`NH_(3)(g)+3Cl_(2)toNCl_(3)(g)+3HCl(g)DeltaH_(1)` `N_(2)(g)+3H_(2)(g)to2NH_(3)(g)DeltaH_(2)` `H_(2)(g)+Cl_(2)(g)to 2HCl(g)DeltaH_(3)` The heat of formation of `NCl_(3)`(g) in the terms of `DeltaH_(1)DeltaH_(2)DeltaH_(3)` is A. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))(2)-(3)(2)DeltaH_(3)`B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))(2)-(3)(2)DeltaH_(3)`C. `DeltaH_(f)=DeltaH_(1)-(DeltaH_(2))(2)-(3)(2)DeltaH_(3)`D. None of the above

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1.	`NH_(3)(g)+3Cl_(2)toNCl_(3)(g)+3HCl(g),DeltaH_(1)` `N_(2)(g)+3H_(2)(g)to2NH_(3)(g),DeltaH_(2)` `H_(2)(g)+Cl_(2)(g)to 2HCl(g),DeltaH_(3)` The heat of formation of `NCl_(3)`(g) in the terms of `DeltaH_(1),DeltaH_(2),DeltaH_(3)` is :A. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`C. `DeltaH_(f)=DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`D. None of the above
Answer» Correct Answer - A The required equation is `(1)/(2)N_(2)(g)+(3)/(2)Cl_(2)(g)toNCl_(3)(g)`, `DeltaH_(f)=?` `(i)+(1)/(2)xx(ii)-(3)/(2)xx(iii)` `DeltaH_(f)=-DeltaH_(1)+(1)/(2)DeltaH_(2)-(3)/(2)DeltaH_(3)`

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