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Let the original salary be x. It is given that the new salary is Rs 1,54,000.

Original salary + Increment = New salary

However, it is given that the increment is 10% of the original salary.

Therefore,

x + 10/100  X x = 154000

100x/100 = 15400

x = ( 154000 X 100/100 )

x = 140000

Thus , the original salary war Rs 1,40,000.

C.P. of a VCR = Rs 8000

The shopkeeper made a loss of 4 % on VCR.

This means if C.P. is Rs 100, then S.P. is Rs 96.

When C.P. is Rs 8000, S.P. = Rs ( 96/100 x 8000 )  = Rs 7680

C.P. of a TV = Rs 8000

The shopkeeper made a profit of 8 % on TV.

This means that if C.P. is Rs 100, then S.P. is Rs 108.

When C.P. is Rs 8000, S.P. = Rs ( 108/100 x 8000 ) = Rs 8640

Total S.P. = Rs 7680 + Rs 8640 = Rs 16320 

Total C.P. = Rs 8000 + Rs 8000 = Rs 16000

 Since total S.P.> total C.P., there was a profit. 

Profit = Rs 16320 − Rs 16000 = Rs 320

Profit % = Profit / C.P x 100 = 320/16000 x 100

= 2%

Therefore, the shopkeeper had a gain of 2% on the whole transaction.

Principal = Cost price of the scooter = Rs 42,000 Depreciation = 8% of Rs 42,000 per year

= Rs (42000 x 8 x 1/100)

 = Rs 420 x 8 x 1 = Rs 3360

Value after 1 year = Rs 42000 − Rs 3360 = Rs 38,640

We have,

Percentage of calcium in chalk = 10%

Percentage of carbon in chalk = 3%

Percentage of oxygen in chalk = 12%

Weight of chalk = 2 1/2 kg 

= 5/2 kg 

= 2.5 kg x 1000 g 

= 2500 gm

Amount of carbon in chalk = 3% of 2500 g 

= 3/100 x 2500 

= 25 x 3 

= 75 g

Amount of calcium in chalk = 10% of 2500 g 

= 10/100 x 2500 

= 10 x 25 

= 250 g

Hence, amount of carbon and calcium are 75 g and 250 g respectively.

When an improper fraction is converted into percentage then the answer can also be less than 100.

False

(c) 20.8%

Explanation: 

Radhika bought a car for Rs. 250000.

Cost price = Rs.250000

Its price decreased next year for 10%.

Thus, new price = 250000 – (10/100) × 250000

= 250000 – 25000 = 225000

Again, the price of car decreased by 12% next year. So the price will be:

= 225000 – 225000 × (12/100)

= 225000 – 27000

= 198000

So, the overall decrease in percentage of car price = (250000-198000)/250000 × 100

= (52000/250000) × 100 = 520/25 = 20.8%

Correct answer is 4/5

We have, 150%

For ratio, 150% : 1

= 150/100 : 1

= 3/2 : 1

= 3/2 x 2 : 1 x 2

= 3 : 2

Correct answer is 3:2

females = 30%

males = 40%

= 100 – (30 + 40)

remaining are children = 100 – 70 = 30%

∴ Percentage of children = 30%

By selling a book for Rs 50, a shopkeeper suffers a loss of 10%. The cost price of the book is Rs 60.

Flalse

Amount received after depositing Rs 800 for a period of 3 years at the rate of 12% per annum is Rs 896.

False

Interest paid by Fabina = P x R x T/100

= Rs (12500 x 12 x 3/100)  = Rs 4500

Amount paid by Radha at the end of 3 years = A 

= P(1 + R/100)ⁿ

A = Rs [12500(1 + 10/100)³]

= Rs [12500(100 +10/100)³]

= Rs (12500 x 110/100 x 110/100 x 110/100)

= Rs 16637.50

C.I. = A − P = Rs 16637.50 − Rs 12500 = Rs 4,137.50

The interest paid by Fabina is Rs 4,500 and by Radha is Rs 4,137.50.

Thus, Fabina pays more interest.

Rs 4500 − Rs 4137.50 = Rs 362.50

Hence, Fabina will have to pay Rs 362.50 more.

Correct answer is (a) 100%

Aahuti purchased a house for ₹ 50,59,700 and spent ₹ 40300 on its repairs. To make a profit of 5%, she should sell the house for ₹ 5355000.

Froom the question it is give that,

Cost price of house purchased by Aahuti = ₹ 50,59,700

Amount spent to repair the house = ₹ 40,300

Then, total cost price of house = ₹ 50,59,700 + 40,300

= ₹ 5100000

Profit % = (profit/CP) × 100

5 = ((SP – CP)/CP) × 100

5 = ((SP – 5100000)/5100000) × 100

(5 × 5100000)/100 = SP – 5100000

SP = ₹ 5355000

Interest = (P×R×T)/100 , where T is Time R% is Rate and P is Principal.

