InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 801. |
Stability of the species `Li_(2), Li_(2)^(-), Li_(2)^(+)` increases in the order ofA. `Li_(2) lt Li_(2)^(+) lt Li_(2)^(-)`B. `Li_(2)^(-) lt Li_(2)^(+) lt Li_(2)`C. `Li_(2) lt Li_(2)^(-) lt Li_(2)^(+)`D. `Li_(2)^(+) lt Li_(2) lt Li_(2)^(+)` |
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Answer» Correct Answer - b `Li_(2) (3+3 = 6) = sigma 1s^(2), sigma 1s^(2) sigma 2s^(2)` Bond order `= (N_(b)-N_(a))/(2) = (4-2)/(2) = 1` `Li_(2)^(+) (3+3-1=5) = sigma 1s^(2), sigma 1s^(2) sigma 2s^(1)` Bond order `= (3-2)/(2) = (1)/(2) = 0.5` `Li_(2) (3+3+1=7) = sigma 1s^(2), sigma 1s^(2) sigma 2s^(2) , sigma_(2s^(1)` Bond order `= (4-3)/(2) = (1)/(2) = 0.5` Stability order is `Li_(2) gt Li_(2)^(+) gt Li_(2)^(-) (because Li_(2)^(-)` has more number of electron in antibonding orbitals which destabilizes the species) |
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| 802. |
A arrange the following resonating structures in the order of decreasing stability . |
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Answer» Structures(I) and (II) have greater number of covalent bonds hence, these are more stable than either (III) or (IV) Furthermore, between I and II, structure I has no formal charges and hence is more stable than structure (II) (b) Structure (IV) is less stable than (III) because in (IV) the poitive charge is on oxygen, which is a more `EN` atom than carbon on which positive charge is present in (III) Thus the order of stability is `IgtIIgtIIIgtIV` . |
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| 803. |
Drw all the possible resonating structures for azide ion `(N_(3)^(-)ion).` Which our of these are actually feasible ? |
| Answer» Out of these, the reasenating structure (IV) is in cyclic from with bohnd angles of `60^(@)` Because of the strain involved in the ring, this structure is not feasiblel. All other structures are fesibile. | |
| 804. |
Carbonyl group has following resonating structures (I) The correct order of stablity of these structures isA. I gtII gt IIIB. III gtI gt IIC. I gtIII gt IID. III gtII gt I |
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Answer» Correct Answer - b The resonating structure with minimum or no charge is more stable . Thus , the stability of (III) is maximum . The structure (I) is more stable than structure (II) as the negative charge is power on more electronegative atom. |
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| 805. |
Statement : The molecule cis-1-chloropropene is more polar than trans-1-chloropropene . Explanation : The magnitude of resultant vector in chloropropene is non-zero.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true and the reason is the correct explanation of the assertion.C. If assertion is true but reason is false.D. if assertion is false but reason is true. |
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Answer» Correct Answer - d Both cis -and trans form are polar .Trans is more polar due to higther value of dipole moment due to addition nature of `CH_(3)` and CI vectors. |
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| 806. |
Bonds presents in `CuSO_(4) .5H_(2)O` isA. Electrovalent and covalentB. Electrovalent and coordinateC. Electrovalent, covalent and coordinateD. Covalent and coordinate |
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Answer» Correct Answer - c `CuSO_(4),SH_(2)O` has electrovalent , covalent and coordinate bonds , `Cu^(2+) [O^(-)- overset(O)overset(uarr)underset(O)underset(darr)S- O^(-)]SH_(2)O` |
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| 807. |
The sequence that correctly describes the relative bond strengths pertaining to oxygen molecule and its cation or anion isA. `O_2^(2-) gt O_2^(-) gt O_2 gt O_2^(+)`B. `O_2 gt O_2^(+) gt O_2^(2-) gt O_2^(2+)`C. `O_2^(+)gt O_2 gt O_2^(2-) gt O_2^(-)`D. `O_2^(+) gt O_2 gt O_2^(-) gt O_2^(2-)` |
| Answer» Correct Answer - D | |
| 808. |
Polarisation involves the distortion of the shape of an anion by an adjacently placed cation In this context, which of the following statements is correct ? .A. Maximum polarisation is brought about by a cation of high chargeB. Maximum polarisation is brought about by a cation of high chargeC. A large cation is likely to bring about a high degree of polarisation .D. The polarising power of a cation is less than that of an anion |
| Answer» Correct Answer - A | |
| 809. |
Statement-1 : Polarisation is the distortion of the shape of an anion by adjacently placed cation. and Statement-2 : Maximum polarisation is brought by a cation of high charge .A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True , Statement-2 is FalseD. Statement-1 is False , Statement-2 is True |
| Answer» Correct Answer - B | |
| 810. |
