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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
The incrasing order of the first ionisation enthaplies of th elecments ` B , P, S` and `F` ( lowest first ) is :A. `Flt S lt FltP`B. ` P lt S lt B lt F`C. `B lt P lt S lt F`D. `B lt S lt P lt F` |
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Answer» Correct Answer - D Ionisation enrgy increrase along the period , decrease down the group . |
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| 52. |
The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. `(v) gt (iv) gt (i) gt (iii) gt (ii)`B. `(v) gt (i) gt (ii) gt (iii) gt (iv)`C. `(ii) gt (iv) gt (iii) gt (i) gt (v)`D. `(iv) gt (iii) gt (i) gt (ii) gt (v)` |
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Answer» Correct Answer - A `H_2O` has the highest boiling point on account of hydrogen bonding while `PH_3` has the lowest boiling point on account of lowest molecular mass and absence of `H-` bonding. This confirms the answer. `SbH_3` has the 2nd highest boiling point on account of high molecular mass. `NH_3` has higher boiling point than `AsH_3` on account of hydrogen bonding. |
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| 53. |
Among `KO_(2),ALO_(2)^(Θ)`,`BaO_(2)` and `NO_(2)^(+)`,unpaired electrons is present in .A. `NO_(2)^(+)` and `BaO_(2)`B. `KO_(2)` and `AlO_(2)^(-)`C. `KO_(2)` onlyD. `BaO_(2)` only |
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Answer» Correct Answer - C Unpaired electrons are present in `KO_(2)` while others have paired electron `NO_2^(+)` =22 electrons, `BaO_(2)`=72 electrons `AlO_(2) =30` electrons , `KO_(2)`=35 electrons |
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| 54. |
The correct order of bond angles in `NH_(3),PCl_(3)"and"BCl_(3)` isA. `PCl_(3)gtNH_(3)gtBCl_(3)`B. `NH_(3)gtBCl_(3)gtPCl_(3)`C. `NH_(3)gtPCl_(3)gtBCl_(3)`D. `BCl_(3)gtNH_(3)gtPCl_(3)` |
| Answer» (d) `{:(NH_(3),(107^(@))),(PCl_(3),(93^@)),(BCl_(3),(120^@)):}` | |
| 55. |
The correct order of hybridization of the central atom in the following species `NH_3,[PtCl_(4)]^(2-),PCl_(5),` and `BCl_(3)` isA. `dsp^(2),dsp^(3),sp^(2)` and `sp^(3)`B. `sp^(3),dsp^(2),dsp^(3),sp^(2)`C. `dsp^(2),sp^(2),sp^(3),dsp^(3)`D. `dsp^(2),sp^(3),sp^(2),dsp^(3)` |
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Answer» Correct Answer - B Hybridization of N in `NH_(3)` is `sp^(3)` that of Pt in `[PtCl_(4)]^(2-)` is `dsp^(2)` that P in `PCl_(5)` is `sp^(3)d` and that of B in `BCl_3` is `sp^(2)`. |
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| 56. |
The correct order of hybridisation of the central atom in the following species ` NH_3 ,[PtCl_4 ]^(2-) , PCl_5` and ` BCl_3` is :A. `dsp^(2),dsp^(3),sp^(2)` and `sp^(3)`B. `sp^(3),dsp^(2),sp^(3)d` and `sp^(2)`C. `dsp^(2),sp^(2),sp^(3)` and `dsp^(3)`D. `dsp^(2),sp^(3),sp^(2)` and `dsp^(3)` |
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Answer» Correct Answer - b |
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| 57. |
Which among the following is true ?A. Bond order ` prop 1 /( Bond length ) prop` Bond energyB. Bond ordr `prop` Bond length `prop 1/( Bond energy )`C. Bond order `prop 1/(Bond length) prop 1 /("Bond energy" )`D. Bond order ` prop` Bond length ` prop` Bond energy `. |
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Answer» Correct Answer - A Follow review. |
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| 58. |
Shape and hybridization of `IF_5`, respectively, areA. pentagonal pyramidal, `sp^3d^3`B. square pyramidal, `sp^3d^2`C. seesaw, `sp^3d`D. trigonal bipyramidal, `sp^3d` |
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Answer» Correct Answer - B Ground-state valence shell electron configuration of `I` is `5s^2 5p^5`. Thus, it has 7 valence electrons, 5 valence `e^(-)s` are used to hold 5 F atoms while 2 valence `e^(-)s` form one lone pair of electrons. Thus, its steric number is `5+1=6`. This implies `sp^3d^2` hybridization, octahedral geometry, and square pyramidal shape (due to one lone pair). |
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| 59. |
Hybridization of central atom in `NH_3` isA. `sp^3`B. `sp`C. `sp^2`D. `dsp^2` |
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Answer» Correct Answer - A `N` in `NH_3` is the central atom and is `sp^3`-hybridized because its `SN` is `3+1=4`. It uses `4sp^3` hybrid orbitals to form `NH_3`. |
