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701.

Define rate law and rate constant. Explain ratelaw with two examples.

Answer»

Rate Law : It is the expression which relates the rate of reaction withconcentrationof the reactants. The constant of proportionality ‘k’ is known as rate constant.

Rate constant: When the concentration of reactants isunity, then the rate of reaction is known as rate constant. It is also called specific reaction rate.

ans me

702.

definition of hyperconjugation

Answer»

Hyperconjugation is the stabilising interaction that results from the interaction of the electrons in a sigma bond (usually C-H or C-C) with an adjacent empty or partially filled p-orbital or a pi orbital to give an extended molecular orbital that increases the stability of the system.

703.

C. p-orbitals are....... in shape.a. spherical b. dumb bellc. double dumbell d. diagonal

Answer»

Anorbitalis a wave function for an electron defined by the three quantum numbers, n, ℓ and ml.Orbitalsdefine regions in space where you are likely to find electrons.p orbitals(ℓ = 1) are dumb-bellshaped. The three possiblep orbitalsare always perpendicular to each other.

p-orbitals are in (dumb bell) shapehope this will help you like my answer and MARK IT AS BEST ANSWER

p-orbitals are dumb bell shapedI hope it will be the most suitable answer

p orbital is in dumbbell shape

p orbital is dumbbel shape

p orbital is in dumbell shape due to an electron in p orbital can have equal probability of being either half only the two electrons present so it is in dumbell shape

dumbbell shape is the right answer for this question

I think dumbell shape

the right answer is dumb bell shape of p orbitals

P-ORBITAL IS DUMB BELL

704.

Explain sp allyunuJULUIExplain sp°82 hybridisation taking SF6 exampleUsing VSEPR theory explain the structure of the a)BeCl2 b)CH4_c) H2Q_d) NH3 e)SO2mibonding molecular orbitals.

Answer»

Withsp3d2, the s, p and d orbitals which arehybridizedall come from the same energy level, for instance, it has been taught that when sulfur combines with six fluorine atoms to make SF6 that the 3s, 3p and two 3d orbitals hybridize to make thesp3d2 hybridorbital set. But d2sp3 is different.

705.

17. Explain Hyperconjugation effect.18. Explain the preparation of Lassaigne's extract.

Answer»

17.Hyperconjugation is the stabilising interaction that results from the interaction of the electrons in a σ-bond (usually C-H or C-C) with an adjacent empty or partially filled p-orbital or a π-orbital to give an extended molecular orbital that increases the stability of the system.

18.Preparation of Lassaigne’s Extract:A small pellet of metallic sodium together with a little of the substance is heated to red hot in an ignition tube. It is then suddenly plunged into about 10ml of distilled water in a china dish. The mixture is boiled well and filtered. The filtrate is the Lassaigne's extract.

706.

13. Explain 2 preparation of benzene?14. Explain chemical properties of haloarenes?

Answer»

13. Benzeneand its homologues may bepreparedby the following methods.

By the decarboxylation of sodium benzoate.

By heating phenol with zinc.

By the polymerization of ethyne (acetylene)

By the reduction ofbenzenediazonium chloride.

By the hydrolysis of sulphonic acid.

14. Haloarenes are chemically less reactive than haloalkanes. They can undergo the following reactions:

Replacement by hydroxy group (formation of phenol)

When aryl halides are heated at 623 K and under pressure (300 atm), with aqueous solution of sodium hydroxide, the halogen atom is replaced by hydroxyl group forming phenol. Firstly sodium phenoxide is formed, which on acidification gives phenol.

This reaction forms the basis for the manufacture of phenol by Dow's process.

Substitution by amino group (formation of aniline)

The halogen atom is replaced by amino group when aryl halides are heated with aqueous ammonia in the presence of cuprous oxide (catalyst) at 475 K and under a pressure of 60 atm.,

Substitution by cyano group (formation of cyanobenzene)

The halogen atom is replaced by cyano group on heating with anhydrous cuprous cyanide in the presence of pyridine or dimethylformamide (DMF).

The cyanobenzene can be converted into other useful compounds like Benzamide, benzoic aid and benzylamine under different conditions.

Effect of substituents in haloarenes (aryl halides) on the reactivity

The reactivity of haloarenes is markedly affected by the presence of certain groups at certain positions of the ring. The presence of electron withdrawing groups such as -NO2,-CN, -COOH, etc. at 'o' and 'p' positions to the halogen atom, greatly activates the halogen towards nucleophilic substitution reactions. For example, chlorobenzene is converted into phenol by aqueous NaOH only at temperatures above 573 K, whereas 'p' chloronitrobenzene is converted into nitrophenol by aqueous NaOH at a lower temperature of 433K. As the number of ortho and para nitro groups on the ring is increased the reactivity increases.

