InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1901. |
Which of the following has magnesium?A. ChlorophyllB. HaemocyaninC. Carbonic abhydraseD. Vitamin `B_(12)` |
| Answer» Correct Answer - A | |
| 1902. |
The hormone which controls the process of burning of fats, protiens, and carbohydrates and liberates energy in the body is:A. ThyroxineB. AdrenalineC. InsulinD. Cortisone |
| Answer» Correct Answer - C | |
| 1903. |
Which of the following is correct statemet ?A. Starch is a polymer of `alpha`-glucoseB. Amylose is a component of celluloseC. Proteins are composed of only one type of amino acidD. In cylic structure of fructose, there are four carbons and one oxygen atom |
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Answer» Correct Answer - A Starch is also known as amylum which occurs in all green plants. A molecules of starch `(C_(6)H_(10)O_(5))_(n)` is built of a large number of `alpha`-glucose ring joined through oxygen atom. |
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| 1904. |
Which of the following has magnesium?A. Vitamin `B_(12)`B. ChlorophyIIC. HaemocyaninD. Carbonic anhydrase |
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Answer» Correct Answer - B It is a green plant pigment, which absorbs energy from sunlight, enabling the plants to build up carbohydrates from atmospheric `CO_(2)` and `H_(2)O` by photosynthesis. It consists of a mixture of two pigments. ChorophyII- a `(C_(55) H_(72) O_(5) N_(4) Mg)` and chorophyII - b `(C_(55) H_(70) O_(6) N_(4) Mg)` |
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| 1905. |
`alpha-D (+)-`glucose and `beta-D(+)-`glucose are:A. anomersB. epimersC. enantiomersD. geometrical isomers |
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Answer» Correct Answer - A Diastereomers with more than one stereocenter that differ in the configuration about only one stereocenter are called epimers. Anomers are epimers whose configuration differ about the `(C - 1. alpha - D - (+) -` glucose and `beta - D - (+) -` glucose and anomers as they differ only in the configuration carbon (The aldehyde carbon before cyclisation). |
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| 1906. |
Give any two reasons to understand that glucose molecule has no open chain structure. |
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Answer» Open chain structure of glucose could not explain `to` why glucose doesnot respond to schiffs test `to` why it does not react with `NaHSO_3 " and " NH_3` `to` why there is mutarotation |
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| 1907. |
A fatty acid has a carboxyl group attached to an R group. The number of carbon atoms in R group of a fatty acid may beA. 1 carbon to 19 carbonsB. 2 carbons to 19 carbonsC. 1 carbons to 20 carbonsD. 2 carbond to 20 carbons |
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Answer» Correct Answer - A (A) A fatty acid has a carboxyl group attached to an R group. The number of carbon atoms in R group of a fatty acid may be 1 carbon to 19 carbon. |
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| 1908. |
Essential amino acids includeA. leucineB. valineC. tryptophanD. all of these |
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Answer» Correct Answer - D Essential amino acid are those which cannot be systhesised by organism in the body and are obtained from plants, e.g., valine, leucine, isoleucine phenylalanine, threonine, lysine, tryptophan, methionine. Non-essential amino acids can be synthesised by the organism and may not be the requisite components of diet, e.g., serine cysteine, proline, glycine asparagine, glutamine and tyrosine. |
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| 1909. |
An example of aromatic amino acid isA. tyrosineB. phenylalanineC. trytophanD. all of these |
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Answer» Correct Answer - D Aromatic amino acids posses cyclic structure in the side chain, e.g., phenylalanine, tryptophan (actually heterocyclic) or trysine (having OH group). |
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| 1910. |
Number of active sites in allosteric enzyme isA. OneB. TwoC. ThreeD. Four |
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Answer» Correct Answer - B (b) One is active site and second is allosteric site. |
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| 1911. |
the curve given below shows wnzymatic acitvity with relation to three conditions (pH , temperature and substrate concentration ). what do the two axes ( x and y) represent ?A. `{:("X-axis","Y-axis"),((a)"Enzymatic activity","Temperature"):}`B. `{:("X-axis","Y-axis"),((b)"Enzymatic activity","pH"):}`C. `{:("X-axis","Y-axis"),((c)"Temperature","Enzyme Acitivity"):}`D. `{:("X-axis","Y-axis"),((d)"Substrate concentration","Enzymatic Activity"):}` |
