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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
401. |
A uniformly wound long solenoid of inductance `L` and resistance `R` is cut into two parts in the ratio `eta:1`, which are then connected in parallel. The combination is then connected to a cell of emf `E`. The time constant of the circuit isA. `L//R`B. `L//2R`C. `2L/R`D. `L//4R` |
Answer» Correct Answer - A |
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402. |
When a coil is joined to a cell, the current through the cell grows with a tiem constant `tau`. The current will reach `10%` of its steady-state value of timeA. `0.1tau`B. `tau In (0.1)`C. `tauIn (0.9)`D. `tauIn (10-9)` |
Answer» Correct Answer - D |
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403. |
Two long thin wires ABC and DEF are arranged as shown in Fig. They carry equal currents I as shown. The magnitude of the magnetic field at O is A. zero only at the centre of the loopB. `(mu_(0)I)/(4pia)`C. `(mu_(0)I)/(2pia)`D. `(mu_(0)I)/(2sqrt(2)pia)` |
Answer» Correct Answer - C |
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404. |
In the current shown Fig., `X` is joined to `Y` for a long time and then `X` is joined to `Z`. The total heat produced in `R_(2)` is A. `(L varepsilon^(2))/(2R_(1)^(2))`B. `(Lvarepsilon^(2))/(2R_(2)^(2))`C. `(Lvarepsilon^(2))/(2R_(1)R_(2))`D. `(Lvarepsilon^(2)R_(2))/(2R_(1)^(3))` |
Answer» Correct Answer - A |
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405. |
In the circuit shown in fig.. Time constant and steady state current will be A. `0.25 s, 0.75 A`B. `0.75 s, 0.25 A`C. `0.25 s, 0.25 A`D. `0.5 s, 0.5 A` |
Answer» Correct Answer - A |
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406. |
In the circuit shows in Fig, the coil has inductance and resistance. When `X` is joined to `Y`, the time constant is `tau` during the growth of current. When the steady state is reached, heat is produced in the coil at a rate `P`. `X` is now joined to `Z`. After joining `X` and `Z`: A. The total heal produced in the coil is `P tau`B. The total heat producd in the coil is `1/2 Ptau`C. The total heat produced in the coil is `2Ptau`D. The data given is not sufficeint to reach a conclusion |
Answer» Correct Answer - B |
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407. |
If fig. the difference of potential between (B) and (D) is - A. `+ 0.67 V`B. `-0.67V`C. `2V`D. `1.33V` |
Answer» Correct Answer - C |
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408. |
A wire of resistance `0.5 omega m^(-1)` is bent into a circle of radius `1m`. The same wire is connected across a diameter `AB` as shown in fig. The equivalent resistance is A. `pi ohm`B. `(pi)/((pi + 2)) ohm`C. `(pi)/((pi + 4)) ohm`D. `(pi + 1) ohm` |
Answer» Correct Answer - C |
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409. |
The current -voltage - variation for a wire of copper of length (L) and area (A) is shown in fig. The slope of the line will be A. less if experiment is done at a heigher temperatureB. more if a wire of silver of same dimension is usedC. will be doubled if the lengths of the wire is doubledD. will be halved if the length is doubled |
Answer» Correct Answer - C |
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410. |
The variation of electric potential with distance from a fixed point is shown in figure. What is the value of electric field at `x = 2m` - A. ZeroB. `6//2`C. `6//1`D. `6//3` |
Answer» Correct Answer - A |
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411. |
Two point charges repel each other with a force of 100N. One of the charges is increased is increased by 10% and the other is reduced by 10% . The new force of repulsion at the same distance would beA. `100 N`B. `21 N`C. `99 N`D. None of these |
Answer» Correct Answer - C |
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412. |
The electric flux from a cube of edge l is `phi`. If an edge of the cube is made `2l` and the charge enclosed is halved, its value will beA. `phi//2`B. `2phi`C. `4phi`D. `phi` |
Answer» Correct Answer - A |
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413. |
A thin semicircular conducting ring of radius `R` is falling with its plane verticle in a horizontal magnetic inducting `B`. At the position `MNQ`, the speed of the ring is `V` and the potential difference developed across the ring is A. zeroB. `1/2BvpiR^(2)`, and `M` is at a higher potentialC. `piRBv`, and `Q` is at a higher potentialD. `2RBv`, and `Q` is at a higher potential |
Answer» Correct Answer - D |
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414. |
Statement X: When electric current flows vertically upwards the direction of the magnetic field lines produced by a straight conductor are in anti clock wise direction. Statement Y : When electric current flows vertically down-wards the direction of the magnetic field lines produced by a straight conductor are in clock wise direction. A) Both statements are trueB) Both statements are false C) X is true, Y is false D) X is false, Y is true |
Answer» A) Both statements are true |
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415. |
Does it (continuous rotation of coil) help us to generate electric current? |
Answer» Yes. Continuous rotation of coil helps us to generate electric current. |
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