Polarisation involves the distortion of the shape of an anion by an adjacently placed cation In this context, which of the following statements is correct ? .A. Maximum polarization is done by cation of high chargeB. A large cation is likely to bring larger degree of polarizationC. A smaller anion is likely to undergo a higher degree of polarizationD. Minimum polarization is done by cation of small size |
| Answer» Correct Answer - A | |
| 811. |
Polarisation involves the distortion of the shape of an anion by an adjacently placed cation In this context, which of the following statements is correct ? .A. Maximum polarisation is done by a cation of high chargeB. A large cation is likely to bring large degree of polarisationC. A smaller anion is likely to undergo a high degree of polarisation .D. Minimum polarisation is done by a cation of small size |
| Answer» Correct Answer - A | |
| 812. |
From the following which group of elements easily forms cationA. F,CI,BrB. Li,Na,KC. O,S,SeD. `N,P,As` |
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Answer» Correct Answer - b Li, Na and K arealkali metals with low ionization energy and one electronin their outermost shell so they will form cation easily |
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| 813. |
Statement : The lattice energy of silver halids is ` AgF gt AgCl gt AgBr gt AgI`. Explanation : `AgF` is water soluble .A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - b In spin of higher lattice energy AgF is soluble because F is extentensively bydrated and heat of hydration predominates over lattice energy. |
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| 814. |
Which of the folowing angles corresponds to `sp^(2)` hybridisation ?A. `90^(@)`B. `120^(@)`C. `180^(@)`D. `109^(@)` |
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Answer» Correct Answer - B Bond angel `120^(@)` correspondus to `sp^(2)` hybridisation. |
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| 815. |
Which of the folowing have identical bond orders ? .A. `CN^(Theta)`B. `O_(2)^(Theta)`C. `NO^(o+)`D. `CN^(o+)` |
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Answer» Correct Answer - A::C `CN^(Theta)` and `NO^(o+)` have 14 electrons each and an identrical bond order of three . |
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| 816. |
If `Z-axis` is the molecular axis, then `pi-`molecular orbitals are formation by the formed by the overlap ofA. `s+p_(z)`B. `p_(s)+p_(z)`C. `p_(z)+p_(z)`D. `p_(s)+p_(s)` |
| Answer» Correct Answer - d | |
| 817. |
The attractive force which holdes various constituents togrther in different chemical species is calledA. valence bondB. chemical bondC. atomic bondD. electrovalent bond. |
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Answer» Correct Answer - B it is the correct answer. |
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| 818. |
Which iof the folowing molecule contains one pair of non-bonding electrons?A. `CH_(4)`B. `NH_(3)`C. `H_(2)O`D. `HF` |
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Answer» Correct Answer - b In `NH_(3)` nitrogen has one lone pair of electron |
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| 819. |
The hybridisation of the central atom will change whenA. `NH_(3)` combined with `H^(+)`B. `H_(3)BO_(2)` combined with `OH`C. `NH_(3) forms NH_(2)`D. `H_(2)O` combines with `H^(+)` |
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Answer» Correct Answer - b `B(OH)_(3)+OH^(-) rarr B(OH)_(4)` `sp^(2) sp^(3)` |
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| 820. |
Taking Z-axis as the internuclear axis, explain why ` 2p_(x) or 2p_(y)` orbital does not combine with 2s obtial to form molecular orbtals ? |
| Answer» The small ++ overlap cancels the +- overlap . Hence , there is not net overlapping . | |
| 821. |
In the formation of `pi`-bond, the atomic orbitals overlap in such a way thatA. their axis remain parallel to each other and perpendicular to the internuclear axisB. their axis remain parallel to each other and parallel to the internuclear axisC. their axis remain perpendicular to each other and parallel to the internuclear axisD. their axis remain perpendicular to each other and perpendicular to the internuclear axis. |
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Answer» Correct Answer - A It is the correct answer. |
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| 822. |
Linear overlap of two atomic p-orbitals leads to a sigma bond . |
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Answer» Correct Answer - T True -The linear overlap of two atomic p-orbitals leads to a `sigma` -bond . |
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| 823. |
When atomic orbitals overlap head-on , the bond formed is ……….. Whereas when they overlap laterally , the bond formed is ………. |
| Answer» ` sigma-bond,pi-bond` | |
| 824. |
