InterviewSolution
Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
The two compounds `[Co(SO_(4))(NH_(3))_(5)]Br` and `[Co(SO_(4))(NH_(3))_(5)]Cl` represent:A. Linkage isomerismB. Ionisation isomerismC. Co-ordination isomerismD. no isomerism |
|
Answer» Correct Answer - D Different complexes |
|
| 102. |
The percentage of `Mg^(2+)` ions in a solution can be tested by adding a solution ofA. Statement-1 is true,Statement-2 is True, Statement-2 is a correct explanation for Statement-5B. Statement- is True, Statement-2 is True, Statement-2 is not a correct explanantion for Statement-5C. Statement-1 is True,Statement-2 is FalseD. Statement-1 is False, Statement-2 is True. |
|
Answer» Correct Answer - C EDTA forms complex with `Ca^(2+)` and `Mg^(2+)`. |
|
| 103. |
The compounds `[Co(SO_(4))(NH_(3))_(5)]Br` and `[Co(SO_(4))(NH_(3))_(5)]Cl`A. Linkage isomerismB. Ionisation isomerismC. coordinatio isomerismD. no isomerism |
|
Answer» Correct Answer - 4 `[Co(SO_(4))(NH_(3))_(5)]Br` and `[Co(SO_(4))(NH_(3))_(5)]Cl` represent no isomerism because they are different compounds. |
|
| 104. |
The shape of `[Co(NH_(3))_(6)]^(3+)` isA. Statement-1 is true,Statement-2 is True, Statement-2 is a correct explanation for Statement-4B. Statement- is True, Statement-2 is True, Statement-2 is not a correct explanantion for Statement-4C. Statement-1 is True,Statement-2 is FalseD. Statement-1 is False, Statement-2 is True. |
|
Answer» Correct Answer - A `[Co(NH_(3))_(6)]^(2+)` , has `7 + 6 xx 2 = 19 e^(-)` `[Co(NH_(3))_(6)]^(3+)` has `6 + 6 xx 2 = 18 e^(-)` `18e^(-)` is more stable . |
|
| 105. |
The type of hybridisation present in `[Cu(NH_(3))_(4)]^(+2)` ion isA. `sp^(3)`B. `dsp^(2)`C. `sp^(3)d`D. `sp^(3)d^(2)` |
|
Answer» Correct Answer - 3 Spectral studies show that one 3d orbital is empty |
|
| 106. |
The magnetic moment of `[Ni(Cl)_(4)]^(2-)` isA. `2.85 BM`B. `1.83 BM`C. `4.86 BM`D. `5.95 BM` |
|
Answer» Correct Answer - 1 `Cl^(-)` is weak field ligands so rearrangement of electron is not possible. Hence `Ni^(+2)` ion contains two unpaired electrons. |
|
| 107. |
`Fe^(3+)` compounds are more stable than `Fe^(2+)` compounds becauseA. Statement-1 is true,Statement-2 is True, Statement-2 is a correct explanation for Statement-3B. Statement- is True, Statement-2 is True, Statement-2 is not a correct explanantion for Statement-3C. Statement-1 is True,Statement-2 is FalseD. Statement-1 is False, Statement-2 is True. |
|
Answer» Correct Answer - A `Fe^(3+)` is hard acid and `F^(-)` is a hard base (Pearson concept) . Stable complex is formed . Further `Fe^(3+)` can oxidize `I^(-)` to `I_(2)`. |
|
| 108. |
Assign the hybridisation, shape and magnetic moment of `K_(2)[Cu(CN)_(4)]`A. `sp^(3)`, tetrahedral, 1.73 BMB. `dsp^(2)` square planar, 1.73 BMC. `sp^(3)`, tetrahedral, 2.8 BMD. `dsp^(2)`, square planar, 2.8 BM |
|
Answer» Correct Answer - 2 In `K_(2)[Cu(CN)_(4)]` complex `Cu^(+2)` has `dsp^(2)` hybridiasation due to strong field ligand. It has one unpaired `e^(-)`. |
|
| 109. |
