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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
Find the product: 2.9 × 100 |
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Answer» 2.9 × 100 On multiplying a decimal by 100, the decimal point is shifted to the right by two places. We have, 2.9 × 100 = 290 |
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| 52. |
Find the product: 0.83 × 10 |
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Answer» 0.83 × 10 On multiplying a decimal by 10, the decimal point is shifted to the right by one place. We have, 0.83 × 10 = 8.3 |
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| 53. |
Find the product: 0.08 × 100 |
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Answer» 0.08 × 100 On multiplying a decimal by 100, the decimal point is shifted to the right by two places. We have, 0.08 × 100 = 8 |
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| 54. |
Find the product: 0.6 × 100 |
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Answer» 0.6 × 100 On multiplying a decimal by 100, the decimal point is shifted to the right by two places. We have, 0.6 × 100 = 60 |
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| 55. |
Find the product: 6.7314 × 1000 |
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Answer» 6.7314 × 1000 On multiplying a decimal by 1000, the decimal point is shifted to the right by three places. We have, 6.7314 × 1000 = 6731.4 |
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| 56. |
Find the product: 84.003 × 10 |
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Answer» 84.003 × 10 On multiplying a decimal by 10, the decimal point is shifted to the right by one place. We have, 84.003 × 10 = 840.03 |
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| 57. |
Find the product: 0.06 × 100 |
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Answer» 0.06 × 100 On multiplying a decimal by 100, the decimal point is shifted to the right by two places. We have, 0.003 × 100 = 0.3 |
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| 58. |
Find the product: 7.54 × 10 |
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Answer» 7.54 × 10 On multiplying a decimal by 10, the decimal point is shifted to the right by one place. We have, 7.54 × 10 = 75.4 |
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| 59. |
Find the product: 73.92 × 10 |
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Answer» 73.92 × 10 On multiplying a decimal by 10, the decimal point is shifted to the right by one place. We have, 73.92 × 10 = 739.2 |
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| 60. |
Add: 23.8, 8.94, 0.078 and 214.6 |
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Answer» 23.8, 8.94, 0.078 and 214.6 First convert the given decimals into like decimals. We get, 23.800, 8.940, 0.078 and 214.600 Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column. Writing these decimals in column from and adding, we get: 23.800 8.940 0.078 214.600 ________________ 247.418 ________________ Hence, the sum of the given decimals is 247.418 |
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| 61. |
Subtract: 13.876 from 22 |
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Answer» 13.876 from 22 Converting the decimals into like decimals, we get 13.876 from 22.000 Writing them into column form with the larger one at the top and subtracting, we get: 22.000 -13.876 _____________ 8.124 _____________ Hence (13.876-22) = 8.124 |
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| 62. |
Subtract: 36.74 from 52.6 |
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Answer» 36.74 from 52.6 Converting the decimals into like decimals, we get 36.74 and 52.60 Writing them into column form with the larger one at the top and subtracting, we get: 52.60 -36.74 _____________ 15.86 _____________ Hence (36.74 – 52.6) = 15.86 |
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| 63. |
Add: 26.9, 19.74, 231.769 and 0.048 |
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Answer» 26.9, 19.74, 231.769 and 0.048 First convert the given decimals into like decimals. We get, 26.900, 19.740, 231.769 and 0.048 Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column. Writing these decimals in column from and adding, we get: 26.900 19.740 234.769 0.048 ______________ 278.457 ______________ Hence, the sum of the given decimals is 278.457 |
