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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Alcohol and HF molecule contains __________ & _____________ hydrogen bonds.(a) intramolecular, intermolecular(b) intermolecular, intermolecular(c) intermolecular, intramolecular(d) intramolecular, intramolecularThis question was posed to me in homework.This question is from Hydrogen Bonding in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct CHOICE is (b) INTERMOLECULAR, intermolecular

For EXPLANATION I WOULD say: The presence of hydrogen between MOLECULES is intermolecular hydrogen bond and the presence of hydrogen bond in the molecule itself is intramolecular hydrogen bond. So it’s intermolecular in case of alcohol and water.

2.

In a hydrogen bond, the electron pair that is shared moves away from hydrogen.(a) True(b) FalseThe question was asked in an internship interview.This key question is from Hydrogen Bonding in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct option is (a) True

Best EXPLANATION: Yes, in the formation of a hydrogen bond, the electron pair moves away from hydrogen. This OCCURS due to the HIGH electronegativity of other atoms participating in a hydrogen bond. So NATURALLY, hydrogen has positive CHARGES and electrons move away.

3.

Which of the following molecule can form a hydrogen bond with hydrogen?(a) Sodium(b) Oxygen(c) Aluminum(d) RubidiumI have been asked this question by my college director while I was bunking the class.Question is from Hydrogen Bonding topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct choice is (b) Oxygen

The explanation is: Most ELECTRONEGATIVE ELEMENTS can only form hydrogen bonds with hydrogen, Among Sodium, Oxygen, Aluminium, and RUBIDIUM, Oxygen is the electronegative ELEMENT. So only oxygen can form a hydrogen BOND.

4.

Which of the following molecules doesn’t involve hydrogen bond formation?(a) H2O(b) O-nitrophenol(c) NaCl(d) HFThe question was posed to me in quiz.The question is from Hydrogen Bonding topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct OPTION is (c) NaCl

For EXPLANATION I would say: Water, Hydrogen fluoride INCLUDE intermolecular hydrogen while o-nitrophenol has INTRAMOLECULAR hydrogen bonding. Sodium Chloride NaCl has an ionic bond that is MUCH stronger than hydrogen bond.

5.

The magnitude of the H-bonding depends on the ___________ of the compound.(a) surroundings(b) system(c) atmosphere(d) physical stateI have been asked this question in an interview for job.I'm obligated to ask this question of Hydrogen Bonding in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right choice is (d) PHYSICAL state

Easy explanation: The MAGNITUDE of the H-bonding depends on the physical state of the COMPOUND. In the gaseous state, it is minimum and in the solid state, it is maximum. There is a great influence on a compound’s STRUCTURE and PROPERTIES.

6.

Water molecules contain _____________ hydrogen bond/s.(a) intermolecular(b) intramolecular(c) both intermolecular and intramolecular(d) neither intermolecular nor intramolecularThe question was asked in exam.I would like to ask this question from Hydrogen Bonding topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (a) intermolecular

For explanation I would say: In a water MOLECULE, the HYDROGEN bonds are formed between other MOLECULES but not within the same molecule. The presence of hydrogen between molecules is intermolecular hydrogen bond and presence of hydrogen bond in the molecule itself is INTRAMOLECULAR hydrogen bond.

7.

In a hydrogen bond, hydrogen has a positive charge.(a) True(b) FalseI got this question during an internship interview.My enquiry is from Hydrogen Bonding in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT option is (a) True

For EXPLANATION I WOULD say: IN the HYDROGEN bond, the other element is highly electronegative, So the hydrogen becomes electropositive comparatively in this case and there is a displacement of electrons towards the electronegative SIDE. Hence hydrogen has a positive charge.

8.

Which bond acts like a bridge two molecules formed by a covalent bond?(a) Covalent bond(b) Ionic bond(c) Hydrogen bond(d) Metallic bondI got this question in semester exam.The query is from Hydrogen Bonding topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct CHOICE is (c) Hydrogen bond

To ELABORATE: For example, consider a molecule that’s FORMED due to a covalent between hydrogen and fluorine. Here hydrogen acquires a positive charge. Hydrogen bond FORMATION occurs between hydrogen in a molecule and fluorine of the other molecule.

9.

