

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
7901. |
Anatomcontains________ particles suchas protons , neutronsand electrons . |
Answer» SOLUTION :SUBATOMIC | |
7902. |
An atoin of an element has three electrons in 4p subshell. Calculate the atomic number of the element |
Answer» SOLUTION :The electronic configuration of the element having three electrons in 4P subshell is `[Ar]4s^23d^(10)4p^3` THEREFORE, the ATOMIC number is 33. | |
7903. |
An aqueous solution with pH value zero is |
Answer» ACIDIC |
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7905. |
An aqueous solution turns red litum solution blue. Excess addition of which solution would reverse the change - ammonium hydroxide solution or hydrochloric acid ? |
Answer» Solution :Hydrochloric acid because adding EXCESS acid to the BASE WOULD turn blue LITMUS solution RED. | |
7906. |
An aqueous solution turns red litmus solution blue. Excess addition of which of the following solution would reverse the change ? |
Answer» BAKING powder |
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7907. |
An aqueous solution turns red litmus solution blue. Excess addition of which of the following solution would reverse the change? |
Answer» BAKING powder Other options baking powder, lime and ammonium hydroxide solution are basic compounds.So the blue litmus solution would not change the colour by adding these compounds. |
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7908. |
An aqueous solution of NaCl is |
Answer» Solution :neutral | |
7909. |
An aqueous solution of Mohr's salt can give a precipitate with NaOH or NH_(4)OH. But the aqueous solution of potassium ferrocyanide cannot give a precipitate with both reagents. How do you account for this ? |
Answer» Solution :(i) characteristics of double SALTS (ii) type of salts (III) COMPARISON of ions present in their salt solution (IV) requisite of a salt to give a PRECIPITATE |
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7910. |
An aqueous solution of metal nitrate 'P' reacts with sodium bromide solution to form yellow precipitate compound 'Q' which is used in photography. 'Q' on exposure to sunlight undergoes decomposition reaction to form metal present in along with a raddish brown gas. Identify 'P' and 'Q' Write balanced chemical equation for the chemical reaction. List two categories in which this reaction can be placed. |
Answer» Solution :(i) P is silver nitrate, `AgNO_(3)`. <BR> Q is silver BROMIDE, `AgBr`. (ii) `AgNO_(3)(aq)+NaBr(aq)overset("Sunlight")(to)underset("(Q)")underset("Silver bromide")(AgBr(s))+NaNO_(3)(aq)` `2AgBroverset("Sunlight")(to)2Ag+underset("(Brown gas)")underset("Bromide")(Br_(2))` (iii) Decomposition of silver bromide can be put under TWO CATEGORIES : (a) Decomposition reaction. (b) PHOTOCHEMICAL reaction. |
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7911. |
An aqueous solution of metal nitrate (P) reacts with sodium bromide solution to form an yellow precipitate of a compound (Q) which is used in photography. Q on exposure to sunlight, undergoes decomposition reaction to form the metal present in P along with a reddish brown gas Write the chemical reaction and the type of chemical reaction. |
Answer» SOLUTION :`AgNO_3+NaBrtoAgBr+NaNO_3` This is double displacement REACTION. `2AgBr(s)TO2AG(s)+Br_2(G)` This is Photochemical decomposition |
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7912. |
An aqueous solution of metal nitrate (P) reacts with sodium bromide solution to form an yellow precipitate of a compound (Q) which is used in photography. Q on exposure to sunlight, undergoes decomposition reaction to form the metal present in P along with a reddish brown gas Identify P and Q |
Answer» <P> SOLUTION :P is `AgNO_3` and Q is AGBR |
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7913. |
An aqueous solution of ferrous sulphate is taken and subjected to electrolysis. Calculate the number of electrons flowing through the circuit when 0,7 g of iron is deposited at cathode (atomic mass of Fe = 56) |
Answer» Solution :EQUIVALENT mass of IROM `= (56)/(2) = 28` `(FE^(+2) + 2e^(-) rarr Fe)` 1 faraday of electricity is required to deposit 28 g of iron. 1 faraday charge is required to deposit `6.023 xx 10^(23)` ELECTRONS. `:.` 28 g of Fe required to deposit `6.023 xx 10^(23)` electrons. 0.7 g of Fe required to deposit `= (6.023 xx 10^(23) xx 0.7)/(28) = 1.5 xx 10^(23)` electrons |
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7914. |
An aqueous solution of ethanoic acid contains |
Answer» IONS only |
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7915. |