Which of the following is most stable?A. `[Fe(H_(2)O)_(6)]^(3+)`B. `[Fe(CN)_(6)]^(3-)`C. `[Fe(C_(2)O_(4))_(3)]^(3-)`D. `[FeCl_(6)]^(3-)` |
|
Answer» Correct Answer - 3 Chelate (ring) complexes are most stable. |
|
| 110. |
The magnetic moment of `[Ni(Cl)_(4)]^(2-)` isA. Statement-1 is true,Statement-2 is True, Statement-2 is a correct explanation for Statement-2B. Statement- is True, Statement-2 is True, Statement-2 is not a correct explanantion for Statement-2C. Statement-1 is True,Statement-2 is FalseD. Statement-1 is False, Statement-2 is True. |
|
Answer» Correct Answer - D `Delta_(0)Pt^(2+) gt Delta_(0)Ni^(2+)` , The `Cl^(-)` ligand could pair up `e^(-)` in 5d orbitals but could not pair up `e^(-)` in 3d orbitals . 5d orbitals are more open and diffused than 3d orbitals. |
|
| 111. |
Aqueous solution of `Ni^(2+)` contains `[Ni(H_(2)O)_(6)]^(2+)` and its magnetic moment is 2.83 B.M. When ammonia is added in it, the predicted change in the magnetic moment of solution is:A. It will remain sameB. It increases from 2.83 B.M.C. It decreases from 2.83 B.M.D. It can not be predicted theoretically. |
|
Answer» Correct Answer - 1 In any `Ni^(+2)` octahedral complexes hybridisation is `sp^(3)d^(2)` and `mu=2.83 BM` |
|
| 112. |
Which is a low spin complex?A. `[Fe(CN)_(6)]^(3-)`B. `[Co(NO_(2))_(6)]^(3-)`C. `[Mn(CN)_(6)]^(3-)`D. All of these |
|
Answer» Correct Answer - 4 `CN^(-)` and `NO_(2)^(-)` are strong field ligand complexes hybridisation |
|
| 113. |
Which of the following pairs of d-electron configuration exhibit both low and high spin tetrahedral complexA. `d^(1), d^(2)`B. `d^(3), d^(4)`C. `d^(7), d^(8)`D. `d^(9), d^(10)` |
|
Answer» Correct Answer - 2 `d^(3)` and `d^(4)` system have `e_(g)^(2)t_(2g)^(1)` and `e_(g)^(2)t_(2g)^(2)` (high spin state configuration). `e_(g)^(3)t_(2g)^(0)` and `e_(g)^(4)t_(2g)^(0)` (low spin state configurations) |
|
| 114. |
Which of the following complexes is a paramagnetic complex?A. `K_(2)[Ni(CN)_(4)]`B. `Ni[H_(2)O)_(6)](NO_(3))_(2)`C. `[Co(NH_(3))_(6)]Cl_(3)`D. `[Pt(NH_(3))_(4)]Cl_(2)` |
|
Answer» Correct Answer - 2 `[Ni(H_(2)O)_(6)](NO_(3))_(2)` has two unpaired `e^(-)` due to high spin complex |
|
| 115. |
Which of the following are paramagnetic?A. `K_(4)[Ni(CN)_(4)]`B. `K_(3)[Cr(CN)_(6)]`C. `K_(3)[Co(CN)_(6)]`D. `K_(2)[Ni(CN)_(4)]` |
|
Answer» Correct Answer - 2 In `K_(3)[Cr(CN)_(6)], Cr^(+3)` has `d^(2)sp^(3)` and has there unpaired electrons |
|
| 116. |
The correct order of magnetic moments (spin values in B.M.) among is:A. `[MnCl_(4)]^(2-) gt [CoCl_(4)]^(2-) gt [Fe(CN)_(6)]^(4-)`B. `[MnCl_(4)]^(2-) gt [Fe(CN)_(6)]^(4-) gt [CoCl_(4)]^(2-)`C. `[Fe(CN)_(6)]^(4-) gt [MnCl_(4)]^(2-) gt [CoCl_(4)]^(2-)`D. `[Fe(CN)_(6)]^(4-) gt [CoCl_(4)]^(2-) gt [MnCl_(4)]^(2-)` |
|
Answer» Correct Answer - 1 For `Mn^(+2) to n=5` for `Co^(+2) to n=3` for `Fe^(+2) to n=0` |
|
| 117. |
Which one of the following has lowest value of paramagnetic behaviour?A. `[Fe(CN)_(6)]^(3-)`B. `[Co(CN)_(6)]^(3-)`C. `[Cr(CN)_(6)]^(3-)`D. `[Mn(CN)_(6)}^(3-)` |
|
