InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
The number of geometrical isomers of the [Pt(NH3)2Cl2] is(a) 3(b) 2(c) 4(d) 1 |
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Answer» The answer is (a) 3 |
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| 152. |
The stabilisation of coordination compounds due to chelation is called the chelate effect. Which of the following is the most stable complex species?(i) [Fe(CO)5](ii) [Fe(CN)6]3–(iii) [Fe(C2O4)3]3–(iv) [Fe(H2O)6]3+ |
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Answer» (iii) [Fe(C2O4)3]3– |
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| 153. |
Mention the types of isomerisms in coordination compounds. |
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Answer» There are two principal types of isomerisms in coordination compounds as follows : (A) Stereoisomerism (B) Structural isomerism (OR Constitutional isomerism) (A) Stereoisomerism is further classified as :
(B) Structural isomerism is further classified as :
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| 154. |
Atomic number of Mn, Fe, Co and Ni are 25, 26 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?(i) [MnCl6]3–(ii) [FeF6]3–(iii) [CoF6]3–(iv) [Ni(NH3)6]2+ |
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Answer» (i), (iii) (i) [MnCl6]3– (iii) [CoF6]3– |
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| 155. |
What is the coordination number of(a) Co in [CoCl2(en)2]+ = 6(b) Ir in [Ir(C2O4)2Cl2]3+ and(c) Pt in [Pt(NO2)2(NH3)2] ? |
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Answer» (a) Coordination number of Co in [CoCl2(en)2]+ = 6 (b) Coordination number of Ir in [Ir(C2O4)2 Cl2]3+ = 6 (c) Coordination number of Pt in [Pt(NO2)2 (NH3)2] = 4 |
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| 156. |
Raju : Coordination compounds are coloured. Ramu : No, co-ordination compounds are colourless.1. Whose statement is correct? 2. Explain the reason for your answer. |
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Answer» 1. Raju’s statement is correct. Coordination compounds are usually coloured. 2. The colour of coordination compounds is due to d-d transition. |
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| 157. |
Write the IUPAC names of the following compounds.1. K3M[Fe(CN)6]2. [CO(NH3)5(CO3)]Cl |
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Answer» 1. Potassiumhexacyanoferrate (III) 2. Pentaamminecarbanatocobalt (III) chloride |
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| 158. |
The names of some co-ordination compounds are given below :EDTA Haemoglobin cis-platin Vitamin B12D-penicillamine Chlorophyll Ni(CO)4(a). Classify the above compounds on the basis of application of coordination compounds?(b). There are given some of the coordination compounds Name them.1. K3[Fe(C2O4)3] 2. [Cr(CN)3]3+3. [CoSO4(NH3)4]NO3 4. [CO(NO2)3(NH3)3] |
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Answer» (a). On the basis of application of coordination compounds :
(b). The coordination compounds are : 1. K3[Fe(C2O4)3] – Potassiumtrioxalatoferrate(III) 2. [Cr(CN)3]3+ – Trisethylenediaminechromium(III) ion 3. [CoSO4(NH3)4]NO3 – Tetraamminesulphato- cobalt(III) nitrate 4. [CO(NO2)3 (NH3)3] – Triamminetrinitrito-N-cobalt(III) |
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| 159. |
The charge of Ni in [Ni(CO)4] is(a) +1 (b) +2 (c) 0 (d) +4 |
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Answer» (c) 0 The charge of Ni in [Ni(CO)4] is 0. |
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| 160. |
Naming of mononuclear coordination compounds and rules. |
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Answer» The principle of additive nomenclature is followed while naming the coordination compounds. The following rules are used (i) The cation is named first in both positively and negatively charged coordination entities. (ii) The ligands are named in an alphabetical order before the name of the central atom/ion. (iii) The name of the anionic ligands end in –o, those of neutral and cationic ligands are the same except aqua for H2O, ammine for NH3, carbonyl for CO and nitrosyl for NO. these are placed within enclosing marks . (iv) When the prefixes mono, di, tri, etc., are used to indicate the number of the individual ligands in the coordination entity. When the names of the ligands include a numerical prefix, then the terms, bis, tris , tetrakis are used, the ligand to which they refer being placed in parenthesis. (v) Oxidation state of the metal in cation, anion, or neutral coordination entity is indicated by roman numeral in parenthesis. (vi) If the complex ion is a cation , the metal is same as the element. (vii) The neutral complex molecule is named similar to that of the complex cation. |
