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12051.

Two electrolytic cells, one containing acidified ferrous sulphate and another acidified ferric chloride,are in series. The ratio of masses of Iron deposited at the cathode in the two cells will be

Answer»

`3:1`
`2:1`
`1:1`
`3:2`

ANSWER :D
Discussion
12052.

Write down the products in the following reactions:

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SOLUTION :
Discussion
12053.

Which of the following is not a filler ?

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`TiO_(2)`
`BaSO_(4)`
`CaSO_(4)`
`SiO_(2)`

Solution :`CaSO_(4)`
Discussion
12054.

Which of the following compound may be optical active ?

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`Co(en)_(2)Cl_(2)`
`[Rh CL Br NH_(3) PH_(3)]^(-)`
`CU(en)_(2)Cl_(2)`
All of these

Answer :A
Discussion
12055.

Vander Waal's equation of state is obeyed by real gases. For n molesof a real gas, the expression will be

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`((P)/(N)+(NA)/(V^(2)))((V)/(n-b))=RT`
`(P+(a)/(V^(2)))(V-b)=NRT`
`(P+(na)/(V^(2)))(nV-b)=nRT`
`(P+(n^(2)a)/(V^(2)))(V-nb)=nRT`

Solution :n/a
Discussion
12056.

When diethyl ehter is treated with excess of CI_(2) in the presence of sunlight, the product formed is :

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`CH_3CHCI-O-CH_2CH_3`
`CH_3CHCI-O-CHCICH_3`
`CCI_3CCI_2-O-CCI_2CCI_3`
`CH_3CCI_2-O-CHCICH_3`

SOLUTION :NA
Discussion
12057.

Which of the following are examples of sparingly soluble salt electrodes ?

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`OH_((aq))^(-)|O_(2(g)), PT`
`Cl_((aq))^(-)|Hg_(2)Cl_(2(s)), Pt`
`Cd_((aq))^(2+)|Cd_((s))`
`SO_(4(aq))^(2-), Ag_(2)SO_(4(s))|Ag_((s))`

Solution :`Ag_2NO_4` is sparingly soluble SALT.
Discussion
12058.

Which of the following is a mixed anhydride

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NO
`NO_(2)`
`N_(2)O_(5)`
`N_(2)O`

Solution :`UNDERSET("mixed acid anhydride")(2overset(+4)(N)O_(2) +H_(2)O)to HNO_(2)+H overset(+5)(N)O_(3)`
Discussion
12059.

Which of the following is an invalid vant Hoff factorin thegiven process?

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`0.6`
`0.8`
`0.5`
`0.4`

ANSWER :D
Discussion
12060.

Which of the following reactions are dispro-portionation reactions ? (i) Cu^(+) rarr Cu^(2+) + Cu (ii) 3MnO_(4)^(2-) + 4H^(+) rarr 2MnO_(4)^(-) + 2H_(2)O (iii) 2KMnO_(4) rarr K_(2)MnO_(4) + MnO_(2) + O_2 (iv) 2MnO_(4)^(-) + 3Mn^(2+) + 2H_(2)O rarr 5MnO_(2) + 4H^+

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(i),(ii)
(i),(ii),(iii)
(ii),(iii),(iv)
(i),(iv)

SOLUTION :`(i) Cu^(+)` is oxidised to `Cu^(2+)` and REDUCED to Cu.
In (ii), `MnO_(4)^(2-)` ions are oxidised to `MnO_(4)^(-)` and reduced to `MnO_(2)`.
Discussion
12061.

Which of the following are secondary pollutants?

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CO, `CO_(2), SO_(2)`, HYDROCARBON
`SO_(3), NO_(2), HNO_(3), H_(2)SO_(4)`
Both (A) and (B)
NONE of these

Answer :B
Discussion
12062.

Which of the following can act s Lowery-Bronsted and well as base?

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`HCI`<BR>`SO_4^(2-)`
`HPO_4^(2-)`
`Br^-`

ANSWER :C
Discussion
12063.

Which is not an application of adsorption?

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Purification of WATER by its exchange
To CREATE vacuum
CHROMATOGRAPHIC ANALYSIS
HUMIDITY control

Answer :A
Discussion
12064.

The science of using microorganisms for the beneficial effects in industries is called:

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Biotechnology
Genetic engineering
Enzymology
Microbiology

Answer :B
Discussion
12065.