Interest = (P × R × T)/100, where

T is Time period

R % is Rate of Interest and

P is Principal.

The difference of interest for 2 years and 3 years on a sum of ₹ 2100 at 8% per annum is ₹ 168.

From the question it is given that,

P = ₹ 2100

Time = 2 years

Rate = 8%

Then, we know the formula of Simple interest I = (P × R × T)/100

I = (2100 × 2 × 8)/100

I = 33600/100

I = ₹ 336

Then,

Time = 3 years

I = (P × R × T)/100

I = (2100 × 3× 8)/100

I = 50400/100

I = ₹ 504

The difference of interest for 2 years and 3 years = 3 years – 2 yeas

= ₹ 504 – ₹ 336

= ₹ 168

To convert a fraction into a per cent, we Multiply it by 100.

A fraction with its denominator 100 is called a per cent.

25 ml is 0.5 per cent of 5 litres

Let us assume 25 ml be Q % of 5 liters.

So, 25 ml = Q % of 5l

25 = (Q/100) × 5 × 1000

Q = (25 × 100)/(5 × 1000)

Q = 0.5%

25 ml is 0.5 per cent of 5 litres.

Interest on Rs 12500 at 18% per annum for a period of 2 years and 4 months is Rs 5250.

Rs.364

Explanation: 

Number of pens = 100

Rate of per pen = Rs.3.50

Cost of 100 pens = 100 × 3.50 = 350

Sales tax on pen = 4%

Total amount paid = 350 × (4/100) + 350

= 350 × 1/25 + 350

= 14 + 350

= 364

Nasim bought a pen for Rs 60 and sold it for Rs 54. His Loss % is 10.

If 20 lemons are bought for Rs 10 and sold at 5 for three rupees, then Profit in the transaction is 20%.

Narain bought 120 oranges at Rs 4 each. He sold 60 % of the oranges at Rs 5 each and the remaining at Rs 3.50 each. His Profit is 10%.

Principal (P) = Rs 10,000

Rate = 8% per annum or 4% per half year

Number of years = 1 year

There are 2 half years in 1 year.

A = P (1 + R/100)ⁿ

= Rs [10000 (1 + 4/100)²]

= Rs [10000 (1 + 1/25)²]

= Rs (10000 x 26/25 x 26/25) = Rs 10816

C.I. = A − P = Rs 10816 − Rs 10000 = Rs 816

(a) Principal (P) = Rs 10, 800

Rate (R) 12 1/2% = 25/2% ( annual )

Number of years (n) = 3

Amount, A = p( 1 + R/100 )ⁿ

= Rs [10800 (1 + 25/200)³]

= Rs [10800(225/200)³]

= Rs ( 10800 x 225/200 x 225/200 x 225/200 )

= Rs 15377.34375

= Rs 15377.34  (approximately)

C.I. = A − P = Rs (15377.34 − 10800) = Rs 4,577.34

(b) Principal (P) = Rs 18,000 

Rate (R) = 10% annual

Number of years (n) = 2 1/2 years

The amount for 2 years and 6 months can be calculated by first calculating the amount for 2 years using the compound interest formula, and then calculating the simple interest for 6 months on the amount obtained at the end of 2 years. Firstly, the amount for 2 years has to be calculated.

A = Rs [18000( 1 + 1/10 )²] 

= Rs (18000 x 11/10 x 11/10)

= Rs 21780

By taking Rs 21780 as principal, the S.I. for the next 1/2 year will be calculated.

S.I = Rs (21780 x 1/2 x 10 / 100) = Rs 1089

∴ Interest for the first 2 years = Rs (21780 − 18000) = Rs 3780

And interest for the next 1/2 year = Rs 1089

∴ Total C.I. = Rs 3780 + Rs 1089 = Rs 4,869

A = P + C.I. = Rs 18000 + Rs 4869 = Rs 22,869

(b) ₹ 2016

From the question it is given that,

A bicycle is purchased for ₹ 1800

Bicycle is sold at a profit of 12%.

Its selling price is =?

We know that, Profit percent = (Profit/CP) × 100

12 = (Profit/₹ 1800) × 100

(12 × 1800)/100 = Profit

Profit = 12 × 18

Profit = ₹ 216

Then, Profit = SP – CP

216 = SP – 1800

SP = 216 + 1800

SP = ₹ 2016

Sonal bought a bed sheet for ₹ 400 and sold it for ₹ 440. Her Profit% is 10.

