2:1`

ANSWER :C
4858.

Question : The ratio of homozygous dominant and homozygous recessive in dihybrid cross is

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` 1 : 16`
`1:8`
`16:1`
NONE of these

Solution :none of these
4859.

Question : The ratio of methane, ammonia and hydrogen in Stanley Miller's experiment was

Answer»

`3:1:2`
`2:1:2`
`1:2:1`
`5:4:1`

SOLUTION :`2:1:2`
4860.

Question : The ratio of homozygous and hetrozygous organisms in the F_(2) of monohybrid corss

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`1:1`
`3:1`
`1:3`
`1:2`

ANSWER :A
4861.

Question : The ratio of F2 generation of a dihybrid cross having pure , monohybrids , dihybrids plants is

Answer»

`1:2:1`
`1:2:4`
`1:4:8`
`1:1:2`

ANSWER :A
4862.

Question : The ratio of 1:1:1:1 is obtained from a cross between the parents.

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RRYY `XX` rryy
RRYy `xx` rryy
RrYY `xx` Rryy
RrYy `xx` rryy

Solution :RrYy `xx` rryy
4863.

Question : The ratio between the number of kinds of homozygous genotypes and the number of kinds of heterozygous genotypes in the F_(2) of monohybrid cross

Answer»

`1:1`
`1:2`
`1:2:1`
`2:1`

ANSWER :D
4864.

Question : The ratio of a dihybrid test cross is

Answer»

`9:3:3:1`
`1:1`
`1:1:1:1`
`1:2:1:2`

ANSWER :C
4865.

Question : The ratio between the number of 2 - carbon and 3 - carbon intermediates having -NH_2 group formed in photosynthetic oxidation cycle is

Answer»

`1:1`
`2:1`
`3:2`
`3:4`

ANSWER :B
4866.

Question : The ratio between carrier, disease free & diseased individual on marriage between two carriers of sickle cell anaemia will be -

Answer»

`0 : 2 : 1`
`0 : 1 : 1`
`1 : 2 : 1`
`2 : 1 : 1`

ANSWER :D
4867.

Question : The ratio ………is seen in inhibitory gene interaction.

Answer»

`9:7`
`9 : 3 : 4`
`13:3`
`9 : 6 :1`

4868.

Question : The rate of transpiration will be very less in situation where:

Answer»

Ground WATER is sufficiently available
Wind is BLOWING with a very HIGH velocity
Environment is very HOT and dry
Relative humidity is very high

Answer :D
4869.

Question : The rate of transpiration can be measured with the help of:

Answer»

AUXANOMETER
Refractometer
Spectrophotometer
Potometer

Answer :D
4870.

Question : The rate of synthesis of m-RNA is regulated by what ?

Answer»

PROMOTER GENE
REGULATORY gene
Operator gene
Structural gene

Solution :Promoter gene
4871.

Question : The rate of release of carbon dioxide into the atmosphere is significantly increased by A.rapid deforestation B. massive burning of fossil fuels for energy and transport C. burning of wood D. combustion of organic matter E. volcanic activity

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B,C,D,E,F
A,B,C,D,E,F
A,B,C,D
A,C,D,E,F

Solution :A,B,C,D,E,F
4872.

Question : The rate of photosysnthesis is determined by the factor available at

Answer»

very LOW
OPTIMUM
SUB optimum
maximum

Answer :C
4873.

Question : The rate of photosynthesis is maximum in

Answer»

GREEN light
Blue light
Red light
Far-red light

Answer :C
4874.

Question : The rate of photosynthesis is higher in:

Answer»

Very HIGH light
Continuous light
Red light
Green light

Answer :C
4875.

Question : The rate of increase of biomass is called ……….. .

Answer»

GROSS PRIMARY productivity
net primary productivity
secondary productivity
pyramid of biomass

Answer :B
4876.

Question : The rate of formation of new organic matter by rabbit in a grassland, is called

Answer»

Net PRODUCTIVITY 
SECONDARY productivity 
Net primary productivity 
Gross primary productivity 

SOLUTION :Secondary productivity
4877.

Question : the rate of decomposition increases if detritus is rich in

Answer»

Lignin and CHITIN
NITROGEN compounds like PROTEIN and NUCLEIC acid
tennis and cellulose
chitin and phenotics

Answer :B
4878.

Question : The rate of decomposition of detritus is affected by the abiotic factors like availability of oxygen, pH of the soil substratum, temperature etc. Discuss.

Answer»

Solution :Detritus or animals and plant parts are decomposed by microbes like bacteria and fungi. The rate of these DECOMPOSES is affected by abiotic factors like temperature, moisture, pH of soil and light.
Soil pH affects composition of acidic and alkaline microbes. Anaerobiosis and acrobiosis occure in absence of oxygen and PRESSURE of oxygen respectively.
The substance is COMPLETELY decomposed in presence of oxygen while anaerobiosis and aerobiosis processes occure in absence of oxygen and presence of oxygen. Similarly microbes do not possess growth in best WAY at high temperature but EITHER at high or low temperature tallerent microbes possess growth.
4879.

Question : The rate of convertion of light energy into chemical energy of organic molecules in an ecosystem is

Answer»

NET Primary PRODUCTIVITY
Gross Primary Productivity
Net Secondary Productivity
Gross Secondary Productivity

ANSWER :B
4880.

