Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

12251.

Which of the following aqueous solution shas osmotic presseure nearest to that of an equimolar solution of K_(4)[Fe(CN)_(6)]

Answer»

`Na_(2)SO_(4)`
`BaCl_(2)`
`Al_(2)(SO_(4))_(3)`
`C_(12)H_(22)O_(11)`

Answer :C
12252.

What type of linkage holds together the monomers of DNA and RNA ?

Answer»
12253.

Which method is suitable to prepare I_(2)sol and Se sol?

Answer»

Reduction
Hydrolysis
OXIDATION
peptisation

Solution :oxidation
12254.

Which of the following choices match(es) with hydrogen gas at 200 atm and 273 K?

Answer»

`Zne1`
ATTRACTIVE FORCES are DOMINANT
PV = nRT
P(V - NB) = nRT

Answer :A::D
12255.

When 0.01 moleof a cobalt complex is treated with excess silver nitrate solution, 4.305 g silver chloride is precipitated. The formula of the complex is

Answer»

`[Co(NH_(3))_(3)Cl_(3)]`
`[Co(NH_(3))_(5)Cl]Cl_(2)`
`[Co(NH_(3))_(6)]Cl_(3)`
`[Co(NH_(3))_(4)Cl_(2)]NO_(3)`

SOLUTION :4.305 g AgCl = `(4.305)/(143.5)` mole = 0.03 mole
As 0.01 mole of the COMPLEX gives 0.03 mole of AgCl, this shows that there are 3 ionizable Cl. Hence, FORMULA is (c ).
12256.

Which of the following is not used to distinguish ethene from ethane

Answer»

IODINE in `C Cl_4`
BROMINE in `C Cl_4`
Alkaline `KMnO_4`
Ammonical `Cu_2Cl_2`

Answer :D
12257.

Which of the following solutions of NaCl has the higher specific conductance ?

Answer»

0.001N
0.01N
0.1 N
1 N

Answer :D
12258.

Which of the following species will be decomposed on acidification

Answer»

`[AG(NH_(3))_(2)]^(+)`
`[Cu(NH_(3))_(4)]^(2+)`
`[Zn(OH)_(4)]^(2-)`
`[Pb(OH)_(4)]^(2-)`

SOLUTION :`[Ag(NH_(3))_(2)]^(+), [Cu(NH_(3))_(4)]^(2+), [Zn(OH)_(4)]^(2-)` and `[Pb(OH)_(4)]^(2-)` will be DECOMPOSED on aciditication
12259.

Which one of the polymer is used as insulation for cables, making toys?

Answer»

HDPE
LDPE
teflon
orlon

Solution :LDPE
12260.

Write Nernst equation for Daniell cell.

Answer»

Solution :`E_("CELL") = E_("cell")^@ -(l_n[Zn^(2+)])/([CU^(2+)])`
OR
`E_("cell") = E_("cell")^@ - (0.059)/2 LOG"" ([Zn^(2+)])/([Cu^(2+)])`
OR
`E_("cell") = E_("cell")^@ -(2.303RT)/(2F) log "" ([Zn^(2+)])/([Cu^(2+)])`
12261.

Thermodynamically most stable form of carbon is :

Answer»

Diamond
Coke
Charcoal
Graphite

Answer :D
12262.

Which metal in the first series of transition metals exhibits +1 oxidation state most frequently and why ?

Answer»

SOLUTION :Cu has the ELECTRONIC configuration `3d^(10)4s^(1)`. It can easily lose `4s^(1)` electron to give the stable `3d^(10)` configuration. Hence, it shows +1 oxidation state.
12263.

What is the product of the reaction: C_(6)H_(5)N = NCl overset("Phenol")rarr ?

Answer»

Solution :p-Hydroxy azobenzene is obtained by the COUPLING REACTION with phenol, which is an orange RED colour DYE.
12264.

Which one of the following nitro compounds does not react with nitrous acid?

