InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7351. |
Atomsin a molecule are heldby ___. |
| Answer» SOLUTION :chemicalbonds | |
| 7352. |
Atoms: Highly reactive:: molecules : ______. |
| Answer» SOLUTION :Lessreactive | |
| 7353. |
Atomscan becreated anddestroyed |
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| 7355. |
Atomicity of Phosphorous is |
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Answer» 1 |
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| 7356. |
Atomicity of an element is equal to …………… . |
| Answer» SOLUTION :`("MOLECULAR MASS")/("ATOMIC mass")` | |
| 7357. |
Atomicity of ammonium pohosphate molecule is |
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Answer» 5 `(NH_(4))_(3)PO_(4)` No. of atoms =3 No. of H atoms =12 No. of P atoms =1 No. of O atoms =4 Total cross =20 |
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| 7359. |
Atomicity of ammonium phosphate molecule is |
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Answer» 6 |
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| 7360. |
Atomicityof amonoatomicelementis ________. |
| Answer» SOLUTION :MOLECULAR MASS / ATOMICMASS | |
| 7361. |
Atomic theory was given by |
| Answer» Solution : John Dalton | |
| 7362. |
Atomic radius of lithium is greater than the atomic radius of fluorine.Give reason |
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| 7363. |
Atomic radius of Lithium is ________ pm. |
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Answer» 41 |
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| 7364. |
Atomic radius, ionic radius, electron affinity are called __________ properties . |
| Answer» SOLUTION :PERIODIC | |
| 7366. |
Atomic radius goes on increasing down a group. |
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Answer» SOLUTION :(i) ATOMIC radius is the distance between the centre of the atom to its outermost shell. (ii) New shells are added to the atoms of the elements as we go down from top to bottom in a group. (iii) The outermost ELECTRONS go further and further away from the nucleus, extending the radius and ultimately increase in the SIZE of the atom. HENCE, atomic radius goes on increasing down a group. |
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| 7367. |
Atomic radius goes on decreasing while going from left to right in a period. |
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Answer» Solution :(i) Atomic radius is the distance between the centre of the ATOM and its OUTMOST shell. (ii) Atomic radius decreases across a period. (iii) This is because valence electrons are being added to the same outermost shell or to the same energy level because of which the electrons added EXPERIENCE GREATER pull from the nucleus. (iv) This results in the electrons moving closer to the nucleus. Hence, the atomic radius goes on decreasing while going from left to RIGHT in a period. |
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| 7368. |
Atomic radius |
| Answer» Solution :For an isolated atom, ATOMIC radius is the distance between the centre of the NUCLEUS of an atom to its OUTERMOST SHELL. | |
| 7369. |
Atomic radii of the elements of the second period are given below: Period II elements: B Be O N Li C Atomic radius (pm): 88 111 66 74 152 77 Arrange them in decreasing order of their atomic radii. |
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Answer» Solution :Decreasing order of the atomic RADII: Period II ELEMENTS :`LigtBegtBgtCgtNgtO` Atomic radius (pm): 152 111 88 77 74 66 |
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| 7370. |
The atomic radii of the elements of second period are given below: (a) Arrange these elements in the decreasing order of their atomic radii (Keeping the element with the largest atomic radius first). (b) Are the elements now arranged in the pattern of a period in the periodic table? (c) Which elements have the largest and the smallest atoms? (d) From this data, infer how the atomic size (or atomic radius) of the elements changes as you go from left to right in a period? |
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Answer» Solution :(i) The decreasing ORDER of atomic radii is : `Li (152) gt Be (111) gt B (88) gt C(77) gt N(74) gt O(66)` (ii) No, the arrangement of the elements is not systematic. The correct arrangement is as given above. (iii) The element Li has the LARGEST atoms while the element O has CHE smallest atoms. (iv) The atomic radii of the elements decrease in moving from LEFT to the right. |
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| 7371. |
Atomic radii decreasesas we move from left to right of periodic table.Justify your answer . |
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Answer» Solution :(i) As we MOVE alongthe PERIOD , the shell NUMBER remains same but the number of protons increases . (ii) increases positive charges impose strong attraction over ELECTRONS and thus the electron cloud shrinks towardsthe nucleuswhich results in decrease in atomic SIZE . |
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| 7372. |
Atomic orbitals are……….centric and molecular orbitals are………… centric. |
| Answer» SOLUTION :MONO, POLY | |
| 7373. |
Atomic numbers of a few elements are given below : 10, 20, 7, 14 (a) Identify the elements. (b) Identify the group number of these elements in the Periodic Table. (c) Identify the period of these elements in the Periodic Table. (d) What would be the electronic configuration for each of these elements ? (e) Determine the valency of these elements. |