707.

A Radio set of 60 Watts Run for 50 hours . How many units of electrical energy are consumed.

Answer»
708.

Q13) How does sprinkling of salt help in clearing the snow covered roads in hilly area?Wxplain the phenomenon involve in the process?

Answer»

When salt is spread over snow covered roads, snow starts melting from the surface because of the depression in freezing point of water and it helps in clearing the roads.

709.

1.Whal do you e B U12. What is green chemistry? How will i helpecrcase entQ13.Chlorophvil, the green colouriny, material of piut contains 2.68% ol tnagnesium bymass. Calculate the umber of moles of magnesiurn and atoms in 5.00 g oi thiscomplex. IAtomic mass ol Mg-24inud by the terms?Entropy

Answer»

Mass of chlorophyll = 5.0 gPercentage of Mg = 2.68 g2.68 x 2 0Mass of Mg in 5.0 g of chlorophyll = 2.69 x 5.0/100= 0.1345 g6.022 X {{10}^{23}} atoms of magnesium = 24 g.’. 24 g of Mg contains 6.022 X {{10}^{23}} atoms

0.1345 g of Mg contains 6.022 X ${{10}^{23}}$/24x 0.1345

= 3.73x {{10}^{21}} atoms

710.

58] Two substances A and B are present such that[A°) = 4[Bº] and half life of A is 5 min and thatof B is 15 min. If they start decaying at the sametime following first order kinetics how much timelater will take if the concentration of both ofthem would be same?1) 15 min2) 50 min3) 35 min4) 62 min

Answer»

Initial concentration of A = [Ao]Amount of A left inn1half lives =(12)n1[Ao]

Initial concentration of B = [Bo]Amount of A left inn2half lives =(12)n2[Bo]

According to the question, concentration of both will be same,

[Ao]/2^n1=[Bo]/2n^24/2^n1=1/2^n2(SinceAo=4Bo)2^n1/2^n2=2^22(n1−n2)=2^2n1−n2=2n2=n1−2Also,t=n1×t(1/2A)t=n2×t(1/2B)Let the concentration of both become equal after time t

n1×t1/2/n2×t1/2=n1×5/n2×15=1n1/n2=3n1=3n2Usingaboverelationinequationn2=n1−2n2=3n2−2n2=1Therefore,n1=3Puttingthisvaluein,t=n1×t1/(A)=3×5=15minutes

711.

At absolute zero volume of a given mass of a gasbecomes absolutely zero. Explain.

Answer»

Absolute zero,temperatureat which athermodynamicsystem has the lowest energy. It corresponds to −273.15 °C on theCelsius temperature scaleand to −459.67 °F on theFahrenheit temperature scale

see if there is no volume then where is the space for gas to move

i meant that without volume (space) there cannot be any thing soAt absolute zero volume of a given mass of a gas becomes absolutely zero

712.

At 248° C, the kp for the reaction, SbCl, (g)SbCl, (g)+ Ch (9) is 1.07 atm at a total pressureof 1 atm . Calculate the degree of dissociation of SbCls(1) 0.516(2) 0.718(3) 0.321(4) of these

Answer»
713.

F.13 AB dissociates as 2AB (g)2A (g)+ B, (9)When the initial pressure of AB is 500 mm, the totalpressure becomes 625 mm when the equilibrium isattained. Calculate Kp for the reaction assumingvolume remains constant.(A) 500(C) 750(B) 125(D) 375

Answer»
714.

o)seu0o Second order4)secondHow much time it require to complete161 For certain first order reaction, 75% of the reaction complete in 30 min.99.9% of the reaction?(2) 100 min(4) 300 min50 min(3) 90 minK is rate constant)

Answer»

Order of reaction = 1Let the initial concentration be [A]0 = 100%[A]t = 100 -75 = 25%Rate law for first order rectionK = (2.303/t)log[A]0/[A]tfor (75%) - time is 30 minutes

Substituting the values we get K = (2.303/30)*log[100/25]And k = 0.04621 per minute

now % completion is 99.9 [A]t = 0.1%

therefore t = (2.302/k)*log[100/0.1] t = (2.303/0.04621)*(3) = 149.5 = 150mins.

715.

