InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3401. | 
                                    Which of the following has 28 molecular mass 2(B) CzHs(C) Costa(A) C2H2DICALWhich of the following is unsaturated hydrocarbon ?(B) MOHON(A)widmombar of Hea homologous series? | 
                            
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                                   Answer»  answer 6(c) and 7(d) 6(b)7(c) answer c) is the correct answer  | 
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| 3402. | 
                                    Why NaCI appears to be yellow in colour? | 
                            
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                                   Answer»  Yellow colourin NaCI is due to metal excess defect due to which unpaired electrons occupy anionic sites, known as F-centres. These electrons absorb energy from the visible region for the excitation which makes crystalappear yellow  | 
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| 3403. | 
                                    6) Write the electron-dot structures for sodium, oxygen andmagnesium) Show the formation of Na o and MaO hiy the t | 
                            
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| 3404. | 
                                    UUTUUA certain metal when irradiated with light!(v = 3.2 x 1016 Hz) emits photo electrons withtwice kinetic energy as did photo electronswhen the same metal is irradiated by light(y = 2.0 x 1016 Hz). Calculate v, of electron?(1) 1.2 x 1014 Hz (2) 8 x 1015 Hz(3) 1.2 x 1016 Hz (4) 4 x 1012 Hz | 
                            
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| 3405. | 
                                    Caleulate energy of one mole of photonsof radiation whose frequency Is 5 10piSe | 
                            
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                                   Answer»  Energy of one photon is given by the expression E = hVwhere, h = PlancKs constant = 6.636 x 10^-34J s-1V= Frequency of radiation = 5x 10^14Hz= 5 x 10^14s-1.E= (6.636 x 10^34J s-1 x 5 x 10^14s-1)= 33.18 x 1020JOne mole of photon = 6.023 x 10^23photonsTherefore, Energy of one mole of photon = (6.023 x 10^23x 33.18 x 10^-20J) = 199.84 x 10^3JEnergy of one mole of photon = 199.84 kJ  | 
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| 3406. | 
                                    Problem 2,6Calculate energy of one mole of photonsof radiation whose frequency Is 5 x10iz. | 
                            
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                                   Answer»  Energy of one photon is given by the expression E = hVwhere, h = PlancKs constant = 6.636 x 10^-34J s-1V= Frequency of radiation = 5x 10^14Hz= 5 x 10^14s-1.E= (6.636 x 10^-34J s-1 x 5 x 10^14s-1)= 33.18 x 10^20JOne mole of photon = 6.023 x 10^23photonsTherefore, Energy of one mole of photon = (6.023 x 10^23x 33.18 x 10^-20J) = 199.84 x 10^3JEnergy of one mole of photon = 199.84 kJ  | 
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| 3407. | 
                                    38,A bulb emits light of wavelengthAHow many photons are emitted by the bulb per second?A) 3 x 10184500A. The bulb is rated as 150 watt and 8 % ofthe energy is emitted as light.1018 oronsB) 27.2 x 1012.72 x 1018 | 
                            
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                                   Answer»  Each photon has energy ofhνh = planks constantν= frequency of lightIf there are N photons emitted then the total energy radiated isNhν.Average power is given byP=Energy/time=E/t=Nhν/tButN/t=nis the number of photons emitted per second.Therefore,n=P/hν.ν=c/λSo,n=Pλ/hcIf all the power is not radiated then the effective power = rated power x efficiency.So the number of photons emitted per secondn=Peffλ/c=P×ηλ/hcwhereη is the efficiency.In the problem power P = 150W, wavelengthλ = 4500A and efficiency is 8% = 0.08So number of photons emitted per second,n=(150×0.08*4500*10^-10)/(6.6×10&^−34)*(3*×10^8)= 27.2*10^1827.2*10^18number of photons will be emitted per second by the bulb  | 
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| 3408. | 
                                    Analysis show that nickel oxide consists of nickel ion with 96% ions having ds configuration and4% having d7 configuration. Which amongst the following best represents the formula of theoxide? | 
                            
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| 3409. | 
                                    The equation representsdecomposition reaction15. | 
                            
