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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
If transmitted power is 10 kW, the field strength at a distance is 50 mV/m. If transmitted power is reduced to 2.5 kW, the field strength at the same point will be |
| Answer» E ∝ Pt . | |
| 102. |
Some features of advanced mobile phone service are Which of the above are true? |
| Answer» All the three features are necessary. | |
| 103. |
The carrier frequency will be if L = 50 µH and C = 1 nF. |
| Answer» L = 50 µH, C = 1 nF . | |
| 104. |
In case of probability of the message is 1 to 16 then the information will be |
| Answer» . | |
| 105. |
The saving of power in DSB-SC modulated at 80% is |
| Answer» . | |
| 106. |
A 400 W carrier is modulated to a depth of 75 percent. The total power in modulated wave will be |
| Answer» Sideband frequencies will be fc ± fm. | |
| 107. |
A geostationary satellite |
| Answer» It orbits the earth in a 24 hour period. Thus it appears to be stationed over one spot of the globe. | |
| 108. |
In equally tampered scale, frequency of each tone equals the frequency of lower adjacent tone multiplied by |
| Answer» Since these are 12 intervals in one octave, hence (2)1/12. | |
| 109. |
A carrier is modulated by two modulating waves A and B having modulation indices of 0.6 and 0.8 respectively. The overall modulation index is |
| Answer» . | |
| 110. |
A communication channel disturbed by additive white, Gaussian noise has a bandwidth of 4 kHz and SNR of 15. The highest transmission rate that this channel can support (in k bits/sec) is |
| Answer» Channel capacity = 4000 log2 (1 + 15) = 16000 bits/s. | |
| 111. |
The reactance of coupling capacitor for AC signals in an amplifier, should be |
| Answer» XC for ac signal should be low so that the attenuation is minimum. | |
| 112. |
In a circuit the value of resistor is made four times. The noise voltage generated by this resistance will |
| Answer» Noise voltage ∝ R. | |
| 113. |
A resistor of 10 kΩ has an rms noise voltage of 1 mV under a certain set of conditions. A resistor of 20 kΩ under the same conditions will have an rms noise voltage of |
| Answer» i ∝ R. | |
| 114. |
Which camera tube has highest sensitivity and very wide spectral response? |
| Answer» New vicon has very high sensitivity and very wide spectral response which extends well into infrared region. | |
| 115. |
A computer monitor uses 180 W in normal operation and 20 W in sleep mode. The computer is on all the 24 hours but is in sleep mode for 18 hours a days. The energy units saved in 30 days are |
| Answer» . | |
| 116. |
Resonant circuits are used in |
| Answer» RF amplifiers use resonant loads (L and C in parallel). | |
| 117. |
Linear diode detector utilizes |
| Answer» Detection (also called demodulation) is due to rectification property of diode. | |
| 118. |
In the equivalent circuit of a moving coil cone type loudspeaker, the mass of the moving system is represented by |
| Answer» Mass has inertia and is analogous to inductance. | |
| 119. |
Quantizing error occurs in |
| Answer» An analog number cannot be converted into an exact digital number. This is called quantizing error. | |
| 120. |
In audio cassettes the width of each recording track is |
| Answer» Each track is 2.5 mm wide. | |
| 121. |
The most commonly used transistor amplifier circuit is |
| Answer» Common emitter connection has high power gain, and good current and voltage gains. | |
| 122. |
If aspect ratio is and number of lines in each frame is 625, the number of picture elements in one frame is |
| Answer» Since there are 625 lines in one frame, the number of picture elements is . | |
| 123. |
In a satellite system circular polarization is to be obtained. The antenna used is |
| Answer» Helical antenna produces a circularly polarized radiation if its two components are at right angles and are equal. It is very commonly used in radio telemetry. | |
| 124. |
A horizontal output stage is cutoff for retrace and 40% of trace. If time for each horizontal line is 64 μs and retrace time is 12 μs, the transistor is conducting for about |
| Answer» Total time for each horizontal line = . Time for trace = 64 - 12 = 52 μs. Time for which transistor is not conducting = 12 + 0.4 x 52 = 32.8 ms. Time for which transistor is conducting = 64 - 32.8 = 31 μs. | |
| 125. |
Indicate the false statement: If SWR on a transmission line is infinite, the line is terminated in |
| Answer» If line is OC or SC or terminated in pure reactance, SWR is 1. | |
| 126. |
In TV signals colour burst is used |