A molecule named o-nitrophenol consists of ______________hydrogen bond/s.(a) intermolecular(b) intramolecular(c) both intermolecular and intramolecular(d) neither intermolecular nor intramolecularThe question was posed to me by my college director while I was bunking the class.This intriguing question originated from Hydrogen Bonding topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct ANSWER is (B) intramolecular

For explanation I WOULD say: The presence of hydrogen between molecules is INTERMOLECULAR hydrogen BOND and presence of hydrogen bond in the molecule itself is intramolecular hydrogen bond. In o-nitrophenol, there is a hydrogen bond between the hydrogen of the hydroxide group and oxygen.

10.

Nitrogen, fluorine and oxygen are ___________ in nature.(a) electronegative(b) electropositive(c) metallic(d) semi-metallicI had been asked this question during an interview.This interesting question is from Hydrogen Bonding topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct option is (a) electronegative

The EXPLANATION is: Electronegativity is the tendency of a neutrally isolated GASEOUS atom to attract an electron. This is high in the case of nitrogen, oxygen, and fluorine. So the NEGATIVE CHARGE in the hydrogen bond is towards them.

11.

What is the total number of electrons in the Chlorine molecule?(a) 17(b) 34(c) 18(d) 16This question was posed to me in an online interview.Query is from Bonding in Some Homonuclear Diatomic Molecules in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The CORRECT option is (b) 34

The BEST I can explain: A Chlorine atom is MADE up of 17 electrons. When two Chlorine atoms share an electron covalently, the Chlorine molecule is formed. So the Chlorine molecule Cl2 has a TOTAL of 17 + 17 atoms = 34 atoms.

12.

H2, N2, O2 and Li2 are ______________(a) heteronuclear diatomic molecules(b) heteronuclear triatomic molecules(c) homonuclear diatomic molecules(d) homonuclear triatomic moleculesI have been asked this question in semester exam.This key question is from Bonding in Some Homonuclear Diatomic Molecules topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The CORRECT option is (c) homonuclear diatomic MOLECULES

Explanation: The molecules that have the same atoms in them are called as homonuclear molecules. The molecules that have only two atoms are called diatomic molecules. So H2, N2, O2, and LI2 are called homonuclear diatomic molecules.

13.

Which of the following is true regarding nitrogen molecule.(a) Diamagnetic(b) Paramagnetic(c) Bond order is 2(d) Total number of electrons in the molecule is 13This question was posed to me in an internship interview.I'm obligated to ask this question of Bonding in Some Homonuclear Diatomic Molecules topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (a) Diamagnetic

Easiest explanation: The Nitrogen molecule N2 is diamagnetic in NATURE as it contains zero single electrons, all the electrons are paired. Its bond ORDER is CALCULATED as 3 and the TOTAL number of electrons the nitrogen molecule are 14.

14.

The electronic configurations of molecules change when the number of electrons is ________(a) 10(b) 20(c) 17(d) 14This question was posed to me in class test.The query is from Bonding in Some Homonuclear Diatomic Molecules in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right answer is (d) 14

For explanation: The ELECTRONIC CONFIGURATION below number of ELECTRONS= 14, i.e. number of electrons = 12 is σ1s^2σ*1s^2σ2s^2 σ*2s^2π2px^2π2y^2but after 14, TAKE number of electrons = 16 is σ1s^2σ*1s^2σ2s^2σ*2s^22pz^2π2px^2π2y^2π*2px^1π*2py^1 So the change COMES near 2pz orbital’s place.

15.

O2 is paramagnetic in nature.(a) True(b) FalseThis question was addressed to me in my homework.This question is from Bonding in Some Homonuclear Diatomic Molecules topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct OPTION is (a) True

Best explanation: σ1s^2σ*1s^2σ2s^2σ*2s^22pz^2π2px^2π2y^2π*2px^1π*2py^1 is the electronic CONFIGURATION of O2 molecule. According to this, it has TWO unpaired electrons, making it paramagnetic and is ATTRACTED by the magnetic field.

16.

The number of electrons in bonding orbital and anti-bonding orbital of Lithium molecule are ______ and _______ respectively.(a) 4, 4(b) 2, 2(c) 2, 4(d) 4, 2The question was posed to me in my homework.Question is from Bonding in Some Homonuclear Diatomic Molecules in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right choice is (d) 4, 2

The explanation is: The lithium molecule is denoted by LI2. When the lithium molecule is formed, each of the lithium shares an electron in the 2s ORBITAL. Its ELECTRONIC configuration is σ1s^2σ*1s^2σ2s^2. So the NUMBER of electrons in bonding orbital and anti-bonding orbital of Lithium molecule are 4 and 2respectively.

17.