Two non-reactive gases A and B are present in acontainer with partial pressures 200 and 180 mmof Hg. When a third non-reactive gas C is addedthen total pressure becomes 1 atm then molefraction of C will be(1) 0.75(2) 0.5(3) 0.25(4) Cannot be calculated

Answer»

2 non-reactive gases A & B present in a container with partial pressure 200 and 180 mm of Hg. When a third non-reactive gas C is added, then the total pressure becomes 1 ATM. What is the mole fraction of C?

Answer

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5 ANSWERS

Ameya Deshmukh, studies Science and Mathematics at St. Joseph's Convent High School, Jalgaon (2019)

Answered Sep 16, 2017

According to Dalton's Law of Partial Pressures, here, the pressure exerted by C will not be affected by A and B.

And the total pressure exerted will just be the scalar sum of all the partial pressures.

Letxbe the partial pressure of C.

Hence-

200 mm of Hg + 180 mm of Hg + x =1 atm

x = 1 atm-380 mm of Hg

But 1atm = 760 mm of Hg.

Therefore,x = 760-380=380 mm of Hg.

Moreover,

Partial Pressure Mole fraction × Total Pressure

Hence-

380 mm of Hg= X of A × 760 mm of Hg.

X of C = 1/2 =0.5

The mole fraction of C is0.5

716.

The partial pressure of hydrogen in a flaskcontaining 2 g H2 and 32 g SO2 is(1) 1/16th of total pressure(2) 1/9th of total pressure(3) 2/3rd of total pressure(4) 1/8th of total pressure

Answer»

PARTIAL PRESSURE OF HYDROGEN= MOLE FRACTN OF H2X TOTAL PRESSURE

moles of H2= 2/2= 1

MOLES OF SO2= 32/64 = 0.5

P.P OF H2= 1/ 1.5 X TOTAL PRESSURE = 2/3 0F TOTAL PRESSURE(3RD OPTN)

717.

he partial pressure of hydrogen in a flaskcontaining 2 g H2 and 32 g SO2 is(1) 1/16th of total pressure(2) 1/9th of total pressure(3) 2/3rd of total pressure(4) 1/8th of total pressure. T

Answer»

PARTIAL PRESSURE OF HYDROGEN= MOLE FRACTN OF H2X TOTAL PRESSURE

moles of H2= 2/2= 1

MOLES OF SO2= 32/64 = 0.5

P.P OF H2= 1/ 1.5 X TOTAL PRESSURE = 2/3 0F TOTAL PRESSURE(3RD OPTN)

718.

.iAThe haif life fon radinactive decay o e is 5730 years. Anachanulogicalortifaer containing wond had only s0% of he ound in a living treeEstimate the age of the sample

Answer»

thanks

719.

The rate constant of a reaction is 3x102 min. What is the order of the reaction? (461faforatato 6** *1 3*102 min faforancora una fasada?)[HS'12]The concentration of a solution having concen-tration 0.24 M is reduced to 0.12 M in 10 hoursand 0.06 M in 20 hours. What is the rate con-stant of the reaction? ( 7 597 shot to 10--------------

Answer»

First order reaction .As the unit is min^-1

720.

The rate constant of the first order reaction is0.346 min^-1. What is the half life period. (2003)

Answer»

half life =0.693/0.346=2min

721.

The rate constant of a reaction is 3x10^2 minWhat is the order of the reaction?

Answer»
722.

5.For a chemical reaction variation in concentra- |tion, In [R] vs. time (min) plot is shown below:[HS '13] iin [R]t(min)(a) What is the order of the reaction?(b) What is the unit of rate constant k, forthe reaction?(c) If initial concentration of the reactant ishalf of the original concentration, how will112 change?TRO(d) Draw the plot of log TeT vs. time (s). !

Answer»

(i) First order. (ii) S^-1/time^-1

723.

Dipole moment

Answer»

A dipole moment is the product of the magnitude of the charge and the distance between the centers of positive and negative charges. It is denoted by the Greek letter ‘µ’.

724.

both carbon and silicon. Compare the ability of cteau80. (o) How can diamonds be made artificially ? How do synthetic diamonds differ from naturalornes ?nd and graphite. What causes these differen

Answer»

Artificial diamonds are made by subjecting pure carbon or graphite to high pressure and temperature this method of preparing diamonds is called High pressure,High temperature (HPHT).Second method of preparing diamonds is (CVD) Chemical vapour deposition in this method hydrogen and carbon gas are kept in chamber which contain filament and microwave and again same process is repeated in which high temperature and pressure is applied. Natural diamonds have internal flaws but artificial diamond do not have any flaws

725.