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| 64. |
Take out of 3.547 from 7.2. |
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Answer» Given 3.547 from 7.2 7.2 – 3.547 3.653 |
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| 65. |
Find the product:(i) 4.74 × 10(ii) 0.45 × 10(iii) 0.0215 × 10(iv) 0.0054 × 10 |
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Answer» (i) Given 4.74 × 10 Here we have to do normal multiplication with shifting the decimal point by one place to the right Therefore 4.74 × 10 = 47.4 (ii) Given 0.45 × 10 Here we have to do normal multiplication with shifting the decimal point by one place to the right Therefore 0.45 × 10 = 4.5 (iii) Given 0.0215 × 10 Here we have to do normal multiplication with shifting the decimal point by one place to the right Therefore 0.0215 × 10 = 0.215 (iv) Given 0.0054 × 10 Here we have to do normal multiplication with shifting the decimal point by one place to the right Therefore 0.0054 × 10 = 0.054 |
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| 66. |
By how much should 59.71 be decreased to get 34.58? |
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Answer» Let x be the unknown number 59.71 – x =34.58 59.71 – 34.58 = x x = 59.71 – 34.58 x = 25.13 25.13 should be decreased by 59.71 to get 34.58 |
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| 67. |
What is to be added to 36.85 to get 59.41? |
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Answer» Given 36.85 and 59.41 Let the unknown number be x x + 36.85 = 59.41 x = 59.41 – 36.85 x = 22.56 Hence 22.56 is to be added to 36.85 to get 59.41 |
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| 68. |
Find the product:(i) 3.14 × 17(ii) 0.745 × 12(iii) 28.73 × 47(iv) 0.0415 × 59 |
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Answer» (i) Given 3.14 × 17 First multiply as usual without looking at the decimal point 3.14 × 17 = 578 Now mark the decimal point in the product to have one place of decimal as there in the given decimal 3.14 × 17 = 57.8 (ii) Given 0.745 × 12 First multiply as usual without looking at the decimal point 0.745 × 12 = 894 Now mark the decimal point in the product to have three places of decimal as there in the given decimal 0.745 × 12 = 8.94 (iii) Given 28.73 × 47 First multiply as usual without looking at the decimal point 28.73 × 47 = 135031 Now mark the decimal point in the product to have two places of decimal as there in the given decimal 28.73 × 47 = 1350.31 (iv) Given 0.0415 × 59 First multiply as usual without looking at the decimal point 0.0415 × 59 = 24485 Now mark the decimal point in the product to have four places of decimal as there in the given decimal 0.0415 × 59 = 2.4485 |
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| 69. |
Find:(i) 1.07 × 0.02(ii) 211.9 × 1.13(iii) 10.05 × 1.05(iv) 13.01 × 5.01 |
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Answer» (i) Given 1.07 × 0.02 First multiply as usual without looking at the decimal point 1.07 × 0.02 = 00214 Sum of the decimals is 4 Now mark the decimal point in the product to have four places of decimal as there in the given decimal 1.07 × 0.02 = 0.0214 (ii) Given 211.9 × 1.13 First multiply as usual without looking at the decimal point 211.9 × 1.13 = 239447 Sum of the decimals is 3 Now mark the decimal point in the product to have three places of decimal as there in the given decimal 211.9 × 1.13 = 239.447 (iii) Given 10.05 × 1.05 First multiply as usual without looking at the decimal point 10.05 × 1.05 = 105525 Sum of the decimals is 4 Now mark the decimal point in the product to have four places of decimal as there in the given decimal 10.05 × 1.05 = 10.5525 (iv) Given 13.01 × 5.01 First multiply as usual without looking at the decimal point 13.01 × 5.01 = 651801 Sum of the decimals is 4 Now mark the decimal point in the product to have four places of decimal as there in the given decimal 13.01 × 5.01 = 65.1801 |
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| 70. |
Find the product: 11.1 × 1.1 × 0.11 |
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Answer» 11.1 × 1.1 × 0.11 First we find the product of 111 × 11 × 11 Now, =111 × 11 = 1221 = 1221 × 11= 13431 Sum of decimal places in the given decimals = 4 So, the product must contain 3 places of decimals. ∴ 11.1 × 1.1 × 0.11= 1.3431 |
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| 71. |
