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88451.

A mixture of twosalt was treated as follows : i. The mixturewas heatedwith magnanese dioxide andconcentratedsulphuric acid , when a yellowish -greengaswas liberated. ii. The mixture onheatingwithsodiumhydroxidesolutiongave a gaswhich turnedred litmusblue iii. Itssolution in watergave a blue precipitatewith potassiumferricyanide andredcolourtionwith ammoniumthiocynate iv. The mixture was boiled with potassium hydroxide and the libratedgas was bubbledthrough an alklinesolutionof K_(2)HgI_(4)to give a brownprecipitateidentifythe two salts givesionic equationfor thereactioninvolvedin the tests (i) , (ii) and (iii).

Answer»

Solution :The maxiturecontain `Fe^(2+) ,NH_(4)^(oplus) + CI^(Theta)` ions (with an impurity of `Fe^(3+)` ions)

`rarr "Test of" NH_(3)` is confirmed.
`rarr "Mixture must be containing" NH_(4)Cl`
`Cl^(Theta) + MnO_(2) + H_(2)SO_(4) to underset("Greenish yellow")(Cl_(2)) uarr GAS + MnSO_(4)`
Mixture + `NaOH to NH_(4)OH underset(NaOH)(to) NH_(3) uarr overset(Red)underset("Litmus")(to)` blue
`underset(KOH)(Boil) gas overset(K_(2)H_(2)I_(4))(to)` brown `NH_(3)` confirmed
`NH_(4)Cl` is confirmed.
Now `Fe^(2+) + K_(4)[(FeCN)_(6)] to underset("Ferro-ferri cyanide")(Fe[Fe(CN)_(6)]_(2)`) blue
`rarr` Mixture contains `FeCl_(2)`
Last is interseting as it signifies presence of
`Fe^(3+) (Fe^(3+) + NH_(4)CNS to Fe(SCN)_(3)]`
Either `Fe^(2+) overset("Oxidised")(to) Fe^(3+)` or may be mixture contains `FeCl_(3)`
88452.

A mixture of two salts is not water soluble but dissolves completely in dil HCl to form a colourless solution. The mixture could be :

Answer»

`AgNO_(3)` and KBR
` BaCO_(3)` and ZnS
` FeCl_(3)` and `CaCO_(3)`
`Mn(NO_(3))_(2) MgSO_(4)`

Answer :B
88453.

A mixture of two organic compounds was treated with sodium metal in ether solution Isobutane was obtained as a product . The two chlorine compounds are :

Answer»

METHYL CHLORIDE and PROPYL chloride
Methyl chloride and ETHYL chloride
isopropyl chloride and methyl chloride
Isopropyl chloride and ethyl chloride

Answer :C
88454.

A mixture of two organic compound is added to cold water. After filtration, water-insoluble compound (A) burns with a smoky flame and it does not respond to Lassaigne's and Beilsteins test. When a small amount of this is added to NaHCO_(3) solution, a colourless gas is evolved with effervescene. when this comopound is heated with CH_(3)OH in acidic medium, it gives the characteristic smell of oil of wintergreen. compound (B), which is water soluble, burns with a non-smoky flame and its sodium extract is prepared with cane sugar. It gives the Prussian blue colour with freshly prepared solutions of FeSO_(4)+2-3 drops NaOH and with few drops of H_(2)SO_(4). when a small amount of this compound is heated in a dry test tube, a colourless gas is evolved that turns moist red litmus paper blue and a white residue is left. this white residue is dissolved in water and a drop of CuSO_(4) is added in the basic medium -a violet colour is obtained. identify the compounds (A) and (B) with the help of the reactions involved.

Answer»

Solution :(i) Compound `(A)` is insoluble in water and burns with a smoky flame, hence it should be an aromatic compound.
(ii) It has no specific element such as `N,S` and halogens and gives `CO_(2)` gas with `NaHCO_(3)` solution, hence it should contain `(-COOH)` group.
(iii) It gives oil of wintegreen (methyl salicylate) with `CH_(3)OH` in acidic medium, hence it is salicylic acid.