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| 161. |
Name the following coordination compounds according to IUPAC system of nomenclature: (i) [Co(NH3)4 (H2O) Cl]Cl2 (ii)[CrCl2(en)2]Cl, (en = ethane –1, 2 – diamine) |
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Answer» (i) Tetraammine aqua chloridocobalt(III)chloride. (ii) Dichlorido bis (ethane-1,2-diamine)chromium(III) Chloride |
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| 162. |
Summarise the rules of IUPAC nomenclature of coordination compounds. |
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Answer» Following rules are followed for naming coordination compounds recommended by IUPAC : 1. In case of a complexion or a neutral molecule, name the ligand first and then the metal. 2. The names of anionic ligands are obtained by changing the ending -ide to -o and -ate to -ato. 3. The name of a complex is one single word. There must not be any space between different ligand names as well as between ligand name and the name of the metal. 4. After the name of the metal, write its oxidation state in Roman number which appears in parentheses without any space between metal name and parentheses. 5. If complex has more than one ligand of the same type, the number is indicated with prefixes, di-, tri-, tetra-, penta-, hexa- and so on. 6. For the complex having more than one type of ligands, they are written in an alphabetical order. Suppose two ligands with prefixes are tetraaqua and dichloro. While naming in alphabetical order, tetraaqua is written first and then dichloro. 7. If the ligand itself contains numerical prefix in its name, then display number by prefixes bis for 2, tris for 3, tetrakis for 4 and so forth. Put the ligand name in parentheses. For example, (ethylenediamine)3 or (en)3 would appear as tris (ethylenediamine) or tris(ethane-l, 2-diamine). 8. The metal in cationic or neutral complex is specified by its usual name while in the anionic complex the name of metal ends with 'ate'. |
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| 163. |
Consider the complexes [Cu(NH3)4][PtCl4] and [Pt(NH3)4] [CuCl4]. What type of isomerism these two complexes exhibit? |
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Answer» Since in these two given complexes, there is an exchange of ligands between cationic and anionic constituents, they exhibit coordination isomerism. |
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| 164. |
Which of the following complexes formed by Cu2+ ions is most stable?(i) Cu2+ + 4NH3 → [Cu(NH3)4]2+, logK = 11.6(ii) Cu2+ + 4CN– → [Cu(CN)4]2–, logK = 27.3(iii) Cu2+ + 2en → [Cu(en)2]2+, logK = 15.4(iv) Cu2+ + 4H2O → [Cu(H2O)4]2+, logK = 8.9 |
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Answer» (ii) Cu2+ + 4CN– → [Cu(CN)4]2–, logK = 27.3 |
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| 165. |
The number of unpaired electrons in [CO(NH3)6]3+ is :(a) 0 (b) 1 (c) 2 (d) 4 |
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Answer» Option : (a) 0 |
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| 166. |
The number of unpaired electrons in [NiClJ2- and [Ni(CN)4]2- are respectively, (a) 2, 2 (b) 2, 0 (c) 0, 0 (d) 1, 2 |
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Answer» Option : (b) 2, 0 |
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| 167. |
In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.(i) Assertion and reason both are true, reason is correct explanation of assertion.(ii) Assertion and reason both are true but reason is not the correct explanation of assertion.(iii) Assertion is true, reason is false.(iv) Assertion is false, reason is true.Assertion:([Fe(CN)6]3– ion shows magnetic moment corresponding to two unpaired electrons.Reason : Because it has d2sp3 type hybridisation. |
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Answer» (iv) Assertion is false, reason is true. |
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| 168. |