What should be added to 3.07 to get 3.5?a) 0.57 b) 0.34 c) 0.43 d) 0.02 |
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Answer» c) 0.43 Let us assume the missing number be x, Then, = 3.07 + x = 3.5 By sending 3.07 from left hand side to the right hand side it become -3.07. We get, = 3.5 – 3.07 = x = 0.43 |
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| 72. |
Divide: 0.02 by 100 |
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Answer» 0.02 by 100 On dividing a decimal by 100, the decimal point is shifted to the left by two places. We have, = 0.02 ÷ 100 = (0.02/100) = 0.0002 |
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| 73. |
Find the product: 0.2 × 0.02 × 0.002 |
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Answer» 0.2 × 0.02 × 0.002 First we find the product of 2 × 2 × 2 Now, =2 × 2 = 4 = 4 × 2= 8 Sum of decimal places in the given decimals = 6 So, the product must contain 3 places of decimals. ∴ 0.2 × 0.02 × 0.002= 0.000008 |
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| 74. |
Add the following:(i) 41.8, 39.24, 5.01 and 62.6(ii) 18.03, 146.3, .829 and 5.324 |
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Answer» (i) Given 41.8, 39.24, 5.01 and 62.6 41.8 39.2 5.01 + 62.6 148.65 (ii) Given 18.03, 146.3, 0.829 and 5.324 18.03 146.3 0.829 + 5.324 170.483 |
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| 75. |
(1.007- 0.7) = ?a) 1 b) 0.37 c) 0.307 d) none of these |
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Answer» c) 0.307 First convert the given decimals into like decimals = (1.007 – 0.700) = 0.307 |
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| 76. |
Divide: 1286.5 by 1000 |
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Answer» 1286.5 by 1000 On dividing a decimal by 1000, the decimal point is shifted to the left by three places. We have, = 1286.5 ÷ 1000 = (1286.5/1000) = 1.2865 |
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| 77. |
Divide: 0.58 by 100 |
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Answer» 0.58 by 100 On dividing a decimal by 100, the decimal point is shifted to the left by two places. We have, = 0.58 ÷ 100 = (0.58/100) = 0.0058 |
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| 78. |
What should be subtracted from 0.1 to get 0.03?a) 0.7 b) 0.07 c) 0.007 d) none of these |
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Answer» b) 0.07 Let us assume the missing number be x, Then, = 0.1 – x = 0.03 By sending – x from left hand side to the right hand side it become x and 0.03 from right hand side to the left hand side it become -0.03. We get, = 0.1 – 0.03 = x = 0.07 |
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| 79. |
Find the product: 2.1 × 0.21 × 0.021 |
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Answer» 2.1 × 0.21 × 0.021 First we find the product of 21 × 21 × 21 Now, =21 × 21 = 441 = 441 × 21= 9261 Sum of decimal places in the given decimals = 6 So, the product must contain 3 places of decimals. ∴ 2.1 × 0.21 × 0.021= 0.009261 |
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| 80. |
Evaluate: (1.2)2 |
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Answer» (1.2)2 The above question can be written as, (1.2) × (1.2) First we find the product of, = (12) × (12) = 144 Sum of decimal places in the given decimals = 2 So, the product must contain 2 places of decimals ∴ (1.2)2 = 1.44 |
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| 81. |
Find the area of a rectangle whose length is 5.5m and breadth is 3.4m. |
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Answer» Given length of rectangle = 5.5m Breadth of rectangle = 3.4 m Area of rectangle = length × breadth = 5.5 × 3.4 = 18.7 m2 |
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| 82. |
By how much should 34.79 be increased to get 70.15? |
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Answer» Let x be the unknown number x + 34.79 = 70.15 x = 70.15 – 34.79 x = 35.36 35.36 should be increased to 34.79 to get 70.15 |
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| 83. |
Between Which two Whole numbers on the number line are the given numbers lie? Which of these Whole numbers is nearer the number?(a) 0.8(b) 5.1(c) 2.6(d) 6.4(e) 9.1(f) 4.9 |