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| 60. |
Which of the following order is incorrect for thermal stability :-A. `BeO gt MgO gt CaO`B. `NH_(3) lt H_(2)O lt HF`C. `HF lt HCl lt HBr lt HI`D. `Li_(2)SO_(2) lt Na_(2)SO_(4) lt K_(2)SO_(4) lt Rb_(2)SO_(4) lt Cs_(2)SO_(4)` |
| Answer» Correct Answer - C | |
| 61. |
Which of the following solvent will have highest solubility of KCl ?A. `C_6 H_6(D=0)`B. `(CH_3)_2, CO (D=2)`C. `CH_3OH (D = 32)`D. `C Cl_4` (D=0). |
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Answer» Correct Answer - C More is DEC value, more is solubility |
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| 62. |
"Solubility of alkali metal fluorices increases down the group " Select correct explanation for given statement`:`A. Hydration energy increases and lattice energy decreases down the groupB. Both energy decrease down the group but decrease in hydration energy is rapidC. Both energy decrease down the group but decrese in lattice energy is rapidD. Both energy increase down the group but increase in hydration energy is rapid. |
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Answer» Correct Answer - 3 Although both hydration and lattice energies of alkali metal fluorides decreases down the group and hydration energy dominates over lattice energy ,therefore, solubility increases down the group. |
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| 63. |
For which crystalline substance does the solubility in water increase upto ` 312^@C` and then decrease readily ?A. `1CaCl_2 . 2H_2O`B. `Na_2SO_4 .10H_2O`C. `FeSO_4 .4H_2O`D. Alums |
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Answer» Correct Answer - B On heating it loses water molecules . |
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| 64. |
Which of the following solubility order is not correct :-A. `MgF_(2) lt MgCl_(2) lt MgBr_(2) lt Mgl_(2)`B. `Be(OH)_(2) lt Mg(OH)_(2) lt Ca(OH)_(2) lt Sr(OH)_(2)`C. `Li_(2)O lt Na_(2)O lt K_(2)O lt Rb(2)O lt Cs_(2)O`D. `CsF lt CsCl lt CsBr lt Csl` |
| Answer» Correct Answer - D | |
| 65. |
Assertion :-`CO_(2)` molecules is non-polar while `SO_(2)` Reason : - Carbon atom is smaller than sulphur.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True, but the Reason is False.D. If both Assertion & Reason are false |
| Answer» Correct Answer - B | |
| 66. |
Assertion:- `ZN^(+2)` is more polarising than `Mg^(+2)`. Reason :- A pseudo inert gas configuration `Zn^(+2)` has high `Z_(eff)`, Then inert gas configuration of `Mg^(+2)`A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True, but the Reason is False.D. If both Assertion & Reason are false |
| Answer» Correct Answer - A | |
| 67. |
The main axis of diatomic molecule is `z`. The orbitals `p_x` and `p_y` overlap to formA. `pi` molecular orbitalB. `sigma` molecular orbitalC. `delta` molecular orbitalD. no bond will be formed |
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Answer» Correct Answer - D Since `p_x` and `p_y` orbitals are perpendicular to each other, they cannot overlap sideways or end-to-end. Thus, no bond will be formed. |
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| 68. |
If the z-axis is the molecular axis, then `piMOs` are formed by the overlap of (i) `p_z` and `p_z` (ii) `p_y` and `p_y` (iii) `s` and `p_z` (iv) `p_x` and `p_x`A. (ii), (iv)B. (i), (iii)C. (i), (ii)D. (ii), (iii) |
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Answer» Correct Answer - A Overlap of the orbitals along the axis joining the nuclei produces `sigma` molecular orbitals, while lateral overlap of atomic orbitals forms `pi` molecular orbitals. |
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| 69. |
Pick out the isoelectronic structures from the following . `I CH_3^+ (II) H_3O^+ , (III) NH_3, (IV) CH_3^-` :A. I and IIB. III and IVC. I and IIID. II, III and IV |
| Answer» Correct Answer - B::D | |
| 70. |
Which one of the following molecules is expected to exhibit diamagnetic behaviour? (i) `N_2` (ii) `O_2` (iii) `S_2` (iv) `C_2`A. (i), (ii), (iii), (iv)B. (ii), (iii)C. (i), (iii)D. (i), (iv) |
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Answer» Correct Answer - D Both `N_2` and `C_2` are diamagnetic `C_2impliessigma1s^2sigma^**1s^2sigma2s^2sigma^**2s^2{:(pi2p_x^2,,),(pi2p_y^2,,):}]` `N_2impliessigma1s^2sigma^**1s^2sigma2s^2sigma^**2s^2{:(pi2p_x^2,,),(pi2p_y^2,,):}]sigma2p_x^2` Both `O_2` and `S_2` are paramagnetic with two unpaired electrons each. |
