Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Production lofting and simple lofting both are same phenomena.(a) True(b) FalseI had been asked this question in an interview.I'd like to ask this question from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

Right answer is (b) False

The best explanation: Lofting is the method for DEFINING EXTERNAL geometry of the aircraft. Production lofting is most detailed TYPE of the lofting. It is USED to provide EXACT and accurate mathematical model of the body.

2.

What do you mean by longitudinal control lines?(a) Smooth lines which controls overall shape of the conic cross-section(b) Lines which expands to vertical direction only(c) Lines which go in horizontal direction only(d) Line which can be expanded only in lateral directionThis question was posed to me during a job interview.Origin of the question is Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Correct answer is (a) SMOOTH lines which controls overall shape of the CONIC cross-section

Easy explanation: Longitudinal control lines are smooth lines through which conic CURVES are connected. SINCE, it CONNECTS all different conics, it will control the overall shape of the body itself during lofting.

3.

Wing has planform area of 2m^2. If wing is paper thin then, find wetted area of the wing.(a) 4m^2(b) 10m^2(c) 5m^2(d) 20m^2The question was posed to me in final exam.Asked question is from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer» RIGHT CHOICE is (a) 4m^2

The best explanation: Given, planform AREA = 2m^2.

Since, wing is PAPER thin wetted are = 2*planform area = 2*2 = 4m^2.
4.

Following diagram shows _____________(a) Circle to square adapter(b) Triangle to circle adapter(c) Triangle to ellipse(d) Elliptic converterI have been asked this question in unit test.I would like to ask this question from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct choice is (a) Circle to square ADAPTER

Best explanation: Above diagram is showing a typical problem during lofting NAMELY, ‘circle to square adapter’. In such cases, DESIGNER is required to loft body with different cross-section. For e.g. A nozzle of typical jet is square at inlet but at front face it is circular. HENCE, such problems are required to be solved through various techniques of circle to square adapter.

5.

Define control station.(a) Original cross-section used for longitudinal control lines(b) Auxiliary lines(c) Conic shape with circle only(d) Elliptic contour onlyI have been asked this question by my school teacher while I was bunking the class.This intriguing question comes from Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer» CORRECT answer is (a) ORIGINAL cross-SECTION used for longitudinal control lines

The explanation is: Control stations are original cross section which are used to develop longitudinal lines. Control stations are also KNOWN as control cross- section. Control stations can be any type of conic curve. It can be circular, elliptic or any c/s as per our REQUIREMENT.
6.

A good sketch should include _______________(a) overall aerodynamic concepts, location of components etc(b) only lifting area(c) only drag area(d) only volumeThis question was addressed to me during an interview for a job.I need to ask this question from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT option is (a) overall aerodynamic concepts, LOCATION of components ETC

Explanation: A GOOD sketch is the one that highlights as much as detail as it can. It should include overall aerodynamic concepts, internal placements of components, landing gear location etc.

7.

Which of the following is an advantage of conic lofting?(a) Availability of diverse curves(b) Availability of simple drag only(c) Availability of simple lift drag(d) Availability of lift and drag onlyI have been asked this question in a job interview.My question comes from Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT option is (a) Availability of DIVERSE curves

For explanation: Conic lofting is DONE by using conic curves. A conic has number of different curves in family such as circle, ELLIPSE etc. We can generate all such shapes via conic lofting. Hence, it is one of the ADVANTAGES of it that it has availability of diverse curves.

8.

An unstable A/C configuration is a typical wing-aft tail body. IF MAC is 4m then, what would be the approximated location of the CG?(a) 2m(b) 5m(c) 6m(d) 7mThe question was asked in final exam.This intriguing question comes from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Right ANSWER is (a) 2M

Explanation: TYPICAL LOCATION Cg for an UNSTABLE wing = 50% of MAC = 50% of 4 = 0.5*4 = 2m.

9.