Answer» Correct Answer - 3 For `Fe^(+3)` and `Mn^(+2) to n=5` For `Co^(+3) to n=4` For `Cr^(+3) to n=3` |
|
| 118. |
The number of geometrical isomers of `[Co(NH_(3))_(3)(NO_(3))_(3)]` isA. `0`B. `2`C. `3`D. `4` |
|
Answer» Correct Answer - 2 `Ma_(3)b_(3)`: facial and meridional |
|
| 119. |
The following solutions requires three moles of `AgNO_(3)` for the complete precipitation of all the chloride ions present in itA. One litre of 1M `[Co(NH_(3))_(6)]Cl_(3)`B. Three litres of 1M `[Co(NH_(3))_(4)Cl_(2)]Cl`C. One litre of 1.5 M `[Co(NH_(3))_(5)Cl]Cl_(2)`D. all the above |
|
Answer» Correct Answer - 4 `n = MxxV` |
|
| 120. |
Complex ions `[NiCl_(4)]^(2-)`,`[Ni(CN_(4)]^(2-)` Similar in theior given properties:A. Oxidation stateB. Co-Ordination numberC. Mangnetic momentD. Clour |
|
Answer» Correct Answer - a,b `[NiCl_(4)]^(2-)` is paramagnetic and `[Ni(CN)_(4)]^(2-)` is diamagnetic . Color is different . |
|
| 121. |
Which does not obey EAN rule?A. `Fe(CO)_(5)`B. `K_(4)[Fe(CN)_(6)]`C. `[Cu(NH_(3))_(4)]SO_(4)`D. `[Co(NH_(3))_(6)]Cl_(3)` |
|
Answer» Correct Answer - 3 `EAN = 29 - 2 + 2xx4 = 35` So, it does not obey EAN rule. |
|
| 122. |
The complex which does not obey EAN rule isA. `[Fe(CO)_(5)]^(0)`B. `[Cr(CO)_(3)(NO)_(2)]^(0)`C. `[Fe(CO)_(3)(NO)_(2)]^(0)`D. `[Fe(CO)_(2)(NO)_(2)]^(0)` |
|
Answer» Correct Answer - c Note that `2NO -= 3CO, NO "is" 3e^(-)` donor and CO is `2e^(-)` donor . |
|
| 123. |
Which does not obey EAN rule?A. `K_(4)[Fe(CN)_(6)]`B. `K_(3)[Fe(CN)_(6)]`C. `[Co(NH_(3))_(6)]Cl_(3)`D. `[Ni(CO)_(4)]` |
|
Answer» Correct Answer - 2 `EAN = Z-x+nxxy`, Z= At number of metal ion, x = charge of metal ion, n=secondary valency |
|
| 124. |
Which of the following obey EAN rule?A. `[Co(NH_(3))_(6)]^(3+)`B. `Cr(CO)_(6)`C. `[V(CO)_(6)]^(-)`D. `[Zn(EDTA)]^(-2)` |
|
Answer» Correct Answer - a,b,c,d All obey EAN rule . |
|
| 125. |
Which of the following obey18`e^(-)`rule?A. `Cr(CO)_(6)`B. `Ni(CO)_(4)`C. `Cr(C_(6)H_(6))_(2)`D. `Fe(C_(5)H_(5))_(2)` |
|
Answer» Correct Answer - a,b,c,d Consider outer electronic configuration. Eg : `[Cr(CO)_(6)] : Cr(O) : d^(4) s^(2) , 6 + 6 xx 2 = 18 e^(-) C_(6) H_(6)` and `C_(5)H_(5)^(-)` are `6pi e^(-)` systems . |
|
| 126. |
Select the correct statementA. Chelatiojn effect is maximum for five and Six memberd ringsB. Greater the charge on the central metal cation greater ,the value of `Delta (CFSE)`C. In complex ion `Delta_(Oct)lt P`(Pairing energy) and it is a low spin complexD. `[CoCl_(2)(NH_(3))_(2)(en)]^(o+)` complex ion will have four different isomers |
|
Answer» Correct Answer - a,b `[CoF_(6)]^(3-)` is a high-spin complex . |
|
| 127. |
Which of the following is correct about Tetraamminedithiocyanato-s cobalt(III) tris(oxalato)cobaltate(III)?A. Formula of the complex is `[Co(SCN)_(2)(NH)_(3)][Co(OX)_(3)]`B. It is a chelating complex and show linkage isomerismC. It shown optical isomerismD. It shows geometal isomerism |
|
Answer» Correct Answer - b,c,d Formula `[Co(SCN)_(2) (NH_(3))_(4)]_(3) [Co(OX)_(3)]` |
|
| 128. |