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| 71. |
It is believed that atoms combine with each other such that the outermost shell acquires a stable configuration of 8 electrons. If stability were attalned with 6 electrons rather than 8. What would be the formula of the stable fluoride ion.A. `F^(-)`B. `F^(+)`C. `F^(2+)`D. `F^(3+)` |
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Answer» Correct Answer - B No. of valence electrons in F are 7. thus, in order to have 6 valence electrons, it msut loose one electron and will have the formula `F^(+)`. |
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| 72. |
In ` HCHO,` there are `X` no-bonding electron pairs Y sigama -bonds and Z pi-bonds , ` X , Y` and Z are :A. ` 1,1, 3`B. ` 2,3 ,1`C. ` 1,2,3`D. none of these |
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Answer» Correct Answer - B `HCHO ` is represented as `underset ( :O: )underset(||)(H-C-H)`. |
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| 73. |
Which of the following molecules has the highest value of carbon-carbon bond energy?A. `C_2H_4`B. `C_3H_8`C. `C_2H_2`D. `C_2H_6` |
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Answer» Correct Answer - C With increase in bond order, bond length decreases while bond orders. However, the bond enthalpy of `CO (kJ "mol"^(-1))` is more than that of `N_2(946 kJ "mol"^(-1))` because CO is polar while `N_2` is nonpolar. Moreover, CO exhibits resonance. |
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| 74. |
Which of the following molecules has the maximum bond enthalpy?A. `N_2(g)`B. `CO(g)`C. `F_2(g)`D. `HF(g)` |
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Answer» Correct Answer - B Both `N_2(overset(..)N-=overset(..)N)` and `CO ( : C-=O: )` have identical bond orders. However, the bond enthalpy of `CO(kJ "mol"^(-1))` is more than that of `N_2 (946 kJ "mol"^(-1))` because CO is polar while `N_2` is nonpolar. Moreover, CO exhibits resonance. |
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| 75. |
If molecule `MX_3` has zero dipole moment, the sigma bonding orbitals used by M (atomic number `lt2l`) areA. pure pB. sp hybridC. `sp^2` hybridD. `sp^3` hybrid |
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Answer» Correct Answer - C Zero dipole moment of `MX_3` implies that it has trigonal planar geometry which can be correlated to `sp^2` hybridization. |
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| 76. |
A sigama-bonded moelcuar `MX_3` is T-shaped . The number of lone paris of electons around M is :A. zeroB. `2`C. `1`D. unpredictable |
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Answer» Correct Answer - B ` F_(3) Cl` is ` T-shaped . ` (##DPB_PHY_CHM_IX_C15_E01_032_S01.png" width="80%">.Cl has tow line pair of electrons . |
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| 77. |
In which of the following metal to metal bond is present ?A. Cupric chlorideB. Stannous chlorideC. Mercurous chlorideD. Mercuric chloride |
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Answer» Correct Answer - C `Cl-Hg-Hg-Cl` Mercurous ion is represented as `Hg_(2)^(2)` . It is evidenced by the fact that its `mu=0,i.e.,` it is diamagnetic. It is possible only when there is presence of a metal-metal bond. |
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| 78. |
The percentage of sodium in a breakfast careal labelled as `110 mg` of sodium per `100 g` of cereal is:A. `11%`B. `1.10%`C. `0.110%`D. `110%` |
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Answer» Correct Answer - C `(110xx10^(-3) g Na)/("100 g total")xx100=0.110% Na` |
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| 79. |
Hydrogen bonding is maximum in:A. EthanolB. Diethyl etherC. Ethyl chlorideD. Triethyl amine. |
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Answer» Correct Answer - A H-Bonding is maximum in EtOH among the given species. |
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| 80. |
The metallic lustre exhibited by sodium is explained byA. diffusion of sodium ionsB. excitation of free protonsC. oscillation of loose electronsD. existence of body centred cubic lattice |
| Answer» (c ) Metallic lustre is due to oscillation of loose electrons. | |