(B) State and explain Nemst's Distribution lawIn the distribution of benzoic acid between water and benzene, the following results wereobtained2.9797.01.501.95C, (In Water)C, (In Benzene)24.2041.2What information do you gather regarding the molecular state of benzoic acid in benzene?

Answer»

Since Caq/Corg½ is practically constant benzoic acid exists as a dimer (n=2) in benzene.Molecular condition of benzoic acid in benzene is 1/slope = n = 2 , molecules of benzoic acid associate in benzene.

726.

roct: Visit the places where powderfcoating, Teflon coating is done. Getinformation about the process andpresent it in the class.

Answer»

The powder coatingthat gets applied is just that-a powder. It basically gets sprayed onto the surface and then dries to form a coating. The surface of the item that is being coated with Teflon is sandblasted so that it receives a lot of tiny micro-abrasions. This rougher surface is easier for the non-stick Teflon to grab onto. However, this method has been shown to create a rather weak bond with the item it is being coated onto. This is why some cookware may be more easily scratched than others.

thankyou mam but I have to complete it in my activity book because of that I want answer in points such as title , introduction , framework , procedure , conclusion and persnol opinion . mam if u can give ans in points please

727.

1 mole each of CO(g), H 0(g), H2(g) and CO2(g)are placed in one litre flask at 25°C. Whenioliowing equilibrium is set-upCO(g) + H2O(g) CO2(g) + H2(g)Kp 9. Hence CO2 present at equilibrium is:

Answer»
728.

47. Which of the following pairs of gases contain the samenumber of molccules?(1) 16 g of O, 14 g of N2(2) 8 g of O2, 22 g of CO2(3) 28 g of N2, 22 g of CO2(4) 32 g of O2, 32 g of N2

Answer»
729.

Name the gas that supports burning. o

Answer»

Oxygen is the gas that supports burning.

730.

what type of combustion is represented by:-1. burning a white phosphorus in air at room temperature?2. burning of LPG in a gas stove?3. ignition of a cracker?4. burning of coal dust in a coal mine?

Answer»

a) Spontaneous Combustionb) Rapid Combustionc) Explosive Combustion(or explosion)d) Spontaneous Combustion

731.

125 mL of 1 0% NaOH (w/v) is added to 125 ml of 1 0% HCI(w/v). The resultant solution becomes(1) alkaline(3) acidic(2) strongly alkaline(4) neutral

Answer»

Reaction precedes as :

NaOH + HCl ----- NaCl + H2O

This is a neutralization reaction where one mole oh HCl reacts with one mole of NaOH to form the salt. One mole of NaCl is formed.Hence, entire NaOH and HCl is utilized to form the salt. The resulting solution is neutral.

732.

What volume of water is required to make 0.2 M solution from 16 mL of a 0.5 M solution ? Mcte(A) 24 ml840 mL(C) 6.4 mlL(D) 20 mL

Answer»

let V be the volume needed to make 0.2M

now no. of moles in the initial solution = 0.5*(0.016)

so, final concentration is 0.2 => 0.2 = 0.5*(0.016)/V => V = 0.5*(0.016)/0.2 = 0.04 l = 40ml.

so, we will add 40-16 = 24 ml more water to the solution to convert 0.5M to 0.2M

733.

hy should a magnesium ribbon be cleaned before burni

Answer»
734.

Why does magnesium ribbon start floating on hot water?

Answer»

magnesium is not more reactive as calcium hence calcium can react with react with cold water but magnesium cannot is can react with hot water .So when it reacts with hot water it forms magnesium hydroxide and hydrogen .The hydrogen gas evolved doesn't catch fire because the heat evolved is very low . But it forms bubbles and stick to the surface of magnesium and thus as a result magnesium starts floating on water due to the hydrogen gas.hence magnesium ribbon start floating on water.

735.

"hy should a magnesium ribbon be cleaned before burning 1

Answer»
736.

9. The correctly reported answers of the addition of294.406, 280.208 and 24 will be(1) 598.61(3) 598.6(2) 599(4) 598.614

Answer»
737.

Properties of Ethanollinud at room temperat

Answer»
738.

To set fire to a combustible substance, you have to heat it to a certain minimum temperatWhat is this minimum temperature called? If this minimum temperature is very low for a certainsubstance, what is the substance called?ure.

Answer»

This minimum temperature is called ignition temperature.

Such substances are called inflammable substances.