Which of the following is an anaesthetic ?

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`C_(2)H_(4)`
`CHCl_(3)`
`CH_(3)Cl`
`C_(2)H_(5)OH`

Answer :2
Discussion
12066.

What is Z given reaction ?

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ANSWER :C
Discussion
12067.

Which drugs are used in treatment of stress, mild and serve mental diseases ?

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Analgesics
TRANQUILIZERS 
ANTIMICROBIALS 
ANTACIDS 

SOLUTION :Tranquilizers
Discussion
12068.

We mix equal volume of two aqueous solution.Match the following : {:("Column-I","Column-II"),((A)"0.2 M KOH+ 0.5 M HCOOH", (p)0.7),((B)0.1 M NaCl+0.1 M NaNO_3,(q)between 1 "to "7),((C )0.1 M NH_4Cl+0.1 M NaOH,(r)7),((D)0.5 M HCl+0.1 M NH_4OH,(s)"greater than" 7),([log_10 2=0.3],(t)"less than 7"):}

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Solution :(A)acidic buffer will form(B)both are salt of SASB( C )WEAK base `NH_4OH` will form(D)remain STRONG acid solution
Discussion
12069.

Which among following statements are correct?

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Energy needed for homolytic bond fission is less than that requried for the hetroytic bond fission
Homolytic bond fission gives NEUTRAL speciec which is paramagnetic for the
Homolytic bond fission TAKES PLACE in non polar solvents
Cation and anion is produced by heterolytic bond fission

Solution :N/A
Discussion
12070.

When KOH solution is added to the potassum dicromate solution, then solution become yellow in colour. Due to….

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Conversion of CHROMATE ION to the dichromate ions
Conversion of dichromate ion to the chromate ions
Oxidation state of cromium become +4 from +6
Oxidation state of cromium BECOMES +6 from +4

Answer :B
Discussion
12071.

Which of the following compounds shows tautomerism?

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`NH_(2)-OVERSET(O)overset(||)(C)-NH_(2)`
`NH_(2)-overset(S)overset(||)(C)-NH_(2)`

`CH_(3)-overset(O)overset(||)(C)-CH_(3)`

ANSWER :A::B::C::D
Discussion
12072.

Why are the elements of Group - 18 known as noble gases?

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Solution :The elements of GROUP of 18 have their valence SHELL ORBITALS completely FILLED. As a result, they react with only a few elements (oxygen and fluorine) only under certain conditions. Therefore, they are called noble gases.
Discussion
12073.

Which of the following molecule has non-superimposible mirror images ?

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ANSWER :C
Discussion
12074.

When (CH_(3))_(3)CNH_(3)^(+)Cl^(-) is heated, product is

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`(CH_(3))_(3)C Cl, NH_(4)Cl`
`(CH_(3))_(2)C=CH_(2), NH_(4)Cl`
`(CH_(3))_(3)CNH_(2), HCl`
None of these.

Answer :B
Discussion
12075.

Which of the following set of elements are Ferromagnetic in nature

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ZN, CD and Hg
Cu, Ag and AU
Fe, Co and Ni
Sc, TI and U

Answer :C
Discussion
12076.

The zeolites have shape selectivity depending on

Answer»

ATOMIC STRUCTURE
PORE structure
Molecular structure
None

ANSWER :B
Discussion
12077.

Which of the following has see saw geometry

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`SF _(6)`
`SeF_(4)`
`Se _(2) Cl _(2)`
`SCl_(2)`

ANSWER :B
Discussion
12078.

Which of the following statements is not correct for fibres?

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Fibres possess HIGH tensile strength and high MODULUS.
Fibres impart crystalline nature.
Characteristic FEATURES of fibres are due to strong INTERMOLECULAR forces like hydrogen bonding.
All are correct

Solution :All the given statements about fibres are correct.
Discussion
12079.

The volume of a gas decreases from 500 c c to 300 c c when a sample of gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is

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`-2.16 J`
`12.156 J`
`2.16 J`
`101.3 J`

Solution :Here: Change in
Volume (V) = 500 - 300 = 200cc = 0.2 litre,
PRESSURE (P) = 0.6 atm and HEAT LIBERATED (q) = 10 J
Work done (W) = `PDeltaV=(0.2xx0.6)=0.12` litre-atm
But 1 litre - atm = 101.3 J.
hence `W=0.12xx101.3=12.156J`.We also know that heat is liberated, therefore it would be negative. Thus change in `DeltaE=q+W=-10+12.16=2.16J`.
Discussion
12080.