Buttock-planes are used to __________(a) evaluate the smoothness of A/C fuselage(b) evaluate Lift(c) find lift curve(d) find lift curve slopeThe question was posed to me by my college director while I was bunking the class.Enquiry is from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

Correct option is (a) evaluate the smoothness of A/C FUSELAGE

Easy explanation: BUTTOCK planes or butt planes are vertically oriented cuts which can be used to FIND smoothness of the A/C fuselage. Lift curve SLOPE is found by using lift and AOA. Lift can be estimated by measuring pressure difference between UPPER and lower surface.

10.

Following diagram represents _______________(a) cross-section development via longitudinal control lines(b) vertical plane(c) arbitrary body with circle profile only(d) body with elliptic profile onlyThis question was addressed to me in homework.The doubt is from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct CHOICE is (a) cross-section DEVELOPMENT VIA longitudinal control lines

Explanation: Above diagram is representing the development of a typical cross-section via longitudinal control lines. Lines which are connecting various cross-section is nothing but the longitudinal control line. This diagram is showing EITHER typical plan or SIDE view.

11.

As a designer our task is to generate fuselage through conic lofting method. If an intermediate C/S shape is elliptic then, what should be the appropriate value of conic shape parameter?(a) 0.4142-0.5(b) 0.7(c) 0.8369(d) 1.2-1.5I had been asked this question during an interview.My question is taken from Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer»

The correct ANSWER is (a) 0.4142-0.5

Best explanation: Given, intermediate cross section = elliptic.

Conic shape parameter CSP = DS / DC, where D = midpoint of line drawn from end point A to end point B, C = tangent point, S = SHOULDER point.

When CSP = 0.4142 and AC = BC then it will generate circular shape.

Now, when CSP = 0.5 it will produce parabola. Hence, to generate elliptic cross section value of CSP should be between 0.4142 and 0.5 BASED on our REQUIREMENT.

12.

A constant percent chord line is drawn from root airfoil to tip airfoil in linear interpolation method.(a) True(b) FalseThe question was posed to me by my school principal while I was bunking the class.The question is from Configuration Layout topic in division Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT choice is (a) True

For explanation I would say: Linear interpolation technique is used to create intermediate airfoil section as weighted average. To do so first both airfoils are connected with line. Next STEP is to draw a constant PERCENT chord line from root to tip airfoil. After following RESPECTIVE STEPS we will get airfoil section as per our requirements.

13.

A fighter jet is flying with wing span of 90ft. If mean aerodynamic chord MAC is at 30ft from tip chord then, to design such wing which type of planform should I use?(a) Delta(b) Rectangular(c) Square(d) TriangleI have been asked this question during an online interview.Origin of the question is Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

Right choice is (a) Delta

The best explanation: Given, wing SPAN b=90ft, location of MAC from tip = 30FT

Location of MAC from root y = b/2 – 30ft = 90/2 – 30 = 45-30 = 15ft.

To find planform let’s find TAPER ratio first from y.

Location of MAC is given as, y = (b/6)*(1+t+t^2) / (1+t). …. (1)

From given options, let’s consider delta wing first.

Delta wing has taper ratio near to none. Let’s consider taper ratio to be zero for idle case.

Hence, by substituting value of taper ratio in EQ (1),

Y = (90/6)*1+0+0/1+0 = 90/6 = 15ft.

This value is same as we found earlier from given data. Hence, wing planform is delta.

14.

Process of defining external geometry of an A/C is ___________(a) lofting(b) drafting(c) drawing(d) flutterI got this question in my homework.Question is taken from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Correct answer is (a) LOFTING

Explanation: Lofting is defined as the process in which external geometry of an A/C is defined. It is nothing but the mathematical modelling the OUTER layer of the AIRCRAFT. FLUTTER is RELATED to control surface. Drawing and drafting are related to each other.

15.

Which of the following is correct?(a) Flat wrap technique is cost effective(b) Flat wrap is very costly(c) Flat wrap is not lofting method(d) Flat wrap is very much lift producingThis question was posed to me in an online quiz.Origin of the question is Configuration Layout topic in division Configuration Layout and Loft of Aircraft Design

Answer»

The correct choice is (a) Flat WRAP technique is cost effective

The BEST I can explain: Flat wrap method is USED for flat surfaces. Complex curvature are required more money to fabricate. If a surface is flat-wrapped then we can directly wrap a flat sheet around its cross section. By doing so we can REDUCE the cost and HENCE, it is cost effective.

