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89251.

A group of atoms can function as a ligand only when:

Answer»

It is a small molecule
It has an unshared ELECTRON pair
It is a negatively CHARGED ion
It is a POSITIVELY charged ion

Answer :B
89252.

A is

Answer»

an alkyne
an alkane
an ALKENE
an alkene (or) a diene

Answer :D
89253.

A group of atoms can function as a ligand only when

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it is a small molecule
it has an UNSHARED electron pair
it is a NEGATIVELY CHARGED ion
it is a POSITIVELY charged ion.

Answer :B
89254.

(A) is:

Answer»

a.
b.
c.
d.`No reaction`

SOLUTION :`SeO_(2)//AcOH` SELECTIVELY hydroxylates ALLYLIC POSITION. `(3^(@) gt 2^(@) gt 1^(@) "allylic")`.

So the answer is `(b)`.
89255.

A group of acidic oxide is

Answer»

`CrO_(3),Mn_(2)O_(7)`
`ZNO,Al_(2)O_(3)`
`CaO,ZnO`
`Na_(2)O, Al_(2)O_(3)`

Solution :`CrO_(3) and Mn_(2)O_(7)` are acidic oxide since they react with water to form acid.
`CrO_(3)+H_(2)Orarrunderset("acid")underset("Chromic")(H_(2)CrO_(4)),Mn_(2)O_(7)+H_(2)Orarrunderset("acid")underset("Permagnic")(2HMnO_(4))`
89256.

A group closely related compounds which can be expressed by a general formula and in which two consecutive members differ by 14 in their molecular masses is called:

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a HOMOLOGOUS SERIES
a homogeneous series
a heterogenous series
an electrochemical series.

ANSWER :A
89257.

A is :

Answer»




SOLUTION :N//A
89258.

A group 14 elements is oxidised to form corresponding oxide which is gaseous in nature , when dissolved in water pH of the water decrease further addition of group 2 hydroxides leads to precipitation. This oxide can be

Answer»

`GeO_(2)`
`CO`
`CO_(2)`
`SnO_(2)`

Solution :`CO_(2)` forms carbonic ACID `H_(2)CO_(3)`, when dissolved in WATER, CO is neutral, whereas other TWO `GeO_(2) and SnO_(2)` are SOLIDS.
89259.

(A) Group 18 elements are called noble gases(R) group 18 elements form only very few compounds

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Both (A) and (R) are true and (R) is the CORRECT explanation of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :A
89260.

A group 14 element is to be converted into ntype semiconductor by doping it with a suitable impurity. To which group should this impurity belong ?

Answer»

Solution :To MAKE n-type semiconductors, group-14 ELEMENT MUST be doped with group-15 elements.
89261.

(A): Iron pyrate is used in the extraction of iron releases pollutants like sulphurdioxide (R) : Ores which are abundent with non metals produce poluting gases

Answer»

Both (A) and (R) are TRUE and (R) is the CORRECT explanation of (A)
Both (A) and (R) are true and (R) is not the correct explanationof (A)
(A) is true but (R) is FALSE
Both (A) and (R) are false

ANSWER :B
89262.

A group 14 element is to be converted into n-type semiconductor by doping it with a suitable impurity. To which group should this impurity belong?

Answer»

SOLUTION :GROUP 15, group 14 elements doppped with electron rich group 15 elements make n TYPE SEMICONDUCTORS.
89263.

(A) Iron metal is refined in blast furnace (R) Blast furnace is used to perform roasting

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Both (A) and (R) are TRUE and (R) is the correct explanation of (A)
Both (A) and (R) are true and (R) is not the correct EXPLANATIONOF (A)
(A) is true but (R) is FALSE
Both (A) and (R) are false

Answer :D
89264.

(A) Ionic solids conduct electricity in solid state. (R) Their conduction is due to the presence of electrons

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Both (A) and (R) are TRUE and (R) is the CORRECT explanation of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :D
89265.

A :Grignard's reagent is prepared in the presence of ether .R : Grignard's reagent is soluble and stable in ether.

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If both ASSERTION & Reason are TRUE and the reason is the correct explanation of the assertion, then mark (1)
If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
If Assertion is true STATEMENT but Reason is false , then mark (3)
If both Assertion and Reason are false statements , then mark (4)

Answer :A
89266.

(A) Ionic solids are characterized by high melting and boiling point. (R) Ionic solids have coulombic forces of attraction between their ions.

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Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :A
89267.

(A) : lodine is the only halogen that is naturally available in positive oxidation states (R): Iodine is slightly electropositive among halogens .