Which is an acyclic compound:

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Methane
Benzene
Pyrrole
Cyclobutane

Answer :A
Discussion
12081.

What is tincture of iodine and what is it used for ?

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Solution :It is the solution of 2-3% ALCOHOL in water. IODOFORM is USED as an antiseptic for WOUNDS.
Discussion
12082.

Which element is present in pitchblende :

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U
Ce
Ba
Mg

Answer :A
Discussion
12083.

The strength order of pi bond is

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2p-3pgt 2p-3d GT 2p-3p gt 3p-3p
2p-2plt2p-3d lt2p-3plt 3p-3p
2p-2p lt2p-3d lt2p-3p gt 3p-3p
2p-2p lt2p-3d gt2p-3p lt3p-3p

Answer :1
Discussion
12084.

What is the standard cell potential E^(@) for an electrochemical cell in which the following reaction takes place spontaneously ? Cl_(1) (g)+ 2Br ^(-) to Br_(2) (aq) +2Cl^(-) , Delta G^(@)=-50.6kJ

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`1.2V`
`0.53V`
`0.26 V`
`-0.53V`

SOLUTION :`DeltaG^(@)=-nFE^(@) . E^(@) =(-DeltaG^(@))/(NF).`
`E^(@) =(-(-50.61J))/(2xx96500xx10^(-3))=0.26V`
Discussion
12085.

What happen's to the solubility of gas in liquid with the increase in temperature? Give reason.

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Solution :Dissolution of GAS in a liquid is an EXOTHERMIC process and HENCE on INCREASING TEMPERATURE, solubility decreases.
Discussion
12086.

Which of the following reactions has downward slope in the Elligham diagram ?

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`(4)/(3)Al+O_(2) to (2)/(3)Al_(2)O_(3)`
`2C+O_(2) to 2CO`
`2Zn +O_(2) to 2ZnO`
`2CO+O_(2) to 2CO_(2)`

ANSWER :B
Discussion
12087.

Which of the following compounds on boiling with alkaline KMnO_(4) and subsequent acidification will not give Benzoic acid?

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anisole
toluene
benzyl alcohol
acetophenone

Solution :
Discussion
12088.

The units of cell constant are:ohm^-1cm^-1,cm,ohm^-1cm,cm^-1

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`ohm^-1cm^-1`
`CM`
`ohm^-1cm`
`cm^-1`

ANSWER :D
Discussion
12089.

What are point defects ?

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Solution :If the deviation occurs due to missing atoms, displaced atoms or extra atoms the IMPERFECTION is named as a point DEFECT. Such DEFECTS arise due to imperfect packing during the ORIGINAL crystallisation or they may arise from thermal vibrations of atoms at ELEVATED temperatures.
Discussion
12090.

Which of the following units is useful in relating concentration of solution with its vapour pressure?

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mole FRACTION
parts PER million
MASS parcentage
molality

SOLUTION :The vapour pressure of a solution is related to itsoncentration in terms of mole fraction. According to Raoult's LAW.
`P=P_(A)+P_(B)=P_(A)^(@)x_(A)+P^(@)__Bx_(B).`
Discussion
12091.

Which of the following statements is / are true ? (i) PH_5 and BiCl_5 do not exist (ii) p pi - d pi bond is present in SO_2 (iii) I_3^(+) has bent geometry (iv) SeF_4 and CH_4 have same shape

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(i) , (II) , (III)
(i) , (iii)
(i) , (iii) , (IV)
(i) , (ii) , (iv)

ANSWER :A
Discussion
12092.

Which is/are correct statement(s) for XeF_(2)?

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It has BENT structure
It is hydrolysed rapidly in aqueous solution of a base
It oxidizes `CL^(-)` and `I^(-)` to `Cl_(2)` and `I_(2)` respectively
Both B and C

Answer :D
Discussion
12093.

What is the atomicity of propane molecule?