Match the complexes listed in column-I with characteristic(s) listed in column-II. |
|
Answer» (A-p,q,r) :(B-p,q,r,s) (c-p,q,r):(D-p). (A) CO stronger field ligand comples for pairing of electrons and so `sp^(3)` hybridissation and diamagnetic. Ligand is two electon donor. (B) When NO molecule co-ordinates with metal atom to from metallic nitrosyls, the single electron present in `pi**` antibonding molecular orbital is transferred to metal atom M so that NO molecules is converted into `NO^(+)` since `NO^(+)` is isoelectronic with CO molecule, this ion coordinated with M ion as a two electron donor in metal nitrosyls in the same way as CO coordinatr to M atom in metal carbonyls.Note than NO molecule is a three electron donor. Now the empty `pi**` antibonding molecular orbital can overlap with the filled d-orbital of metal from `M^(-)toNO^(+)pi` bond. (C) `[Ni(PF_(3))_(4)]` has bonding like that of `[Ni(PF_(4))]` |
|
| 129. |
Match the complexes listed in column-I with characteristic (s)/type hybridisation listed in column-II. |
|
Answer» (A-Q,S) ,(B-Q,S) ,(C-P,R), (D-Q,S). (A), (B) `3s^(6)` configuration, `d^(2)sp^(3)` hybridisation. `[CoF_(6)]^(3-)` is a high spin complex and is paramagnetic. ( C) `NO_(2)` strong field ligand, so complex for pairing of electron and thus it is diamagnetic with `d^(2)sp^(3)` hybridisation |
|
| 130. |
Which of the following releases metal slowly to give uniform coating in electroplating is?A. metal saltsB. double saltsC. complex saltD. alums |
|
Answer» Correct Answer - 3 The complex dissociates and existing equilibrium with the ions |
|
| 131. |
The square planar complexes areA. `[Pt(NH_(3))_(2)Cl_(2)]`B. `[Ni(CN)_(4)]^(2-)`C. `[NiCl_(4)]^(2-)`D. `[PtCl_(4)]^(2-)` |
|
Answer» Correct Answer - a,b,d `[NiCl_(4)]^(2-)` is tetrahedral |
|
| 132. |
`Zn^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(2)]^(+2), K_(1) = 2xx10^(-3)` `[Zn(NH_(3))_(2)]^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(4)]^(2+), K_(2) = 1.5xx10^(-3)` Find out the instability constant? |
|
Answer» `K_(C) = K_(1).K_(2) = 2xx10^(-3)xx1.5xx10^(-3) = 3xx10^(-6)` Instability constant is inverse of stability constant `(1)/(K_(C)) = (1)/(3xx10^(-6)) = 3.3xx10^(5)` |
|
| 133. |
The shape of the complex species will be square planar if its coordination number isA. `2`B. `6`C. `5`D. `4` |
|
Answer» Correct Answer - 4 Shape of complex depends on coordinatio number. If coordination number = 4, shape is tetrahedral (or) square planar |
|
| 134. |
Match the complexes listed in column-I with characteristic (s)/type of bridisation listed in column -II |
|
Answer» (A-q,r,t), (B-q,r,t),(C-p,s),(D-r,s). (A) `d^(6)` - configurration, `Co^(3+) rarrd^(2)sp^(3)` diamagnetic. En multidentate ligand - chelation possible. (B) `d^(6)` - configuration, `Co^(3+)` and diamagnetic `rarrd^(2)sp^(3)` Stabillsation through helation -ox multidentate ligand. ( C) `d^(7)` - configuration, `Co^(2+)` and paramagnetic with three unpaired electrons - `sp^(3)d^(2)` (`H_(2)O` weak field ligand). (D) `d^(7)` - configuration `Co^(2+)` and paramagnetic, one electron jumps to 5s - orbital, `d^(2)sp^(3)` |