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

Answer :A
89268.

A grignard reagent is prepared by reacting magnesium:

Answer»

METHYL amine
Diethyl ether
Ethyl iodide
Ethyl alcohol

Answer :C
89269.

(A) Iodine oxides are more stable than chlorine and bromine oxides (R ) Iodine is the solid halogen ,but chlorine and bromine are gaseous and liquid halogens

Answer»

Both (A) and (R ) are true and (R ) is the correct explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

ANSWER :B
89270.

A greenish yellow gas reacts withh an alkali metal hydroxide to form a halate, which can be used in:

Answer»

`Br_(2),KBrO_(3)`<BR>`Cl_(2),KClO_(3)`
`I_(2),NalO_(3)`
`Cl_(2),NaClO_(3)`

ANSWER :B
89271.

(A) :Grignard synthesis is always carried out in ethereal solution. (R) H_2Ois polar solvent .

Answer»

Both A & R are TRUE, R is the CORRECT explanation of A
Both A & R are true, R is not correct explanation of A
A is true, R is false
A is false, R is true

Answer :B
89272.

(A) Iodine is least basic whereas fluorine is most basic , among halogens (R ) The reactivity of halogens increases from fluorine to iodine

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

Answer :D
89273.

(A) Iodine does not react with water (R ) Reaction of iodine with water is non spontaneous

Answer»

Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

ANSWER :A
89274.

A greenishyellowgas (B) is obtainedwhena mixtureof a blackpowder (A), NaCl andand concH_(2)SO_(4)is heated. When gas (B)is passedthrough liquorammonia , N_(2) gas is liberated . Whenone fo thecompounds obtainedby passing the gas (B) throughhot KOHsolutionis heated with (A), O_(2)is obtained . Identify (A) &(B) and writethe reactions involved .

Answer»

SOLUTION :A : `MnO_(2), B: Cl_(2)`
89275.

(A) Iodine is dissolved well in aqueous KI solution (R ) Iodine forms a complex tri -iodide ion in aqueous KI solution

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Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

Answer :A
89276.

A greenish yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fire works safety matches. The gas and halate respectively are

Answer»

`Br_(2)KBrO_(3)`
`Cl_(2),KClO_(3)`
`l_(2),NaIO_(3)`
`Cl_(2),NaClO_(3)`

Solution :`3Cl_(2)+6KOH to KClO_(3)+5KCl+3H_(2)O`
`KClO_(3)` is used in FIRE works and safety MATCHES and `Cl_(2)` is greenish yellow gas.
89277.

(A) Insulators are generally good conductors(R) Insulators have free electrons

Answer»

Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :D
89278.

A greenish yellow gas ‘X’ is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate solution gives a white precipitate. The saturated aqueous solution also dissolves magnesium ribbon with the evolution of a colourless gas ‘Y’. Identify gases ‘X’ and ‘Y’.

Answer»

Solution :`UNDERSET(X)(Cl_(2))+H_(2)OrarrHCl+HClO`
`AgNO_(3)+HClrarrunderset(("whiteppt."))(AgCl)+HNO_(3)`
`Mg+2HClrarrunderset(("Y"))(MgCl_(2))+H_(2)`
89279.

(A): lodine appears in violet colour. (R): Iodine absorbsviolet part of electro magnetic radiation .

Answer»

Both (A) and (R ) are true and (R ) is the CORRECT explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

Answer :C
89280.

A greenish-yellow coloured gas is liberated on heating a mixture of "_______________"

Answer»

`NACL + H_(2) SO_(4)`
`Kl + HCl`
`MnO_(2) + HCl`
`KBr + HCl`

Solution :`MnO_(2) + 4HCl RARR MnCl_(2) + Cl_(2) + 2H_(2)O`
89281.

(A): Iodine displaces bromine from KBrO_3 (R): Iodine is strong oxidizing agent than bromine.

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

ANSWER :C
89282.

A greenish-yellow coloured gas is liberated on heating a mixture of two substances which are:

Answer»

KBR + HCL
KI + HCl
`MnO_2 + HCl`
`NACL + H_2SO_4`

ANSWER :C
89283.