Answer»

`CH_(3)-CH_(2)-CH_(2)-NO_(2)`
`(CH_(3))_(2)CH-CH_(2)NO_(2)`
`(CH_(3))_(3)C NO_(2)`
`CH_(3)-UNDERSET(O)underset(||)(C)-underset(CH_(3))underset(|)(CH)-NO_(2)`

SOLUTION :`-3^(@)` nitroalkane
12265.

When excess of KI is added to copper sulphate solution

Answer»

No REACTION takes place
Potassium IODIDE is oxidized
Copper sulphate is oxidised
Cuprous iodide is formed

Answer :B
12266.

Three moles of an ideal diatomic gas undergoes a change in state from A to B reversibly as follows: Which of the statements is//are correct regarding the above process:

Answer»

Work done on the GAS is `2700 R`
In the above process, pressure varies INVERSELY with SQUARE of volume.
Heat supplied to the gas is `4050 R`
Data INSUFFICIENT for the calculation of work and heat supplied.

Solution :N//A
12267.

Which is true in the case of [Ni(CO)_4] complex:

Answer»

`sp^3` hybridisation
Tetrahedral shape
Diamagnetic
All are correct

Answer :D
12268.

What is the major product of the following reaction?

Answer»




ANSWER :C
12269.

Which of the following will give cis-diol

Answer»




SOLUTION :
12270.

Which polymer is obtained by condensation polymerization between HMDA and Adipic acid ?

Answer»

Dacron
Nylon-6,6
RAYON
TEFLON

SOLUTION :Nylon-6,6
12271.

Which of the folloiwng will not act as oxidising agents ?

Answer»

`CrO_(3)`
`MoO_(3)`
`WO_(3)`
`CrO_(4)^(2-)`

Solution :A species can ACT as oxidizing agent only when metal ispresent in HIGH oxidation state but lower oxidation state is more stable . As higher oxidation states of Mo and W are more stable, they will not act as oxidizing agent.
12272.

What is the name given to number of collisions per second per unit volume of the reaction mixture?

Answer»

SOLUTION :COLLISION FREQUENCY
12273.

The weight of two elements which combine with one another are in the ratio of their :

Answer»

AT. WT.
Mol.wt.
eq.wt.
none

Answer :C
12274.

Which of the following is most electronegative

Answer»

O
S
Te
Se

SOLUTION :`{:("ELEMENT-","O","S","SC","Te","Po"),("Electronegativity-",3.5,2.5,2.4,2.1,2.0):}`
12275.

Which one of the following is not a condensation polymer ?

Answer»

Melamine
Glyptal
Dacron
NEOPRENE

Solution :Neoprene is an addition polymer of isoprene.
`UNDERSET"CHLOROPRENE"(nCH_2=CH-overset(CL)overset|C=CH_2) overset(O_2 " or peroxides")to underset"Neoprene"((--CH_2-overset(Cl)overset|C=CH-CH_2--))`
12276.

Which of the following statement(s) is (are) correct. When a mixture of NaCl and K_2Cr_2O_2 is gently warmed with conc. H_2SO_4

Answer»

A deep red vapours is evolved
The vapours when passed into NaOH solution GIVES a YELLOW solution of `Na_2CrO_4`
Chlorine gas is evolved
Chromyl chloride is formed

Solution :`K_2Cr_2O_7 +Cl^(-) rarr underset("(Red)")(CrO_2Cl_2) uarr`
`CrO_2Cl_2 + NaOH rarr underset("(Yellow Solution)")(Na_2CrO_4) overset(PB^(+2))rarr underset("(Yellow ppt)")(PbCrO_4uarr)`
12277.

Which of the following statements is correct for Ni(CO)_(4)" and "[Co(CO)_(4)]^(-) ?

Answer»

Both are paramagnetic
Both are isostructural and ISOELECTRONIC
Both involve `d^(3)s` hybridisation
Synergic BONDING is not involved

Answer :B
12278.