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                                   Answer»  Ans :- Adecomposition reactionoccurs when one reactant breaks down into two or more products. It can berepresentedby the generalequation: AB → A + B. Inthis equation, ABrepresentsthe reactant that begins thereaction, and A and Brepresentthe products of thereaction.  | 
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| 3410. | 
                                    Q.2. The parasitism in which the host and parasite belong to the same genus or famly is/(a) kleptoparasitism(c) hyperparasitism(b) adelphoparasitism(d)brood parasitismthe oxygen inwater and ki | 
                            
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                                   Answer»  b. Adelphoparasitism Adelphoparasitism also known as sibling-parasitism, occurs where thehostspecies is closely related to theparasite, often in thesame familyorgenus.  | 
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| 3411. | 
                                    Balance the following chemical equations.(a)' HNO3 + Ca(OH), + Ca(NO3)2 +H,0(b) NaOH+H,50. → Na, SO4+H,0(c) NaCl + AgNO, → AgCl + NaNO,(d) BaCl, + H, SO, → Baso, + HCI | 
                            
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| 3412. | 
                                    6.Balancethe following chemical equations.(a) HNO3 + Ca(OH) Ca(NO)+ H,O(b) NaOH + H,SO4Na, SO4 + H,O(c) NaCl + AgNOAgCl+ NaNO3' 2 | 
                            
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| 3413. | 
                                    12. O2 is present in 1 litre flask at a pressure of 1.52 x 103 mm of Hg. Calculate mass of O2 at0°C | 
                            
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                                   Answer»  NOTE THIS STEP :First we should calculate the number of moles of the gas under the given condition by the relationPV = nRT HereP= 7.6 * 10-10mm Hg = 7.6 *10-10/760 atm. = 1 * 10-12atm. V= 1 litre T= 273 + 0 = 273K R= 0.082 litre atm./K/mol Putting the values in equation n=PV/RT= 1 *10-12*1/0.082 *273 moles now since 1 mole = 6.023 * 1023molecules 10-12/0.082 *273 moles = 6.023 *1023*10-12/0.082 *273 molecules = 2.7 * 1010molecules  | 
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| 3414. | 
                                    Problem 2.9The threshold frequency vo for a metalis 7.0 x104 s1. Calculate the kineticenergy of an electron emitted whenradiation of frequency V Ξ1.0 >< 1015 s-hits the metal. | 
                            
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| 3415. | 
                                    The threshold frequency v, for a metalis 7.0 x1014 s. Calculate the kineticenergy of an electron emitted whenradiation of frequency v-1.0 x10 shits the metal15 -l | 
                            
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                                   Answer»  If frequency of radiation =1.0x 10^¹⁵s⁻¹Energy of radiationis equal to Planck's Constant(6.626 x10^⁻³⁴m²kg / s) multiplied by frequencyEnergy of radiation=6.626 x 10^⁻¹⁹ J An electron on the surface requires a certain amount of energy to free itself from the atom. That energy is (Threshold frequency x Planck's constant)Energy to free electron=4.638 x 10^⁻¹⁹ J Kinetic Energy of electron= Energy of radiation-Energy to free electron KE=1.988 x 10^⁻¹⁹ J≈ 2 x 10^⁻¹⁹ J  | 
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| 3416. | 
                                    21. Using the Gibbs energy change, AG+63.3 kJ,for the following reactionAg2CO,(s)2Ag (aq) + CO (ao)the Ksp of Ag2CO3(s) in water at 25°C is(R 8.314 J K-1 mol-1)(1) 3.2 x 10-26(3) 2.9 x 10-3[AIPMT-2014](2) 8.0 x 10-12(4) 7.9 x 10-2 | 
                            
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| 3417. | 
                                    Calculate the minimum amount of energy that the protonsmust possess to eject electrons from caesium metal. Thethreshold frequency of caesium metal is 4.6x10 sec14 | 
                            
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| 3418. | 
                                    Balance the following equations:a) HNO3 Ca (OH)2Ca (NO)2 + H2O | 
                            