(iv) Compound `(B)` is water soluble and burns with a non-smoky flame. hence it should be an aliphatic compound.
(V) This compound has less carbon content because its sodium extract is prepared with sucrose and it gives PRUSSIAN blue colour with freshly prepared solution of `FeSO_(4)+2-3` drops of `NaOH` and a few drops of `H_(2)SO_(4)`, hence it is nitrogen-containing compound.
`NaCN+FeSO_(4)toNa_(4)[FE(CN)_(6)]+Na_(2)SO_(4)`
`FeSO_(4)overset([O])toFe_(2)(SO_(4))_(3)`
`3Na_(4)[Fe(CN)_(6)]+3Fe_(2)(SO_(4))_(3)toFe_(4)[Fe(CN)_(6)]_(3)+6Na_(2)SO_(4)`
(vi) On heating, it gives ammonia gas, which turns red litmus blue. hence, it contains `(-COONH_(2))` group.
(vii) It ALSO gives the biuret test.
`2NH_(2)CONH_(2)overset(triangle)toNH_(2)CONHCONH_(2)+NH_(3)uarr`
`NH_(2)CONHCONH_(2)overset(Cu^(2+))to`violet colour
Hence, this compound is urea `(NH_(2)CONH_(2))`.
88455.

A mixture of two or more than two amino acids are separated by

Answer»

Osmosis
Ultracentrifugation
ELECTRODIALYSIS
ELECTROPHORESIS

SOLUTION :Electrophoresis
88456.

A mixture of two organic chlorie compounds was treated with sodium metal in ether solution. Isobutane was obtaned as a product. The two chlorine compounds are

Answer»

Methyl chloride and propyl chloride
Methyl chloride and ETHYL chloride
isopropyl chloride and methyl chloride
Isopropyl chloride and ethyl chloride

Solution :`underset("Isopropylchloride")(CH_(3)-underset(CH_(3))underset(|)(C)H-Cl)+2Na+underset("Methyl chloride")(Cl-CH_(3))underset(ether)OVERSET(dry)tounderset("Isobutane")(CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(3))+2NaCl`
88457.

A mixture of two moles of carbon monoxide and mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If DeltaH is the enthalpy change and DeltaE is the change in interval energy, then

Answer»

`DeltaH gt DeltaE`
`DeltaH LT DeltaE`
`DeltaH = DeltaE`
the RELATIONSHIP depends on the CAPACITY of the vessel.

Answer :B
88458.

A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If DeltaH is the enthalpy change and DeltaE is the change in internal energy, then

Answer»

`DELTAH gt DeltaE`
`DeltaH LT DeltaE`
`DeltaH = DeltaE`
The relationship depends on the capacity of the vessel

Solution :Formation of `CO_(2)` from CO is an EXOTHERIC reaction, heat is evolved from the system, i.e., energy is lowered. THUS, EXOTHERMIC reactions occur spontaneously on account of decrease in enthalpy of system. Thus, `DeltaE gt DeltaH`.
88459.

A mixture of two immiscible liquids water and nitrobeneze boiling at 372 K has partial vapour pressures of water 733 mm and nitrobenzene 27 mm. Calculate the weigth ratio of liqid components in distillate.

Answer»


ANSWER :D
88460.

A mixture of two gases, having partial pressure P_1 and P_2 has total pressure P, then according to Dalton's law :

Answer»

<P>`P =P_1 + P_2`
`P = SQRT (P_1 + P_2)`
`P = P_1 XX P_2`
`P = (P_1 + P_2)/2`

ANSWER :A
88461.

A mixture of two gases AsH_(3) and SbH_(3) is passed through a tube heated at the middle position. Two mirror like depositions are observed of which (I) is before the hot position and (II) is after the hot position. These depositions I and II are of

Answer»

SB and As
As and Sb
Both As
Both Sb

Answer :A
88462.