Assertion Ionic compounds tend to be non-volatile Reasoning Intermolecular forces in these compounds are weak .A. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`B. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`C. If `(A)` is correct but `(R )` is incorrectD. If `(A)` is incorrect but `(R )` is correct |
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Answer» Correct Answer - C Correct reason Intermolecular forces (i.e electrostatic forces) in ionic compounds are strong Thus they form big crystal lattices and are non volatile . |
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| 825. |
`PCI_(5)` exists but `NCI_(5)` does not becauseA. Nitrogen has no vacant `2`-d orbitalB. `NCl_(3)`is unstableC. N-atom is much smaller than PD. Nitrogen is highly inert |
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Answer» Correct Answer - a The excitation of `2d` electron is not possible |
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| 826. |
`{:(,"Column I(Molecular orbital)",,"Column II (Nodal planes present,Symmetry)"), ((A),sigma_(2s),(p),"0"),((B),sigma_(2p_(z)) ,(q),"1"),((C),pi _(2p_(x))^(**),(r),"2"),((D),pi _(2p_(y))^(**) ,(s),"Gerade"):}` (Take Z-axis as the internuclear axis) |
| Answer» Correct Answer - (A-p,s ;B-q ;C-q,s ; D-r,s) | |
| 827. |
Assertion. Pi bond is never formed alone . It is formed along with a sigma bond . Reason. Pi bond is formed by sideway overlap of p-orbitals only.A. If both assertion and reason are correct, and reason is the correct explanation of the assertion.B. If both assertion and reason are correct , but reason is not the correct explanation of the assertion.C. If assertion is correct, but reason is incorrect .D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - c Correct R . Pi bond may be formed by sideway overlap of p with p or p with d - orbitals. |
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| 828. |
The number of nodal planes in `pi2p_(x)` and `pi^(**)2p_(x)` are two and one respectively . |
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Answer» Correct Answer - F The number of nodal planes in `pi 2px` and `pi^(**)2px` are one and two respectively . |
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| 829. |
Name the types of interaction or intermolecular forces of which potential energy-distance function are given below (a) `Eprop (1)/ (r ) ` (b) `E prop (1)/(r^(2))` (c ) `E prop (1)/(r^(3))` (d) `E prop (1)/(r^(4))` (e) `E prop (1)/(r^(6))` . |
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Answer» (a) Ionic Ion -dipole (non van der Waals forces) (c ) Dipole -dipole (non van der Waals forces) (d) Ion -induced dipole or London dispersion forces or instantaneous dipole -induced dipole (all van der Waals forces) . |
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| 830. |
In the reaction `2PCI_(5) hArr PCI_(4)^(o+) + PCI_(6)^(Θ)` the change in hybridisation is from .A. `sp^(3) d to sp^(3) and sp^(3) d^(2)`B. `sp^(3) d to sp^(3) and sp^(3) d^(2)`C. `sp^(3) d to sp^(3) and sp^(3) d^(2)`D. `sp^(3) d to sp^(3) and sp^(3) d^(2)` |
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Answer» Correct Answer - A `underset(uarr sp^(3)d)(2PCI_(5))hArr underset(uarrsp^(3))(PCI_(4)^(o+)) +underset(uarrsp^(3)d^(2))(PCI_(6))^(Theta)` |
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| 831. |
Assertion . Both `pi(2p_(x)) and pi^(**) (2p_(x))` molecular orbitals have one nodal plane each . Reason. All molecular orbitals formed by sideway overlapping of 2 p orbitals have one nodal plane.A. If both assertion and reason are correct, and reason is the correct explanation of the assertion.B. If both assertion and reason are correct , but reason is not the correct explanation of the assertion.C. If assertion is correct, but reason is incorrect .D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - d Correct A . `pi (2p_(x))` has one nodal plane whereas ` pi^(**) (2p_(x))` has two nodal planes . Correct R. Bonding `pi-`molecular orbitals have one nodal plane whereas antibonding `pi`-molecular orbitals have two nodal planes. |
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| 832. |
Which of the following intermolecular force is vander Waals interaction (i) Ion dipole, (ii) Dipole -Dipole (iii) Ion - induced dipole (b) Which of the following intermolecular forces ion nonvan ber Waals interaction (i) Dipole induced dipole (ii) Instantaneous dipole induced dipole(iii) Ion- induced dipole (iv) None (c ) Which of the foolowing intermolecular forces have a potential energey distance function as `E prop (1)/(r^(2))` (i) Ion -dipole (ii) Dipole -dipole (iii) Ion -induced dipole (iv) London dispersion forces . |
| Answer» ` (a) (iii) (b) (iv) (c ) (i)` . | |
| 833. |