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| 3419. | 
                                    42. A certain radio station broadcasts a frequency of 900 klHz. The wavelength of electromagnetic radiation broadcast bythe radio station is:A) 900 mB) 270 mC) 2.70 kmD) 330 m | 
                            
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                                   Answer»  The frquency of the radiation emmited. v = 900 kHz = 900 * 103Hz = 900 * 103s-1 We know that wavelength * frequency = velocity (constant) Or wavelength = velocity / frequency where velocity = 3.0 * 108m s-1 wavelength = 3.0 * 108m s-1/ 900 * 103s-1 wavelength = 3 / 90 * 104m = 333m Thus, wavelength of radiowave brodcast by the station is 333m...  | 
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| 3420. | 
                                    +2Ca4NaOs | 
                            
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                                   Answer»  The reaction can be feasible because , Ca2+ can combine with two anions and hence 1 Ca2+ can displace , 2Na+ and will form rings like structure by connecting with two -ve charged ions so, it will replace 4Na+ ions  | 
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| 3421. | 
                                    52. A change which can occur on its ownwithout the external influence is called as(a) reversible change(b) isothermal change(c) spontaneous change(d), non-spontaneous change | 
                            
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                                   Answer»  spontaneous changeoption(c) option C might be correct option.  | 
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| 3422. | 
                                    5. Find the values of the following T-ratios(1) cosec 315° (ii)COs 2100 | 
                            
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                                   Answer»  cosec(315°)= 1/sin(315)= 1/-sin(45) = -√2 cos(210)= cos(180+30°)= -cos(30)= -√3/2  | 
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| 3423. | 
                                    Gipmu | 
                            
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| 3424. | 
                                    how to identify formula when solving a electricity numarials | 
                            
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                                   Answer»  If voltage and resistance are given and you have to find the value of current use Ohm's law V is equal to IxR  | 
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| 3425. | 
                                    pradeep | 
                            
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                                   Answer»  To give spiritual or intellectual insight (enlighten someone)  | 
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| 3426. | 
                                    Prove that Cp-Cv = R | 
                            
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                                   Answer»  It is Mayer's equation. Derivation: ΔU = ΔQ + ΔW ΔU = Cv ΔT (At pressure is constant) ΔQ = Cp ΔT (At pressure is constant) ΔW = -P ΔV (Negative since the calculation been complete) Pv = RT (1 mole of gas) Because of pressure is constant, R is also constant Change in V will make change in T PΔV = R ΔT Cv ΔT = CpΔT - RΔT Divided by ΔT Cv = Cp - R Cp - Cv = R Like my answer if you find it useful!  | 
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| 3427. | 
                                    potato chips, they are packIn order to prevent the spoilage of potato chips, they arep in a wireatmosphere of2. H21. Cha3. N | 
                            
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                                   Answer»  tq  | 
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| 3428. | 
                                    Let us takeone more example. What is thepercentage of carbon, hydrogen and oxygen | 
                            
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                                   Answer»  There are 2 C atoms, 6 H atoms and 1 O2atom in 1 molecule of ethanol.So,mass of 1 molecule = 2 X mass of C atom + 6 X mass of H atom + 1 X massof O2atom = (2 X 12) + (6 X 1) + (1 X 16) {atomic wt. of C atom is 12,H atom is 1 and O2 atom is16} = 24 + 6 +16 = 46. Now, % composition ofcarbonatom is = (2 X mass of C atom)/mass of ethanol molecule= 2 X 12 / 46=24 / 46= 0.5217 To convert it into %;- =0.5217 * 100%= 52.17 % % composition ofhydrogen= (6 X mass of H atom)/mass of ethanol mol.= 6 X 1 / 46=0.1304=13.04% % composition ofoxygen= (1 X mass of oxygen atom)/mass of ethanol mol.= 1 X 16 / 46= 16 / 46 To convert it into %;- =0.3478 * 100% =34.78% thus, % composition of ethanol is52.17% C, 13.14% H and 34.78% Oby weight  | 
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| 3429. | 
                                    82.Write IUPAC names of the following compoundsi. BrBriii.CH2 BrBr3 Br | 
                            