A mixture of two enantiomers in equimolar proportions is optically _____(Active, Inactive)

Answer»


ANSWER :INACTIVE
88463.

A mixture of two completely miscible non-ideal liquids which distill as such without change in its composition at a constant temperature as though it were a pure liquid. This mixture is known as

Answer»

BINARY LIQUID mixture
Azeotropic mixture
EUTECTIC mixture
IDEAL mixture

Answer :B
88464.

A mixture of two amino acids having pl 9.60 and 5.40 can be separated

Answer»

by adjusting the pH of the solution at 9.60
by adjusting the pH of the solution at 5.40
by adjusting the pH of the solution at 7.0
by adjusting the pH of the solution at 14.0

Solution :Every amino acid exists exclusively as dipolar ion when the pH of the solution is equal to its isoelectric POINT (pl), HENCE at this pH it does not migrate to either electrode, while at other pH, an amino acid migrates either to CATHODE or to anode DEPENDING upon its pH. Thus, at pH 9.60, amino acid with pl 5.40 will exist as an anion and migrate to anode while that with pl 9.60 will not migrate to any electrode. SIMILARLY, at pH 5.40, amino acid with pl 9.60 will exist as cation and migrate to either electrode.
88465.

A mixture of two amino acids having p1 9.60 and 5.40 can be separated

Answer»

by ADJUSTING the pH of the solution at 9.60
by adjusting the pH of the solution at 4.20
by adjusting the pH of the solution at 7.0
by adjusting the pH of the solution at 7.5

Solution :EVERY amino acid EXISTS exclusively as dipolar ion when the pH of the solution is equal to its isoelectric point (pl), hence at this pH it does not migrate to EITHER electrode, while at other pH, an amino acid migrates either to cathode or to anode depending UPON its pI.Thus at pH 9.60, amino acid with pl 5.40 will exist as an anion and migrate to anode, while that with pl 9.60 will not migrate to any electrode.
88466.

A mixture of TiCl_(4) with Al(CH_(3))_(3) is used as Zieglar catalyst for the manufacture of

Answer»

POLYBUTADIENE.
PVC.
rubber.
polythene.

ANSWER :D
88467.

A mixture of three protiens, (A) (pepsin), (B) (haemo-globin), and (C ) (lysozyme) was seperated by elctrophoresis method at pH=7. The pH at isoelectric point (pI) of the proteins are pI of (A), (B), and (C ) which are 1.1,6.7, and 11.0, respectively. which of the statement are correct?

Answer»

Pepsin (A) will migrate to the CATHODE.
Lysozyme (C ) will migrate to the anode.
Haemoglobon will not migrate.
At pH=7, (A) and (C ) would PRECIPITATE out while (B) would remain in the solution.

Solution :Is in a very acidic range, has more anionic groups at `pH=7`, and will migrate to the positive electrode (cathode). `(B)(PI=6.7)` is present mostlywith net zero charge and moves very littel or will not migrate. `(C )(pH=11.0)`, the very BASIC protein, EXISTS mainly in the cationic form and migrates to the negative electrode (anode). At `pI`, amino acids have least solubities, so `(B)` `(pH=6.7)`, `[pH` very close to `pH` of the mixture `(pH=7)]`, is least soluble and would precipitate out, while `(A)` and `(C )` would remain in the solution.
88468.

A mixtureof TiCI_(4) and trialkylaluminiumis "______"

Answer»

hydroformylationof obfine
ZEIGLER - NattaCatalyst
Interstitialcompounds
FERROMAGNETIC

ANSWER :B
88469.

A mixture of three amino acids X-(pH = 3.2), Y-(pH = 5.7, and Z-(pH = 9.7) under electrophoresis at pH = 7.7, in which direction will each componeat of the mixture move?

Answer»

X to anode, Y and Z to cathode
X to anode Y STATIONARY, Z to cathode
X to cathode, Y stationary, Z to anode
X and Y to anode, Z to cathode

Answer :C
88470.