Arrange the following types of intermolecular forces in order of decreasing their strength (a) Ion dipole (b) Keesom forces (C ) Dispersion or London forces (d) Dipole-induced dipole (e) lon-induced dipole (Debye forces) . |
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Answer» Ion dipole gt Keesom forces (dipole -dipole) gt Ion - induced dipole (Debye forces )gt Dipole -induced dipole gt Dispersion or London forces `(a gt b gt e gt d gt c)`. |
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| 834. |
Taking Z-axis as the intermolecular axis , when two `2p_(x)` orbitals of two atoms/ions overlap, the molecular orbitals formed are …………. and ……… |
| Answer» `pi_(2_(p_(x))),pi_(2_(p_(x)))^(**)` | |
| 835. |
In which of the following molecular the intermolecular force is of the type induced dipole indiced dipole ?A. `CI_(2)`B. `HCI`C. `CH_(2)OH`D. `C_(2)F_(6)` |
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Answer» Correct Answer - a `CI_(2)` being a nonpolar molecule will result in induced dipole interaction |
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| 836. |
Assertion Bond order in a molecule can assume any value positive integral or fractional value including zero Reasoning It depends on number of electrons in the bonding and antibonding orbitals .A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true |
| Answer» Correct Answer - C | |
| 837. |
Statement-1 : Strength of H-bonding depends upon temperature . Statement-2 : H-bonding has no effect on specific heat of a substance . Statement-3 : One hydrogen atom bonded to an electronegative element can form only one H-bond .A. TTTB. TFFC. TFTD. FFT |
| Answer» Correct Answer - C | |
| 838. |
Assertion Bond order in a molecule can assume any value positive integral or fractional value including zero Reasoning It depends on number of electrons in the bonding and antibonding orbitals .A. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`B. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`C. If `(A)` is correct but `(R )` is incorrectD. If `(A)` is incorrect but `(R )` is correct |
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Answer» Correct Answer - A `(R )` is the correct explantion of `(A)` thus is because bond order ` =(1)/(2) (N_(b) -N_(a))` . |
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| 839. |
Which of the following have identicla bond order ?A. `CN^(-)`B. `O_(2)^(-)`C. `NO^(+)`D. `CN^(+).` |
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Answer» Correct Answer - A::C (a,c) have bond order equal to 3. |
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| 840. |
`CO_(2)` is iso-structural with :A. `HgCl_(2)`B. `C_(2)H_(2)`C. `SnCl_(2)`D. `NO_(2).` |
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Answer» Correct Answer - A::B `CO_(2),HgCl_(2) and C_(2)H_(2)` are all linear molecules. |
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| 841. |
Statement 1 : Bond order in a stable molecule can be fractional. Statemetn 2: The value of bond order depends upon the number of electrons in bonding and antibonding molecular orbitals.A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-7B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-7C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true. |
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Answer» Correct Answer - a Statement 2 is the correct explanation for Statement 1. |
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| 842. |
Element `X` is strongly electropositive and element `Y` is strongly electronegative. Both are univalent. The compound formed would beA. `X^(-)Y^(-)`B. `X^(-)Y^(-)`C. `X-Y`D. `XrarrY` |
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Answer» Correct Answer - A `X^(+)Ybar` Beacause electropositive elments form cation and electronegative elements form anion . |
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| 843. |
Element `X` is strongly electropositive and element `Y` is strongly electronegative. Both are univalent. The compound formed would beA. `X^(+) Y^(-)`B. ` X - Y`C. `X ^(-)Y^(+)`D. `X to Y` |
| Answer» Correct Answer - A | |
| 844. |
Which of the two peroxide ion or superoxide ion has larger bond length ? |
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Answer» The bond length in a molecule is dependent on bond order The higher is the bond order smaller will be the bond length Peroxide ion `O_(2)^(2)` `O_(2)^(2-):KK^(**) (sigma 2s)^(2) (sigma^(**)2s)(sigma2p_(z))^(2) (pi 2p_(x))^(2) (pi2p_(y))^(2)` `(pi^(**)2p_(x))^(2) (sigma^(**)2p_(y))^(2)` Bond order `= (10-8)/(2) =1` Superoxide ion, `O_(2)^(Θ)` `O_(2)^(Theta:KK^(**)) (sigma2s)^(2) (sigma^(**2s))^(2) (sigma2p_(z))^(2) (pi 2p_(z))^(2) (pi 2p_(y))^(2)` `(pi^(**)2px)^(2)(pi^(**)2p_(y))^(1)` Bond order `= (10-7)/(2) = 1.5` Bond order of superoxide ion is higher thajn peorxide ion hence bond lenght of peroxide ion is larger . |
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