16.

From following diagram find the value of MAC of wing.(a) 5.8m(b) 6.8m(c) 2.5m(d) 10mThis question was addressed to me in my homework.My doubt stems from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Correct CHOICE is (a) 5.8m

For EXPLANATION: Given, Cr = 10m, Ct = 2M and TAPER ratio t = Ct/Cr = 2/10 = 0.2

MAC is given by,

MAC = (2/3)*Cr*((1+t+t2) / (1+t))

= (2/3)*10*((1+0.2+0.2^2) / (1+0.2)) = 5.79 = 5.8m.

17.

Find the approximated volume for body as shown in below.(a) 77m^3(b) 77m(c) 7.7m(d) 77 cmThis question was addressed to me in exam.This intriguing question comes from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Correct choice is (a) 77m^3

Easy explanation: Volume = area under the curve

= area of triangle + rectangle area + 8 + 4 + 6 = 0.5*6*3 + 5*10 + 8 + 4 + 6 = 9+50+8+4+6 = 77m^3.

18.

A wing has thickness of 15% of chord then, find the approximated wetted area. Given exposed area A is 10m^2.(a) 20.55m^2(b) 26.55(c) 36(d) 56This question was addressed to me during an internship interview.My question is taken from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Right choice is (a) 20.55m^2

The explanation: GIVEN thickness t = 15% of chord = 0.15*c, A = 10m^2.

For given thickness, wetted area AW is given by,

Aw = A*(1.977+0.52*(t/c)) = 10*(1.977+0.52*0.15) = 20.55m^2

19.

Following diagram represents?(a) Wing fillet(b) Wing chamfer(c) T-tail arrangement(d) Wing dragThis question was posed to me in examination.I need to ask this question from Configuration Layout topic in section Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT option is (a) Wing fillet

For EXPLANATION I would say: Wing fillets are arcs as shown in figure. Wing fillets are USED to improve smoothness of the root of the AIRFOIL as shown. This will result in improvement of aerodynamic efficiency. A typical fillet is a circular ARC.

20.

Wetted area of a rectangular body is 64.64m^2. Find the average projected area.(a) 16.16m^2(b) 15.85 m^2(c) 25.368 km(d) 45.45 cmThis question was addressed to me by my school principal while I was bunking the class.This interesting question is from Configuration Layout topic in division Configuration Layout and Loft of Aircraft Design

Answer» CORRECT option is (a) 16.16m^2

The explanation is: GIVEN, AW = 64.64m^2.

Now, average projected AREA A = Aw/4 = 64.64/4 = 16.16m^2.
21.

If for a given fuselage Stop=10m^2, Aside=14m^2, L = 10m then, find the ratio of wetted area to the volume of fuselage.(a) 3.42 per m(b) 6.68 per m^3(c) 8.36 m(d) 4.001I have been asked this question by my college director while I was bunking the class.This intriguing question originated from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

Correct answer is (a) 3.42 per m

The EXPLANATION: GIVEN, Stop=10m^2, Aside=14m^2, L = 10m.

Now ratio of wetted area AW and volume V is given by,

Aw/V = 2*L*(Stop + Aside) / (Stop*Aside)

Aw/V = 2*10*(10+14) / (10*14) = 20*24/140 = 3.42 per m.

22.

Which of the following is correct?(a) We can generate flat wrap surface by using linear interpolation method(b) Flat surfaces can only be generated by using linear interpolation(c) Linear interpolation will never give flat surface(d) Linear interpolation is only used for flat wrap surfacesI have been asked this question in unit test.Asked question is from Configuration Layout topic in division Configuration Layout and Loft of Aircraft Design

Answer»

Correct choice is (a) We can generate flat WRAP surface by using linear interpolation method

To explain: A flat wrap surface has same tangent ANGLES for DIFFERENT conic curves. When linear interpolation method is used, it does not always provide constant cross-sections or c/s with same tangent angles. Hence, it MAY or may not produce flat wrap. We can generate flat wrap by providing some CONSTRAINTS as well.