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                                   Answer»  1 orhto bromobenzene 1: bromobenzene 2: 1,3,5 tribromobenzene 3:benzybromide  | 
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| 3430. | 
                                    PCRA stands for | 
                            
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                                   Answer»  PCRA stands for Petroleum Conservation Research Association(PCRA) is an organization established in India in 1978, under the aegis of the Indian Ministry of Petroleum and Natural Gas that is engaged in promoting energy efficiency in various sectors of the economy. thanks😀😁😂  | 
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| 3431. | 
                                    name the reaction used in joining railway tracks and name the obtained metal | 
                            
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                                   Answer»  Thermite is the chemical that is used in welding of railway tracks. It is normally a mixture of iron oxide and aluminium metal. When reacted it, Aluminium reduces iron oxide to iron and itself gets oxidised i.e. a redox reaction occurs Fe2O3+ 2 Al → 2 Fe + Al2O3 Due to the exothermic nature the reaction, iron is obtianed in molten form and can be used for welding of the railway tracks.  | 
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| 3432. | 
                                    Compound X and aluminium are used tojoin railway tracks.(i) Identify the compound X.(ii) Name the reaction.(111) Write the equation for it. | 
                            
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                                   Answer»  (i) X is Fe2O3, i.e. iron (III) oxide. (ii)The reaction involved is thermite reaction or aluminothermy. (III)  | 
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| 3433. | 
                                    A hot air balloon has a volume of 2800m at 99° C. What is the volume if theair cools to 80° C?(Ans:2657 m) | 
                            
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                                   Answer»  the volume of the air cool is 2657cm³ 2657 is the right answer  | 
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| 3434. | 
                                    Hot air balloons float in air becauseof the low density of the air inside theballoon. Explain this with the help ofan appropriate gas law. | 
                            
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                                   Answer»  According to Charles law, the volume is proportional to temperature at constant pressure. Now, if gas is heated up, it’s temperature rises hence, its volume also rises.in hot air balloon the air is heated, hence its volume increases so it’s density decreases. As we known that a fluid of less density floats on another object with less density, hence the hot air balloon gets heated up and rises up you know,The operation of a hot air balloon depends on Charles' Law, the Ideal Gas Law, and Archimedes' Principle. heliumballoondisplaces an amount ofair(just like the empty bottle displaces an amount of water). As long as the weight of the helium plus theballoonfabric is lighter than theairit displaces, theballoonwillfloat in the air. It turns out that helium is a lot lighter thanair.  | 
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| 3435. | 
                                    assignment on associated colloids | 
                            
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                                   Answer»  Associated colloids are microheterogeneous systems in which the particles of the colloidal dispersed phase (micelles) are formed by the agglomeration of molecules or ions of the substance dissolved in the dispersion medium. Associationcolloidsare microheterogeneous systems in which the particles of thecolloidaldispersed phase (micelles) are formed by the agglomeration of molecules or ions of the substance dissolved in the dispersion medium. OR, Associated colloids are the colloids which act as electrolyte at low concentration and show colloidal behaviour at high concentration. Example: Soap solution.  | 
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| 3436. | 
                                    , aballoonp sailing in pacific ocean where temperature is 23.4is filled with 2 L whatreaches Indian ocean when temperaair, what will be the volume of balloon when the shipture is 26.1° C | 
                            
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| 3437. | 
                                    p eti neä¸.cryssta atise end unic cell | 
                            
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                                   Answer»  Crystal Lattice Crystal Lattice is a three-dimensional representation of atoms and molecules arranged in a specific order/pattern. In other words, a crystal lattice can be defined as a geometrical arrangement of constituent particles of matter (atoms, ions or molecules) as points in space. There are total 14 possible three-dimensional lattices. Crystal lattices are also known byBravais Lattices, named after the scientist Auguste Bravais. Unit Cell The smallest possible portion or part of the crystal lattice which repeats itself in different directions of the lattice is called the unit cell. Many unit cells combine to geometrically form the crystal lattice.  | 
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| 3438. | 
                                    a. What is meant by radioactivity?b. When is said to be the nucleusunstable? | 
                            
