A wire can be broken by applying a load of 20kg wt. Then the force required to break the wire of twice the diameter and same length same material isA. 5 kg wtB. 160 kg wtC. 80 kg wtD. 20 kg wt

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1.	A wire can be broken by applying a load of 20kg wt. Then the force required to break the wire of twice the diameter and same length, same material, isA. 5 kg wtB. 160 kg wtC. 80 kg wtD. 20 kg wt
Answer» Correct Answer - C Breaking force = Stress `xx` Area `theefore " Stress"=("Breaking force")/("Area")=(20)/(pi D^(2)//4)` `i.e. (20)/(pi D^(2)//4)=(Fxx4)/(pi (2D)^(2))=80` kg wt

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A wire can be broken by applying a load of 20kg wt. Then the force required to break the wire of twice the diameter and same length, same material, isA. 5 kg wtB. 160 kg wtC. 80 kg wtD. 20 kg wt