23.

Wetted area has effect on drag estimation.(a) True(b) FalseThis question was posed to me in a national level competition.My query is from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Correct option is (a) True

To explain I would say: Wetted area will affect the AMOUNT of the fluid FRICTION when it touches the skin of the BODY. Hence, it affects skin friction of the body. As skin friction is affected, the drag ESTIMATION is also been affected.

24.

My fuselage has length of 10.12m and volume of 8m^3. Now if I want to design same fuselage but with volume of 16m^3 then, what should be the length of fuselage? Given, all others parameters are held constant.(a) 5.06m(b) 1012cm(c) 1000mm(d) 6.025mI had been asked this question in exam.The doubt is from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Right choice is (a) 5.06m

Best EXPLANATION: GIVEN, LENGTH of old fuselage L1 = 10.12m, volume of old fuselage V1 = 8m^3.

Now, we are asked to design same fuselage which has volume of 16m^3.

Hence, new volume V2 = 16m^3.

Internal volume V is inversely proportional to length L of the fuselage.

Here, we have been asked held all other PARAMETERS constant.

Hence, L2 = (V1/V2)*L1 = (8/16)*10.12 =5.06m^3.

25.

A fuselage is designed with circular C/S only. Average projected area is 28.2m^2 then, find the wetted area of this fuselage.(a) 88.6m^2(b) 96 m(c) 540cm(d) 253mThis question was posed to me in an online quiz.Asked question is from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

Correct answer is (a) 88.6m^2

Easiest explanation: Given, average projected AREA A = 9 m^2.

Now, WETTED area AW = π*A = π*28.2 = 88.59 = 88.6m^2.

26.

Conic is represented by _____(a) AX^2 + BY^2 + CXY + DX + EY + F = 0(b) AX^2 + BY^2 + CXY + DX + EY = 0(c) AX^2 + BY^2 + CXY + EY + F = 0(d) AX^2 + BY^2 + CXY + DX = 0The question was posed to me in an internship interview.The origin of the question is Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

Right choice is (a) AX^2 + BY^2 + CXY + DX + EY + F = 0

The explanation: A conic is a 2^nd degree curve. Conic in simple mathematical language is defined by USING AX^2 + BY^2 + CXY + DX + EY + F = 0. Constants are based on our requirements. WE can PRODUCE different cross-section shape such as circle, PARABOLA etc. by using conic.

27.

Following diagram is showing an intermediate step of the conic lofting technique. What will be the value of angle marked by’?’?(a) Any arbitrary value(b) Always be 50°(c) Always 20rad(d) Will be AB alwaysI had been asked this question in an interview for internship.This interesting question is from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct option is (a) Any arbitrary value

Easy EXPLANATION: After the selection of end points (A and B) and their tangent point C next step is to find point-S. When it is done the next step is to DRAW a line from a tangent point that can be at any arbitrary angle. This line COULD be at 20°, 50°, 60° or any arbitrary value as we DESIRED. Once, this step is completed then, we can go further to find the next point of conic curve.

28.

A wing is to be loft with span as 2m and reference area of wing is 4m^2. If we want to design the wing with taper ratio of 0.6 then what will be the value of tip chord?(a) 2.5m(b) 2.50m(c) 2.65m(d) 25.6mThis question was posed to me during a job interview.I would like to ask this question from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

Correct CHOICE is (a) 2.5m

Easiest explanation: GIVEN, SPAN b=2m, area S = 4m^2, TAPER ratio t = 0.6

Now, root CHORD Cr is given by,

Cr = 2*s / b (1+t) = 2*4 / 2(0.6+1) = 8/2*1.6 = 2.5m.

29.