Coordination number used in coordination of compounds is somewhat different than that used in solid state. Explain. |
Answer»
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| 169. |
Discuss briefly giving an example in each case the role of coordination compounds in:(i) biological systems(ii) medicinal chemistry and(iii) analytical chemistry(iv) extraction/metallurgy of metals. |
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Answer» (i) Role of coordination compounds in biological systems: (ii) Role of coordination compounds in Medicinal chemistry: Certain coordination compounds of platinum (for example cis-platin) are used for inhibiting the growth of tumors. (iii) Role of coordination compounds in analytical chemistry: During salt analysis, a number of basic radicals are detected with the help of the colour changes they exhibit with different reagents. These colour changes are a result of the coordination compounds or complexes that the basic radicals form with different ligands. (iv) Role of coordination compounds in interaction or metallurgy of metals: The process of extraction of some of the metals from their ores involves the formation of complexes. For example in aqueous solution, gold combines with cyanide ions to form [Au(CN)2]. From this solution, gold is later extracted by the addition of Zn metal. |
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| 170. |
A complex is made of Co (III) and consists of four NH3 molecules and two CI- ions as ligands. What is the charge number and formula of complexion? |
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Answer» The complex ion has formula, [Co(NH3)4CI2]+. The charge number is + 1. |
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| 171. |
The number of ions produced by the complex [CO(NH3)4CI2] Cl is :(a) 1 (b) 2(c) 3 (d) 4 |
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Answer» Option : (b) 2 |
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| 172. |
How many ions are produced from the complex CO(NH3)6Cl2 in solution?(i) 6(ii) 4(iii) 3(iv) 2 |
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Answer» (iii) The given complex can be written as [CO(NH3)6]Cl2 Thus, [CO (NH3)6]+ along with two Cl- ions are produced. |
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| 173. |
Amongst the following ions which one has the highest paramagnetism? (a) [Cr(H2O)6]3+(b) [Fe(H2O)6]2+ (c) [CU(H2O)6]2+ (d) [Zn(H2O)6]2+ |
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Answer» Option : (b) [Fe(H2O)6]2+ |
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| 174. |
Amongst the following ions which one has the highest magnetic moment value?(i) [Cr(H2O)6]3+(ii) [Fe(H2O)6]2+(iii) [Zn(H2O)6]2+ |
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Answer» (i) n = 3 µ = \(\sqrt{n(n+2)}\) = \(\sqrt{3(3+2)}\) = \(\sqrt{15}\) ≈ 4BM (ii) n = 4 µ = \(\sqrt{4(4+2)}\) = \(\sqrt{24}\) ≈ 5 BM (iii) n = 0 |
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| 175. |
CoSO4Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3 to give white precipitate, but does not react with BaCl2. Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3. Answer the following questions. (i) Identify ‘A’ and ‘B’ and write their structural formulas. (ii) Name the type of isomerism involved. (iii) Give the IUPAC name of ‘A’ and ‘B’. |
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Answer» (i) A - [Co(NH3)5SO4]Cl B - [Co(NH3)5Cl]SO4 (ii) Ionisation isomerism (iii) (A), Pentaamminesulphatocobalt (III) chloride (B), Pentaamminechlorocobalt (III) sulphate. |
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| 176. |
What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex? |
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Answer» When white light falls on the complex, some part of it is absorbed. Higher the crystal field splitting, lower will be the wavelength absorbed by the complex. The observed colour of complex is the colour generated from the wavelength left over. |
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| 177. |
The CFSE for octahedral [CoCl6]4– is 18,000 cm–1. The CFSE for tetrahedral [CoCl4]2– will be(i) 18,000 cm–1(ii) 16,000 cm–1(iii) 8,000 cm–1(iv) 20,000 cm–1 |
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Answer» (iii) 8,000 cm–1 |
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