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There are 3 important control structures in Python

There are 2 types of looping constructs

Usually in Python, for loop uses the rangeQ function in the sequence to specify the initial, final and increment values. rangeQ generates a list of values starting from start till stop – 1.

for counter_variable in sequence:

statements – block 1

[else: # optional block

statements – block 2]

Program code:

for i in range(1, 6):

for i in range(65, 65 + i)

a = chr (j)

print a

print

(d) Both a and b

Answer is (d) n

The if., else statement provides control to check the true block as well as the false block.

Following is the syntax of ‘if.else’ statement.

Syntax:

if:

statements – block 1

else:

statements – block 2

num 1 = int (input(“Enter first number : “))

num 2 = int (input(“Enter second number : “))

num 3 = int (input(“Enter third number : “))

if (num 1 < num 2) and (num 1 < num 3):

smallest = num 1

elif (num 2 < num 1) and (num 2 < num 3):

smallest = num 2

else:

smallest = num 3

print(” The smallest number is” , smallest)

Output:

Enter first number: 12

Enter second number: 7

Enter third number: 15

The smallest number is 7 

(a) Nested if

num = int(input(“Enter a number : “)) if num > 0:

print (“positive number”)

elif num = = 0:

print(“zero”)

else:

print (“Negative number”)

Output:

Enter a number: 2

positive number

ch = input(“Enter a character : “)

if ch in (‘a’ , ’A’ , ‘e’ , ‘E’ , ‘i’ , ‘I’ , ‘o’, ‘O’ , ‘u’ , ‘U’):

print (ch, ’is a vowel’)

else:

print (ch the letter is not a vowel’)

Output:

Enter a character:

e e is a vowel

While is the entry check loop

n = int (input(“Enter any year”))

if (n % 4 = 0):

print “Leap Year”

else:

print “Not a Leap Year”

Output:

Enter any Year 2000

Leap Year

Program:

for i in range(0, 5):

for j in range(5, i, -1):

print (“*” , end = “”)

print ( )

num 1 = int (input(“Enter first number : “))

num 2 = int (input(“Enter second number : “))

num 3 = int (input(“Enter third number : “))

if (num 1 > num 2) and (num 1 > num 3):

largest = num 1

elif (num 2 > num 1) and (num 2 > num 3):

largest = num 2

else:

largest = num3

print (“The largest number is” , largest)

Output:

Enter first number: 7

Enter second number: 5

Enter third number: 4

The largest number is 7

n = int(input(“Enter any Number : “)) temp = n rev = 0 

while (n >0):

dig = n%10 

rev = rev * 10 + dig

n = n // 10

if (temp = = rev):

print (“palindrome”)

else:

print (“not a palindrome”)

Output: 

Enter any Number 2332

palindrome

Odd Number (3 digits)

for a in range (100, 1000)

if a % 2 = = 1:

print b

Output:

101, 103, 105, 107, .. …… 997, 999

n = input(“Enter any number”) sum = 0 for i in range(i, n + 1): sum = sum + i print “sum = “ , sum

Output:

Enter any number 5 

sum =15

i = 1

while (i< = 6):

for j in range (1, i):

print (j, end = \t’)

print (end = ’\n’)

i+ = 1f