From the question, it is given that, cost price of bed = ₹ 400

Selling price of bed = ₹ 440

SP is more than CP so, Profit = SP – CP

= 440 – 400

= ₹ 40

We know that, Profit percentage = (Profit/CP) × 100

= (40/400) × 100

= 10%

(b) Rs 4,080

Explanation: 

P = Rs.50000, R = 4%, T = 2 years

A = P(1+R/100)^T 

= 50000(1+4/100)² 

= 50000(1+1/25)²

A = 50000(26/25)² 

= 54080

Compound interest = A – P 

= 54080 – 50000 

= Rs. 4080

(b) R < r

If the total amount received after 2 yr is same for both simple interest and compound interest on same principal, then the rate of simple interest is greater than the rate of compound interest.

i.e.R < r

(c) A earns less profit than B

Explanation: 

Cost price of tape recorder bought by A = Rs.8000

Cost price of tape recorder for B =20% profit on cost price for A

= 20/100 x 8000 + 8000

= 20 x 80 + 8000

= 1600 + 8000

= Rs.9600

Cost price of tape recorder sold to C = 20% profit on cost price for B

= 20/100 x 9600 + 9600

= 1929 + 9600

= Rs.11520

Here, profit for A= Rs.1600 Profit for B = Rs.1920

So, A earns less profit than B.

(a) Rs 1,056

Explanation: 

Marked price = Rs.1200

Discount = 12%

Since, Discount = Discount% on Marked price

Discount price = 12% of 1200 

= 12/100 × 1200 

= 12 × 12 

= 144

Selling price = Marked price-discount price 

= 1200 – 144 

= Rs. 1056

(c) Rs 506

Explanation: 

Price of teapot = Rs. 120

Price of set of cups = Rs. 400

Latika sold teapot at a profit of 5%

Selling price of teapot = 5/100 x 120 + 120

= 120/20 +120

= 6 + 120 = Rs.126

Also, cups were sold at a loss of 5%.

Now, selling price of cups = 400 –5/100 x 400

= 400 – 20

= Rs. 380

Therefore, total amount received = Rs. 126 + Rs. 380 = Rs. 506

(a) 8

Explanation:

Rate of interest is compounded after every three months.

Thus, the time period for amount in a year will be 4 times.

If amount is taken for 2 year, then 4 × 2 = 8 times charged in 2 year.

(a) 5%

Explanation: 

Marked price = Rs. 80

Sold price = Rs.76

We know that,

Selling price = Marked price – Discount

Discount = Marked price – Selling price

Discount = Rs.80-Rs.76 = Rs.4

Discount % = 4/80 x 100 = 5%

(b) Rs. 1400

Explanation: 

Let marked price = x

Discount = 20%

Selling price = 1120

Hence,

1120 = x – x × 20/100

1120 = x – x/5

1120 = 4x/5

x = (1120×5)/4 = 1400

Rs.199.50.

Explanation: 

Marked price = Rs. 200

Discount = 5%

Selling price = 200 – (5/100) × 200

= 200-20

= 190

Selling price including 5% tax = 190+(5/100)×190

= 190 + 9.5

= Rs. 199.5

(a) Rs 500

Explanation: 

Say, marked price = x

Cost price = Rs.360

As per the question;

x – [x×(10/100)] – [(25×360)/100] = 360

x – x/10 – 90 = 360

9x/10 = 360 + 90

9x = 4500

x = 500

We have, total population = 8000

Literate people = 80% of total population = 80/100 x 8000 = 6400

Literate women = 40% of literate people = 40/100 x 6400 = 2560

Ratio of literate women to total population = 2560 : 8000 = 2560/320 : 8000/320 = 8:25

Hence, the ratio of women to total population is 8:25.

Given that, Lemons bought at Rs 48 per dozen and sold at Rs.40 per 10.

⇒ cost of 12 lemons = Rs.48 (∵ 1 dozen lemons = 12 lemons)

⇒ Cost price of 1 lemon = 48/12

= Rs.4

Now,selling price of 10 lemons = Rs.40

⇒ Selling price of 1 lemon = 40/10 

= Rs.4

⇒ cost price of 1 lemon = selling price of 1 lemon

⇒ There is neither profit nor loss.

Given, sita managed to score 32 baskets in 35 attempts.

Need to calculate success rate in percentage.

⇒ Success rate = 32/35 x 100

= 3200/35

= 91.43%

Hence, success rate of sita is 91.43%

(c) Rs 24,937.50

Explanation: 

Cost price of TV set = Rs. 26250.

VAT including = 5%

Original price = Cost price of article including VAT = 26250 – (5/100) x 26250

= 26250-1312.5

= 24,937.50

Therefore, original price of TV set is = Rs. 24,937.50

False

From the question it is given that, P = ₹ 350, R = 5%, T = 73 days = 73/365

As we know that,

I = (P × R × T)/100

I = (350 × 5 × 73)/ (100 × 365)

I = ₹ 3.5

Correct answer is (a) 9 : 4

Let the total number of matches played by the team be x.

It is given that the team won 10 matches and the winning percentage of the team was 40%.

Therefore, 40/100 x X = 10

X = 10 x 100/40

X = 25

Thus, the team played 25 matches.