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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In How Many Ways Can The Letters Of The Word 'capital' Be Arranged In Such A Way That All The Vowels Always Come Together? |
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Answer» CAPITAL = 7 VOWELS = 3 (A, I, A) Consonants = (C, P, T, L) 5 letters which can be arranged in 5P5=5! Vowels A,I = 3!/2! No.of ARRANGEMENTS = 5! x 3!/2!=360 CAPITAL = 7 Vowels = 3 (A, I, A) Consonants = (C, P, T, L) 5 letters which can be arranged in 5P5=5! Vowels A,I = 3!/2! No.of arrangements = 5! x 3!/2!=360 |
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| 2. |
The H.c.f And L.c.m Of Two Numbers Are 11 And 385 Respectively. If One Number Lies Between 75 And 125 , Then That Number Is? |
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Answer» Product of numbers = 11 X 385 = 4235 Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => AB = 35 Now, co-primes with product 35 are (1,35) and (5,7) So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7) Since one number lies 75 and 125, the suitable pair is (55,77) Hence , required number = 77. Product of numbers = 11 x 385 = 4235 Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35 Now, co-primes with product 35 are (1,35) and (5,7) So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7) Since one number lies 75 and 125, the suitable pair is (55,77) Hence , required number = 77. |
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