| 81. |
The metallic lustre exhibited by sodium is explained byA. Diffusion of sodium ionB. Excitation of free protonsC. Oscillation of loose electronsD. Existence of body centred cubic lattice |
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Answer» Correct Answer - A Metallic lustre is due to Oscillation of loose electrons. |
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| 82. |
Which pair of moecules will have permanent dipole moment for both members ?A. `SiF_(4)" and "NO_(2)`B. `NO_(2)" and "CO_(2)`C. `NO_(2)" and "O_(3)`D. `SiF_(4)" and "CO_(2)` |
| Answer» (c ) `NO_(2)`and `O_(3)` both having irregular geometry due to which they have permanent dipole moments. | |
| 83. |
Which one of the following is a compound most likely to have a dipole momentA. `CS_2`B. `H_2S`C. `SO_3`D. `SnCl_4` |
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Answer» Correct Answer - B `H_2S` molecule has irregular geometry, because of presence of 2 lone pair of electrons or sulphur atom, and is therefore expected to have a dipole moment |
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| 84. |
`XeF_(2)` is iso-structural with :A. `TeF_2`B. `IC l_2^-`C. `SbCl_3`D. `BaCl_2` |
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Answer» Correct Answer - B `XeF_2 and IC l_2^(-)` both have linear structure and hence are isostructural. |
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| 85. |
In the of the following pairs of molecules /ions both the species are not likely to exist?A. `H_(2)^(+), He_(2)^(2-)`B. `H_(2)^(-), He_(2)^(2-)`C. `H_(2)^(2+), He_(2)`D. `H_(2)^(-), He_(2)^(2+)` |
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Answer» Correct Answer - c |
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| 86. |
In the of the following pairs of molecules /ions both the species are not likely to exist?A. `H_2^- , H_2^(2+)`B. `H_2^(+), He_2^(2-)`C. `H_2^(-), He_2^(2-)`D. `H_2^(+) , He_2` |
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Answer» Correct Answer - D Both `H_2^(2+) and He_2` have zero bond order and hence do not exist |
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| 87. |
The pairs of species of oxygen and their magnetic behaviour are noted below. Which of the following presents the correct description ?A. `O_(2)^(+) , O_(2)` -Both paramagneticB. `O,O_(2)^(2-)`-Both paramagneticC. `O_(2)^(-),O_(2)^(2-)`, Both diamagneticD. `O^(+),O_(2)^(2-)`-Both paramagnetic |
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Answer» Correct Answer - A MOT configuration of `O_(2)` and `O_(2)^(+)` `O_(2),(sigma1s^(2))(sigma^(**) 1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x)^(2)=pi 2p_(y)^(2))(pi^(**) 2p_(x)^(1)=pi^(**)2p_(y)^(1))` Number of unpaired electron=2 so paramagnetic. `O_(2)^(+): (sigma 1s)^(2)(sigma^(**)1s^(2))^(@)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)` `(pi2p_(x)^(2)=pi2p_(y)^(2))(pi^(**)2p_(x)^(1)=pi^(**)2p_(y)^(0))` Number of unpaired electrons =2 , so paramagnetic . |
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| 88. |
Two ice cubes are pressed over each other until they unite to form one block. The force mainly responsible for holding them together isA. van der Waals forceB. dipole-dipole interactionC. H bondingD. covalent bonding |
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Answer» Correct Answer - C Ice is solid `H_2O`. Strong hydrogen bonding occurs among polar covalent molecules containing H and one of the three small, highly electronegative elements: `F, O,` or `N`. |
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| 89. |
When two ice cubes are pressed over each other, they unite to form one cube. Which of the following forces is responsible to hold them together ?A. Vander waal,s forcesB. Hydrogen bond formationC. Covalent attractionD. Dipole-dipole attraction |
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Answer» Correct Answer - B In ice cube all molecules are held by inter molecular hydrogen bond. |
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| 90. |
During the formation of a chemical bond, the potential energy of the interacting atoms is lowered by at least _____________ `kJ mol^(-1)`.A. `40`B. `50`C. `60`D. `30` |
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Answer» Correct Answer - A A chemical bond is a strong attractive force that lowers the potential energy by `40kJ mol^(-1)` or more. |