An aqueous solution of copper sulphate is subjected to electrolysis using platinum electrodes. Calculate the number of electrons flowing through the circuit when 0.3175 g of copper is deposited. Also calculate the number of molecules present in anodic product (atomic mass of copper = 63.5) |
Answer» Solution :`CuSO_(4) + Cu^(2+) + So_(4)^(-2)` `H_(2)O rarr H^(+) + OH^(-)` Among the cations `Cu^(+2) and H^(+), Cu^(+2)` requires lesser discharge potential compared to `H^(+)` so Cu is discharged at cathode. At cathode : `Cu^(+2) + 2e^(-) rarr Cu` For the deposition of 63.5 g of Cu, `2 XX 6.023 xx 10^(23) e^(-)` have to flow through the circuit, THEREFORE, 0.3175 g of Cu requires ? electrons `= (0.3175 xx 2 xx 6.023 xx 10^(23))/(63.5)` `= 6.023 xx 10^(21)` electrons are required AT ANODE : `4OH^(-) rarr 2H_(2)O + 4e^(-) + O_(2)` For the formation of 1 mole of oxygen 4 moles of electrons are required `96,500 C = (N)/(4)` moles of oxygen `= (6.023 xx 10^(23))/(4)` molecule (`6 xx 10^(21)` electrons = 965 C) No. of molecules of oxygen liberated for 965 C `= (965 xx 6.023 xx 10^(23))/(4 xx 96,500) = 1.5 xx 10^(21)` molecules |
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7916. |
An aqueous solution of CH_3 COONa is |
Answer» ACIDIC |
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7917. |
An aqueous solution of a salt has basic nature. What are the types of acid and base from which this salt is formed? |
Answer» WEAK ACID and weak base |
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7918. |
An aqueous solution is prepared by dissolving 90 g of acetic acid in water to make a 1000mLsolution. Density of solution and mole fraction of solute in the solution. |
Answer» Solution :(i) number of moles of solute (II) CALCULATION of weight of solution, solvent (iii) calculation of number of moles of solvent (iv) calculation ofmole FRACTION and molarity (V) 1.5M, 0.03 |
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7919. |
An aqueous solution contains H^(+),Ag^(+),Fe^(2+) and Zn^(2+)ions . The ion that will be reduced first at cathode is . |
Answer» `H^(+)` |
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7920. |
An aqueous solution containing 1M each of Au^(+3), Cu^(+2), Ag^(+), Li^(+)is being electrolysed using inert electrodes the value of standard potentials are E_(Ag^(+)//Ag)^(theta)a=0.80V,E_(cu^(2)+Cu)^(theta)=0.34V,E_(Au^(3+)//Au)^(theta)=1.50V,E_(Li^(+)//Li)^(theta)=-3.03V With increasing voltage, find the sequence of deposition of metals on the cathode. |
Answer» Solution :Only `AU^(3+), Ag^(+)` and `Cu^(2+)` will deposit at CATHODE. Li+ will not deposit at cathode be cause SRP of water is -0.8274V So after `Cu^(2+ ), H_(2)` will evolve at cathode. | |
7921. |
An aqueous solution .A. turns phenolphthalein solution pink. On addition of an aqueous solution .B. to .A., the pink colour disappears. The following statementis true for solution.A. and .B.. |
Answer» A is strongly basic and B is a WEAK base. |
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7922. |
An aqueous electrolyte consits of the ions mentioned in the list , the ion which could be most readily discharged during electrolysis[A. F e 2 + B. C u 2 + C. P b 2 + D. H + ] |
Answer» SOLUTION :`CU^(+)` | |
7923. |
An antiseptic to sterilise wounds and syringes in hospitals |
Answer» PROPANOL |
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7924. |
An antacid is used to neutralize excessacid present in the stomach. |
Answer» |
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7925. |
Why is an ammeter always connected in series in a circuit? What change do you observe in the reading of an ammeter if it is connected in parallel in a circuit? |
Answer» Solution :An ammeter is LAW RESISTANCE DEVICE when it is connected in parallel the resistance of the circuit reduces consider blu therefore a large current flows through the ciruit by virtue of circuit element may damage. | |
7926. |
An amalgam of metal has which other element ? |
Answer» C |
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7927. |
An aluminium can is used to store ferrous sulphate solution. It is observed that in few days holes appeared in the can. Explain the observation and write the chemical equations to support your answer. |
Answer» Solution :It is a displacement reaction. ALUMINIUM is more reactive than IRON. So, FE is displaced by AL and aluminium sulphate is formed and iron is precipitated. `3FeSO_(4) + 2AL rarr Al_(2)(SO_(4))_(3) + 3Fe`. |
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7928. |
The frequency of source of sound is 10Hz. How many times does it vibrate in one minute? |