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Answer» Correct Answer - C (c) X-axis represent temperature and Y-axis represent enzyme activity. All enxymes act at an optimum temperature, above and below this temperature the enzyme activity declines. |
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| 1912. |
Which of the following statements are correct?A. D-Mannose is a C-2 epmier of D-glucose.B. D-Allose is a C-3 epimer of D-glucose.C. D-Gallactose is a C-4 epmier of D-glucose.D. `alpha-D(+)` glucopyranose and `beta-D(+)` glucoforanose are anomers. |
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Answer» Correct Answer - A::B::C They are not anomers, since one glucose is in pyranose form while the other is in furanose form. |
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| 1913. |
Which of the following statements are correct about `alpha`-amino acids.A. All the amino acids which constitute proteins have D-configuration.B. Isoelectric point of glycine is 6.1.C. Valine is an essential amino acidD. In `alpha`-amino acids, the basic group is `(-COO^(Theta))` and acidic groups is `(-overset(o+)(N)H_(3))`. |
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Answer» Correct Answer - B::C::D All statements are self-explanatory. |
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| 1914. |
Which of the following exhibit mutarotation?A. GlucoseB. MaltoseC. FrctoseD. Galactose |
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Answer» Correct Answer - A::B::C::D All of them have hemiacetalic linkage. |
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| 1915. |
Which of the following statements are correct?A. `beta-D(+)` glucopyranose is more stable than `alpha-D(+)` glucopyranose.B. Invert sugar is laevorotatory.C. Dextrose is D (+) glucose.D. Levulose is D (-) fructose. |
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Answer» Correct Answer - A::B::C::D All statements are self-explanatory. |
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| 1916. |
Which statements are correct about sucrose?A. On complete methylation with `Me_(2)SO_(4)//NaOH`, it forms an octa-o-methyl product.B. On complete acetylation with `Ac_(2)O //NaOAC`, it forms a hexaacetate product.C. On complete acetylation with `Me_(2)SO_(4)//NaOH`, it forms hexa-o-methyl product.D. On complete acetylation with `Ac_(2)O //NaOAC`, it forms octa-acetate product. |
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Answer» Correct Answer - A::D In sucrose there are `OH` groups, so it forms octamethylated and acetylated products. |
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| 1917. |
A bacterium with completely radioactive DNA was allowed to replicate in a non- radioactive medium for two generation what `%` of the bacteria should contain radioactive DNA:-A. `100%`B. `50%`C. `25%`D. `12.5%` |
| Answer» Correct Answer - B | |
| 1918. |
The process by which DNA of the nucleus passes genetic information to m -RNA is calledA. TranscriptionB. TranslocationC. TranslationD. Transportation |
| Answer» Correct Answer - A | |
| 1919. |
Dna directed synthesis of m -RNA is calledA. TranscriptionB. TranslocationC. TransductionD. Replication |
| Answer» Correct Answer - A | |
| 1920. |
Define iso electric point. |
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Answer» At a specific pH value, the net charge of an amino acid in neutral is called iso electric point. At a pH value above the iso electric point the amino acid will be negatively charged and positively charged at pH values below the iso electric point. |
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| 1921. |
An example of competitive inhibition of an enzyme is the inhibition ofA. Succinic dehydrogenase by malconic acidB. Cytochrome oxidase by cyanideC. Hexokinase by glucose 6-phosphateD. Carbonic anhydrase by carbon dioxide |
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Answer» Correct Answer - A (A) An example of competitive inhibition of an enzyme is the inhibition of succinic dehydrogenase by malonic acid. |
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| 1922. |
A basic amino acid isA. LeucineB. MethionineC. Aspartic acidD. Lysine |
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Answer» Correct Answer - D (D) Lysine is a basic amino acid. |
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| 1923. |
Tryptophan and proline areA. Amino acidsB. Fatty acidsC. ProteinsD. polysaccharide |
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Answer» Correct Answer - A (A) Tryptophan and proline are amino acids. |
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| 1924. |