|
| 135. |
If the formation constant of `[Cu(NH_(3))_(4)]^(2+)` is `2xx10^(3)`, then its dissociation constant isA. `5xx10^(-4)`B. `2xx10^(3)`C. `5xx10^(-2)`D. `0.2xx10^(3)` |
|
Answer» Correct Answer - a `K_(D)=(1)/(K_(F))=(1)/(2xx10^(3))-5xx10^(-2)` |
|
| 136. |
STATEMENT -1 A solution of `[Ni(H_(2)O)_(6)]^(2+)` is geen but a solution of `[Ni(CN)_(4)]^(2-)` is colourless. STATEMENT-2 : : Energy difference between d level (`i.e.Delta`)for `H_(2)O` complex (paramagnetic) is in the visible region and that for the cyano complex (diamagnetic)is in the UV region.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explation for statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
| Answer» Correct Answer - (A) | |
| 137. |
IUPAC name of the complex `[Cu(NH_(3))_(4)]SO_(4)` isA. cuprammonium sulphateB. copper sulphate tetraammoniaC. tetraamminecopper(II) sulphateD. copper ammonium(IV) sulphate |
|
Answer» Correct Answer - 3 IUPAC name of complex `[Cu(NH_(3))_(4)]SO_(4)` is tetraamminecopper(II) sulphate. |
|
| 138. |
Which of the following does not exhibit optical isomerism?A. `[Cr(NH_(3))_(3)]Cl_(3)`B. `[Cr(en)_(3)]Cl_(3)`C. `[Cr(en)_(2)Cl_(2)]Cl`D. `[Cr(en)(NH_(3))_(2) Cl_(2)]Cl` |
|
Answer» Correct Answer - 1 `Ma_(3)b_(3)` complex: no optical isomerism. (Facial & meridonal) |
|
| 139. |
Which one of the following complexes exhibit chirality?A. `[Cr(o x)_(3)]^(3)`B. `cis-[PtCl_(2)(en)]`C. `cis-[RhCl_(2)(NH_(3))_(2)]^(-)`D. `mer-[Co(NO_(2))_(3)("trien")]` |
|
Answer» (A) ,(A) has three symmetrical bidentate lignds white lack plane of symmetry. (B) and ( C) have square planar geometry and plane of symmetry. (D) has one of the plane of symmeter so (B) ,( C) and (D) will not show chirality. |
|
| 140. |
Coordination compounds plays many important roles in animals and plants. The are essential in the storage and transport of oxygen as electrons transfer agents as catalysts and in photosynthesis Wide range of application in daily life takes place through formation of complexes Photographic fixing qualitative and quantitative analysis purification of water metallurgical extraction are some specific worth mentioning The complex `[Fe(H_(2)O)_(5)NO]^(2+)` is formed in the brown ring test for nitrates when freshly prepared `FeSO_(4)` soultion is added to aqueous solution of `NO_(3)^(Θ)` followed by addition of conc. `H_(2)SO_(4)` Select correct statement about this complex (a) Colour change is due to charge transfer (b) It has iron in `+1` oxidation state and nitrosyl as `NO^(o+)` (c ) It has magnetic moment of `3.87BM` confirming three unpaired electrons in Fe (a) All the above are correct statements .A. Colour change is due to charge transferB. It has iron in `+1` oxidation state and nitrosyl as `NO^(+)`C. It has magnetic moment of 3.87 B.M. confirming three unpaired electrons in FeD. All are correct statements |
|
Answer» Correct Answer - D In `[Fe(H_(2)O)_(5)NO]^(+2)` O.S of Fe is +1. Since `NO^(+)` act as ligand `Fe^(+)` has `3d^(7)4s^(0)`. So, it has three unpaired electrons. |
