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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Convert the given fractional numbers to per cents. |
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Answer» (a) `1/8 = 1/8**100 %= 25/2 % = 12.5%` (b)`5/4 = 5/4**100% = 125%` (c)`3/40 = 3/40**100 = 15/2 = 7.5%` (d) `2/7 = 2/7**100 = 200/7 = 28.57%` |
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| 2. |
Population of Rajasthan = 570 lakhs and population of UP = 1660 lakhs.Area of Rajasthan = 3 lakh km2 and area of UP = 2 lakh km2.(i) How many people are there per km2 in both these States?(ii) Which State is less populated? |
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Answer» Q3) 1)Rajasthan=570/3=140`/km^2` UP=1660/2=830`km^2` 2)rajasthan=140*3lakh=420lakh people UP=830*2=1660lakh people population is more in UP. |
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| 3. |
Find the ratio of:(a) Rs 5 to 50 paise (b) 15 kg to 210 g(c) 9 m to 27 cm (d) 30 days to 36 hours |
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Answer» 1) 1Rs=100paise ratio=500/50=10/1=10:1 2)1Kg=1000g ratio=15000/210=500/7=500:7 3)1m=100cm ratio=900/27=100/3=100:3 4)1day=24 hrs ratio=720/36=20/1=20:1. |
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| 4. |
Krishnamurti bought oranges at Rs 5 a dozen. He had to sell them at a loss of `4%`. Find the selling price of one orange. |
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Answer» Krishnamurti bought 12 oranges for Rs.5 Price of one orange`5/12 rupees` he had to sell them at a loss of 4%. Selling price= original price`-4/100 xx 5/12` =>`5/12(1-4/100)` =>`5/12 xx 96/100=4/10` rupees price of 1 orange=40 paise=4/10 rupees |
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| 5. |
The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? |
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Answer» Price of the scooter last year, `P = 34000` Rs Increase in price,` r = 20%` So, Current price, `A = 34000(1+20/100)` `A = 34000**6/5 = 40800` Rs |
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| 6. |
Find the ratio of the following.(a) Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.(b) 5 m to 10 km (c) 50 paise to Rs 5 |
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Answer» 1)ratio=15/30=1/2 2)1km=1000m, 10km=10,000m ratio=5/10,000=1/2,000 3)1Rs=100paise, 5Rs=500paise. ratio=50/500=1/10. |
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| 7. |
There are 20 girls and 15 boys in a class. (a) What is the ratio of number of girls to the number of boys? b) What is the ratio of number of girls to the students in the class? |
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Answer» Number of boys in the class ` =15` Number of girls in the class ` = 20` Total number of students in the class ` = 20+15 = 35` `:.` Ratio of number of girls to the number of boys` = 20/15 = 4/3 = 4:3` Ratio of number of girls to the students in the class `= 20/35 = 4/7 = 4:7` |
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| 8. |
A scooter was bought at Rs 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year. |
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Answer» let that price be x According to Questions x=42000-42000*(8/100) x=42000-2560 x=39,440. |
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| 9. |
The population of a city decreased from 25,000 to 24,500. Find the percentage decrease. |
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Answer» Decrease`= 25000-24500` `= 500` `% `Decrase = decrease/initial population*100 `= 500/25000*100` `= 2 %` answer |
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| 10. |
Arun bought a car for Rs 3,50,000. The next year, the price went uptoRs 3,70,000. What was the Percentage of price increase? |
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Answer» The initial price of the car in rupees `= 350000` Increase in price in one year in rupees ` = 370000-350000 =20000` So, the percentage increase per year ` = 20000/350000**100 = 200/35 = 40/7%` |
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| 11. |
(i) Chalk contains calcium, carbon and oxygen in the ratio 10:3:12. Find the percentage of carbon in chalk.(ii) If in a stick of chalk, carbon is 3g, what is the weight of the chalk stick? |
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Answer» (i)ratio given in a chalk`= 10 : 3: 12` sum of ratios `= 25` `%C= 3/25 xx 100 = 12 %` (ii)weight of C`= 3g` weight of chalk=`x g` Acc to question `3/x = 3/25` `x =25 g` answer |
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| 12. |
Rahul bought a sweater and saved Rs 20 when a discount of 25% wasgiven. What was the price of the sweater before the discount? |
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Answer» Let cost price of sweater in rupees ` = x` Discount in `% = 25` So, `x**25/100 = 20` `x = 4**20=> x = 80` Rs So, price of sweater without discount is `80` rupees. |
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| 13. |
If Meena gives an interest of Rs 45 for one year at 9% rate p.a.. What is the sum she has borrowed? |
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Answer» `I = (P xx R xx T) /100` `45 = (P xx 9 xx 1)/ 100` `P= (45 xx 100)/ 9 = 500 rs` answer |
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| 14. |
A milkman sold two of his buffaloes for Rs 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each) |
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Answer» Let cost of 1 buffalo=x let cost of 2nd buffalo=y Cost + gains=20,000 x+5/100x=20,000 21/20x=20,000 x=4,00,000/21 Cost - loss =20,000 x-1/10y=20,000 9/10y=20,000 y=2,00,000/9 overall gain or loss= `(4,00,000)/21*5/100-(2,00,000)/9*10/100` =20,000/21=20,000/9 =-1269.84 He is in loss of 1269.84 Rs. |
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| 15. |