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Answer» Solution :(a)`{:("Atomic number","Element"),(10,"Neon(Ne)"),(20,"Calcium(CA)"),(7,"NITROGEN(N)"),(14,"Silicon(Si)"):}` (b)`{:("Atomic number","Group number"),(10,18),(20,2),(7,15),(14,14):}` (c)`{:("Atomic number","Periodic number"),(10,2),(20,4),(2,2),(14,3):}` (d)`{:("Atomic number","Electronic CONFIGURATION"),(10,2","8),(20,2","8","8","2),(7,2","5),(14,2","8","4):}` (e)`{:("Atomic number","Valency"),(10,0),(20,2),(7,3),(14,4):}` |
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| 7374. |
Atomic number of an element is equalto the number of __________ and __________. |
| Answer» SOLUTION :PROTONS , ELECTRONS | |
| 7375. |
Atomic number of an element is 42. Find out the number of electrons present in the valence shell. |
| Answer» SOLUTION : ELECTRONIC CONFIGURATION of the ELEMENT | |
| 7376. |
Atomic number of a few elements are given below: 10, 20, 7, 14 (a) Identify the elements. (b) Identify the Group number of these elements in the Periodic Table.(c) Identify the Periods of these elements in the Periodic Table. (d) What would be the electronic configuration for each of these elements? (e) Determine the valency of these elements. |
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Answer» Solution :(a) Elements – Neon (Ne), Calcium (Ca), Nitrogen (N), Silicon (Si) (B)Group – 18, 2, 15, 14 (c) Period - 2, 4, 2, 3 (d) Electronic configuration- (2,8), (2, 8, 8, 2), (2, 5), (2,8, 4) (e) VALENCY - 0, 2, 3, 4 |
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| 7377. |
Atomic number is the fundamental property of an element'. Write the name of the scientist who proved it by an X-ray experiment. |
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Answer» a)Bohr |
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| 7378. |
Atomic number is numberof ……………… in the nucleus or number of ………………. Revolving around the nucleus is an atom . |
| Answer» SOLUTION : PROTONS, ELECTRONS | |
| 7380. |
Atomic number is considered to be a more appropriate parameter than atomic mass forclassification of elements in a periodic table. Why?How does metallic character of elements vary on moving from(i) left to right in a period? (ii) from top to bottom in a group? Give reasons for your answers. |
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Answer» Solution :The properties of elements depend upon VALENCE ELECTRONS in the atom which in turn depends on the total number of electrons, i.e., atomic number. Therefore, atomic number is a more appropriate parameter than atomic mass for classification of elements. (i) On moving from left to right in a period, the metallic character decreases. This is due to an increase in nuclear charge which tends to pull the electrons closer to the nucleus and reduces the size of the atom. (ii) On moving from TOP to bottom in a GROUP, metallic character INCREASES. This is because new shells are being added as we go down the group. This increases the distance between the valence shell and the nucleus. |
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| 7381. |
Atomic number is considered to be a more appropriate parameter than atomic mass for classification of elements in a periodic table. Why? |
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Answer» Solution :Atomic NUMBER is more important than atomic mass because: Atomic number z indicates the number of protons and electrons in an atom of the element. All the physical and chemical properties of ELEMENTS are due to arrangement of electrons (ELECTRONIC configuration), which depends on the atomic number. Proton .number. is a characteristic property of an element which remains same even when its atom is charged and in all the isotopes of an element. Atomic number is different for different elements and increases steadily by ONE unlike atomic mass. |
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| 7382. |
Atomic number and not the atomic weight is the fundamental property of a element was enunciated by ? |
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Answer» DALTON |
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| 7383. |
How Atomic number is a more fundamental property of an element than its atomic mass? |
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Answer» SOLUTION :(i)The a tomi c number of an element indicates the number of protons in the nucleus or the number of electrons in the atom . (ii) All the atoms of an element have the same atomic number . (iii) The number of electrons PRESENT in the outermostshell of an atom is responsible for the FORMATIONOF compounds either bysharing, accepting or donating electrons. (iv) The chemical properti e s of an e L e m e nt ar e decided by its atomic numbers. Hence, atomic number is a more fundamental property of property of an element than its atomic mass. |
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| 7384. |
Atomicmass unitis __________ of themassof acarbon12 atom . |
| Answer» SOLUTION :one-twelfth | |
| 7385. |
Atomic mass of Nitrogen is 14. which of the following sample contain 6.022 times 10^(23) Nitrogen atoms? (7g Nitrogen, 14g Nitrogen, 28g Nitrogen, 1g Nitrogen) |
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| 7387. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, answerthe followingquestion given ahead : Which one of the given elements is likely to have the smallestatomic radius ?. |