An amino acid may be represented by general formula `H_(2)N overset(R)overset(|)(CH)-COOH`. If `R = -CH_(2)C_(6)H_(5)` then it is phenylalanine (Phe) and if `R = CH_(3)` then it is alanine (Ala). Find the sequence of reagents from those given below to synthesize Phe-Ala. (1) `ZNHoverset(CH_(3))overset(|)(CH)CO_(2)H` , (2) `H_(2)N overset(CH_(3))overset(|)(CH)CO_(2)CH_(2)C_(6)H_(5)` (3) `ZNHoverset(CH_(2)C_(6)H_(5))overset(|)(CH)CO_(2)H` (4) `H_(2)N overset(CH_(2)C_(6)H_(5))overset(|)(CH)CO_(2)CH_(2)C_(6)H_(5)`A. 1 and 2B. 1 and 4C. 2 and 3D. 3 and 4 |
| Answer» Correct Answer - B | |
| 1925. |
Give reactions with support cyclic structure of glucose. |
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Answer» (a) Glucose does not give 2,4‐DNP test, Schiff`s test and sodium hydrogen sulphide test. (b) The pentaacetate of glucose does not react with NH2OH indicating absence of free ―CHO group. (c) Glucose exists in two crystalline form α and β. |
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| 1926. |
The inorganic compounds like sulphate, phosphate, etc., are found inA. acid-souluble poolB. acid-insoluble fractionC. both (i) and (b)D. none of these. |
| Answer» Correct Answer - A | |
| 1927. |
The sum total composition of acid-soluble and acid-insoluble fraction represents the entire composition ofA. dead cellsB. gene poolC. cellular poolD. gene library. |
| Answer» Correct Answer - C | |
| 1928. |
Which of the following is the correct match ?A. `{:("Acid amino","Basic amino","Neutral amino"),("acid","acid","acid"),("Glutamic acid","Lysine","Valine"):}`B. `{:("Acid amino","Basic amino","Neutral amino"),("acid","acid","acid"),("Lysine","Valine","Glutamic acid"):}`C. `{:("Acid amino","Basic amino","Neutral amino"),("acid","acid","acid"),("Glutamic acid","Valine","Lysine"):}`D. `{:("Acid amino","Basic amino","Neutral amino"),("acid","acid","acid"),("Lysine","Glutamic acid","Valine"):}` |
| Answer» Correct Answer - A | |
| 1929. |
The melting points and solubility in water of amino acids are generally higher than that of the corresponding halo acids. Explain.A. amino acids exist as zwitter ions resulting in strong dipole-dipole attractionB. amino acids are optically activeC. due to higher molecular mass of -`NH_(2)` group molecular mass of amino acids is higherD. they interact with water more than halo-acids and have salt like structure . |
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Answer» Correct Answer - A Amino acids exist as zwitter ions, `H_(3)overset(+)N-CHR-COO^(-)` .Because of this dipolar salt-like character, they have strong dipole-dipole attractions . Hence, their melting points are higher than halo-acids . |
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| 1930. |
α-amino acids have relatively higher melting points than the corresponding halo acids. Explain. |
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Answer» The amino acids exits as dipolar Zwitter ion. Due to this dipolar salt like character they have strong dipole-dipole attractions. Thus their melting points are higher than the corresponding haloacids which do not exist as Zwitter ions. |
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| 1931. |
Give reasons as the evidence in support of cyclic structure of glucose. |
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Answer» Correct Answer - (i) Though glucose has aldehyde group, it does not give `2,4-DNP` test (ii) It does not form hydrogen sulphite addition product (iii) The pentacetate of glucose does not react with hydroxyl amine. Amino facts indicate the absence of free `-CHO` group in glucose. (i) Though glucose has aldehyde group, it does not give `2,4-DNP` test (ii) It does not form hydrogen sulphite addition product (iii) The pentacetate of glucose does not react with hydroxyl amine. Amino facts indicate the absence of free `-CHO` group in glucose. |
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| 1932. |
Glucose forms an oxime but glucose penta acetate does not. Explain. |
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Answer» Glucose reacts with NH2OH via the open chain form which has the free –CHO group to form glucose oxime. Glucose penta acetate, on the other hand, cannot be converted into the open chain form because its anomeric hydroxyl group is acetylated and hence does not form the oxime. |
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| 1933. |
The 20 different amino acids have differentA. R-groupsB. carboxylic groupsC. peptide bondsD. amino groups. |
| Answer» Correct Answer - A | |
| 1934. |
Biomolecules areA. inorganic materialsB. organic materialsC. all the carbon compounds obtained from living tissuesD. only DNA and RNA. |
| Answer» Correct Answer - C | |
| 1935. |
Define DNA fingerprinting. |
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Answer» Information regarding sequence of bases on a DNA strand . |
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| 1936. |
What is mutarotation ? |
