

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
What are the limitations of valence bond theory? |
Answer» Limitations of valence bond theory :
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202. |
Match the following :MoleculeHybridization and bond anglei.Watera.Sp2, 120°ii.Boron trifluorideb.Sp3, 104.5°iii.Beryllium fluoridec.Sp3, 109.5°iv.Methaned.Sp, 180° |
Answer» i – b ii – a iii – d iv – c |
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203. |
Give the importance of valence bond theory. |
Answer» Valence Bond theory introduced five new concepts in chemical bonding :
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204. |
Why is hydrogen ion called proton? |
Answer» An atom of hydrogen has one proton in its nucleus and one electron in its valence shell. It donates its valence electron, the residual ion consists of a single proton. It is on account of this fact, that hydrogen ion is called proton. |
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205. |
Why is a molecule of hydrogen more stable than the uncombined atoms? |
Answer» When a molecule of hydrogen is formed from the atoms, energy is released (104 Kcal/mol). Thus the molecules possessing lower energy are more stable than the atoms. |
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206. |
Why a molecule of hydrogen is more stable than the uncombined atoms ? |
Answer» When a molecule of hydrogen is formed from the atoms, energy is released (104 kcal/ mol). The molecules possessing lower energy are more stable, than the atoms. Hence molecule of hydrogen is more stable than uncombined atoms. |
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207. |
(a) What do you understand redox reactions? Explain oxidation and reduction in terms of loss or gain of electrons.(b) Divide the following redox reactions into oxidation and reduction half reactions.(i) Zn + Pb2 → Zn2 + Pb(ii) Zn + cu2 → Zn2 + Cu(iii) CI2 + 2Br → Br2 + 2CI-(iv) Sn2 + 2Hg2 → Sn4 + Hg22+(v) 2Cu+ → Cu + Cu2+(c) Potassium (at No .19) and chlorine (at No. 17) react to form a compound. Explain on the basis of electronic concept. (i) oxidation(ii) reduction(iii) oxidizing agent(iv) reducing agent |
Answer» (a) A reaction in which oxidation and reduction occur simultaneously is called an oxidation-reduction, or simply, a redox reaction. Redox reactions involve the transfer of electrons between two chemical species. The reaction in which electron is gained is called a reduction reaction and the reaction in which electron is lost is called oxidation reaction. The compound that loses an electron is said to be oxidized, the one that gains an electron is said to be reduced. (b)(i) Oxidation :Zn → Zn 2+ Reduction : Pb2+ Pb (ii) Oxidation : Zn → Zn 2+ Reduction : Cu2+ Cu (iii) Oxidation : Br- → Br Reduction : Cl2 → 2Cl- (iv) Oxidation : Sn2+ → Sn4+ Reduction : 2Hg2+ → Hg2 (v) Oxidation : Cu+ → Cu 2+ Reduction : Cu+ → Cu (c)(i) Potassium undergoes oxidation as it loses an electron and forms a cation. (ii) Chlorine undergoes reduction as it gains an electron and forms chloride anion. (iii) Potassium acts a reducing agent and gets oxidised. (iv) Chlorine acts an oxidizing agent and gets reduced. |
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208. |
Define a coordinate bond and give the conditions for its formation. Explain with an example. |
Answer» The bond formed between two atoms by sharing a pair of electrons, provided entirely by one of the combining atoms but shared by both is called a coordinate bond. It is represented by an arrow starting from the donor atoms and ending in the acceptor atom. Conditions: 1. One of the two atoms must have at least one lone pair of electrons. 2. Another atom should be short of at least a lone pair of electrons. The twolone pair of electrons in the oxygen atom of water is used to form coordinate bond with the hydrogen ion which is short of an electron resulting in the formation of the hydronium ion.H2O + H+---> H3O+ Over here the hydrogen ion accepts one lone pair of electrons of the oxygen atom of water molecule leading to the formation of a coordinate covalent bond. |
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209. |
Metals generally form …………….. A) cation B) anion C) positive ion D) both A and C |
Answer» D) both A and C |
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210. |
Non metals generally form …………….. A) cation B) anion C) negative ion D) both B and C |
Answer» D) both B and C |
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211. |
The valency of I, II, III groups respectively are …………….. A) 1, 2, 3 B) 3, 2,1 C) 4, 5, 6 D) 0,1, 2 |
Answer» Correct option is A) 1, 2, 3 |
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212. |
The valency of V, VI, VII groups respectively are……………… A) 1, 2, 3 B) 3, 2,1 C) 0,1,2 D) 1, 2,4 |
Answer» Correct option is B) 3, 2,1 |
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213. |
If an element X belongs to II group and another element Y belongs to VII group then the compound formed between these elements has fomula : A) XY B) X2Y C) X Y2 D) X2 Y3 |
Answer» Correct option is C) X Y2 |
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214. |
Choose the odd one out.(a) H2(b) O2 (c) Cl2(d) F2 |
Answer» (b) O2 . It’s bond order is 2 whereas in others bond order is 1. |
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215. |
An element L consists of molecules.1. What type of bonding is present in the particles that make up L?2. When L is heated with iron metal, it forms a compound FeL. What chemical term would you use to describe the change undergone by L? |