What is the electronic configuration of the carbon atom?(a) 1s^22s^22p^2(b) σ1s^2σ*1s^2σ2s^2σ*2s^2π2px^2π2py^2(c) 1s^22s^22p^1(d) σ1s^2σ*1s σ2s^2π2px^2π2py^2I have been asked this question in an interview.Question is from Bonding in Some Homonuclear Diatomic Molecules in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» RIGHT option is (a) 1s^22s^22p^2

Easiest EXPLANATION: The given question electronic configuration of carbon “atom”, but not carbon “molecule”. So by following Aufbau’s principle and noting that carbon CONTAINS 6 ELECTRONS, the ANSWER is given as 1s^22s^22p^2.
18.

What is the condition, for a molecule do not exist?(a) NA = NB(b) NA > NB(c) NA < NB(d) NA >/< NBThis question was posed to me in unit test.My question is based upon Bonding in Some Homonuclear Diatomic Molecules topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right answer is (a) NA = NB

Easiest explanation: When a molecule’s bond order is EQUAL to zero, the molecule cannot exist. The formula for finding out bond order is \(\FRAC{1}{2}\)(NB – NA). So NA – NB = 0, that is NA = NB. Where NA as the number of anti-bonding MOLECULAR orbitals and NB as the number of bonding molecular orbitals.

19.

Which of the following molecule doesn’t exist?(a) O2(b) H2(c) He2(d) N2I have been asked this question in exam.The doubt is from Bonding in Some Homonuclear Diatomic Molecules in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct OPTION is (B) H2

Explanation: The electronic configuration of HE2 is σ1s^2σ*1s^2. Here NA = NB (where NA as the number of anti-bonding molecular orbitals and NB as the number of bonding molecular orbitals). So the molecule He2 doesn’t exist.

20.

What is the electronic configuration of hydrogen molecule?(a) σ1s^2(b) σ1s^1(c) σ1s(d) σ*1sI had been asked this question in a national level competition.My doubt stems from Bonding in Some Homonuclear Diatomic Molecules topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct option is (a) σ1s^2

Easy explanation: In a hydrogen atom, each hydrogen SHARES an electron from 1S orbital, so in total there are TWO electrons present in 1s bonding orbital of the molecule. So the electronic CONFIGURATION of the hydrogen molecule is σ1s^2.

21.

Which of the following molecule is not true about paramagnetic molecules?(a) Attracted by the magnetic field(b) A molecular orbital is singly occupied(c) An example is oxygen molecule(d) Repelled by the magnetic fieldThis question was addressed to me in exam.The doubt is from Molecular Orbital Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct ANSWER is (d) Repelled by the magnetic field

Best EXPLANATION: Paramagnetic MOLECULES are ATTRACTED by the magnetic field and orbitals are singly occupied. O2 is an example. Whereas DIAMAGNETIC molecules are repelled by the magnetic field, so the option is wrong.

22.

What do you think is the relationship between bond order and bond length?(a) Directly proportional(b) Indirectly proportional(c) No relation(d) Cannot predictThis question was addressed to me during an interview for a job.I want to ask this question from Molecular Orbital Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct choice is (B) INDIRECTLY proportional

Explanation: The bond LENGTH has defined the distance between TWO atoms in a molecule. The bond ORDER depends on the bond length between two atoms in a molecule. As the bond length increases the bond decreases and vice-versa.

23.

What’s the bond order of Oxygen?(a) 3(b) 2(c) 1(d) 0This question was posed to me in an interview for internship.This interesting question is from Molecular Orbital Theory topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct OPTION is (B) 2

The explanation is: The formula of bond ORDER is given by ^1⁄2(NB – NA) When NB is BONDING orbitals and NA is the NUMBER of anti-bonding orbitals. In Oxygen, bond order = 1/2(10-6) = 2. When it’s zero the molecule cannot be formed.

24.

Take NA as the number of Anti-bonding molecular orbitals and NB as the number of Bonding molecular orbitals. The molecule is stable when NA ____________ NB.(a) is greater than(b) is equal to(c) is less than(d) is greater than or equal toThe question was posed to me in an internship interview.I'm obligated to ask this question of Molecular Orbital Theory topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The CORRECT option is (c) is LESS than

For EXPLANATION: When a molecule consists both BONDING MOLECULAR orbitals and anti-bonding molecular orbitals, the higher the number of bonding orbitals, the more the bonding influence and the more stable the molecule will be and vice-versa.

25.