For wing to be lofted as shown in below figure, what will be the approximated value of MAC?(a) 8m from l.e.(b) 8m from t.e.(c) 12m from l.e.(d) 12m from t.e.I got this question during an internship interview.The question is from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer» CORRECT choice is (a) 8M from l.e.

The best I can explain: Given, Cr=12m, Ct=3m SPAN = 2*20 = 40m

Taper ratio t = Ct/Cr = 3/12 = 0.25.

Location of MAC, γ = (b/6)*(1+2*t) / (1+t) = (40/6)*(1+2*0.25) / (1+0.25) = 40*(1+0.5)/6*1.25 = 8m from l.e.
30.

If wing has MAC of 8m then, what will be the location of aerodynamic centre?(a) 2m from l.e.(b) 2m from t.e.(c) At l.e.(d) At t.e.The question was posed to me in an internship interview.My question is taken from Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT CHOICE is (a) 2m from l.e.

For explanation: Given, MAC = 8M

Location of aerodynamic center = 25% of MAC = 25% of 8 = 0.25*8 = 2m from l.e.

31.

Fillet radius is typically more at rear of the aircraft.(a) True(b) FalseI had been asked this question in an online quiz.My query is from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct option is (a) True

To EXPLAIN: Fillet arcs can be of constant radius or can be of VARYING radius. TYPICALLY, at REAR of an a/c fillet arc radius is more. This will RESULT in reduction of the flow separation.

32.

Following diagram represents _____(a) development of conic lofting(b) lift curve slope(c) always circular shape(d) drag curve slopeThis question was posed to me in a job interview.This key question is from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct option is (a) DEVELOPMENT of CONIC lofting

For EXPLANATION I would SAY: A typical intermediate step of conic lofting is shown in the figure. Here, ‘A’ and ‘B’ points are selected as per requirements and called END points. C is the tangent point and S is known as the shoulder point for given conic lofting development.

33.

Following diagram will generate _____________(a) square C/S shape(b) circular profile(c) elliptic profile(d) flat surfaceThe question was posed to me during a job interview.This question is from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Correct choice is (a) square C/S shape

The best I can EXPLAIN: Above diagram is showing typical conic development. As shown shoulder point s is much NEAR to the tangent point C. Now as a result of this it will generate square or rectangle cross SECTION depending UPON DISTANCE AC and BC. Hence, correct option will be square.

34.

In linear interpolation method, new airfoil is created as ____________(a) weighted average of root and tip airfoil(b) heavier than the root airfoil always(c) higher chord than root always(d) lower chord than tip alwaysI got this question in a national level competition.I want to ask this question from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

Correct OPTION is (a) weighted average of root and tip airfoil

The best I can explain: Linear interpolation METHOD is used to create new airfoil STATION between root and tip airfoil. In general, root airfoil is based on PERFORMANCE and tip is selected for stall properties. Linear interpolation will give new airfoil as weighted average of the root and tip airfoil.

35.

Total exposed area that would get wet if immersed in fluid is called ____________(a) wetted area(b) volume(c) length(d) planform of wingI got this question in unit test.My question is from Configuration Layout topic in portion Configuration Layout and Loft of Aircraft Design

Answer»

The correct choice is (a) wetted area

The explanation: Wetted area is the total EXPOSED area which would get wet if we immersed body in fluid. Volume is product of area and length or DEPTH. Length is measurement of how long an object is. Wing PLANFORM is SHAPE of wing when viewed from top.

36.

What do you mean by the inboard profile’?(a) Most detailed drawing drawn to show greater details of internal components(b) First design of sketch(c) Inboard parts(d) Outboard partsThe question was asked by my college director while I was bunking the class.Query is from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

The correct option is (a) Most detailed drawing drawn to SHOW greater details of internal components

For explanation: before a DESIGN can be finalized it needs to go through number of iterations. After this iterative process we make a design which has most detailed information. This detailed LAYOUT is called INBOARD profile. TYPICALLY, it is far more detailed than the initial layout.

37.