Which aqueous solution will conduct an electric current quite well :

Answer»

Glycerol
Sugar
Hydrochloric acid
Pure water

Answer :C
12279.

which of the methods are suitable for the preparation of methylene cyclohexane ?

Answer»




SOLUTION :In (a), (b), and (c ) (Wittig reaction), the products are but in (d) the PRODUCT is DIFFERENT as GIVEN below.
d.
12280.

Vitamin B_1 is callled

Answer»

ASCORBIC acid
Thiamine
Pyridoxine
Riboflavin

Answer :B
12281.

Write steps to carry out the conversion of phenol to aspirin.

Answer»

SOLUTION :
12282.

Which of the following statements is (are) correct

Answer»

C – N bond LENGTH in `CH_(3)-NH_(2)` is more than that in `C_(6)H_(5)-NH_(2)`
CYANIDES on partial hydrolysis give amides
`CH_(3)CH_(2)CONH_(2)` is converted into `CH_(3)CH_(2)NH_(2)` by using `NaOH+Br_(2)`
Alkyl isocyanides on reduction with `LiAlH_(4)` give secondary amines

Solution :Resonance `uarr` b. length `darr` `R-C-=N overset(H_(2)O)underset("Hypo")toR-overset(O)overset(||)C-NH_(2)`, Hoffmann hypo bromite `R-N-=C to R-NH-CH_(3)`.
12283.

What is the action of Mg in benzene on acetone ?

Answer»

Solution :When a ketone like acetone is treated with a divalent active metal like Mg in benzene, it undergoes reduction forming a complex which on acidic hydrolysis GIVES a dihydroxy COMPOUND, GLYCOL called PINACOL (2, 3-Dimethylbutane - 2, 3-diol).
This is a biomolecular reduction reactiongiven only by ketones and not by aldehydes.
12284.

What will be nature of the solution when chloroform and acetone are mixed ?

Answer»

SOLUTION :The solution will SHOW NEGATIVE DEVIATION from Raoult.s LAW.
12285.

The statements about oxides of chalcogens i) The solubility of dioxides decreases from SO _(2)to Po O _(2) ii) TeO _(2) is highly acidic in nature (iii) Trioxides are more acidic than dioxides The correct combination is

Answer»

Both i & III are CORRECT
All are correct
Only iii is correct
Botha i & II are correct

Answer :A
12286.

When secretion of acid in stomach is increased upto 42 m Eg. Then is known as ?

Answer»

Hypoacidity
Hyperacidity
Insomnia
Mania

Answer :B
12287.

What are the characteristics of the transition elements and why are they called transition elements? Which of the d-block elements may not be regarded as the transition elements ?

Answer»

Solution :Characteristics of the transition elements : The d-block elements are called transition elements because these elements REPRESENT change (or transition) in properties from the most positive electropositive s-block elements to the least electropositive p-block elements.
The ELECTRONIC configuration of Zn, Cd and Hg are represented by the general formula `(n - 1)d^(10) ns^(2).` The orbitals in these elements are completely filled in the GROUND state as WELL as in their common oxidation sates. Therefore, they are not regarded as transition elements.
12288.

Which is a monomer of neoprene in the following ?

Answer»

`CH_2=UNDERSET(CI)underset(|)(C)-CH=CH_2`
`CH_2=underset(CH_3)underset(|)(C)-CH=CH_2`
`CH_2=CH-C-=CH`
`CH_2=CH-CH=CH_2`

ANSWER :A
12289.

What is the coagulation process?

Answer»

Solution :The process by MEANS of which the PARTICLES of the DISPERSED phase in a sol are precipitated is called as coagulation. Coagulation is generally ACHIEVED by the addition of a SUITABLE electrolyte.
12290.

Which one of the following is a weak acid?

Answer»

`HF`
`HCL`
`HBR`
`HI`

SOLUTION :`HBr`
12291.

