InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
If `(9x -5)/(7) + (6 -3x)/(2) =2`, then x = _____A. `2//3B. `3//4`C. `5//4`D. `4//3` |
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Answer» Correct Answer - D `(9x -5)/(7) + (6-3x)/(2) = 2` `= (18x - 10 + 42 - 21x)/(14) = 2` `rArr -3x + 32 = 28` `rArr -3x = -4 rArr x = (4)/(3)` Hence, the correct option is (d) |
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| 52. |
If `(z +5)/(7) + (4(z -11))/(9) + 3 = 0`, then z = ______A. 1B. 2C. `-4`D. 5 |
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Answer» Correct Answer - B `(z+5)/(7) + (4(z-11))/(9) + 3 = 0` `(9(z +5) + 28 (z -11))/(63) + 3 = 0` `9z + 45 + 28 z - 308 + 189 = 0` `37z + 234 - 308 = 0` `37 z = 74` `z = 2` Hence, the correct option is (b) |
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| 53. |
If `(x)/(2) + 1 =3`, then x = _____ |
| Answer» Correct Answer - 4 | |
| 54. |
If `(x)/(5) - 9 = 1`, then x = _____ |
| Answer» Correct Answer - 50 | |
| 55. |
If `3y + 1(1)/(2) + 6(4 -5y) = 12`, then y = _____A. `1//6`B. 11C. `1//2`D. 7 |
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Answer» Correct Answer - C `3y + 1(1)/(2) + 6(4 - 5y) = 12` `3y + (3)/(2) + 24 - 30 y = 12` `-27 y = 12 - 24 - (3)/(2)` `-27 y = -12 - (3)/(2)` `-27 y = - (27)/(2)` `y = (27)/(2 xx 27)` `y = (1)/(2)` Hence, the correct option is (c) |
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| 56. |
Solve : `0.5y + 0.75y = 125` |
| Answer» Correct Answer - 100 | |
| 57. |
Solve for `m : 1.2 m + 2.6 = 5`A. 4B. 3C. 2D. 1 |
| Answer» Correct Answer - C | |
| 58. |
Solve : `0.3 (3y -4.5) + 2.9 (5.5 -5y) = 1` |
| Answer» Correct Answer - 1 | |
| 59. |
Solve for `x : 12x -7 = 7x - 13`A. `-1.2`B. `-1.6`C. `-1.8`D. `-1.4` |
| Answer» Correct Answer - A | |
| 60. |
Solve for `m: (m-3)/(2) + (m-2)/(3) = -13` |
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Answer» Given, `(m -3)/(2) + (m-2)/(3) = -13` `rArr (3(m -3) + 2(m -2))/(6) = -13` `rArr 3m - 9 + 2m - 4 = -78` `rArr 5m = -65` `rArr m = -65//5` `:. M = -13` |
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| 61. |
If `2x -3 = 13`, then x = ______ |
| Answer» Correct Answer - 8 | |
| 62. |
Solve : `(9m+4)/(5) - (27 m + 1)/(8) - (1)/(2) = 0` |
| Answer» Correct Answer - `1//9` | |
| 63. |
Solve for `m : 3(4m + 5) - 4(3-2m) = 13`A. `1//2`B. 2C. `1//4`D. 1 |
| Answer» Correct Answer - A | |
| 64. |
Solve for `x : 3x + 5 gt 7`A. `x gt 3//2`B. `x gt 2//3`C. `x lt 3//2`D. `x lt 2//3` |
| Answer» Correct Answer - B | |
| 65. |
If `0.2 y + 10.2 gt 11, " then " y gt` _______ |
| Answer» Correct Answer - 4 | |
| 66. |
Solve : `2m + 5 gt 9 - 4m, m in Q` |
| Answer» Correct Answer - All rational numbers greater than `(2)/(3)` | |
| 67. |
Solve : `(z)/(2) - (z)/(3) - (z)/(4) = -1` |
| Answer» Correct Answer - 12 | |
| 68. |
Solve : `(y + 2)/(3) + (y + 3)/(2) = y + 1` |
| Answer» Correct Answer - 7 | |
| 69. |
Solve : `(2n + 3)/(6n -5) = 1` |
| Answer» Correct Answer - 2 | |
| 70. |
There are two numbers, the difference between them is equal to twice the smaller number. The sum of the two number is 68. Find the product of the two numbersA. 868B. 965C. 814D. 986 |
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Answer» Correct Answer - a Let the smaller number be x The other number is `68 -x` `68 - x- x = 2x` `68 = 4x` `:. X = 17` `:.` Bigger number `= 68 - 17 = 51` `:.` Product of the number = 867 Hence, the correct option is (a) |
