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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
Total number of lone pair of electrons in ` XeOF_4` is :A. ` 0`B. ` 1`C. ` 2`D. ` 3` |
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Answer» Correct Answer - B `Xe` in`XeOF_4` shows `sp^2 d^(2)-`hybridisation with one lone pair on `Xe` atom. |
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| 352. |
Which of the following ions has resonating structures?A. `SO_4^(2-)`B. `PO_4^(3-)`C. `SO_3^(2-)`D. All of these |
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Answer» Correct Answer - D First we write their Lewis structures: `:underset(..)overset(-..)O-underset( :O: )underset(||)overset( :O: )overset(||)S-underset(..)overset(..-)O:" ":underset(..)overset(-..)O-underset( :O: )underset(||)overset( :O: )overset(||)P-underset(..)overset(..-)O:" " :underset(..)overset(..)O-overset( :O: )overset(||)S-underset(..)overset(..)O:` In each of these ions, there is more than one reasonable location for a multiple bond. Hence, no single Lewis structure can describe any of these ions. More than one resonance structure must be written for an accurate description. |
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| 353. |
The pair of species having identical shapes for molecules of both species isA. `CF_(4),SF_(4)`B. `BF_(3),PCl_(3)`C. `XeF_(2),CO_(2)`D. `PF_(5),IF_(5)` |
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Answer» Correct Answer - C `XeF_(2)` and `CO_(2)` both, are linear in shape. `Fe -underset(...)overset(…)(Xe)-F, O=C=O` |
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| 354. |
In which of the following pairs do the species have identical shapes?A. `XeO_3` and `I_3^(-)`B. `SnCl_4` and `XeF_4`C. `SO_2` and `SO_3`D. `SnCl_2` and `O_3` |
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Answer» Correct Answer - D SN of Sn in `SnCl_2` is `2+1=3`. Therefore, the molecule is angular. In `O_3`, SN of O is `2+1=3`. Therefore, `O_3` is also angular. Similarly, we can work out the steric numbers in other pairs to find out whether they have identical or different shapes. |
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| 355. |
Which of the following molecule has highest bond energy ?A. F-FB. C-CC. N-ND. O-O |
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Answer» Correct Answer - C Nitrogen molecule has highest bond energy due to presence of triple bond. |
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| 356. |
Which of the following complexes is paramagneticA. ChlorineB. NitrogenC. OxygenD. Hydrogen |
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Answer» Correct Answer - C Oxygen is paramagnetic due to the presence of two unpaired electron `O_(2)=sigma(1s)^(2)sigma^(**)(1s)^(2)sigma(2s)^(2)sigma^(**)(2s)^(2)` `sigma(2p_(x))^(2)pi(2p_(y))^(2)pi(2p_(x))^(2)pi^(*)(2p_(y))^(1)pi^(**)(2p_(z))^(1)` |
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| 357. |
In which of the following species the hybrid state of the central atom is same ?A. `SO_2, SO_3`B. `SO_3, SO_4^(2-)`C. `SO_2 , SO_2^(2-)`D. `CH_4HCOOH` |
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Answer» Correct Answer - A Both are `sp^(2)` -hybridisese . |
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| 358. |
The C-H bond distance is the longest in:A. `C_(2)H_(2)`B. `C_(2)H_(4)`C. `C_(2)H_(4)Br_(2)`D. `C_(6)H_(6)` |
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Answer» Correct Answer - C `C_(2)H_(4)Br_(2)` has all single bonds so C-H bond distance is the largests. |
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| 359. |
In which of the following the central atom does not use `sp^3` hybrid orbitals in its bondingA. `BeF_(3)^-`B. `OH_(3)^(+)`C. `NH_(2)^(-)`D. `NF_(3)` |
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Answer» Correct Answer - A In `BeF_(3)^(-)`, Be is not `sp^(3)-`hybridised it is `sp^(2)` hybridised. |
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| 360. |
The ion that is isoelectronic with `CO` isA. `O_2^-`B. `N_2^+`C. `O_2^+`D. `CN^-` |
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Answer» Correct Answer - D Isoelectronic species are having same number of electrons . Number of electrons in CO=6+8=14 Number of electrons in `O_2^+`=16+1=17 Number of electrons in `N_2^+`=14-1=13 Number of electrons in `O_2^+`=16-1=15 Number of electrons in `CN^-`=6+7+1=14 Hence, CO isoelectronic with `CN^-` ion. |
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| 361. |
Which is the correct electron dot structure of `N_(2)O` moleculesA. `:N=N=overset(..)underset(..)(O)`B. `:N-=N^(+)-overset(..)underset(..)("O:")^(-)`C. `overset(..)underset(..)(N)-overset(..)(N)=overset(..)underset(..)(O)`D. `:N=N=overset(..)underset(..)("O:")` |
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Answer» Correct Answer - B `:N-=N^(+)-overset(..)underset(..)("O:")` or `N-=N to O` |
