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1.

617 + 6.017 + 0.617 + 6.0017 = ?

Answer» 617.00 6.017 0.617 + 6.0017 -------- 629.6357 ---------
2.

What decimal of an hour is a second ?

Answer» Required decimal = 1 = 1 = .00027 60 x 60 3600
3.

If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?

Answer» 29.94 = 299.4 1.45 14.5 = 2994 x 1 [ Here, Substitute 172 in the place of 2994/14.5 ] 14.5 10 = 172 10 = 17.2
4.

34.95 + 240.016 + 23.98 = ?

Answer» 34.95 240.016 + 23.98 -------- 298.946 --------
5.

How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

Answer» Sum of decimal places = 7. Since the last digit to the extreme right will be zero (since 5 x 4 = 20), so there will be 6 significant digits to the right of the decimal point.
6.

The correct expression of 6. in the fractional form is:

Answer» 6.46  = 6 + 0.46  = 6 + 46   = 594 + 46   = 640 . 99 99 99
7.

4.036 divided by 0.04 gives :

Answer» 4.036 = 403.6 = 100.9 0.04 4
8.

3. - 2. = ?

Answer» 3.87 - 2.59 = (3 + 0.87) - (2 + 0.59) = 3 + 87 - 2 + 59 99 99 = 1 + 87 - 59 99 99 = 1 + 28 99 = 1.28.
9.

The rational number for recurring decimal 0.125125.... is:

Answer» 0.125125... = 0.125 = 125 999
10.

0.002 x 0.5 = ?

Answer» 2 x 5 = 10. Sum of decimal places = 4 0.002 x 0.5 = 0.001
11.

When 0.232323..... is converted into a fraction, then the result is:

Answer» 0.232323... = 0.23 = 23 99
12.

The expression (11.98 x 11.98 + 11.98 x + 0.02 x 0.02) will be a perfect square for equal to:

Answer» Given expression = (11.98)2 + (0.02)2 + 11.98 x x. For the given expression to be a perfect square, we must have 11.98 x x = 2 x 11.98 x 0.02 or x   = 0.04
13.

3889 + 12.952 - ? = 3854.002

Answer» Let 3889 + 12.952 - x = 3854.002. Then x = (3889 + 12.952) - 3854.002    = 3901.952 - 3854.002    = 47.95.
14.

0.04 x 0.0162 is equal to:

Answer» 4 x 162 = 648. Sum of decimal places = 6.So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10-4
15.

The price of commodity increases by 40 paise every year, while the price of commodity increases by 15 paise every year. If in 2001, the price of commodity was Rs. 4.20 and that of was Rs. 6.30, in which year commodity will cost 40 paise more than the commodity ?

Answer» Suppose commodity X will cost 40 paise more than Y after z years. Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40 0.25z = 0.40 + 2.10 z = 2.50 = 250 = 10. 0.25 25 X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.