A mixture of three amines can be separated into individual one by:

Answer»

CARBYLAMINE reaction
Hinsberg's method
Fracitonal DISTILLATION method
Hofmann's method

Answer :B::C::D
88471.

A mixture of three amines A, B and C is treated with benzene sulphonyl chloride and filtered. B is obtained in the filterate. The mixture containing A and C is treated with KOH so that a becomes soluble while C does not .Now A,B and C are

Answer»

Aliphatic PRIMARY , SECONDARY and tertiary
Aliphatic secondary , tertiary and primary
Aliphatic primary , tertiary and secondary
Aliphatic tertiary , secondary and primary

ANSWER :C
88472.

A mixture of sodium acetate and soda lime is heated and the product treated with excess of chlorine in presence of bright sun light . The product is :

Answer»

`CH_3COOH`
`CH_2BrCOOH`
`CCL_4`
`CH_3Cl`

ANSWER :C
88473.

A mixture of sodium acetate and acetic acid acts as a _____.

Answer»


ANSWER :BUFFER SOLUTION
88474.

A mixture of SO_3,SO_2" and "O_2 gases in a 10.0 litre flask is maintained at a temperature at which the equilibrium constant Kc of the reaction is 100. 2SO_(2(g))+O_(2(g)) hArr 2SO_(3(g)) . If the number of moles of SO_2" and "SO_3 in the flask are equal, the number of moles of O_2 present is

Answer»

`0.01`
`0.1`
`1.0`
`10.0`

ANSWER :B
88475.

A mixture of salts was treated to determine the barium constent. A 0.230 g sample was dissolved and treated with excess potassium chromate. The precipitate of BaCrO_(4) was dissolved in dil HCl to convert BaCrO_(4) to Cr_(2)O_(7)^(2-) anion. The solution treated with excess sodium iodide and trilodide produced was titrated with 21 mL of 0.095 M sodium thiosulphate. Calculate the % of BaCl_(2). 2H_(2)O in the sample. [Given Molar mass of BaCl_(2.2H2O)=244]

Answer»

`70.5%`
`30.25%`
`15.12%`
`110%`

ANSWER :A
88476.

A mixture of salts (Na_(2)SO_(3)+K_(2)Cr_(2)O_(7)) in most tube is treated with dil. H_(2)SO_(4) and resulting gas is passed through lime water . Which of the following observations is correct about this test ?

Answer»

Solution in test tube becomes green and LIME water TURNS milky
Solution is test tube is colourless and lime water turns milky.
Solution in test tube becomes green and limewater remains clear
Solution in test tube remains clear and lime water also remains clear.

Solution :`Na_(2)SO_(3)` reactswith dilute `H_(2)SO_(4)` to give `SO_(2)` gas which reacts with `K_(2)Cr_(2)O_(7) +` DIL`H_(2)SO_(4)` togive a green solutiondue to THEFORMATION of `Cr_(2)(SO_(4))_(3)`. As wholeof `SO_(2)` gas reacts AWAY ,on passing the resulting gas throughlime water, it remainsclear.
88477.

A mixture of salts (Na_(2)SO_(3)+K_(2)Cr_(2)O_(7)) in a test tube is treated with dil. H_(2)SO_(4) and resulting gas is passed through lime-water. Which of the following observations is correct about this test

Answer»

Solution in test tube becomes green and lime-water turns milky
Solution in test tube is colourless and lime-water turns milky
Solution in test becomes green and lime-water REMAINS clear
Solution in test tube remains clear and lime-water also reamains clear.

Solution :`Na_(2)SO_(3)` with dil. `H_(2)SO_(4)` produces `SO_(2)` gas which turns `K_(2)Cr_(2)O_(7)` and lime water into green and milky, respectively.
`Na_(2)SO_(3)+H_(2)SO_(4)toNa_(2)SO_(4)+H_(2)O+SO_(2)uarr`
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+SO_(2)toK_(2)SO_(4)+Cr_(2)UNDERSET("green")((SO_(4)))_(3)+H_(2)O`
`Ca(OH)_(2)+SO_(2)tounderset("milky")(CaSO_(3))+H_(2)O`
88478.