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| 91. |
A metal, M from chaloride in its `+2` and `+4` oxidation states . Which of the following statement about thes chalorides si correct ?A. `MCl_2` is more volatile than `MCl_4`B. `MCl_2` is more soluble in anhydrous ethanol than `MCl_4`C. `MCl_2` is more ionic than `MCl_4`D. ` MCl_2` is more easily hydrolysed than `MCl_4` |
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Answer» Correct Answer - C `MC l_2` higher si oxidations statem of metal ion, nore is efffective nuclear charge on cation and thus more will be deformation of ion. So `mC l_(4)` is more covalent . |
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| 92. |
The energy of hydrogen bond is of the order ofA. `4kJmol^(-1)`B. `40kJmol^(-1)`C. `400kJmol^(-1)`D. `4000kJmol^(-1)` |
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Answer» Correct Answer - A The average energy of a hydrogen bond is quite large for a dipole-dipole interaction (up to `40kJmol^(-1)`). |
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| 93. |
Which of the following has the least bond angle?A. `H_2O`B. `H_2S`C. `H_2Se`D. `H_2Te` |
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Answer» Correct Answer - B Repulsion between lone pairs and bond pairs increases and, hence, bond angle decreases with decrease of electronegativity (or increase of size) of central atom. Thus, decreasing order of bond angle is `H_2O(104.5^@)gtH_2S(92^@)gtH_2Se(91^@)gtH_2Te(90^@)` |
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| 94. |
Which of the following moelcules /ions does not contian upaired electrons ?A. `O_2^(2-)`B. `B_2`C. ` N_2^+`D. `O_2` |
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Answer» Correct Answer - A `O_(2)` has two unpaired electrons , which are paired in ` O_(2)^(2)`. |
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| 95. |
To explain the abnormality in some molecules , the conecpt of H-bonding was introduced , Hydrogen bonding is defined as the phenomenon in which H-bonding beteen two molecules is called intermolecular H-bonding between two molecules is called intermolecular H-bonding .Hbonding within a molecule is called intramolecular H-bonding or within a molecule is called intramolecular H-bonding or chelation .Intermolecular H-bonding favoure for cluster formation whereas intramolecular H-bnding prevents the cluster formation The correct repesentation of H-bonding beteen `NH_3` and `H_2O` is :A. ` H_2 N - H ….OH_2`B. ` H_3 N …. H - OH`C. ` H_2 N - H …. H -OH `D. ` H_2 N …ON_2` |
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Answer» Correct Answer - B ` NH_3` is Lewis base and ` H_2O` is Lewis acid . |
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| 96. |
To explain the abnormality in some molecules , the conecpt of H-bonding was introduced , Hydrogen bonding is defined as the phenomenon in which H-bonding beteen two molecules is called intermolecular H-bonding between two molecules is called intermolecular H-bonding .Hbonding within a molecule is called intramolecular H-bonding or within a molecule is called intramolecular H-bonding or chelation .Intermolecular H-bonding favoure for cluster formation whereas intramolecular H-bnding prevents the cluster formation `HF_2^-` exists in solid state and in liquid `HF` but bot in aqueous solution because :A. `HF_2^- + H_2O rarr H_3 O^+ + 2F^-`B. ` HF+ H_2O rarr H-2 F^+ + OH^-`C. ` HF_2^- +H_2 O rarr H_2 F_2 + OH^-`D. none of these |
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Answer» Correct Answer - A Due to extensive hydration of ` F^-` ion. |
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| 97. |
To explain the abnormality in some molecules , the conecpt of H-bonding was introduced , Hydrogen bonding is defined as the phenomenon in which H-bonding beteen two molecules is called intermolecular H-bonding between two molecules is called intermolecular H-bonding .Hbonding within a molecule is called intramolecular H-bonding or within a molecule is called intramolecular H-bonding or chelation .Intermolecular H-bonding favoure for cluster formation whereas intramolecular H-bnding prevents the cluster formation Which of the following statement is wrong ?A. H-bonding never involves more than two atomsB. The H-bond order is : ` H - F ….H gt H- O ….H gt H - N ….H`C. All the three atoms involved in H -bonding lie in one planeD. Bond energy of H-bonding is about ` 1//2` of covalent bond |