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Answer» (a) 0.8 lies between 0 and 1, and is nearest to 1. (b) 5.1 lies between 5 and 6, and is nearest to 5. (c) 2.6 lies between 2 and 3, and is nears to 3. (d) 6.4 lies between 6 and 7, and is nears to 6. (e) 9.1 lies between 9 and 10, and is nears to 9. (f) 4.9 lies between 4 and 5, and is nears to 5. |
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| 84. |
Find the product:(i) 2.506 × 1000(ii) 20.708 × 1000(iii) 0.0529 × 1000(iv) 1000 × 0.1 |
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Answer» (i) Given 2.506 × 1000 Here we have to do normal multiplication with shifting the decimal point by three places to the right Therefore 2.506 × 1000 = 2506 (ii) Given 20.708 × 1000 Here we have to do normal multiplication with shifting the decimal point by three places to the right Therefore 20.708 × 1000 = 20708 (iii) Given 0.0529 × 1000 Here we have to do normal multiplication with shifting the decimal point by three places to the right Therefore 0.0529 × 1000 = 52.9 (iv) Given 1000 × 0.1 Here we have to do normal multiplication with shifting the decimal point by three places to the right Therefore 1000 × 0.1 = 100 |
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| 85. |
Find the product:(i) 35.853 × 100(ii) 42.5 × 100(iii) 12.075 × 100(iv) 100 × 0.005 |
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Answer» (i) Given 35.853 × 100 Here we have to do normal multiplication with shifting the decimal point by two places to the right Therefore 35.853 × 100 = 3585.3 (ii) Given 42.5 × 100 Here we have to do normal multiplication with shifting the decimal point by two places to the right Therefore 42.5 × 100 = 4250 (iii) Given 12.075 × 100 Here we have to do normal multiplication with shifting the decimal point by two places to the right Therefore 12.075 × 100 = 1207.50 (iv) Given 100 × 0.005 Here we have to do normal multiplication with shifting the decimal point by two places to the right Therefore 100 × 0.005 = 0.5 |
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| 86. |
One meter of cloth costs Rs 152.50. What is the cost of 10.75 meters of cloth? |
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Answer» Given that cost of 1m cloth = Rs 152.50 Cost of 10.75 m of cloth = 152.50 × 10.75 = Rs 1639.375 |
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| 87. |
1)which is greater 1 or 0.99 and 1.093 or 1.092)Lata spent Rs 9.50 for buying a pen and Rs 2.50 for one pencil.How much money did she spend? |
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Answer» (1) `1 = 0.99+0.01` So, `1 gt 0.99` `1.093 = 1.092+0.001` So, `1.093 gt 1.092` (2) Money spent by Lata to buy a pen ` = 9.50 ` Rs Money spent by Lata to buy a pencil ` = 2.50 ` Rs Total money spent by Lata `= 9.50+2.50 = 12` Rs |
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| 88. |
Rahul bought 4 kg 90 g of apples, 2 kg 60 g of grapes and5 kg 300 g of mangoes. Find the total weight of all the fruits he bought |
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Answer» Weight of apples bought by Rahul ` = ` 4 kg 90g ` = 4.090` kg Weight of grapes bought by Rahul ` = ` 2 kg 60g ` = 2.060` kg Weight of mangoes bought by Rahul ` = ` 5 kg 300g ` = 5.3` kg So, total weight of fruits ` = 4.090+2.060+5.300 = 11.450` kg |
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| 89. |
Fill in each of the place holders with the correct symbol > or <.(i) 78.23 ……. 69.85(ii) 3.406……3.46(iii) 5.68……5.86(iv) 14.05……14.005(v) 1.85……1.80(vi) 0.98……1.07 |
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Answer» (i) 78.23 ……. 69.85 By comparing whole numbers 78 > 69 ∴ 78.23>69.85 (ii) 3.406……3.46 By comparing whole number, 3 = 3 By comparing the tenths place digit, 4 = 4 By comparing the hundredths place digit, 0 < 6 ∴ 3.406 < 3.46 (iii) 5.68……5.86 By comparing whole number, 5 = 5 By comparing the tenths place digit, 6 < 8 ∴ 5.68 < 5.86 (iv) 14.05……14.005 By comparing whole number, 14 = 14 By comparing the tenths place digit, 0 = 0 By comparing the hundredths place digit, 5 > 0 ∴ 14.05 > 14.005 (v) 1.85……1.80 By comparing whole number, 1 = 1 By comparing the tenths place digit, 8 = 8 By comparing the hundredths place digit, 5 > 0 ∴ 1.85 > 1.80 (vi) 0.98……1.07 By comparing whole number, 0 < 1 ∴ 0.98 < 1.07 |
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| 90. |
Write each of the following as a decimal.(a) Three hundred six and seven-hundredths(b) Eleven point two three five(c) Nine and twenty five thousandths |