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| 71. |
Solve : `2(k + 3) + 3 (k-4) = 24` |
| Answer» Correct Answer - 6 | |
| 72. |
The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years) |
| Answer» Correct Answer - 22 years | |
| 73. |
One-fifth of a number is 5 more than one-tenth of the number. Find the number |
| Answer» Correct Answer - 50 | |
| 74. |
In a bag, there are 50 paise coins, Rs 1 coins, and Rs 2 coins. The total value of these coins is Rs 30. The number of Rs 2 coins is half the number of Rs 1 coins, which is half the number of 50 paise coins. Find thenumber of Rs1 coins |
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Answer» Let the number of 50 paise coins, Rs 1 coins, and Rs 2 coins in the bag be `f, theta, and t`, respectively. Total value (in Rs) `= (50)/(100) f + 1 theta + 2t = 30` `(f)/(2) + theta + 2t = 30` `t = (theta)/(2) and theta = (f)/(2)` `:. 2t = theta = (f)/(2)` `(1) rArr theta + theta + theta = 30` `:. 3 theta = 30 rArr theta = 10` |
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| 75. |
Solve the following inequations: (a) `x + 5 lt 7, x in R` (b) `4x -3 ge 17, x in Z` (c) `3x -2 lt 1, x in N` |
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Answer» (a) Subtracting 5 from both sides, we get `x + 5 - 5 lt 7 - 5 rArr x lt 2` The set of all the number which are less than 2 is the solution set of the given inequation (b) Adding 3 on both sides, we get `4x - 3 + 3 ge 17 + 3` `4x ge 20` Dividing both sides by 4, we get `(4x)/(4) ge (20)/(4) rArr x ge 5` The set of all the integers which are greater than or equal to 5 is the solution set of the given inequation. (c) Adding 2 on both sides of `3x - 2 + 2 lt 1 + 2`, we get `3x lt 3` Dividing both sides by 3, we get `(3x)/(3) lt (3)/(3) rArr x lt (3)/(3) rArr x lt 1` There is no natural number which is less than 1 `:.` There is no solution for the given inequation in the set of natural numbers |
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| 76. |
Twice a number is added to half the number, and result is 250. Find one-tenth of the number |
| Answer» Correct Answer - 10 | |
| 77. |
The cost of three chairs and four tables is Rs 28,00. If the cost of each chair is Rs 600, then find the cost of each table (in Rs) |
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Answer» The cost of each chair is Rs 600 The cost of three chairs `= 3 xx 600 = Rs 1800` `rArr` Let the cost of each table = T `Rs 1800 + 4T = Rs 2800` (given) `rArr 4T = Rs 1000` `:. T = Rs 250` |
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| 78. |
Five years ago, the age of a person was half of his present age. How old is he now ? |
| Answer» Correct Answer - 10 years | |
| 79. |
Ram, Shyam, and Tarun have a total of Rs 600 with them. The amount with Ram is equal to half of the total amount with the others. Find the amount with Ram (in Rs)A. 150B. 300C. 120D. 200 |
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Answer» Correct Answer - d Let the amounts with Ram Shyam and Tarum be Rs R, Rs S, and Rs T, respectively `R + S + T = 600` (1) `R = (1)/(2) (S +T)` `2R = S + T` `(1) rArr 3 R = 600 rArr R = 200` Hence, the correct option is (d) |
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