Answer» Solution :Since all the SEVEN elementshave same number of electron in their outermostshells, this meansthat they belongto the same group. From the availableinformation , it becomesclear that the group of alkali metals ( group 1 ) . Hydrogen (A) is also included. The elements PRESENTARE : LET us answerthe question asked . The element A (hydrogen ) has the smallestatomic radiussince it is the firstelement ofthe group. |
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| 7388. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, anwerthe followingquestion given ahead : What would be the ratio of number of combining atoms in a compoundformed by the combination element A with carbon ? |
Answer» Solution :Since all the SEVEN elementshave same number of electron in their outermostshells, this meansthat they belongto the same GROUP. From the availableinformation , it becomesclear that the group of alkali metals ( group 1 ) . Hydrogen (A) is also included. The elements presentare : Let us answerthe question asked . The compoundformed between A (H) and carbon is methane `(CH_4)`. In this the two elementsare presentin the ratio of 1: 4 . |
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| 7389. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, anwerthe followingquestion given ahead : Show the formation of the compound by a combination of element C with chlorinewith the help of electronic structure . |
Answer» Solution :Since all the seven elementshave same NUMBER of electron in their outermostshells, this meansthat they belongto the same group. From the availableinformation , it becomesclear that the group of alkali METALS ( group 1 ) . Hydrogen (A) is also INCLUDED. The elements presentare : Let us answerthe question asked . Compoundbetween 'C' and chlorine (CL) is sodium CHLORIDE (NaCl) formed by transferenceof one electron . 
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| 7390. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, anwerthe followingquestion given ahead : Writethe formulaof the compoundformed by the reaction of the element A with oxygen . |
Answer» Solution :Since all the seven elementshave same number of electron in their OUTERMOSTSHELLS, this meansthat they belongto the same group. From the availableinformation , it becomesclear that the group of ALKALI metals ( group 1 ) . HYDROGEN (A) is also INCLUDED. The elements presentare : Let us answerthe question asked . The formulaof compound is `H_2O` . |
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| 7391. |
Atom of one element can be transmuted into atom of other element is known as artificial transmutation. |
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| 7392. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, anwerthe followingquestion given ahead : Will element A to G belongto the same period or same group of the periodictable ? |
Answer» SOLUTION :Since all the seven elementshave same number of electron in their OUTERMOSTSHELLS, this meansthat they belongto the same group. From the availableinformation , it becomesclear that the group of alkali metals ( group 1 ) . Hydrogen (A) is also included. The elements presentare : Let us answerthe QUESTION ASKED . The element A' to G' belongto the same group and not same period . |
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| 7393. |
Atom of seven elementsA,B ,C, D, E,F and G have a differentnumber of electronic shells but havethe same number of electrons in their outermostshells.The element A and C combine with chlorine to form an acidand common salt respectively. The oxide of element A is liquidat room temperatureand is a neutral substancewhile the oxides of theremainingsix elements are basic in nature . Based on the above information, anwerthe followingquestion given ahead : What couldthe elementA be ? |
Answer» Solution :SINCE all the seven elementshave same NUMBER of electron in their outermostshells, this meansthat they belongto the same group. From the availableinformation , it becomesclear that the group of alkali METALS ( group 1 ) . Hydrogen (A) is also included. The elements presentare : LET us answerthe question asked . The ELEMENT A' is hydrogen (H). |
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| 7394. |
Atom is th smallest particle of |
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Answer» compound |
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| 7397. |
At what concentration of Cu^(2+) (aq.) will electrode potential become equal to its standard electrode potential ? |
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| 7398. |
At the equilibrium of a reversible reaction,the concentration of the reactants and the products will be equal. |
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Answer» Solution :FALSE CORRECT statement:At EQUILIBRIUM RATE of forward reaction is equal to rate of backward reaction. |
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| 7399. |
At STP, what will be the volume of 6.022 xx 10^(23) molecules of H_(2) ? |
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| 7400. |
At STP, a certain amount of hydrogen is produced by the reaction of 550 g of impure zinc withexcess amount of HCl. The same volume of hydrogen at STP reduces Fe_(3)O_(4) and produces 336 g of iron.Find the percentage of zinc. (Atomic mass of Zn is 65) |
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Answer» SOLUTION :`ZN+2HCl to ZnCl_(2) + H_(2) , 4H_(2) + Fe_(3)O_(4) to 4H_(2)O + 3Fe` AMOUNT of iron produced ` = 336 g rArr` NUMBER of moles ofiron ` = (336)/56 = 6` To produce 6 moles of iron, it requires 8 moles of hydrogen which further requires 8 moles of Zn. Weight of Zn = `8 xx 65.5 = 524` g, % purity =`(524)/(550) xx 100 = 95.27 %`. |
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