Question : The rate of breakdown of glucose into pyruvic acid is under certain controlling steps. The major controlling step is :-

Answer»

FRUCTOSE 6–P `to` Fructose 1, 6 bisphosphate
PGAL `to` 1, 3 bisphosphoglyceric acid
Glucose 6-P `to` Fructose 6-P
3PGA `to` 2PGA

Answer :A
4881.

Question : The rate of appearance of new forms is linked to the life span of an organism. Explain with the help of a suitable example.

Answer»

SOLUTION : The rate of appearance of new forms is linked to the life span of an organism. Example: Microbes that divide fast have the ability to multiply and BECOME millions of individuals within HOURS. Thus any variation leading to natural selection and appearance of a new species is observable in them within days. For the same thing to happen in a fish or fowl it WOULD take millions of years as life span of these ANIMALS is in years.
4882.

Question : The rate of appearance of new forms is linked to the life cycle or the life span. Explain with a suitable example.

Answer»

Solution :Microbes that DIVIDE fast have the ability to multiply and become millions of individuals within HOURS, a colony of bacteria (say A) growing on a given medium has built in VARIATION in terms of ability to utilise a feed component, a change in the medium composition would bring out only that part of the population (say B), that can survive under the new conditions, this variant population outgrows the others and appears as new species, this would happen within DAYS, for the same thing to happen in a fish or fowl would take million of years as life spans of these animals are in years// or any other relevant example with explanation
4883.

Question : The rate of biomass production in an ecosystem is called productivity. They are of two types- Gross primary productivity and net primary productiviy. How are these two productivities related?

Answer»

SOLUTION :Net primary PRODUCTIVITY is the GROSS primary produtivity - respiration losses.
That is NPP = GPP - R
4884.

Question : The rate at which new tissues are formed in producers in the ecosystem's

Answer»

NET PRIMARY PRODUCTIVITY
gross primary productivity
net SECONDARY productivity
gross secondary productivity

ANSWER :A
4885.

Question : The rate at which light energy of organic molecules is the ecosystem's

Answer»

net primary PRODUCTIVITY
GROSS primary productivity
net secondary productivity
gross secondary productivity

ANSWER :B
4886.

Question : The rarest leucocyte of human blood is

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Basophil
Monocytes
Neutrophil
Eosinophil

Answer :A
4887.

Question : The range of biomagnification of DDT in an aquatic food chain, if starting from 0.003 ppb level in water may go at fish-eating bird level upto

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0.5 ppm
5.0 ppm
15.0 ppm
25.0 ppm

Answer :D
4888.

Question : The r value for human population in India is ..........

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0.15 
0.0502 
0.0205 
0.012 

ANSWER :C
4889.

Question : The r value for flour beetle is ..

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0.15 
0.12 
0.21 
0.012 

ANSWER :B
4890.

Question : The quietest sound that the ear of a man can delete is known as

Answer»

Acoustic zoning
THRESHOLD of hearing
Threshold of PAIN
GREEN muffler

Answer :B
4891.

Question : The quickest method of plant breeding is

Answer»

INTRODUCTION
Selection
Hybridization.
MUTATION BREEDING

Solution :Mutation breeding
4892.

Question : The quantity 1500 mL in the respiratory volumes of a normal human adult refers to

Answer»

MAXIMUM ari that can be BREATHED in and breathed out
RESIDUAL volume
expriatory reserve volume
Total lung capacity minus residual volume

Solution :Residual air is the volume of air that remains in the lungs after the most forcelfu expiration .It equal s to 1500 mL .Resdual air mostly OCCURS in alveoli
Maximum air that can be breathed in and breathed that OCAN be expird over and above the tidal air by most forceful expirationn is the expiratiory reserve volume (1200 mL).
4893.

Question :The quality of which vitamin is increased by LAB?(A) Vitamin A(B) Vitamin B_12(C) Vitamin B(D) Vitamin C

Answer»

VITAMIN A
Vitamin `B_12`
Vitamin B
Vitamin C

Solution :Vitamin `B_12`
4894.

Question : The pyramid of ……….. In sea is always inverted.

Answer»

biomass
energy
numbers
species

Answer :A
4895.

Question : The pyramid of number in a grassland ecosystem

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Linear
Inverted 
Upright
Negative 

ANSWER :A
4896.

Question : The pyramid of biomass in sea is generally.

Answer»

Linear
Inverted
Upright
CYCLIC

ANSWER :B
4897.

Question : Which one of the following shows a pyramid of biomass in a pond ecosystem ?

Answer»

Inverted
Upright
SPINDLE SHAPED
Either spindle shaped or upright

Answer :A
4898.

Question : The pyramid of energy is always upright for eny ecosystem. This situation indicates the fact that :

Answer»

PRODUCERS have the lowest energy CONVERSION dfficiency
carnivoreshave a BETTER energy conversion EFFICIENCY
energy conversion efficiency efficiency is the same in all TROPHIC levels
herbivores have a better energy conversion efficiency than carnivores

Answer :D
4899.

Question : The pyramid of biomass in sea is also inverted, why?

Answer»

Solution :The pyramid of BIOMASS in sea is ALSO generally inverted because the biomass of FISHES FAR exceeds that of phytoplankton.
4900.

Question : The purpose of biological treatment of waste water is to ________ .

Answer»

REDUCE BOD
INCREASE BOD
Reduce SEDIMENTATION
Increase sedimentation

Answer :a