A mixture of salt and water can be separated by

Answer»

Filtration
Decentation
Crystallisation
Kept LONG standing

Answer :C
88479.

A mixture of pure H_(2) and O_(2) can be stored indefinitely without any reaction. Name the catalyst which makes the reaction to occur with explosive violence.

Answer»
88480.

A mixture of pure AgCl and pure AgBr is foundto contain 60.94%Ag by mass. Whatare mass percentages of Cland Br in themixture ?(Ag = 108 , Cl = 35 . 5 Br = 80)

Answer»

Solution :Let us first calculate the weight ratio of AgCland AgBr, theirwts. being supposed to be x and y, g respectivelyin themixture. Apply POAC for AG atoms
AgCl + AgBr `to` Ag
`1 xx ` moles of AgCl + ` 1 xx ` molesAgBr = moles of Ag
`(x)/( 143.5)+(y)/(188) ` = moles of Ag.
`:.` wt. of Ag in the MIXTURE = `((x)/(143.5)+(y)/(188)) xx 108.g`
As GIVEN ,
`(((x)/(143.5)+(y)/(188))xx 108)/(x + y) = 0.6094`
`(x)/(y) = (0.035)/(0.1432)`
`:. % ` of AgCl `= ( x xx 100)/( x + y) = (0.035)/( 0 . 035 + 0.1432) xx 100 = 19.64`
and `%` of AgBr = 80.36
Thus,a 100-g MIXTURECONTAINS 19.64 g of AgCland 80.36 g ofAgBr.
Now calculate the amount of Cl in AgCland the amountof Br in AgBr
Wt. of Cl in 19.64 of AgCl = `(35 . 5)/( 143.5) xx 1964 = 4.85 g`
Wt. of Brin 80.36 g of AgBr `= (80)/(188) xx 80.36 = 34.19 g`
Thus 100 g of themixturecontains 4.85 g of Cl and 34.19 g of Br .
`:.`percentage of Cl = `4.85%`
and percentage of Br = `34.19%`
88481.

A mixture of P,S and T amines is separated by :

Answer»

HOFMANN METHOD
Hinsberg method
DISTILLATION
All

Answer :D
88482.

A mixture of potassium dichromate crystal and conc. H_(2)SO_(4) was added to each of the following four tubes. It was followed by strong heating. Identify the tubes in which the following changes will be observe. Support your answer with the help of chemical equations. (a) formation of violet vapours (b)formation of yellow precipitate (c) formation fo brown liquid(d) appearance of vinegar smell.

Answer»

SOLUTION :(a) Viloet vapour of `I_(2)` will appear in tube (i).
(b) Yellow precipitate of sulphur will apppear in tube (ii).
(c) BROWN liquid containing dissolved bromine will be noticed in tube (iv).
(d) Vinegar SMELL due to acetic acid `(CH_(3)COOH)` will be notice in tube (III).
88483.

A mixture of propyl iodide and ethyl iodide is subjected to Wurtz reaction. Which of the following hydrocarbons is not formed during the reaction ?

Answer»

PROPANE
BUTANE
PENTANE
HEXANE

ANSWER :A
88484.

A mixture of propene and methane is obtained by the cracking

Answer»

1-butene
2-butene
n-butane
Isobutane

Solution :`UNDERSET"n-Butane"(CH_3CH_2CH_2CH_3)OVERSET"CRACKING"to CH_4+CH_3-CH=CH_2`
88485.

A mixture of one volume of gas and two volumes of oxygen, on explosion form two volumes of CO_(2) and one volume of N_(2) under the identical conditions of temperature and pressure. Find the formula of the gas.

Answer»

SOLUTION :`(C_(2)N_(2))`
88486.