What is conic lofting?(a) Lofting done by using various conic curves(b) Lofting done by using various circle only(c) Lofting done by using various triangle curves only(d) Lofting done by using various square curves onlyThe question was posed to me by my college director while I was bunking the class.Asked question is from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Correct option is (a) LOFTING done by using various conic curves

Explanation: When lofting is done by using conic curves then, it is termed as conic lofting. Conic lofting MAY include only CIRCLES but it is not mandatory that if conic lofting is MENTIONED then, it will have circles only.

38.

Consider below wing. Calculate the value of span of wing marked by ‘?’.(a) 3.3m(b) 6.66m(c) 3.36m(d) 6.96mThis question was addressed to me in examination.Origin of the question is Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Correct OPTION is (a) 3.3m

For EXPLANATION: Given, Cr = 4M, Ct = 2m, S = 20m^2

Taper ratio t = Ct/Cr = 2/4 = 0.5.

Hence, wing span of given wing b/2 = S/Cr*(1+t) = 20/4*(1+0.5) = 20/4*1.5 = 3.3m.

39.

Which of the following is correct?(a) Generally, tip airfoils are selected for stall characteristics(b) Always root airfoils are elected for stall characteristics(c) Wing twist will increase thrust by engine(d) Wing twist is not considered for layoutThis question was addressed to me in an interview for job.My doubt is from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

Right answer is (a) Generally, TIP airfoils are SELECTED for stall characteristics

To explain: Generally, tip airfoils are selected for gentle stall properties. Root airfoils are selected for best performance. By doing so we will have BETTER wing which has OVERALL good performance and stall properties.

40.

As a designer, our job is to design a wing which has root chord Cr as 1m. What should be the approximate radius of fillet?(a) 0.1m(b) 1m(c) 2m(d) 2.1mThe question was posed to me in final exam.My question is from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

The CORRECT OPTION is (a) 0.1m

Explanation: TYPICALLY fillet RADIUS can be approximated as 10% of the root chord.

Hence, radius = 10% of Cr = 10% of 1 = 0.1*1 = 0.1m.

41.

Find the wetted area of given body.(a) 65m^2(b) 75(c) 85m^2(d) 200The question was asked during an interview.The above asked question is from Configuration Layout in chapter Configuration Layout and Loft of Aircraft Design

Answer»

Right answer is (a) 65m^2

Easiest explanation: For GIVEN diagram,

Wetted AREA Aw = area under the curve = area of triangle + area of rectangle

Aw = (0.5*6*5) + (10*5) = 15+50 = 65m^2.

42.

Following diagram represents?(a) T.e. kick(b) T.e. extension(c) Rounded tip(d) Straight tipThis question was posed to me by my school principal while I was bunking the class.I would like to ask this question from Configuration Layout topic in section Configuration Layout and Loft of Aircraft Design

Answer»

Right answer is (a) T.e. kick

The best I can EXPLAIN: Above figure is often termed as trailing EDGE kick. A straightened out trailing edge will increase the FLAP chord. It also reduces induced drag. Rounded tip will permit air to flow AROUND tip easily.

43.

At maximum thickness point, fillet is in ____________(a) purely vertical plane(b) purely in hp(c) plane at an angle of less than 20° always(d) plane at 45° alwaysI have been asked this question during an internship interview.I need to ask this question from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer» RIGHT choice is (a) purely VERTICAL plane

Best EXPLANATION: FILLET arcs will be normal to wing surface only at the maximum thickness point. At any other section it is not perpendicular to surface. Hence, at maximum thickness point, fillet is in pure vertical plane.
44.

Following diagram represents?(a) Rounded wingtip(b) LEX(c) Midline tip(d) Blended tipThe question was posed to me during an interview.The question is from Configuration Layout in division Configuration Layout and Loft of Aircraft Design

Answer»

Correct option is (a) Rounded wingtip

For explanation I WOULD say: WINGS can have different wingtip shapes. Above figure is showing a typical rounded wingtip. A smoothly rounded tip allows air to flow EASILY around tip. LEX STAND for leading edge extension.

45.