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| 362. |
The interatomic distance in `H_(2)` and `CI_(2)` molecules are 74 an d198 pm respectively. The bond length of HCI isA. 272 pmB. 136 pmC. 124 pmD. 248 pm |
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Answer» Correct Answer - B Middle length of `H_(2)=74 pm` Length of `H=74/2=37 pm ` Middle length of `Cl_(2)=198 pm` Bond length of HCl=Length of H + length of Cl =37+99=136 pm |
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| 363. |
Which of the following is a the most preferred and hence of the lower energy for `SO_(3)`?A. B. C. D. |
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Answer» Correct Answer - D In `ClO_2`, Cl is `sp^2` hybridized and the bond angle is `118^(@)` In `Cl_2O`, O is `sp^3` hybridized. However, due to repulsion between two large sized Cl atoms the bond angle increases from `109.5^(@)` to `111^(@)` . In `ClO_2^(-)`, Cl atom is `sp^2` hybridized but due to lp-dp repulsions, the bond angle decreases from normal tetrahedral value to `103^(@)`. Thus the increasing order of bond angle is `ClO_2^(-)` lt `Cl_2O` lt`ClO_2` |
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| 364. |
Which can described as a molecule with residual bonding capacityA. `BeCl_(2)`B. NaClC. `CH_(4)`D. `N_(2)` |
| Answer» Correct Answer - A | |
| 365. |
Which of the following molecule consists of numlticentre pi-bonding ?A. EtheneB. ButaneC. BenzeneD. None of thes |
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Answer» Correct Answer - C Benzene has delocalised pi-electron cloud . |
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| 366. |
The unequal sharing of bonded pair of electrons between two atoms in a molecule causes ___________.A. dipole radical formationB. covalent bondC. decomposition of moleculeD. |
| Answer» Correct Answer - A | |
| 367. |
Among the following mixiture dipole-dipole as the mojor interaction is present isA. KCl and waterB. benzene and carbon tetrachlorideC. benzene and ethanolD. acetonitrile and acetone |
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Answer» Correct Answer - D Acetonitrile `(CH_3CN)` and acetone `(CH_3)_2CO` both are polar. |
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| 368. |
In which of the following `p pi-d pi` bonding is observed ?A. `NO_(3)^(-)`B. `CO_(3)^(-2)`C. `BO_(3)^(-3)`D. `SO_(3)^(-2)` |
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Answer» Correct Answer - D `:overset(..)(O)=underset(..)underset("O:")underset(||)(S)=overset(..)overset("O:")` S atoms has 12 electrons in its outermost shell. One `(S-O)pi` bond will be (p-p) `pi` bond while two `(S-O) pi` bond will be (p-d)`pi` bond. |
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| 369. |
In a double bond connecting two atoms there is a sharing ofA. 2 electronsB. 1 electronC. 4 electronsD. All elements |
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Answer» Correct Answer - C In a double bond connecting two atoms sharing of 4 electrons take place as in `H_(2)C=CH_(2)` |
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| 370. |
The bond order in `O_(2)^(+)` isA. 2B. 2.5C. 1.5D. 3 |
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Answer» Correct Answer - B `B.O. =(N_(b)-N_a)/2=(8-3)/2=5/2 =2.5` |
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| 371. |
In which of the following there exists a `p pi-p pi` bondingA. DiamondB. GraphiteC. Dimethyl amineD. Trisilylamine |
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Answer» Correct Answer - D We know that trisilylamine is `sp^(2)`-hybridized therefore `p pi-d pi` bonding is possible due to the availability of vacant d-orbitals with silicon. |
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| 372. |
Identify the paramagnetic substanceA. `B_(2)`B. `C_(2)`C. `N_(2)`D. `F_(2)` |
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Answer» Correct Answer - A If total no. of electron are odd except 16 or 10 (10 in case of `B_(2)`) then these are paramagnetic in nature. |
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| 373. |
Which of the following statement is falseA. `H_2` molecule has one sigma bondB. HCl molecule has one sigma bondC. water molecule has five sigma bonds and one pi bondD. Acetylene molecule has three pi bonds and three sigma bonds |
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Answer» Correct Answer - D `Hoverset(1 sigma)(-) overset(1 sigma)underset(2pi) (-=) C overset(1 sigma)(-)H` Acetylene molecule has `3 sigma` bonds and `2pi` bonds |
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| 374. |
The bond order is of three forA. `N_(2)^(+)`B. `O_(2)^(2+)`C. `N_(2)`D. `NO_(+)` |
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Answer» Correct Answer - A B.O. for `N_(2)^(+)=1/2[N_(b)-N_(a)]=1/2[9-4]=5/2 =2.5` |