(a)Indicate whether the following are S_(N^(1)),S_(N^(2)),E_(1) " or "E_(2) reactions. (i) CH_(3)CH_(2)CH_(2)CI+I^(-) to (ii) (CH_(3))_(3) CBr+CN^(-)(alc.) to (iii) CH_(3)CH(Br)CH_(3) +OH^(-) (alc.) to(iv) (CH_(3))_(3) C-Br+H_(2)O to (b) Give the decreasing order of reactivity of the alkaline hydrolysis of the following alkyl halides toward (A)S_(N^(1))(B) S_(N^(2))(C) in pressure of AgNO_(3). (i) (CH_(3))_(2)C(Br) -C_(2)H_(5) (ii)C_(5)H_(11)Br(iii) C_(2)H_(5)CH(Br)C_(2)H_(5) (c) Give the decreasing order reactivity of the alkaline hydrolysis of hte followinghalides towards S_(N^(1)) (i) MeCI (ii) PhCH_(2)CI(ii)Ph_(2)CHCI(iii)Ph_(3)C-CI. (d) Determine the relative S_(N^(2)) reactivity with NaCI in aprotic DMSO of the following alkyl halides : (A) (i) CH_(3)CHCICH_(2)CH_(3)(ii)CH_(3)CHBrCH_(2)CH_(3) (iii) CH_(3)CHICH_(2)CH_(3)(B) (i) CH_(3)CH(CH_(3))CH_(2)CH_(2)I(ii) CH_(3)CH(CH_(3))CHICH_(3)(iii) CH_(3)CI(CH_(3))CH_(2)CH_(3)(e) Arrange the following in the order of decreasing nucleophilic character: H_(2)O,^(-)OH,CH_(3)O^(-), CH_(3)COO^(-)(f) Arrange thefollowing in the decreasing order as leaving group in S_(N) reaction: CH_(3)COO^(-),C_(6)H_(5)O^(-), C_(6)H_(5)SO_(3)^(-), CH_(3)O^(-)

Answer»

Solution :`(a) (i) CH_(3)CH_(2)CH_(2)-I " is" S_(N^(2)) " reaction "(1^(@)"halide and " I^(-)` is a good nucleophile and poor base.
`(II) CH_(3)CH=CH_(2) " is " E_(2)` reaction, less polar SOLVENT favours `E_(2)`.
`(iv) (CH_(3))_(3)C-OH " is "S_(N^(1))` reaction as `H_(2)O` is not basic enough to remove a proton to give ELIMINATION reaction.
`(b) (A) (i) gt (iii) (3^(@) gt 2^(@) gt 1^(@)" alkyl halides ")S_(N^(1))`.
`(B) (ii) gt (iii) gt (i) (1^(@) gt 2^(@) gt 3^(@) " alkyl halides")S_(N^(2)).`
`(C) (i) gt (iii) gt (ii) : " Heavy ions such as " Ag^(+)" or " Pb^(2+) " catalyse " S_(N^(1))`.
`(C) (iv) Ph_(3) C-CI gt (iii) Ph_(2) CH-CI gt (ii) PhCH_(2) -CI gt (i) NeCI.`
`(d) (A) (iii) gt (ii) gt (i) ("Group leaving ability is " I^(-) gt Br^(-) gt CI^(-))`
`(B) (i) gt (ii) gt (iii) ("steric factor MAKES the reactivity " 1^(@) gt2^(@) gt 3^(@))`.
(e) When the NUCLEOPHILIC centre is same . The nucleophilicity is same as basic character.
Acidic character :`H_(3)O^(+) gt CH_(3)COOHgt CH_(3)OH gt H_(2)O.`
Basicity and nucleophilicity : `H_(2)O lt CH_(3)COO^(-) lt CH_(3)O^(-) lt OH^(-)`.
(f) Weaker thebase or stronger the acid, better is the leaving group.
Acidic character : `C_(6) H_(5)SO_(3)H gt CH_(3)COOH gt C_(6)H_(5)OH gt CH_(3) OH.`
89284.

A green ore (A) of a metal present as a double /mixed compound is treated with HCl and then H_(2)S is passed in the solution. A back precipitate (B) is obtained, that is insoluble in yellow ammonium sulphide. The precipitate is dissolved in HNO_(3) and then excess of NH_(4)OH is added. The solution becomes coloured but this colour is discharged upon addition of KCN in excess due to the formation of compound (C). The solution of (A) in H_(2)O liberates a colourless and odourless gas on reaction with dilute H_(2)SO_(4) and solution of (A) gives white precipitate on addition of BaCl_(2) solution. The procedure used to estimate the metal ion of ore (A) gravimetrically, is ?

Answer»

Treatement of ore with excess KCN
Treatement of solution of ore with AG METAL.
Treatement of ore with excessammonia
Treatement of ore with excess KSCN.

Answer :D
89285.

