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1.	E. 31). A, D and E2). A, B and C3). B, D and E4). A, B and D
Answer» The DIFFERENCE of Red and Blue colour balls is equal to the number of Blue and Green colour balls; ∴ R – B = B – G or B – R = G – B In both cases: 2B = R + G---- (1) GIVEN that: R + B + G = 15 From equation 1: ⇒ 3B = 15 ⇒ B = 5 Hence, R + G = 10 Possible values of G are: 1, 2, 3, 4, 6, 7, 8, 9 It is given that the probability of getting a Green ball is ALWAYS more than 0.2; ∴ G/15 > 1/5 Or G/15 > 3/15 ∴ G > 3 Hence possible values of G: 4, 6, 7, 8, 9

E. 31). A, D and E2). A, B and C3). B, D and E4). A, B and D

Answer»

The DIFFERENCE of Red and Blue colour balls is equal to the number of Blue and Green colour balls;

∴ R – B = B – G or

B – R = G – B

In both cases:

2B = R + G---- (1)

GIVEN that: R + B + G = 15

From equation 1:

⇒ 3B = 15

⇒ B = 5

Hence, R + G = 10

Possible values of G are: 1, 2, 3, 4, 6, 7, 8, 9

It is given that the probability of getting a Green ball is ALWAYS more than 0.2;

∴ G/15 > 1/5

G/15 > 3/15

∴ G > 3

Hence possible values of G: 4, 6, 7, 8, 9

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