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SOLUTION :PROPANE is `C_(3)H_(8)`. Its atomicity `=3+8=11`.
Discussion
12094.

when an primay aromatic amine is treated with NaNO_(2)+HCl at 0^(0)-5^(0)C, a diazonium salt is formed and the reaction is called diazo reaction. In this reaction mineral acid must be added to prevent the coupling reaction of diazonium salt with excess of aryl amine. Diazonium salt is highly useful in the synthesis of number of coloured dyes. When 2, 4-dinitroaniline react with NaNO_(2)+HCI at 5^(0)C followed by reaction with anisole, a coloured compound is formed which can be given as

Answer»




SOLUTION :
Discussion
12095.

You are provided with 1 M solution of NaNO_(3) whose density = 1.25g/mL

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Thepercentage by mass of `NaNO_(3) = 6.8`
The percentage by mass of `H_(2)O = 93.2`
The molality of the SOLUTION is `10.72`
The solution has `0.2` moles of `NaNO_(3)`

Solution :Molarity ` = (10 XX d xx x)/M_(o) `
where d = density of solution, `x = % ` by mass of `NaNO_(3), M_(o) = " mol wt. of " NaNO_(3) = 85`
`1 = (10 xx 1.25 xx (x))/85 rArr= 85/(10 xx 1.25) = 6.8`
` :. % " by mass of " H_(2)O = 100 - 6.8 = 93.2`
HENCE , 1 mole of `NaNO_(3)` is present in `93.2" g of " H_(2)O`
` :. ` Molality` = 1/(93.2) xx 1000 = 10.72 ` molal
Discussion
12096.

What is the product when acetylene reacts with HCN

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`CH_3COCl`
`ClCHCOOH`
`Cl_2CHCHO`
`ClCH_2CHO`

ANSWER :C
Discussion
12097.

Which of the following compounds is used as the satarting material for the preparation of potassium dichromate ?

Answer»

`K_2SO_4.Cr_2(SO_4)_3.24H_2O` (CHROME alum)
`PbCrO_4`( Chrome YELLOW)
`FeCr_2O_4 (Chromite)
PbCrCvPbO (Chrome red)

ANSWER :C
Discussion
12098.

Which of the following does not give haloform reaction:

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`UNDERSET(CL)underset(|)(CH_(2))-underset(O)underset(||)(C)-CH_(3)`
`underset(Br)underset(|)(C)H-underset(O)underset(||)(C)-CH_(3)`
`underset(Cl)underset(|)(CH_(2))-OVERSET(O)overset(||)(C)-CH_(3)`
`PH-underset(O)underset(||)(C)-Ph`

SOLUTION :Haloform reaction
Discussion
12099.

To precipitate silver from sodium argento-cyanide, aluminium can be used . Comment.

Answer»

Solution :To precipitate silver from sodium argentocyanide, all the metals which are more electropositive than silver can be USED. ALUMINIUM is more electropositive than silver. HENCE aluminium can be used to precipitate silver from sodium argentocyanide solution.
Discussion
12100.

When 0.1025 g of benzoic acid was burnt in a bomb calorimeter the temperature of the calorimeter increased by 2.165^(@)C. For benzoic acid DeltaH_("comb")^(@)= -3227 kJ mol^(-1). Calculate the heat capacity of the calorimeter.

Answer»

Solution :The equation forthe combustion is ,
`C_(7)H_(6)O_(2)(s) + 7.5 O_(2)(g) rarr 7CO_(2)(g) + 3H_(2)O(l)," " DELTA H^(@) = 3227 kJ`
Since `7.5` moles of `O_(2)` gas is needed, and 7 moles of `CO_(2)` is produced, some pressure-volume work is done, to the calorimeter:
`PV = Delta n_(g) R T`, where `Delta n=(7-7.5) = -0.5 mol`
`Delta E = Delta H - Delta Hn_(g) RT`
`= -3227 - (0.5 xx 8.314298 xx 298)`
`= -3226kJ//mol` (a small CORRECTION)
The amount of HEAT produced by 0.1025 g benzoic acid is
`q = 0.1025//122.13 xx 3226 = 2.680 kJ`
Thus, the heat CAPACITY is
`C = q_(v)//Delta T = 2.680//2.165 = 1.238 kJ//K`.
After the heat capacity is determined, the calorimeter is ready to be used to measure the enthalpy of combustion of other substances.
Discussion