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| 375. |
Which of the following molecule is linear?A. `SO_(2)`B. `NO_(2)^(+)`C. `NO_(2)^(-)`D. `SCl_(2)` |
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Answer» Correct Answer - B `NO_(2)^(+)` shows sp-hybridization . So its shape is linear. |
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| 376. |
`HgCl_(2)` is a solid containingA. An angular Cl-Hg-Cl moleculeB. A linear Cl-Hg-Cl moleculeC. A T-shaped Cl-Hg-Cl moleculeD. A pyramidal Cl-Hg-Cl molecule |
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Answer» Correct Answer - B It is linear in shape |
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| 377. |
Which contains both polar and non-polar bonds ? .A. `NH_(4)Cl`B. HCNC. `H_(2)O_(2)`D. `CH_(4)` |
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Answer» Correct Answer - A `[H-overset(H)overset(|)underset(H)underset(|)(N)-H]^(+)[Cl^(-)]` , hence `NH_(4)Cl` has both polar and and non -polar bonds. |
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| 378. |
Which one of the following compounds has `sp^(2)` hybridisation ? .A. `CO_(2)`B. `N_(2)O`C. `SO_(2)`D. CO |
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Answer» Correct Answer - C `SO_(2)` has `sp^(2)` hybridisation have the V shape structure `(lt120^(@))` due to 2 lone pair of electron over S atom. `CO_(2)` and `N_(2)O` have the sp hybridisation. |
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| 379. |
The critical temperature of water is higher than that of `O_(2)` because the `H_(2)O` molecule hasA. Fewer electrons than `O_(2)`B. Two covalent bondsC. V-shapedD. Dipole moment |
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Answer» Correct Answer - D Critical temperature of water is higher then `O_(2)` because `H_(2)O` molecule has dipole moment which is due to its V-shape. |
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| 380. |
Which of the following compounds has `sp^(2)`-hybridisation?A. `CO_(2)`B. `SO_(2)`C. `N_(2)O`D. CO |
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Answer» Correct Answer - B No. of hybrid bonds in `SO_(2)=1/2(6+0-0+0)=3` Hence, `SO_(2)` is `sp^(2)` hybridized. |
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| 381. |
Which of the following angle corresponds to `sp^(2) ` hydridisation ?A. `90^(@)`B. `120^(@)`C. `180^(@)`D. `109^(@)` |
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Answer» Correct Answer - B The angle corresponds to `sp^(2)` hybridisation, triangular planar is `120^(@)`. |
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| 382. |
Among the following the compounds , the one that is polar and has central atom with `sp^(2)` hydridisation isA. `H_(2)CO_(3)`B. `BF_(3)`C. `N_2O`D. `HClO_(2)` |
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Answer» Correct Answer - A In `H_(2)CO_(3)` and `BF_(3)` central atom are in `sp^(2)` hybridization but in `H_(2)CO_(3)` due to the ionic character of O-H bond it will be polar (high electronegativity of oxygen ) |
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| 383. |
Most efficient overlapping isA. `sp^2 - sp^2`B. s-sC. `sp^3 -sp^3`D. sp-sp |
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Answer» Correct Answer - C The strength of bonds formed by overlap of `sp^3- sp^3` bond is more because these orbitals have more directional character |
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| 384. |
Correct order of extent of overlapping is :-A. `2s-2s gt 2p-2p gt 2s-2p`B. `1s-1s gt 2p-2p gt 2s-2p`C. `1s-1s lt 2s-2s lt 3s-3s`D. `3s-3s gt 3s-3p gt 3p-3p` |
| Answer» Correct Answer - B | |
| 385. |
In which of the following pairs, the two molecules have identical bond orders :A. `N_(2),O_(2)^(2+)`B. `N_(2),O_(2)^(-)`C. `N_(2)^(-),O_(2)`D. `O_(2)^(+),N_2` |
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Answer» Correct Answer - A B.O. `=1/2[N_(b)-N_(a)]` `N_(2)=1/2[10-4]=6/2=3, O_(2)^(2+)=1/2[10-4]=6/2=3` |
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| 386. |
Which type of overlapping results in the formation of a `pi` bondsA. Axia overlapping of S-S orbitalsB. Lateral overlapping of p-p orbitalsC. Axial overlapping of p-p orbitalsD. Axial overlapping of S-P orbitals |
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Answer» Correct Answer - B `pi`- bond is formed by lateral overlapping of unhybridised p-p orbitals |
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| 387. |
The nature of `pi`-bonds in perchlorate ionA. `O-Cl(d_pi- p_pi)`B. `O-Cl(p_pi- d_pi)`C. `O-Cl(d_pi- d_pi)`D. None of these. |
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Answer» Correct Answer - B The nature of `pi`-bonds in perchlorate ion `(ClO_4^-)` is `ppi - dpi`. |
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| 388. |