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Answer» Correct Answer - D Bond energy of H-bond ltltlt Bond energy of ` H - H ` bond . |
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| 98. |
Lewis concept of covalency of an element involved octet rule .Later on it was found that many elements in their compoinds `e.g, BeF_2,BF_3` etc . Have incomplete octet whereas `PCl_5 ,SF_6` etc , have expanded octet . This classical conept also failed in predicting the geometry of molecules .Modern concept of covalence was propsed in terms of valence bond theory proposed by Heitler and London and later on modified by Pauling nad Slater . Hybridisation concept alongwith valence bond theory although successfully explained the geometry of various molecules but failed in many molecules . the geometry of such molecules was explained by VSEPR concept . Finally molecular orbital theory was porosed by Hund -Mulliken to explain many other anomalies .. Which statements are correct ? (1) Bond angle of `PF_(3) gt PCl_(3)`. (2) Bond angle of `PCl_(3) lt PBr_(3)` (3) `(CH_(3))_(3)N` is pyramidal whereas `(SiH_(3))_(3)N` is planar but both shows `sp^(3)` -hybridisation. (4) Multiple bonds also influence the geometry of molecule and thus `C_(2)H_(2)` has `angleHCH=160^(@)` and `angleHCO=122^(@)` (5) `PCl_(5)` is super-octet moleculeA. `1,3,4,5`B. ` 1, 2,3 4`C. ` 2,3, 4, 5`D. `2, 5` |
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Answer» Correct Answer - B All are facts . |
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| 99. |
Lewis concept of covalency of an element involved octet rule .Later on it was found that many elements in their compoinds `e.g, BeF_2,BF_3` etc . Have incomplete octet whereas `PCl_5 ,SF_6` etc , have expanded octet . This classical conept also failed in predicting the geometry of molecules .Modern concept of covalence was propsed in terms of valence bond theory proposed by Heitler and London and later on modified by Pauling nad Slater . Hybridisation concept alongwith valence bond theory although successfully explained the geometry of various molecules but failed in many molecules . the geometry of such molecules was explained by VSEPR concept . Finally molecular orbital theory was porosed by Hund -Mulliken to explain many other anomalies . Which statements are correct ? (1) `C(CN)_(4)` and `C_(2)(CN)_(4)` have ratio of `sigma` and `pi` bonds same (2) Propanal and propanone have same ratio of `sigma` and `pi` bonds (3) `CO_(2)` and `BeF_(2)` both are linear and possess sp-hybridisation (4) `XeF_(4)` and `SF_(4)` both are square planar and possess `sp^(3)d`-hybridisation (5) `Cl-Cl` bond is stronger than `Br-Br`A. ` 1 , 3, 5`B. ` 1, 2, 4, 5`C. ` 1, 2, 3, 5`D. ` 1, 4, 5` |
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Answer» Correct Answer - C `XeF_4 ( sp^3 d^2 )` and ` SF_ 4 ( sp^3 d)` . |
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| 100. |
Lewis concept of covalency of an element involved octet rule .Later on it was found that many elements in their compoinds `e.g, BeF_2,BF_3` etc . Have incomplete octet whereas `PCl_5 ,SF_6` etc , have expanded octet . This classical conept also failed in predicting the geometry of molecules .Modern concept of covalence was propsed in terms of valence bond theory proposed by Heitler and London and later on modified by Pauling nad Slater . Hybridisation concept alongwith valence bond theory although successfully explained the geometry of various molecules but failed in many molecules . the geometry of such molecules was explained by VSEPR concept . Finally molecular orbital theory was porosed by Hund -Mulliken to explain many other anomalies . Which are true statements among the following ? (1) `I_(3)^(+)` has bent structure (2) `ppi-dx` bons are present in `SO_(2)` (3) `SeF_(4)` and `CH_(4)` has same shape (4) `XeF_(2)` and `CO_(2)` has same shape (5) `SF_(4)` is see-saw structure wherear `ICl_(3)` is `T` shapedA. `1,2,4,5`B. ` 1,2,3,4`C. ` 2,3,4,5`D. ` 1,3,4,5` |
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Answer» Correct Answer - A ` SeF_4` is see - saw shaped whereas ` CH_4` is terahedral . |
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