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Answer» (a) Three hundred six and seven-hundredths `= 306+7/100 = 306.07` (b) Eleven point two three five ` = 11+ .235 = 11.235` (c) Nine and twenty five thousandths ` = 9+25/1000 = 9.025` |
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| 91. |
Add: 9.09, 0.909, 99.9, 9.99, 0.099 |
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Answer» 9.09, 0.909, 99.9, 9.99, 0.099 First convert the given decimals into like decimals. We get, 9.090, 0.909, 99.900, 9.990, 0.099 Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column. Writing these decimals in column from and adding, we get: 9.090 0.909 99.900 9.990 0.099 ____________ 119.988 _____________ Hence, the sum of the given decimals is 119.988. |
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| 92. |
Write each of the following as decimals:(a) Seven – tenths(b) Two tens and nine – tenths(c) Fourteen point six(d) One hundred and two ones(e) Six hundred point eight |
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Answer» (a) Seven – tenths 7/10 = 0.7 (b) Two tens and nine – tenths 20 + 9/10 = 20.9 (c) Fourteen point six 14.6 (d) One hundred and two ones 100 + 2 = 102.0 (e) Six hundred point eight 600.8 |
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| 93. |
Subtract :(a) Rs 18.25 from Rs 20.75(b) 202.54 m from 250 m(c) Rs 5.36 from Rs 8.40(d) 2.051 km from 5.206 km(e) 0.314 kg from 2.107 kg |
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Answer» (a) `20.75` Rs `-` `18.25` Rs` = 2.50` Rs (b)`250m -202.54m = 47.46 m` (c) `8.40` Rs `-` `5.36` Rs` = 3.04` Rs (d) `5.206` km `-` `2.051`km `= 3.155` km (e) ` 2.107` kg `-` `0.314` kg `= 1.793` kg |
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| 94. |
Convert 6.004 as a mixed fraction. |
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Answer» 6.004 Now write the given decimal without the decimal point as the numerator of the fraction. In the denominator, write 1 followed by as many zeros as there are decimal places in the given decimal. Then we have, = 6.004 = (6004/1000) Now reduce the above fraction to the simplest form. = (6004/1000) … [÷ by 2] = (1501/250) = [6(1/250)] |
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| 95. |
Convert 5.6 as a mixed fraction. |
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Answer» 5.6 Now write the given decimal without the decimal point as the numerator of the fraction. In the denominator, write 1 followed by as many zeros as there are decimal places in the given decimal. Then we have, = 5.6 = (56/10) Now reduce the above fraction to the simplest form. = (56/10) … [÷ by 2] = (28/5) = [5(3/5)] |
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| 96. |
Fill in the blanks to make the statement true.5 rupees 5 paise = ₹________. |
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Answer» 5 rupees 5 paise = ₹ 5.05 |
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| 97. |
Write each of the following as decimals:-(a) 88/10(b) 2/10(c) 3/2(d) 2/5 |
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Answer» (a) 88/10 = 80/10 + 8/10 = 8 + 0.8 = 8.8 (b) 2/10 = 4 + 2/10 = 4 + 0.2 = 4.2 (c) 3/2 = (2 + 1)/2 = 2/2 + 1/2 = 1 + 0.5 = 1.5 (d) 2/5 = 0.4 |
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| 98. |
Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her |
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Answer» Length of cloth bought for Nasreen shirt = 3m 20cm` = 3m+20/100m = 3.2m` Length of cloth bought for Nasreen trouser = 2m 5cm `= 2m+5/100m = 2.05m` So, total lenght of cloth bought by Nasreen `=3.2+2.05 = 5.25m = 5m 25cm` |
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| 99. |
Urmila’s school is at a distance of 5 km 350 m from her house.She travels 1 km 70 m on foot and the rest by bus. How much distance does she travel by bus? |
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Answer» Total distance=5.350 km distance traveled by on foot=1.070 km distance travelled by bus=total distance traveled - distance travelled by on foot =5.35-1.07 =4.28 km. |
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| 100. |
Express as km using decimals.(a) 8 m(b) 88 m(c) 8888 m(d) 70 km 5 m |
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Answer» (a) 8 m = 8/1000 = 0.008 km (b) 88 m = 88/1000 = 8.888 km (c) 8888 m = 8888/1000 km = 8.888 km (d) 70 km 5 m = (70 + 5/1000) km = 70.005 km |
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