Which of the bonding orbital has greater energy comparatively?(a) Both Bonding molecular orbital and Anti-bonding molecular orbital have the same energy(b) The energy of Bonding molecular orbital and Anti-bonding molecular orbital depends on the situation(c) Bonding molecular orbital(d) Anti-bonding molecular orbitalThis question was addressed to me in an interview for job.The origin of the question is Molecular Orbital Theory topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct choice is (d) Anti-bonding molecular ORBITAL

The BEST explanation: An ELECTRON that enters bonding ORBITALS stabilizes the MOLECULE as it’ in between two nuclei. Whereas when an electron is entered into the anti-bonding orbital, it needs to pull an electron away from the nucleus.

26.

Sigma molecular orbitals are not symmetrical around the bonding axis.(a) True(b) FalseThis question was addressed to me in a job interview.Question is taken from Molecular Orbital Theory topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» CORRECT answer is (B) False

The best I can explain: According to the nomenclature, SIGMA molecular orbitals are symmetrical AROUND the bonding axis and the pi molecular orbitals are not symmetrical around the bonding axis. So the given STATEMENT is false.
27.

Stability increases, as the energy ___________(a) increases(b) doesn’t change(c) decreases(d) increases and then decreasesThe question was posed to me by my school principal while I was bunking the class.The origin of the question is Molecular Orbital Theory topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» RIGHT choice is (c) decreases

The EXPLANATION is: As the stability increases, the ENERGY of that substance decreases. The HIGHER the energy, the less stable the molecule. So stability is inversely proportional to the energy. This can be seen in any part of the universe.
28.

Which of the following is a condition for the combination of atomic orbitals?(a) Combining atomic orbitals need not have equal energy(b) Combining atomic orbitals must have symmetry as per molecular axis(c) Combining atomic orbitals must overlap to a minimum extent(d) For combining atomic orbitals, X-axis should be taken as a molecular axisI have been asked this question in unit test.I want to ask this question from Molecular Orbital Theory in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct OPTION is (b) COMBINING ATOMIC orbitals must have symmetry as per molecular AXIS

To elaborate: Combining atomic orbitals must have symmetry as per molecular axis is TRUE. The corrected statements are combining atomic orbitals must have equal energy, must overlap to the maximum extent and Z-axis should be taken as the molecular axis.

29.

\(\psi\)MO = \(\psi\)A + \(\psi\)B.(a) True(b) FalseI had been asked this question by my school principal while I was bunking the class.My doubt stems from Molecular Orbital Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT option is (a) True

Explanation: The LINEAR combinations LIKE additions and subtractions of wave functions of individual atomic orbitals indicate the formation of molecules MATHEMATICALLY, as given i.e. \(\psi\)MO = \(\psi\)A + \(\psi\)B. Where \(\psi\) represents the wavefunctions of atomic orbitals.

30.

Combination of two atomic orbitals results in the formation of two molecular orbitals namely _________(a) one bonding and one non-bonding orbital(b) two bonding orbitals(c) two non-bonding orbitals(d) two bonding and non-bonding orbitalsThe question was posed to me in exam.This intriguing question comes from Molecular Orbital Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct OPTION is (a) one BONDING and one non-bonding orbital

Best explanation: F. Hund and R.F. Mullikan proposed Molecular orbital THEORY in the year 1932. According to this theory, the COMBINATION of two atomic orbitals results in the formation of two molecular orbitals NAMELY one bonding and one non-bonding orbital.

31.

Which of the following statement is true regarding hybrid orbitals?(a) The amount of orbitals formed after the hybridization is not equal to the number of orbitals before hybridization(b) The hybrid orbitals don’t have equal energy(c) They can form more stable bonds than the pure orbitals(d) Hybridization doesn’t indicate geometryThis question was posed to me in an international level competition.This key question is from Molecular Structure in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT choice is (c) They can form more stable bonds than the pure orbitals

The explanation is: The true statements of the INCORRECT ONES are the number of orbitals FORMED after the hybridization is equal to the number of orbitals before hybridization, the hybrid orbitals have equal energy and the hybridization indicates geometry.

32.

What is the geometry of PCl5 molecule?(a) Square pyramidal(b) V-shape(c) Trigonal bipyramidal(d) TetrahedralThis question was addressed to me in my homework.I'm obligated to ask this question of Molecular Structure topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» CORRECT option is (c) Trigonal bipyramidal

For explanation: As the PCl5 molecule undergoes sp^3d hybridization, it POSSES the geometry the trigonal bipyramidal. In the SHAPE, the CENTRAL atom is Phosphorous and the atoms at the FIVE corners are Chlorine.
33.