A mixture of nitrogen and water vapour is admitted to a flask which contains a solid drying agent. Immediately after admission, the pressure of the flask is 760 mm. After some hours the pressure reached a steady value of 745 mm. (a) Calculate the composition, in mole per cent, of the original mixture. (b) If the experiment is done at 20^(@)C and the drying agent increases in weight by 0.15 g, what is the volume of the flask ? (The volume occupied by the drying agent may be ignored.)

Answer»

Solution :(a) `p_(N_(2)) + p_(H_(2)O) = 760 MM`
`p_(N_(2)) = 745 mm`
`p_(H_(2)O) = 760-745 = 15 mm`.
MOLE % of `N_(2)` = pressure % of `N_(2)`
`= (745)/(760) xx 100 = 98.03%`.
`therefore` mole % of `H_(2)O = 100 - 98.03 = 1.975%`.
(b) Since the weight of drying agent increases by 0.15 g,
weight of `H_(2)O = 0.15 g`.
Mol. wt of `H_(2)O = 18`.
`therefore` mole of `H_(2)O = (0.15)/(18)`
`p_(H_(2)O) = 15 mm = (15)/(760)` atm.
Applying `PV = NRT` in the flask of volume V litres (say)
`(15)/(760) xx V = (0.15) xx 0.082 (273 + 20)`
`V = 10.28` litres.
88487.

A mixture of nitrogen and water vapours is admitted to falsk at 760 torr which contains a sufficient solid dryig agent, after long time the pressure reached a stedy value of 722 torr. If the experiment is done at 27^(@)C and drying agent increaes in weight by 0.9gm, what iws the volume of flask? Neglect any possible vapour pressure of drying agent and volume occupied by drying agent.

Answer»

443.34L
246.3L
12.315L
24.63L

Solution :Vapore pressure of water =760-722=38 torr
`n_(H_(2)O)=(0.9)/(18)=0.05`
`V=(nRT)/(P)=(0.05xx(0.0821)(300))/((38)/(760))=24.63L`
88488.

A mixtureof naphthalene and benzoic can beseparated by :

Answer»

chromatograhic
sublimation
fractional crystallisation
distillation

SOLUTION :N//A
88489.

A mixture of nitrogen and hydrogen in a proportion of 1 : 3 by volume was subjected to a pressure of 30 atm and a temperature of 723 K. After equilibrium was established, and cooled, the analysis indicated that the mixture contained 6% of ammonia by volume. Calculate K_p

Answer»

SOLUTION :`4.85 XX 10^(-5) atm^(-2)`
88490.

A mixture of NH_(3)( g) and N_(2) H_(4)(g) is placed in a sealed vessel at 27^(@)C . The total pressure of the gas is 0.5 atm. The vessel is heated to 927^(@)C where the following decomposition reaction take place : N_(2) H_(4) rarr N_(2)(g) + 2H_(2)(g) 2NH_(3)(g) rarr N_(2)(g) + 3H_(2) ( g) The pressure in the vessel at this stage becomes 4.5 atm. The mole percent of NH_(3)(g) in the original mixture was :

Answer»

0.25
0.6
0.75
0.8

Answer :C
88491.

A mixture of NaI and NcCl gave with sulphuric acid, Na_(2)SO_(4) equal in mass to the original mixture taken. Find the percentage composition of the mixture.

Answer»


ANSWER :0.513:1
88492.

A mixture of NaCl and K_(2)Cr_(2)O_(7) is heated with conc. H_(2)SO_(4) ,deep red vapours and formed .Which of the following statements is false?

Answer»

The vapours contain `CrO_(2)Cl_(2)` only
The vapours give a yellow solution with NaOH
The vaopurs when passed into LEAD acetate in acetic give a yellow precipitate.
The vapours contain `CrO_(2)Cl_(2)` and `Cl_(2)`

Solution :`4NaCl+K_(2)Cr_(2)O_(7)+3H_(2)SO_(4)to2NaS_(2)O_(4)+K_(2)SO_(4)+2CrO_(2)Cl_(2)+3H_(2)O`
CHROMYL chloride test is a C.T for `Ci^(-)`
`CrO_(2)Cl_(2)+underset(("yellow"))(4NaOH)toNa_(2)Cro_(4)+2H_(2)O+2NaCl`
`Na_(2)CrO_(4)+underset("yellow ppt")((CH_(3)CrO)_(2))pbtopbCro_(4)+2CH_(3)COONa`
88493.