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                                   Answer»  a. Radioactivity defined as the spontaneous emission of particles (alpha, beta,neutron) or radiation (gamma, K capture), or both at the same time, from the decay of certain nuclides that these particles are, due to an adjustment of their internal structure.Radioactivity can be natural or artificial. In natural radioactivity, the substance already has radioactivity in the natural state.In artificial radioactivity, the radioactivity has been induced by irradiation. b.Thenucleusof this kind of atom issaidto be stable. In some atoms the binding energy is not strong enough to hold thenucleus together, and thenucleiof these atoms aresaidto beunstable.Unstableatoms will lose neutrons and protons as they attempt to become stable.  | 
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| 3439. | 
                                    (4) 2.50 atmFor the equilibrium, CH,CH2CH2CH3CH,-CH-CH3(9)CHiso-butaneIf the value of Kc is 3.0, the percentage by mass of iso-butane in the equilibrium mixture would be(1) 75%(3) 30%(2) 90%(4) 60% | 
                            
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| 3440. | 
                                    311. If LPG cylinder contains a mixture of butane and isobutane, then the amount of oxygen that would be required forcombustion of 1 kg of it will beA) 1.8 kgB) 2.7 kgC) 4.5 kgD)3.58 kg | 
                            
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| 3441. | 
                                    convert aniline into iodobemzene | 
                            
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                                   Answer»  the  | 
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| 3442. | 
                                    Write the structure of the alkene formed by dehydrohalogenation1-bromo-1-methylcyclohexane with alcoholic KOH | 
                            
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| 3443. | 
                                    10.Give the structure of the following compoundsi. 3-Bromo-2-methylpentaneiii. 1-Chlorobutaneii. 2-Bromo-3-ethyl-2-methylhexaneiv. 1,1,1-Trichloroethane | 
                            
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                                   Answer»  i.  | 
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| 3444. | 
                                    Draw the structure of carbon compound 1,2-di-Bromo-cyclo-Butan | 
                            
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| 3445. | 
                                    Q.28. Draw the structure for the following compounds: (i) Ethanoic acid (ii) Bromopentane (ii) Butane(iv) Hexanal | 
                            
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| 3446. | 
                                    ii) Aniline to p-bromo aniline | 
                            
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| 3447. | 
                                    (rvpon Mmesqv 0 LML ——“— | 
                            
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                                   Answer»  The actual magnitude of a numerical value or measurement, irrespective of its relation to other values  | 
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| 3448. | 
                                    What are conformations?Please tell me how questions can come in exam regarding this topic | 
                            
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                                   Answer»  The different 3-D shapes a molecule can turn itself into through rotation are calledconformational isomers.They’re the same molecule, but in different shapes. Remember that opposite charges attract, like charges repel? Here’s two “conformations” of ethane, C2H6. In the “conformation” on the left, the bonds on the adjacent carbon atoms are closer together than they are in the “conformation” on the right. Electrons don’t like each other’s company! (like charges repel). Since the bonds in the conformation on the right are farther apart, it is also more stable. What this means is that the molecule on the left feels strain, which can be relieved through rotation of the C-C bond by 60 degrees. (a common term for this is “torsional strain”.)Like when you take a spring, and you twist it – there is a tension that arises there – it wants to twist back to its original state.  | 
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| 3449. | 
                                    L Barium chioride reacts with aluminium sulphate to give aluminium chloridezwo types in which the above reaction can be classified | 
                            
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                                   Answer»  Aluminum sulfate + Barium chloride → Aluminum chloride + Barium sulfate.Al2(SO4)3+ 3BaCl2------> 2AlCl3+ 3BaSO4state two types in which this reaction can be classified.1) Precipitation Reaction2)Double displacement reaction  | 
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| 3450. | 
                                    structure of propane | 
                            
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                                   Answer»  A propane molecule has three carbon atoms and eight hydrogen bonds. Propane has a molecular mass of molar mass is 44.097 g/mol and has a free rotation and a tetrahedral conformation. The structure of propane is given as-   | 
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