The orbitals formed after hybridization have equal energy.(a) True(b) FalseThis question was posed to me during an interview.The question is from Molecular Structure topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct answer is (a) True

Explanation: The hybridization is the INTERMIXING of different ORBITALS in order to form a new set of equivalent orbitals otherwise known as HYBRID orbitals. All the hybrid orbitals those have undergone the same hybridization have the same amount of ENERGY.

34.

Mention the types of orbitals that undergo hybridization in order to get octahedral geometry?(a) s-orbital only(b) s-orbital and p-orbital(c) s-orbital, p-orbital, and d-orbital(d) d-orbital and p-orbitalI had been asked this question in an online interview.My query is from Molecular Structure topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct answer is (c) s-orbital, p-orbital, and d-orbital

Explanation: Octahedral geometry is POSSIBLE when the atomic ORBITALS under UNDERGOING sp^3d^2 or d^2sp^3 hydration only. So it involves one s-orbital, three p-orbitals, and TWO d-orbitals. An example of this is SF6.

35.

What do you think is the number of sigma bonds in an ethene molecule?(a) 6(b) 7(c) 4(d) 5I got this question in quiz.I want to ask this question from Molecular Structure topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct OPTION is (d) 5

The EXPLANATION: The FORMULA of ethene molecule is C2H4. There is one SIGMA bond between two carbon atoms and 2 sigma bonds between each of the carbon and the hydrogens. So in total, it’s five (one pi-bond is present between the 2 carbon atoms).

36.

What is the bond angle of H-C-H in methane molecule?(a) 104.5°(b) 109.5°(c) 108°(d) 120°The question was posed to me in my homework.The origin of the question is Molecular Structure topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct answer is (B) 109.5°

To EXPLAIN I would say: The molecule of methane i.e. CH4 had undergone sp^3 hybridization (1 s-orbital and 3 p-orbitals COMBINE to give 4 sp^3 orbitals). It exhibits tetrahedral geometry. In tetrahedral geometry, the angle between the BONDS of corner atoms and the central atom is 109.5°.

37.

What type of hybridization does a BCl3 molecule undergo?(a) sp(b) sp^2(c) sp^3(d) sp^3dThe question was posed to me during an interview for a job.The question is from Molecular Structure topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct choice is (b) sp^2

For explanation: In the BCl3 molecule, one s-orbital and two p-orbitals intermix and form three equivalent hybrid ORBITS. Therefore it UNDERGOES sp^2 hybridization and FORMS TRIGONAL planar shape, like B in the center and CL in the 3 corners.

38.

The orbitals that are resulted from sp hybridization have _______% s-character and ________% p-character.(a) 25, 75(b) 75, 25(c) 20, 80(d) 50, 50I have been asked this question in quiz.Asked question is from Molecular Structure topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right option is (d) 50, 50

To ELABORATE: When one s-orbital and p-orbital UNDERGO hybridization, 2 sp orbitals are formed. One sp-orbital has 50% s-character and 50% p-character. They possess LINEAR GEOMETRY and it’s also CALLED diagonal hybridization.

39.

The phenomenon of forming completely new atomic orbitals by intermixing them is known as ___________(a) Allocation(b) Hybridization(c) Chemical bond formation(d) Electron configurationI got this question in exam.My question is taken from Molecular Structure topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» CORRECT choice is (b) Hybridization

The explanation is: The exact meaning of hybridization is the intermixing of DIFFERENT ORBITALS in order to form a NEW set of equivalent orbitals otherwise known as hybridized orbitals. These hybrid orbitals are used in bond FORMATION.
40.

Who introduced the concept of hybridization?(a) Pauling(b) London(c) Sidgwick(d) AlexanderThe question was asked during an interview for a job.Query is from Molecular Structure topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right OPTION is (a) Pauling

Explanation: In order to explain the bonding and shapes of EVERY polyatomic atomic molecule LIKE METHANE, carbon tetrachloride, water, boron trifluoride, etc, Pauling put-forth the concept of hybridization.

41.

Which type of bond is present between hydrogens in hydrogen molecule?(a) Sigma bond(b) Pi bond(c) Ionic bond(d) Metallic bondI had been asked this question in examination.I'd like to ask this question from Valence Bond Theory topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct CHOICE is (a) Sigma bond

To explain: The head-on or end to end TYPE of overlapping is PRESENT in sigma bond. A sigma bond is a type of covalent bond. It MAY also be called an axial OVERLAP. In case of the hydrogen molecule, its s-s overlapping.

42.