Answer» 1. Covalent bonding is observed in atoms which are similar. Hence, covalent bonding is present in the particles which make up element L. 2. When L is heated with iron metal, it forms a compound FeL. Here, oxidation of Fe and reduction of L occur as follows: Fe → Fe2+ + 2e– (Direct combination or synthesis) |
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216. |
What are the different between single covalent bond and double covalent bond? |
Answer» Single covalent bond: A covalent bond formed by the mutual sharing of one pair of electrons is called a single covalent bond, or simply a single bond. A single covalent bond is represented by a small line (−) between the two atoms. Double covalent bond: A covalent bond formed by the mutual sharing of two pair of electrons is called a double covalent bond, or simply a double bond. A double covalent bond is represented by two small horizontal lines (=) between the two atoms. E.g. O=O, O=C=O etc. |
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217. |
Match the following:a) Sharing one pair of electrons — i) Double bond b) Sharing two pairs of electrons — ii) Single bond c) Sharing three — iii) Triple bond pairs of electrons A) a → i, b → ii, c → iii B) a → iii, b → ii, c →i C) a →ii, b →i, c → iii D) a →iii, b → i, c → ii |
Answer» C) a →ii, b →i, c → iii |
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218. |
1A° = ……………..A) 10-10</sup? mB) 0.1 nmC) 100 pmD) all of these |
Answer» D) all of these |
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219. |
Bond length is usually given in…………….. A) angstrom unit B) m C) nmD) Both A and C |
Answer» D) Both A and C |
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220. |
An sp3 hybrid orbital contains : (A) 1/4 s-character(B) 1/2 s-character(C) 2/3 s-character(D) 3/4 s-character |
Answer» Hybridization is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory. In sp3 hybridisation, 1s-oribital and 3p orbitals are mixed to form 4 equivalent sp3 orbitals. So every sp3 orbital contains 1/4th of s-orbital and 3/4th of p-orbitals. |
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221. |
The order of strength of overlapping is A) s-s > p-p > s-p B) s-p = s-s = p-p C) s-p > s-s > p-p D) p-p > s-p > s-s |
Answer» D) p-p > s-p > s-s |
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222. |
Consider the following four species and answer the below given questions.O2-, O2, O2+,O22-i. What is the bond order of O2+ ?ii. Which species is least stable? |
Answer» i. Electronic configuration of O2+ can be given as : (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (σ2pz)2 (π2px)2 (π2py)2 (π*2px)1 (π*2py)0 ∴ Bond order = \(\frac{1}{2}\) (10 – 5) = 2.5 ii. Stability of the molecule or species ∝ Bond order Bond order decreases as : O2+ > O2 > O2- > \(O_2^{2-}\) ∴ Stability decreases as : O2+ > O2 > O2- > \(O_2^{2-}\) Hence, Least stable species is \(O_2^{2-}\). |
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223. |
What is Polar Covalent bond? Explain with example. |
Answer» 1. If a covalent bound is formed between atoms having different electronegativities. the atom with higher electronegativity will have greater tendency to attract the shared pair of electrons towards itself than the other atom. As a result, the cloud of shared electron pair gets distorted and polar covalent bond is formed. 2. Example – HF – Hydrogen fluoride: The electronegativities of hydrogen and fluorine on Pauling’s scale are 2.1 and 4 respectively. It means that fluorine attract the shared pair of electrons approximately twice as much as hydrogen which leads to partial negative charge on fluorine atom and partial positive charge on hydrogen atom. Hence, the H – F bond is said to be a polar covalent bond. |
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224. |
Choose the correct answer – Which of the following is a common characteristic of a covalent compound.(A) High melting point(B) Consists of molecules(C) Always soluble in water(D) Conducts electricity when it is in the molten state. |
Answer» (B) Consists of molecules |
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225. |
State the type of bonding in the following molecules –(1) Water ;(2) Calcium oxide |
Answer» (1) Water → covalent bond. (2) Calcium oxide → ionic bond or electrovalent bond |
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226. |
Predict the type of bonding in the following molecules :(i) Oxygen(ii) Calcium oxide(iii) Water(iv) Methane(v) Ammonium ion(vi) Nitrogen(vii) Magnesium chloride(viii) Carbon dioxide(ix) Carbon tetra chloride(xi) Hydrogen cyanide(x) Hydrogen chloride |
Answer» (i) Covalent bond (ii) Ionic bond (iii) Covalent bond (iv) Covalent bond (v) Covalent bond (vi) Ionic bond (vii) Covalent bond (viii) Covalent bond (ix) Covalent bond (xi) Covalent and co-ordinate bonds (x) Covalent bond |
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227. |
State the type of bonding in the following molecules.(a) Water(b) Calcium oxide(c) hydroxyl ion,(d) methane,(e) ammonium ion(f) ammonium chloride |
Answer» a. Water - Covalent bond b. Calcium oxide - Ionic bond c. Hydroxyl ion - Polar covalent bond d. Methane - Covalent bond e. Ammonium ion - Co-ordinate covalent bond f. Ammonium chloride - Covalent, coordinate and ionic bonds |
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228. |
Lattice enthalpy of LiF is more than that of NaF. Explain. |
Answer» As the size of the cation decrease, lattice enthalpy increases. Li+ ion is smaller than Na+ ion. Hence, Lattice enthalpy of LiF is more than that of NaF. |