A green ore (A) of a metal present as a double /mixed compound is treated with HCl and then H_(2)S is passed in the solution. A back precipitate (B) is obtained, that is insoluble in yellow ammonium sulphide. The precipitate is dissolved in HNO_(3) and then excess of NH_(4)OH is added. The solution becomes coloured but this colour is discharged upon addition of KCN in excess due to the formation of compound (C). The solution of (A) in H_(2)O liberates a colourless and odourless gas on reaction with dilute H_(2)SO_(4) and solution of (A) gives white precipitate on addition of BaCl_(2) solution. After dissolving the precipitate in HNO_(3) aqueous K_(4)[Fe(CN)_(6)] is added and a precipitate is formed.

Answer»

It is a reddish brown precipitate of `Cu_(2)[Fe(CN)_(6)]`.
It is a reddish brown precipitate of `K_(2)Cu_(3)[Fe(CN)_(6)]_(2)`
It is a chocolate brown precipitate of `Cu_(2)[Fe(CN)_(6)]`.
It is a chocolate brown precipitate of `K_(2)Cu_(3)[Fe(CN)_(6)]_(2)`

ANSWER :C
89286.

(A) Inductive and electromeric effects require polar nature in the molecule. (R) Polar nature in inductive effect isa must but not necessarily in electromeric effect.

Answer»

If both (A) and(R) are CORRECT and (R) is the correct EXPLANATION of (A).
If both (A) and (R) are correct but (R) is not the correct explanation of (A).
If (A) is correct but (R) is INCORRECT.
IF (A) is incorrect but (R) is correct.

Answer :D
89287.

A green ore (A) of a metal present as a double /mixed compound is treated with HCl and then H_(2)S is passed in the solution. A back precipitate (B) is obtained, that is insoluble in yellow ammonium sulphide. The precipitate is dissolved in HNO_(3) and then excess of NH_(4)OH is added. The solution becomes coloured but this colour is discharged upon addition of KCN in excess due to the formation of compound (C). The solution of (A) in H_(2)O liberates a colourless and odourless gas on reaction with dilute H_(2)SO_(4) and solution of (A) gives white precipitate on addition of BaCl_(2) solution. The green ore (A) is ?

Answer»

`CuSO_(4). Cu(OH)_(2)`
`PbCO_(3).PB(OH)_(2)`
`PbSO_(4).Pb(OH)^(2)`
` CuCO_(3).Cu(OH)_(2)`

Answer :D
89288.

(A) In vapour state S_(2) molecule is paramagnetic like O_(2) (R ) S_(2) molecule in vapour state contains two unpaired electrons in bonding molecular orbitals

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT explanation of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R )are false

ANSWER :C
89289.

A green mass isformedin the charcoulcavity test when a colourless salt (X) is fussed withchbalt mitrate (X) may contain

Answer»

Aluminium
copper
Barium
Zine

Solution :Follow cobalt nitrate test
`ZnSO_(4) + Na_(2)CO_(3) RARR ZnCO_(3) + NASO_(4)`
`ZnCO_(3) rarr ZnO + CO_(2)`
`2Co(NO_(3))_(2) rarr 2CoO + 4NO_(2) + O_(2)`
`CoO + ZnO rarrunderset((Green))(CoZnO_(2))`
89290.

(a) In the titration of FeSO_(4) with KMnO_(4) in the acidic medium, why is dil. H_(2)SO_(4) used instead of dil. HCI ? (b) Give reasons : (i) Among transition metals, the highest oxidation state is exhibited in oxoanions of a metal. (ii) Ce^(4+) is used as an oxidising agent in volumetric analysis. (iii) Transition metals form a number of interstitial compounds. (iv) Zn^(2+) salts are white while Cu^(2+) salts are blue.

Answer»

Solution :(a) HCl gets oxidised to `Cl_(2)` by `KMnO_(4)` whereas `H_(2)SO_(4)` does not.
(b) (i) METAL oxoanion may be represented as `MO_(x)^(y-)`
where y ranges between 1 to 2 and x ranges between 2 to 4.
On calculation of oxidation state of the metal in oxoanion, we find that it is the maximum.
(ii) `Ce^(4+)` can gain an electron and, therefore, it acts as an oxidising AGENT.
`Ce^(4+)+e^(-)toCe^(3+)`
(iii) These elements have VOIDS in which small atoms like C, B can fit TIGHTLY to give interstitial compounds.
(iv) `Zn^(2+)` does not have vacant d-orbitals or unpaired electrons in d-orbital. `Cu^(2+)` has ONE unpaired electron and vacant d-orbitals.
89291.