The strength of covalent ___________extent of overlapping of orbitals.(a) may be or may not be related(b) is independent on(c) is dependent on(d) is not related toThis question was posed to me in exam.This intriguing question comes from Valence Bond Theory in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right ANSWER is (C) is DEPENDENT on

To explain: As per the concept of valence bond theory, the partial merging of atomic ORBITALS id knowns as overlapping. The extent of overlapping is DIRECTLY proportional to the strength of the covalent bond, i.e. it is dependent.

43.

The bond enthalpy of ___________molecule is 435.8 kJ mol^-1.(a) Hydrogen(b) Oxygen(c) Nitrogen(d) HeliumThis question was addressed to me by my college professor while I was bunking the class.This question is from Valence Bond Theory in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct option is (a) Hydrogen

Easy explanation: The amount of energy that is required to break a chemical BOND in a MOLECULE into INDIVIDUAL atoms is known as bond ENTHALPY. 435.8 kJ mol^-1 is required to DISSOCIATE a hydrogen molecule into two hydrogen atoms.

44.

Which of the following molecules geometry is true?(a) BrF5 – Triagonal pyramidal(b) ClF3 – T-shape(c) PCl5 – See-saw(d) SF4 – Triagonal bipyramidalI got this question by my college professor while I was bunking the class.Origin of the question is Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (b) ClF3 – T-shape

To explain: The molecule ClF5 has T-shape as it 3 bonding pairs and 2 lone pairs, so it’s true. The molecules BrF5, PCl5, and SF4 have the shapes square PYRAMIDAL, trigonal bipyramidal and see-saw respectively.

45.

All the __________ species(molecules and ions) have the same bond order.(a) isotopic(b) isoelectronic(c) isobaric(d) isoneutronicThis question was addressed to me in an online quiz.This question is from Bond Parameters in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right choice is (B) isoelectronic

For explanation: The molecules and IONS that contain the same number of electrons are CALLED isoelectronic SPECIES. They all have the same bond order. For example, the molecules and ions like N2, CO and NO^+ have the bond order 3 and 14 electrons.

46.

The shape a molecule occupies allows to minimize repulsions among them and maximize the space between them.(a) True(b) FalseI got this question by my school teacher while I was bunking the class.My question is based upon Valence Shell Electron Pair Repulsion (VSEPR) Theory in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Right option is (a) True

Explanation: As the postulate of Valence Shell Electron PAIR Repulsion Theory (VSEPR), a MOLECULE tends to FORM a shape or ORIENTATION that has little repulsion comparatively and the higher distance between the electron PAIRS comparatively.

47.

A chemical bond formation that involves the complete transfer of electrons between atoms is _______(a) ionic bond(b) covalent bond(c) metallic bond(d) partial covalent bondThis question was addressed to me in an interview for job.Enquiry is from Ionic or Electrovalent Bond in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (a) ionic bond

For EXPLANATION: Ionic bond, which is otherwise KNOWN as electrovalent bond forms between two ATOMS by the transfer of electrons between them. It GENERATES oppositely charged ions. Positively charged ions are mostly METALS and the vice-versa.

48.

Calculate the formal charge of C in CH4.(a) 4(b) 1(c) -4(d) 0I got this question in an interview.Question is taken from Kossel-Lewis Approach to Chemical Bonding in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct OPTION is (d) 0

The best explanation: The formula for finding out the formula charge of an in a molecule = total NUMBER of valence electrons – total number of non-bonding electrons – 1/2(total number of bonding electrons). So here, FORMAL charge of C = 4 – 0 – 8/2 = 0.

49.

Which of the following molecule doesn’t involve covalent bond?(a) H2O(b) CCl4(c) NaCl(d) O2I have been asked this question during an online exam.My enquiry is from Kossel-Lewis Approach to Chemical Bonding in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct option is (c) NaCl

Explanation: The formation of NaCl MOLECULE where Na and Cl transfer electrons to each other forming Na^+ and Cl^–. There is no SHARING of electrons i.e. no COVALENT bond. Whereas the molecules H2O, Cl2 and O2 involve sharing of electrons.

50.

What are the units of measuring the bond angle?(a) meters(b) kilograms(c) degree(d) moleThe question was posed to me during an interview.This interesting question is from Bond Parameters in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct option is (c) degree

The best explanation: The angle between TWO BONDS from the same atom that is bonded to different atoms is called the bond angle. It EXPRESSED in the units of degree EXPERIMENTALLY by spectroscopic methods. It depicts the shape of the molecule in a 3D dimension.