|
| 141. |
Which of the following complexes exhibit optical isomerism?A. trans-tetramminebis (thiocyanato)chromium(III)ionB. cis-diamminedicarbonatocobaltate(III) ionC. trans-diamminedicarbonatocobaltate(III) ionD. cis-bis(glycinato)platinum(II) |
|
Answer» Correct Answer - B Cis `-[Co(NH_(3))_(2)(CO_(3))_(2)]^(-)` ion exhibits optical isomerism. |
|
| 142. |
Which of the following compounds shows optical isomerism?A. `[Cr(C_(2)O_(4))_(3)]^(3-)`B. `[Co(CN)_(6)]^(3-)`C. `[Cu(NH_(3))_(4)]^(2+)`D. `[ZnCl_(4)]^(2-)` |
|
Answer» Correct Answer - 1 `C_(2)O_(4)^(2-)` is a bidetate ligand. |
|
| 143. |
Which of the following isomeric pairs shows ionization isomerism?A. `[Co(NH_(3))_(6)][Cr(CN)_(6)]` and `[Cr(NH_(3))_(6)][Co(CN)_(6)]`B. `[Cr(H_(2)O)_(6)Cl_(3)` and `[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O`C. `[Pt(NH_(3))_(2)Cl_(2)]` and `[Pt(NH_(3))_(4)][PtCl_(4)]`D. `[Co(NH_(3))_(5)Br]SO_(4)` and `[Co(NH_(3))_(5) SO_(4)]Br` |
|
Answer» Correct Answer - 4 In (4) primary valency groups are different. |
|
| 144. |
The coordination number of Pt in cisplatin is _____________ . |
|
Answer» Correct Answer - 4 `cis-[Pt(NH_(3))_(2)Cl_(2)]`. |
|
| 145. |
Which one of the following can get oxidized easily ?A. `[Co(NH_(3))_(6)]^(3+)`B. `[Co(NH_(3))_(6)]^(2+)`C. `Fe(Co)_(5)`D. `Cr(CO)_(6)` |
|
Answer» Correct Answer - b `[Co(NH_(3))_(6)]^(2+) : 25 + 6 xx 2 = 37` , when it gets oxidized it attains `36e^(-)`(Kr). |
|
| 146. |
In Ziesses salt C=C bond length is : `"Note":{{:(C-C"bond length in enthance is 1.54Å"),(C=C"bond length in enthance is 1.34Å"),(C-=C"bond length in enthance is 1.20Å"):}}`A. `1.37A^(@)`B. `1.19A^(@)`C. `1.87A^(@)`D. `1.34A^(@)` |
|
Answer» Correct Answer - a Zieses salt : `K[PtCl_(3)(C_(2)H_(4))]` , On coordination , the electrons are given into `pi^(**)` MO of ethylene. |
|
| 147. |
The ligand that gives dark blue color with curic ion in the laboratory isA. `NH_(3)`B. `I^(-)`C. `CN^(-)`D. `S_(2)O_(3)^(2-)` |
|
Answer» Correct Answer - 1 `[Cu(NH_(3))_(4)]^(2+)` |
|
| 148. |
Which of the following facts about the complex `[Cr(NH_3)_6]Cl_3` is wrong?A. The complexes innvolves `d^(2)sp^(3)` hybridisation and is octahedral shapeB. The complex is paramagneticC. The complex is an outer orbital complexD. The complex gives white prepipitate which silver nitrate solution |
|
Answer» Correct Answer - 3 `d^(2)sp^(3)`, inner orbital complex. |
|
| 149. |
In `[Ti(H_(2)O)_(6)]^(3+)` complex `Ti^(3+)` has only one electron in 3d-orbital. Its spectrum shows a single absorption peak of `5000Å` then correcponding energy is |
|
Answer» `E = (N_(0).hc)/(lambda)` `=(6.023xx10^(23)xx6.63xx10^(-34)xx3xx10^(8))/(5xx10^(-7))` `= 238 kj//mol` |
|
| 150. |
The color of `[Ti(H_(2)O_(6)]^(3+)` is due toA. Charge transfer transitionB. `d to d` transitionC. Ligand to metal charge transfer tranitionD. Metal to ligand charge transfer transition |
|
Answer» Correct Answer - 2 `3d^(1), d to d` transition |
|