Answer» Solution :100 times. 50 HZ frequency MEANS AC generator completes 50 cycles in 1 SECOND. | |
7929. |
An alloy is a heterogenous mixture of metals. |
Answer» |
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7931. |
Choose the correct answer An alkaline earth metal . |
Answer» SOLUTION :Calcium | |
7933. |
An aldehyde as well as a ketone can be represented by the same molecular formula, say C_(3)H_(6)O. Write their structures and name them. State the relation between the two in the language of science. |
Answer» Solution :`OVERSET("Propanal (aldehyde),")(H-underset(H)underset(|)overset(H)overset(|)C-underset(H)underset(|)overset(H)overset(|)C-overset(H)overset(|)C=O)""overset("PROPANONE (ketone),")(H-underset(H)underset(|)overset(H)overset(|)C-underset(O)underset(||)C-underset(H)underset(|)overset(H)overset(|)C-H)` These TWO compounds are called isomers i.e., compounds having same molecular FORMULA but DIFFERENT structural formula. |
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7934. |
An aldehyde and a ketone can be represented by the same molecular formula, say C_3H_6O. Write their structures and name them. State the relation between the two in the language of science. |
Answer» SOLUTION :The aldehyde and KETONE with the same molecular formula `C_3H_6O` are propanaldehyde and propanone. `underset("Propanal")(H-underset(H)underset(|)overset(H)overset(|)(C ) -underset(H)underset(|)overset(H)overset(|)(C )-overset(H)overset(|)(C )-O) "" underset("Propane")(H-underset(H)underset(|)overset(H)overset(|)(C )-underset(O)underset(|)(C )-underset(H)underset(|)overset(H)overset(|)(C )-H)` They are CALLED isomers. |
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7937. |
An acid solution is diluted with water. How will the pH of the solution change ? |
Answer» SOLUTION :The PH of the solution will INCREASE. | |
7938. |
An absent-mined prodessie, Mr Waage, took elements A and B in areaction vessel at room temperature, to study the reactionA+ 2B rArr 2C +D. He took the concentration of B as 1.5 times the concentration of A. After the reaction reached equilbrium, he round that the concentrations of A and D were equal. However, he forgot to calculate K_(c) and removed oneof the products from the mixture. Now, can you calculate K_(c) for the equilibrium attained in his experiment and help him out ? |
Answer» Solution :`A + 2B hArr2C +D` Initialconcentrationa 1.5a 0 0 EQUILIBRIUM concentrationa-x 1.5a-2x 2x x At equilibrium, the concentration of A and that of D are equal `therefore a-x = x IMPLIES a=2x ` or ` x=a//2` `K_(c)=((2x)^(2)x)/((a-x)(15a-2x)^(2))` as a=2x `implies (4x^(2).x)/(x xx (x)^(2))implies K_(c) = 4` |
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7940. |
Amongst the followng the most metallic elements is |
Answer» F |
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7941. |
Amongst the following elements which has the largest atomic size ? |
Answer» magnesium |
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7942. |
Amongst the elements of period 3 : Na Mg Al Si P S Cl Ar Indicate the atomic numbers of the following type of elements:Elements forming positive ions |
Answer» SOLUTION :ELEMENTS forming POSITIVE ions: Na (11), Mg (12), AL (13) | |
7943. |
Amongst the elements of period 3 : Na Mg Al Si P S Cl Ar Indicate the atomic numbers of the following type of elements:Metals |
Answer» Solution :METALS: NA (11), MG (12), AL (13) | |
7944. |
Amongst the elements of period 3 : Na Mg Al Si P S Cl Ar Indicate the atomic numbers of the following type of elements:Elements forming negative ions |
Answer» <P> SOLUTION :Elements forming negative ions: P(15), O(16), CL(17) |
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7945. |
Amongst the elements of period 3 : Na Mg Al Si P S Cl Ar Indicate the atomic numbers of the following type of elements:Nonmetals |
Answer» Solution :NONMETALS: Si (14), P (15), O (16), Cl (17), AR (18) | |
7946. |
Amongst element X (2,8,6) and Y (2,8,8) which is more reactive and why? |
Answer» X because it is a metal |
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7947. |
Amongthe given species A^(-),A^(+), and A, the smallest one in size is ___________ |
Answer» SOLUTION :ATOMIC NUMBER | |
7948. |
Among the given species A^(-), A^(+), and A, the smallest one is size is …………….. . |
Answer» SOLUTION :`A^(+)` | |
7949. |
Among the following , the orbitals that has the lowest energy is |
Answer» 5f |
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7950. |
Among the following, the molecule with linear geometry is |
Answer» `C_(2)H_(4)` `O=C=O` ![]() |
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