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229. |
Who proposed the electronegativity scale? |
Answer» Linus Pauling |
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230. |
Define electronegativity? |
Answer» In a covalent bond the relative ability of each atom to attract the bonded pair of electrons towards itself is called electronegativity. |
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231. |
Which of the following solutions are conductors of electricity? a) Sugar solution,b) Alcohol solution, c) Glucose solution, d) Salt solution. |
Answer» Salt solution is good conductor of electricity because common salt (NaCl) is an ionic compound and the rest are covalent compounds. |
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232. |
Which of the following elements form a unipositive ion ? A) Mg B) Al C) Ca D) Na |
Answer» Correct option is D) Na |
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233. |
Which of the following anions has Ne electronic configuration? A) Cl- B) O2-C) P3-D) Br- |
Answer» Correct option is B) O2- B) O²- is the correct answer
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234. |
For each compound, give the formulae of the ions formed in aqueous solutions. |
Answer» HCl + H2O → H3O+ + Cl- HBr + H2O → H3O+ + Br- |
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235. |
What is ionic linkage? |
Answer» When two oppositely charged ions are engaged in a bond, it is known as ionic linkage. |
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236. |
How do you know the valence of a metal? |
Answer» The number of electrons lost from a metal atom is the valence of its element which is equal to its group number. Ex : Na and Mg have valence 1 and 2 respectively. |
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237. |
Which of the following is true for CO2?C = O bondCO2 moleculeApolarnon-polarBnon-polarpolarCpolarpolarDnon-polarnon-polar |
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Answer»
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238. |
Which O2 molecule is pargmagnetic. It is explained on the basis of :a. Hybridisation b. VBT c. MOT d. VSEPR |
Answer» Option : c. MOT |
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239. |
The angle between two covalent bonds is minimum in :a CH4b. C2H2c. NH3d. H2O |
Answer» Option : d. H2O |
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240. |
What changes are observed in atoms undergoing ionic bonding? |
Answer» Due to the electron transfer the following changes occurs – (i) Both the atoms acquire stable noble gas configuration. (ii) The atom that loses electrons becomes +vely charged called cation whereas that gains electrons becomes –vely charged called anion. (iii) Cation and anion are held together by the coulombic forces of attraction to form an ionic bond. |
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241. |
What is the difference between lone pair of electrons and bonded pair of electrons? |
Answer» Lone pair of electrons do not take part in bond formation where as bonded pair of electrons take part in bond formation. |
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242. |
Define bond order. |
Answer» Bond order is defined as number of bonds between two atoms in a molecule. |
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243. |
Why does the number of chlorine atoms differ in these compounds? Try to find out by analyzing the valency of the elements Na, Mg, Al, Cl and C. Analyse Table |
Answer» Examine the above table and identify how to write the chemical formula from valency. Compare your findings with the following.
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244. |
Write the valencies of following elements. a) Be b) N and what is the compound formed when these two reacted? |
Answer» a) The electronic configuration of Be is 1s2 2s2. So its valency is 2. b) The electronic configuration of Nitrogen is 1s2 2s2 2p3. So its valency is 3. ∴ Formula of the compound is Be3N2. |
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245. |
What is meant by valency? |
Answer» Valency is the combining capacity of the atoms of an element. It can be treated as the number of electrons lost gained or shared by an atom during chemical combination. |
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246. |
In the formation of magnesium oxide- How many electrons are donated by magnesium? |
Answer» There are 2 electrons |
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247. |
Why are bonding molecular orbitals more stable than antibonding molecular orbitals? |
Answer» Bonding molecular orbital has lower energy and hence greater stability than the corresponding antibonding molecular orbital. |
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248. |
An atom X has three electrons more than the noble gas configuration. What type of ion will it form? Write the formula of its:(i) sulphate(ii) nitrate(iii) phosphate(iv) carbonate(v) hydroxide |
Answer» It will form a cation : M3+ M2(SO4)3 M(NO3)3 M3(PO4)3 M2(CO3)3 M(OH)3 |
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249. |
Mention the basic tendency of an atom which makes it to combine with other atoms. |
Answer» Atoms combine with other atoms to attain stable octet or noble gas configuration |
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250. |
What could be the reason for this? |
Answer» They have 8 (e-) electrons in their outermost orbit. |
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