739.

an element has mass no.56 and +3 oxidation state in this element no. of neutron is 30.4% more then no. of electron find the no of electron

Answer»

Let the number of electrons in ion = xNumber of neutrons = x+0.304x = 1.304xNumber of electrons in neutral atom = x+3Number of protons in neutral atom = x+3Mass number = 56(x+3)+(1.304x)=56X = 23Number of protons = x+3 = 26Symbol of ions = Fe3+

740.

4 g of Ar has pressure P at T kelvin in a vessel. On keeping the sample at 50°Chigher temp, 0.8 g of gaswas given out to maintain the pressure P. The original temperature was(200 K)

Answer»
741.

1.In which of the following compounds, the oxidation state of l-atom is highest?(4) IF(1) KI,(3) KIO(2) KIO

Answer»
742.

5. Calculate the molar mass of HCl HNOsandC2H2

Answer»

HCl = 1+35.5= 36.5g/molHNO3 = 1 +14 +3(16) = 1 + 14 + 48 = 63 g/molC2H2 = 2(12)+2(1) = 24 + 2 = 26 g/mol

743.

In the first transition series of elements, which element shows highoxidation state?est

Answer»

The elements which give the greatest number of oxidation states occur in or near the middle of the series. For example, manganese exhibits all the oxidation states from +2 to+7.

in the first element pakistan ki maa ka bhosda transition with series

744.

Account for the following:(i) Mn is more stable than Fe+7.towards oxidation to +3 state.(ii) The enthalpy of atomisation is lowestfor Zn in first series (3d) of thetransition elements. Delhi 2014

Answer»

1)Electronic configuration of Mn2+is [Ar]183d5.

Electronic configuration of Fe2+is [Ar]183d6.

It is known that half-filled and fully-filled orbitals are more stable. Therefore, Mn in (+2) state has a stable d5configuration. This is the reason Mn2+shows resistance to oxidation to Mn3+. Also, Fe2+has 3d6configuration and by losing one electron, its configuration changes to a more stable 3d5configuration. Therefore, Fe2+easily gets oxidized to Fe+3oxidation state.

2)The more extensive themetallic bonding of an element, the more will be its enthalpy of atomization. In all transition metals (except Zn, electronic configuration: 3d10 4s2), there are someunpairedelectrons that account for their strongermetallicbonding

745.

(i) Element of the first transition series which has highest second ionisatiHighest oxidation state shown by a transition elementw are following conversions carried out?i) Methyl bromide to ethyl alcohol) Phenol to anisole

Answer»

copper has highest second ionisation enthalpy

Manganese, which is in the middle of the period, has thehighest numberofoxidation states,

746.

20. Account for following with reasons:(i) Zn +2 salts are white but Cu+2 salts are blue.(ii) Transition elements form interstitial com-pounds.(iii) Transition metals show catalytic properties.

Answer»

i) Cu2+ has an unpaired electron (its configuration is [Ar] 3d9), whereas Zn2+ has all paired electrons (configuration [Ar] 3d10). Pairing electrons leads to diamagnetism, and unpaired electrons leads to paramagnetism. Also, the unpaired electron in the copper ion allows electron transition in the visible region to take place, so the ion is coloured.

ii) Transition metals are large in size and contain lots of interstitial sites. Transition elements can trap atoms of other elements (that have small atomic size), such as H, C, N, in the interstitial sites of their crystal lattices. The resulting compounds are called interstitial compounds.

i

iii)

747.

State Boyle's LawState Charles Law

Answer»

Boyle law : The law, discovered by Robert A. Boyle in 1662, states that at a fixed temperature, the volume of gas is inversely proportional to the pressure exerted by the gas. In other words, when a gas is pumped into an enclosed space, it will shrink to fit into that space, but the pressure that gas puts on the container will increase.

Charles states : It states that if pressure remains constant, the volume of a mass of gas is proportional to its absolute temperature. The absolute temperature is always 273 Kelvin more than the centigrade temperature.

thanks😀😁😂

748.

1. State the properties of liquid state.

Answer»

Liquidstake on the shape of their container.

Theliquid stateof matter is an intermediatephasebetween solid and gas.

Like the particles of a solid, particles in aliquidare subject to intermolecular attraction; however ,liquidparticles have more space between them, so they are not fixed in position

749.

easoGive difference between solid state and gaseous state8.

Answer»
750.

QUESTIONS BASED ON HYDROGEN SPECTRUMICx :What is the wavelength of the light emitted when the electron in a tydrogen stonerpoes a transition from an energy level with n4 to an energy level with n2umber of 82.000 cm

Answer»