A green chromium compound (B) which on acidification gives a orange coloured compound

Answer»

Solution :`A : FeCr_(2) O_(4) "" B: Na_(2)Cr_(4)"" C: Na_(2)Cr_(2) O_(7)`
`4FeCr_(2) O_(4) + 8Na_(2) CO_(3) + 7O_(2) to8Na CrO_(4) + 2Fe_(2) O_(3) + 8CO_(2)`
`(A)"" (B )`
`Na_(2) CrO_(4)+ H_(2) SO_(4) to Na_(2) Cr_(2) O_(7) + Na_(2) SO_(4) + H_(2) O`
89292.

A green mass is formed in the charcoal cavity test when a colourless salt (X) is fused with cobalt nitrate. X contains

Answer»

`Al^(3+)`
`CU^(2+)`
`Ba^(2+)`
`Zn^(2+)`

Solution :Green COLOUR FORMED is due to ZnO.Co O
89293.

(A): In the smelting of copper pyrites in blast furnace, Cu_2 S formed but not FeS. (R) : Cu has greater affinity to 'S' than to 'O' where as Fe has greater affinity to 'O' than to 'S'.

Answer»

Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanationof (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :A
89294.

A green chromium compound (C). Identify A, B, C. Write equations for reactions.

Answer»

SOLUTION :`A : FeCr_(2) O_(4) "" B: Na_(2)Cr_(4)"" C: Na_(2)Cr_(2) O_(7)`
`4FeCr_(2) O_(4) + 8Na_(2) CO_(3) + 7O_(2) to8Na CrO_(4) + 2Fe_(2) O_(3) + 8CO_(2)`
`(A)"" (B )`
`Na_(2) CrO_(4)+ H_(2) SO_(4) to Na_(2) Cr_(2) O_(7) + Na_(2) SO_(4) + H_(2) O`
89295.

(A): In the smelting of copper pyrites in blast furace, Cu_(2)S formed but not FeS. (R): Ca has greater affinity to 'S than to where as fe has greater affinity to than to's

Answer»

A and are TRUE, R explains A
A and RARE true, Reinot EXPLAIN A
A is true R is false
A is false R is true

Answer :A
89296.

A grating has 5.7 xx 10^(3) lines per cm. If X-rays of wavelength 546 nm are incident on the grating, find the angle of reflection for the first order diffraction maximum.

Answer»

SOLUTION :`9.95^(@)`
89297.

(A): Graphite is an example of neutral refractory material used in furnaces (R) : Chemically graphite is most stable allotrope of carbon

Answer»

Both A & R are TRUE, R is the CORRECT explanation of A
Both A & R are true, R is not correct explanation of A
A is true, R is false
A is false, R is true

Answer :C
89298.

(A) : In the separation of inert gases, by Dewar's method He gas does not absorbed on activated charcoal (R ) : Among noble gases helium has less atomic size The correct answer is

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A) and (R )are true and (R ) is not correct explanation of (A)
(A) is true but (R ) is FALSE
(A) is false but (R ) is true

Answer :A
89299.

A green chromium compound (A) on fusion with alkali gives a yellow

Answer»

SOLUTION :`A : FeCr_(2) O_(4) "" B: Na_(2)Cr_(4)"" C: Na_(2)Cr_(2) O_(7)`
`4FeCr_(2) O_(4) + 8Na_(2) CO_(3) + 7O_(2) to8Na CrO_(4) + 2Fe_(2) O_(3) + 8CO_(2)`
`(A)"" (B )`
`Na_(2) CrO_(4)+ H_(2) SO_(4) to Na_(2) Cr_(2) O_(7) + Na_(2) SO_(4) + H_(2) O`
89300.

(a) In the preparation of p - bromo acetanlllde from acetanilide. (i) Name the regents used . (ii) Write the equation for the reaction involved . (iii) What is the colour of the product obtained .

Answer»

Solution :(i) Bromine glacial acetic acid

Middle oil FRACTION is COOLED, naphthalene crystallizes. It is removed crude phenol is washed with dilute `H_(2) SO_(4)` and then treated with NAOHSOLUTION .
(ii) Sodium phenate formed, in the aqueous layer is separdted, acidified lo REGENERATE (get) phenol.
`C_(6)H_(5)OH+NaOH rarrC_(6)H_(5)ONa+H_(2)O`
`C_(6)H_(6)ONa+HCI rarr C_(6)H_(5)OH+NaCI`
( For acidification `CO_(2)` or `H_(2)SO_(4)` can be used )
(III) Orange.