Strongest bond isA. C-CB. C=CC. `C-=C`D. All are equally strong |
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Answer» Correct Answer - C `C-=C` is a mutiple bond so it is strongest |
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| 389. |
Which set contains par of elements that do not belong to same froup but show chemical resemblaces ?A. Hf,ZrB. K, RbC. Be ,AlD. B,Al |
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Answer» Correct Answer - C Be and Al show diagonal relationship. |
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| 390. |
An element of p-block in which last electron enters into s-orbital of valence shell insteatd of p-orbital is :A. AsB. GaC. TeD. He |
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Answer» Correct Answer - D He is a p-block element whith `1s^2` configuration. |
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| 391. |
The C-C bond length is shortest inA. `sp-sp`B. `sp^(2)-sp`C. `sp^(2)-sp^(2)` bondD. `sp^(2)-sp` |
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Answer» Correct Answer - A Decreasing order of bond length `C-C gt C=C gt C-=C` |
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| 392. |
The boiling point of methanol is greater than methyl thiol becauseA. There is intramolecular hydrogen bonding in methanol and intermolecular hydrogen bonding in methyl thiolB. There is intermolecular hydrogen bonding in methanol and no hydrogen bonding in methyl thiol.C. There is no hydrogen bonding in methanol and intermolecular hydrogen bonding in methyl thiolD. There is no hydrogen bonding in methanol and intramolecular hydrogen bonding in methyl thiol. |
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Answer» Correct Answer - B In methanol `(CH_3OH)` intermolecular H-bonding increases the b.pt. S with less electronegativity (than O) and larger atomic size (than O) can not take part in H-bonding as methyl thiol `(CH_3SH)` has lower b.pt. than `CH_3OH`. |
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| 393. |
Which is most viscous ?A. `CH_3OH`B. `C_2H_5-OH`C. `overset(CH_2OH)overset|(CH_2OH)`D. None |
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Answer» Correct Answer - C Extent of hydrogen bonding is more |
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| 394. |
The boiling point of heavy water isA. `108^@` CB. `101.4^(@)`CC. `99^(@)`CD. `110^(@)`C |
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Answer» Correct Answer - C It is less than `100^(@)`C because of lack of formation of H bonds |
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| 395. |
Fluorine molecule is formed byA. The axial p-p overlapB. The sidewise p-p overlapC. The axial s-p overlapD. The overlap of two `sp^2` hybrid orbitals. |
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Answer» Correct Answer - A The `I_2` molecule is formed by the axial over of p-orbitals forming sigma bond. |
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| 396. |
The bond in the formation of fluorine molecule will beA. due to s-s overlappingB. due to s-p overlappingC. due to p-p overlappingD. due to hybridization |
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Answer» Correct Answer - C In fluorine molecule formation p-p orbitals take part in bond formation |
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| 397. |
Which of the following is paramagnetic ?A. COB. `O_2^-`C. `CN^-`D. `NO^+` |
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Answer» Correct Answer - B `O_2^-` has one unpaired electron and hence is paramagnetic |
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| 398. |
The correct statement with regard to `H_2^(+)` and `H_2^(-)` isA. Both `H_(2)^(+)` and `H_(2)^(-)` do not existB. `H_(2)^(-)` is more stable than `H_(2)^(+)`C. `H_(2)^(+)` is more stable than `H_(2)^(-)`D. Btoh `H_(2)^(+)` and `H_(2)^(-)` are equally stable |
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Answer» Correct Answer - B Though the bond order of `H_(2)^(+)` and `H_(2)^(-)` are same (0.5) but the `H_(2)^(+)` ion is slightly more slightly more stable than `H_(2)^(-)` ion since `H_(2)^(-)` has one electron in the antibonding orbitals which results in the repulsion and hence decreases the stablity. |
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| 399. |
The net dipole moment of `H_(2)O` molecule isA. zeroB. `1.85` DC. `4.90xx10^(-30)`cmD. `0.80xx10^(-30)` cm |
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Answer» (b) The dipole moment of a molecule is the vector sum of the dipole moments of various bonds. e.g. In `H_(2)O` molecule which has a bent structure , two O-H bonds are oriented at an angle of `104.5^(@)` with dipole moment 1.85D. |
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| 400. |
How many sigma-bonds are present in ` CH_3 - CH_3` ? |
| Answer» ` CH_3 -CH_3` has ` 7 sigma -bonds` . | |