What will be the resulting curve if following cone is cut through plane as shown?(a) Circle(b) Ellipse(c) Rectangle(d) SquareThe question was asked by my school principal while I was bunking the class.Asked question is from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct answer is (a) Circle

The explanation is: CONIC shape is DEPENDENT on the way we cut the cone. As SHOWN in the figure, if conic is cut through a plane which is perpendicular to the AXIS of the cone then, the resultant shape will be a circle. Similarly, if plane is slanted then it will produce an ellipse.

46.

As a designer we need to design a single engine fighter A/C having circular nozzle exhaust. Most appropriate control station for nozzle exhaust is ____________(a) circle with nozzle exhaust diameter(b) square of circle diameter(c) triangular(d) elliptic shapeI had been asked this question in examination.My question is based upon Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer»

The correct option is (a) circle with nozzle exhaust diameter

To EXPLAIN: Control station are the original cross-section which are required to COMPLETE the lofting process. Here, our MAIN body is nozzle which has circular cross-section. Hence, original shape required to LOFT this nozzle will be circular also. Hence, control station should be circle with similar diameter as the nozzle.

47.

What is meant by ’butt-plane 40’?(a) Buttock plane is at a distance of 40 unit from fuselage centerline(b) Buttock plane is at a distance of 20 unit from fuselage centerline(c) Buttock plane is at a distance of 80 from fuselage centerline(d) Buttock plane is at the 40° from fuselage centerlineThe question was asked in an interview for internship.Enquiry is from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

Right option is (a) Buttock plane is at a distance of 40 UNIT from fuselage centerline

To explain: Butt-PLANES or buttock planes are defined as vertically oriented cuts which are used for fuselage lofting VERIFICATION. It cuts from the horizontal INTERSECTION of the A/C with vertical planes. These planes are defined by their distance from centerline. Hence, butt-plane 40 can be interpreted as butt plane is at distance of 40 unit from AIRCRAFT centerline.

48.

As a designer, our task is to design wing layout such that the location of MAC from root chord or centre line is at 8ft. Find the appropriate value of the wingspan if wing is rectangular.(a) 32ft(b) 50ft(c) 28m(d) 32mThis question was posed to me during an online exam.The doubt is from Configuration Layout topic in chapter Configuration Layout and Loft of Aircraft Design

Answer»

The correct choice is (a) 32ft

To elaborate: Given, rectangular wing.

MAC location y = 8FT. As wing is rectangular TAPER RATIO t =1.

Wingspan b = (6*y*(1+ t)) / (1+t+t^2) = 6*8*(1+1) / (1+1+1^2) = 6*8*2/3 = 32ft.

49.

If thickness ratio t/c is less or equal to the 0.05 then, the wetted area is ____(a) Swet = 2.003*Sexposed(b) Swet = 2.003*4*Sexposed(c) Swet = 2/Sexposed(d) Swet = 2*SexposedI had been asked this question in an interview for job.My question is taken from Configuration Layout in section Configuration Layout and Loft of Aircraft Design

Answer»

The correct answer is (a) Swet = 2.003*Sexposed

Explanation: Thin BODY has thickness TENDS to NEGLIGIBLE. For a paper thin body WETTED area is twice of the EXPOSED or true planform area. However, for finite thickness of t <= 0.05*c wetted area is approximated as Swet = 2.003*Sexposed.

50.

A fuselage is configure to have length L. What will be the approximated internal volume (V)?(a) V = 3.4*(Stop*Aside/4L)(b) V = 3.4/4L(c) V = 3.4*(Stop*Aside/4)(d) V = 0.4*(Stop*Aside/L)The question was asked during an interview.I would like to ask this question from Configuration Layout in portion Configuration Layout and Loft of Aircraft Design

Answer»

Right OPTION is (a) V = 3.4*(Stop*Aside/4L)

The explanation is: Internal volume of FUSELAGE will be total available volume for crew, cargo, passenger etc. Typically, from side and TOP VIEW we can estimate internal volume. If area of side is Aside and area of top is Stop then, internal volume is given as, V = 3.4*(Stop*Aside/4L), where L = LENGTH of the fuselage.