The standard potential (E^(0)) for the half reaction are asZn to Zn^(2+) + 2e^(-) , E^(0) = + 0.76 V Fe to Fe^(2+) + 2e^(-) , E^(0) = + 0.41 V . The emf for the cell reaction Fe^(2+) + Zn to Zn^(2+) + Feis

Answer»

`-0.35V`
`+0.35V`
`+1.17V`
`-1.17V`

ANSWER :B
12292.

You are given marbles of diameter 10 mm. They are to be placed such that their centres lie in a square bound by four lines, each of length 40 mm. What will be the arrangements of marbles in a plane so that maximum number of marbles can be placed inside the area? Draw the diagram and derive expressions for the num

Answer»

SOLUTION :
12293.

What will be the final product of the reaction of cyclohexanamine with sodium nitrite in dil. HCI?

Answer»




ANSWER :A
12294.

[Y is used infire works, safety matches] 'X' is

Answer»

`Br_(2)` and `Cl_(2)`<BR>`Cl_(2)`
`I_(2)`
`NO_(2)`

Solution :`UNDERSET("(X)")(3Cl_(2))+ 6KOH overset("hot")(rarr) 5KCl+ underset("(Y)")(KClO_(3)) + 3H_(2)O, KClO , KClO_(3) + overset("(Y)")(con. HCl) rarr`
12295.

Which acid is produced when phenol is treated with conc. HNO_(3) ?

Answer»

SOLUTION :PICRIC ACID
12296.

What is the effect of change in concentration of an electrolyte solution on conductivity and molar conductivity.

Answer»

SOLUTION :As concentration DECREASES (dilution INCREASES) conductivity decreases and MOLAR conductivity increases for both WEAK and strong electrolytes.
12297.

Which compound is optically active ?

Answer»

2-methylpropan-1-amine
Butan-2-amine
Butan-1-amine
2-methylpropan-2-amine

Solution :The COMPOUND with ONE CHIRAL CARBON ATOM is optically active.
(A) 2-methylpropan-1-amine : `H_(3)C-overset(CH_(3))overset("|")underset("H ")underset("| ")("C ")-overset("H")overset("|")underset("H")underset("|")("C")-NH_(2)`has no chiral carbon.
(B) Butan-2-amine : `H_(3)C-overset("H ")overset("| ")underset(NH_(2))underset("| ")("C"^(**))-CH_(2)CH_(3)`
The asterik marked carbon is a chiral carbon.
(C ) Butan-1-amine : `CH_(3)-CH_(2)-CH_(2)-CH_(2)NH_(2)` has no chiral carbon.
(D) 2-methylpropan-2-amine : `CH_(3)-overset(CH_(3))overset("|")underset(NH_(2))underset("|")("C ")-CH_(3)` has no chiral carbon.
12298.

Three faraday of electricity is passed through molten solutions of AgNO_3 , NiSO_4 and CrCl_3 kept in three vessels using inert electrodes. The ratio in mol in which the metals Ag, Ni and Cr will be deposited is-

Answer»

`1:2:3`
`3:2:1`
`6:3:2`
`2:3:6`

ANSWER :C
12299.

The weakest base among the following is:

Answer»

NAOH
`CA(OH)_2`
KOH
`Be(OH)_2`

ANSWER :B
12300.

Which of the following nuclear transformations is p, n type?

Answer»

`""_(7)^(14)N+_(0)^(1)nto""_(6)^(14)C+""_(1)^(1)H`
`""_(11)^(23)Na+_(1)^(1)Hto""_(12)^(23)MG+""_(0)^(1)n`
`""_(3)^(7)Li+_(1)^(2)Hto""_(3)^(8)Li+""_(1)^(1)H`
`""_(4)^(9)Be+_(2)^(4)Heto""_(6)^(12)Li+""_(0)^(1)n`

Answer :B