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Answer» Correct Answer - The spontaneous change in specific rotation of an optically active compound in solution with time, to an equilibrium value, is called mutarotation. The spontaneous change in specific rotation of an optically active compound in solution with time, to an equilibrium value, is called mutarotation. |
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| 1937. |
Biological molecules are primarily joined byA. peptide bondsB. ionic bondsC. hydrogen bondsD. covalent bonds. |
| Answer» Correct Answer - D | |
| 1938. |
Identify the amino acids given below and select the correct option. A. `{:(" (i)",," (ii) "(iii)""),("Glycine",,"Serine Alanine"):}`B. `{:(" (i)",," (ii) "(iii)""),("Alanine",,"Glycine Serine"):}`C. `{:(" (i)",," (ii) "(iii)""),("Alanine",,"Serine Glycine"):}`D. `{:(" (i)",," (ii) "(iii)""),("Serine",,"Alanine Glycine"):}` |
| Answer» Correct Answer - B | |
| 1939. |
Simple six memebered ring compound (eg. Cyclohexane) are not soluble in water whereas glucose and sucrose are soluble in water. Explain why ? |
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Answer» Correct Answer - Glucose has five `-OH` group and sucrose has then `-OH` group and because of hydrogen bonding with `H_(2)O` molecules glucose and sucrose are soluble in water. Glucose has five `-OH` group and sucrose has then `-OH` group and because of hydrogen bonding with `H_(2)O` molecules glucose and sucrose are soluble in water. |
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| 1940. |
Glucose or Sucrose are soluble in water but cyclohexane and benzene are insoluble in water. Explain |
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Answer» Glucose contains five-OH groups and Sucrose contains eight-OH groups, because of this they form inter molecular hydrogen bonding, so they are soluble in water. But benzene and cyclohexane do not contain –OH groups, hence do not form inter molecular hydrogen bonding, so they are not soluble in water. |
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| 1941. |
Select the incorrect match from the following .A. Terpenoids - MonoterpenesB. Lectins - Concanavalin AC. Toxins - AnthocyaninsD. Drugs - Vinblastin |
| Answer» Correct Answer - C | |
| 1942. |
Match column I with column II and select the correct option from the given codes. `{:(" Column I",," Column II"),(A." ""Tetrose sugar",,(i)"Galactose"),(B. " " "Pentose sugar",,(ii)"Maltose"),(C." " "Hexose sugar",,(iii)"Erythrose"),(D" ""Disaccharide",,(iv)"Ribose"),(" ",, (v)"Sedoheptulose"):}`A. `A-(v),B-(iv),C(iii),D-(i),(ii)`B. `A-(iii),B-(iv),C(v),D-(ii)`C. `A-(iii),B-(iv),C(i),D-(ii)`D. `A-(i),(ii),B-(iv),C(iii),D-(v)` |
| Answer» Correct Answer - C | |
| 1943. |
What is the function of collagen? |
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Answer» It forms the intercellular ground substance. |
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| 1944. |
Match column I with column II and select the correct option from the given codes. `{:(" Column I",," Column II"),(A." ""Galactose",,(i)"Protein"),(B." " "Anticoagulant",,(ii)"Phospholipid"),(C." " "Fructose",,(iii)"Brain sugar"),(D." ""Lecithin",,(iv)"Heparin"),(E." Insulin ",, (v)"Fruit sugar"):}`A. `A-(v), B-(iii),C-(ii), D-(i), E-(iv)`B. `A-(v), B-(iii),C-(i), D-(iv), E-(ii)`C. `A-(i), B-(ii),C-(iii), D-(v), E-(iv)`D. `A-(iii), B-(iv),C-(v), D-(ii), E-(i)` |
| Answer» Correct Answer - D | |
| 1945. |
Give examples of toxins. |
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Answer» Ricin and Abrin. |
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| 1946. |
What is polymer of amino acids called? |
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Answer» Proteins is polymer of amino acids called |
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| 1947. |
Give few examples of alkaloids. |
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Answer» Morphine and Codeine. |
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| 1948. |
Match the column I with column II and choose the correct combination from the options given. `{:(" Column I",," Column II"),("(Component)",,"(% of the total cellular mass)"),(A."""Ions ",,(i)"1"),(B."" "Lipids",,(ii)"2"),(C."" "Carbohydrates",,(iii)"3"),(D."""Nucleic acids",,(iv)"5-7"),(E."""Proteins",,(v) "10-15"):}`A. `A-(i), B-(ii), C-(iii), D-(iv), E-(v)`B. `A-(ii), B-(iii), C-(i), D-(v), E-(iv)`C. `A-(iii), B-(i), C-(ii), D-(iv), E-(v)`D. `A-(iv), B-(ii), C-(iii), D-(v), E-(i)` |
| Answer» Correct Answer - A | |
| 1949. |
Mention the function of GLUT – 4? |
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Answer» It enables glucose transport into cells. |
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| 1950. |
Which of the following is leavo rotatory?A. FructoseB. GlucoseC. sucroseD. all of these |
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Answer» Correct Answer - A |
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