I borrowed Rs 12,000 from Jamshed at 6% per annum simple interest for 2 years. Had I borrowed this sum at 6% per annum compound interest, what extra amount would I have to pay? |
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Answer» Here, Principal, `P = 12000` Rs Rate of interest, `r = 6%` Time, `t = 2` years So, Simple Interest, `S.I. = (P**r**t)/100 = (12000**6**2)/100=1440` Rs Compound Interest, `C.I. = P((1+r/100)^t-1)` `C.I. = 12000(53/50**53/50 -1) = 12000**0.1236 = 1483.20` Rs So, extra amount paid ` = C.I.-S.I. = 1483.20 -1440 = 43.20` Rupees |
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| 16. |
Find the amount and the compound interest on `Rs 10,000` for `(1) 1/2` years at `10%` per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually? |
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Answer» Principle amount=10,000 Time=1.5 years= 3 half years Interest rate=10% per year=5% per half year `A=P(1+R/100)^n` `A=10,000(1+0.05)^3``A=10,000(1.157)`A=11576 Rs |
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| 17. |
Vasudevan invested Rs 60,000 at an interest rate of 12% per annum compounded half yearly. What amount would he get(i) after 6 months?(ii) after 1 year? |
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Answer» As amount invested is compounded half-yearly, Rate of interest, `r = 12/2 = 6%` per half-yearly Amount invested, `P = 60000` Rs (i) Amount after 6 months, `A_1 = 60000**(1+6/100)^1 = 60000**53/50 = 63600 ` Rs (ii)In one year, time(t) will be `2`. Amount after one year, `A_2 = 60000**(1+6/100)^2 = 60000**53/50**53/50 = 67416` Rs |
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| 18. |
Maria invested Rs 8,000 in a business. She would be paid interest at 5% per annum compounded annually. Find(i) The amount credited against her name at the end of the second year.(ii) The interest for the 3rd year. |
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Answer» Here, Principal , `P = 8000` Rs Rate of interest, `r = 5%` (i) The amount credited at the end of the second year, `A = P(1+r/100)^t` `A = 8000(1+5/100)^2 = 8000**21/20**21/20``A = 20**441 = 8820` Rs (ii) Interest only for the third year can be calculated by finding simple interest on the amount after 2nd year that is, on `8820` Rs as we have calculated in first part. Interest`(I) = (P**r**t)/100 = (8820**5**1)/100 = 441` Rs |
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| 19. |
A shopkeeper purchased 200 bulbs for Rs 10 each. However 5 bulbs were fused and had to be thrown away. The remaining were sold at Rs 12 each. Find the gain or loss %. |
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Answer» The cost price of 200 bulbs in rupees ` = 200**10 = 2000` As 5 bulbs were fused, the total number of bulbs that were sold `= 200-5 = 195` Selling price of all 195 bulbs in rupees `=195**12 = 2340` So, Profit in rupees` = 2340-2000 = 340` So, `%` profit `= 340/2000**100 = 17%` |
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| 20. |
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets ? |
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Answer» Total runs scored by boundaries `= 3**4+8**6 = 60` Total runs scored by running between the wickets ` = 110-60 = 50` `%` of runs scored by running between the wickets ` = 50/110**100 = 500/11 = 45 5/11%` |
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| 21. |
A shopkeeper marks his goods in such a way that after allowing a discount of 12.5% on marked price he still makes a profit of 10%.If the cost price of good is Rs 245, then find its marked price. |
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Answer» the shopkeeper makes a profit of 10%. Gain=selling price-cost price selling price=`245+10/100xx245=Rs.269.5` Now let the marked price be=>X. =>`X-12.5/100xxX=269.5` =>`875/1000xxX=269.5` =>`Rs.308=X` |
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| 22. |
A merchant purchases a wrist watch for `Rs 450` and fixes its list price in such a way that after allowing a discount of `10%`, he earns a profit of `20%`. Then the list price of the watch is |
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Answer» Let the list price of the wrist watch is `x` rupees. As, the merchant had given a discount of `10%` to the list price, `:.` Selling price ` = x**(100-10)/100 = 0.9x` Rs Now, Cost price of the wrist watch `= 450` Rs Profit ` = 20%` `:. 450**(100+20)/100 = 0.9x` `=>450**120/100 = 0.9x` `=>540 = 0.9x` `=> x = 540*10/9 = 600` So, the list price of the watch is `600` Rs. |
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| 23. |
A shopkeeper buys 80 articles for Rs 2,400 and sells them for a profit of 16%. Find the selling price of one article. |
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Answer» Cost of one article=2400/80=30Rs. After 16% profit=30(1.16)=34.8Rs. |
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| 24. |
Amina buys a book for Rs 275 and sells it at a loss of 15%. How much does she sellit for? |
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Answer» Amina buys book for = `rs 275` sells it at loss of `= 15 %` selling price = `CP - loss` `SP = CP - loss` `= 275 - (15 % of 275)` `= 275 - (15 xx 275)/100` `= 275 -165/4` `= 275 - 41.25 = 233.75 rs` answer |
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| 25. |
Ravi buys some toffees at 5 for a rupee and sells them at 2 for a rupee. His gain per cent is |
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Answer» Cost at which ravi bought=`1/5 `rupees. He sells them at =>`1/2 `rupees Gain percent=`(1/2 -1/5)/1/5 xx 100=150%` |
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| 26. |
The population of town increases by 10%annually. If the present population is 22000, find the itspopulation a year ago. |
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Answer» `P+(P*10/100)` `P+0.1P=1.1P` a year pop was x Next year`(x+x*10/100)=2200` `x+0.1x=2200` `1.1x=2200` `x=2000` 1 year ago pop=2000. |
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