A mixtureof Nal and NaCl . whenheated with H_(2)SO_(4) , produced the sameweightof sodium sulphate as thatofthe originalmixture . Calculate percentage of Nal in the mixture .

Answer»


ANSWER :`28 . 85%`
88494.

A mixture of N_(2)and H_(2) in the molare ratio 1:3 attains equlibrium when 50% of mixture has reacted. If P is the total pressue of the mixture, the partial pressure of NH_(3) formed is P//y. The value of y is

Answer»


Solution :`N_(2)+3H_(2)hArr2NH_(3)`
`{:("Initial mole",1,3,0),("At eq.",1-x,3-3x,2x):}`
`therefore` out of 4 mole of MIXTURE, 2 mole have REACTED and hence 2 mole are LEFT.
`therefore1-x+3-3x=2`
or `4x=2or x=0.5`
`therefore"Total mole atequlibrium"=1-x+3-3x+2x=4-2x=4-2xx0.5=3`
No. of mole of `NH_(3)` at equlibrium `2x=2xx0.5=1`
`thereforeP_(NH_(3))=1/3xxP=P/3thereforey=3`
88495.

A mixtureof N_(2) and H_(2) is causedto react in a closedd container to form NH_(3) . Thereaction ceases before either reactant has been totally consumed . At thisstage, 2 . 0 moleseach of N_(2), H_(2) and NH_(3) are present . The moles of N_(2) and H_(2) present originally wererespectively.

Answer»

4 and 4 MOLES
3 and 5 moles
3 and 4 moles
4 and 5 moles

Answer :B
88496.

A mixture of N_2and Ne contains equal moles of each gas and has a total mass of10.0 g. What is the density of this gas mixture at 500 K and 10 atm?

Answer»

SOLUTION :5.88 g/L
88497.

A mixture of N_2 and H_2 is caused to react in a closed container to form NH_3. The reaction decreases before any of the reactant has been totally consumed. At this stage, 2 moles each of N_2, H_2 and NH_3 are present. Then the weight of N_2 and H_2 present originally were respectively

Answer»

112 G and 8 g
84 g and 10 g
84 g and 8 g
122 g and 10 g

Answer :B
88498.

A mixture of methylamine and dimethylamine is given to you. The reagents used to separate the compenents of the mixture are

Answer»

`CHCl_(3)` and HCl
`C_(6)H_(5)SO_(2)` and KOH
`C_(6)H_(5)SO_(2)` and HCl
`CHCl_(3)` and KOH

Solution :(2) A mixture of methylamine (`1^(@)` amine) and dimethylamine (`2^(@)` amine) can be separated with the help of `C_(6)H_(5)SO_(2)Cl` and KOH (Hinsberg.s method).
Methylamine will form
N-methylbenzenesulphonamide which is SOLUBLE in KOH.
Dimethylamine will form N,N-dimethylbenzene-sulphonamide which is INSOLUBLE in KOH.
88499.

A mixture of methyl amine and dimethyl amine is given to you. The regents used to separate the components of the mixture are :

Answer»

`CHCl_(3) and HCl`
`C_(6)H_(5)SO_(2)Cl and KOH`
`C_(6)H_(5)SO_(2)Cl and HCl`
`CHCl_(3) and KOH.`

ANSWER :B
88500.

A mixture of methanol vapours and air is passed over heated copper. The products are

Answer»

CARBON monoxide and hydrogen
formaldehyde and `H_2` gas .
FORMIC ACID and WATER vapour
carbon monoxide and water vapour

Answer :B