| Answer» Colour burst consists of a short train of about 10 cycles sent to the receiver along with synchronous signals. It ensures I and Q phase correctly. | |
| 127. |
The resonant frequency of an R amplifier is 1 MHz and its bandwidth is 10 kHz. The Q factor will be |
| Answer» . | |
| 128. |
It is found that in a telephone system 60 subscribers initiate calls during a 30 minute interval and the total duration of all the calls is 100 minutes. The load is |
| Answer» . | |
| 129. |
The name modem is a contraction of terms modulator demodulator. |
| Answer» Baudot code is 5 bit code. | |
| 130. |
The use of SSB |
| Answer» One side band is eliminated in SSB. Therefore bandwidth is halved. | |
| 131. |
In the absence of noise, if C is channel capacity in bits/s, δ is channel bandwidth in Hz and N is number of coding levels. Then |
| Answer» Hartley law C = 2 δf log2N. | |
| 132. |
The open loop gain of an amplifier is 50 but is likely to change by 20%. If negative feedback with β = 0.1 is used, the change in gain will be about |
| Answer» . Change in gain is about 4%. | |
| 133. |
Audio amplifiers need |
| Answer» Bass means low frequency tones and treble means high frequency tones. | |
| 134. |
Fields are said to be circularly polarised if their magnitudes are |
| Answer» Magnitudes should be equal and phase angle ± 90°. | |
| 135. |
Three analog signals, having bandwidths 1200 Hz, 600 Hz, 600 Hz are sampled at their Nyquist rates, encoded with 12 bit words, and time division multiplexed. The bit rate for the multiplexed signal is |
| Answer» The total message bandwidth = 1200 Hz + 600 Hz + 600 Hz = 2400 Hz Sampling frequency = 4800 samples/sec. Hence, Bit rate = 4800 x 12 57.6 kbps. | |
| 136. |
In a TV, studio the function of vision switcher is to |
| Answer» Viscon switcher has a provision to select any one or more of a large number of inputs and switching then on to outgoing circuits. | |
| 137. |
In the equation of M-ary PSK signal (where E is symbol energy), M becomes large. Then will approach |
| Answer» When M is large, sine term will tend to zero. | |
| 138. |
The trapezoidal pattern of figure is obtained when examining an AM wave by an oscilloscope. Modulation factor of the wave is |
| Answer» . | |
| 139. |
Y signal has maximum percentage of |
| Answer» Y = 0.3 R + 0.59 G + 0.11 B. | |
| 140. |
To ensure good transient response in audio systems the natural frequencies should be |
| Answer» The useful audio range is 40 Hz to 15 kHz. Therefore natural frequency should be outside this range. | |
| 141. |
In a CD player the speed of CD is |
| Answer» Since the circumference of outer tracks is more than that of tracks near the centre, the speed of disc is varied from 200 rpm to 500 rpm. | |
| 142. |
In the output of a DM speech encoder, the consecutive pulses are of opposite polarity during time interval < < . This indicates that during this interval |
| Answer» In delta modulator, when consecutive pulses of polarity are opposite then signal is constant. | |
| 143. |
A fascimile reproduction has a specification of 200 lines per frame, progressive scanning and 5 frames per second. The time to scan one line is |
| Answer» . | |
| 144. |
In an FM system, when the AF is 500 Hz and the AF voltage is 2.4 V, the deviation is 4.8 kHz. If the AF voltage is now increased to 7.2 V, the new deviation will be |
| Answer» Δf' = 2 x 7.2 14.4 kHz New frequency donation will be 14.4 kHz. | |
| 145. |
An AM signal and a narrowband FM signal with identical carriers, modulating signals and modulation index of 0.1 are added together. The resultant signal can be closely approximated by |
| Answer» s(t)AM + s(t)NBFM = A1 sin ωct + A2 cos ωct + (A - B) m m(t) sin ωct it will not be NBFM because μ = 0.1, and SSB with carrier. | |
| 146. |
The equation () = A cos [ω + φ()] where A and ω are constant and φ() is a function of base signal represents Which of the above are true? |
| Answer» This equation can represent frequency, angle and phase modulation. | |
| 147. |
An FM signal with deviation δ is passed through mixer. Its frequency is reduced five fold. The deviation in output of mixer is |
| Answer» Deviation is not affected by mixer. | |
| 148. |
The total number of channels allotted for cellular telephone is |
| Answer» Cellular telephones have been assigned 666 channels (826 to 845 MHz and 870 to 890 MHz). Each channel has width of 30 kHz. | |
| 149. |
Modulation is also called detection. |
| Answer» Demodulation is called detection. | |
| 150. |
The maximum range of a transmitter depends on |
| Answer» Both power and frequency determine the maximum range. | |