InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Expand:i. (2p + q + 5)2 ii. (m + 2n + 3r)2 |
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Answer» i. (2p + q + 5)2 = (2p)2 + (q)2 + (5)2 + 2(2p) (q) + 2(q) (5) + 2(2p) (5) … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = 4p2 + q2 + 25 + 4pq + 10q + 20p ii. (m + 2n + 3r)2 = (m)2 + (2n)2 + (3r)2 + 2(m) (2n) + 2(2n) (3r) + 2(m) (3r) … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = m2 + 4n2 + 9r2 + 4mn + 12nr + 6mr |
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| 2. |
Simplify:(x – 2y + 3)2 + (x + 2y – 3)2 |
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Answer» (x – 2y + 3)2 + (x + 2y – 3)2 = [(x)2 + (- 2y)2 + (3)2 + 2 (x) (- 2y) + 2 (- 2y) (3) + 2 (x) (3)] + [(x)2 + (2y)2 + (- 3)2 + 2 (x) (2y) + 2 (2y) (- 3) + 2 (x) (- 3)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = x2 + 4y2 + 9 – 4xy – 12y + 6x + x2 + 4y2 + 9 + 4xy – 12y – 6x = x + x2 + 4y2 + 4y2 + 9 + 9 – 4xy + 4xy – 12y – 12y + 6x – 6x = 2x2 + 8y2 + 18 – 24y |
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| 3. |
Simplify:(3k – 4r – 2m)2 – (3k + 4r – 2m)2 |
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Answer» (3k – 4r – 2m)2 – (3k + 4r – 2m)2 = [(3k)2 + (- 4r)2 + (- 2m)2 + 2 (3k) (- 4r) + 2 (- 4r) (- 2m) + 2 (3k) (- 2m)] – [(3k)2 + (4r)2 + (- 2m)2 + 2 (3k) (4r) + 2 (4r) (- 2m) + 2 (3k) (- 2m)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = (9k2 + 16r2 + 4m2 – 24kr + 16rm – 12km) – (9k2 + 16r2 + 4m2 + 24kr – 16rm – 12km) = 9k2 + 16r2 + 4m2 – 24kr + 16rm – 12km – 9k2 – 16r2 – 4m2 – 24kr + 16rm + 12km = 9k2 – 9k2 + 16r2 – 16r2 + 4m2 – 4m2 – 24kr – 24kr + 16rm + 16rm – 12km + 12km = 32rm – 48kr |
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| 4. |
Simplify: i. (2a + b)3 – (2a – b)3ii. (3r – 2k)3 + (3r + 2k)3iii. (4a – 3)3 – (4a + 3)3iv. (5x – 7y)3 + (5x + 7y)3 |
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Answer» i. (2a + b)3 – (2a – b)3 = [(2a)3 + 3(2a)2(b) + 3 (2a)(b)2 + (b)3] – [(2a)3 – 3(2a)2(b) + 3 (2a)(b)2 – (b)3] … [(a + b)3 = a3 + 3a2b + 3ab2 + b3, (a – b)3 = a3 – 3a2b + 3ab2 – b3] = (8a3 + 12a2b + 6ab2 + b3) – (8a3 – 12a2b + 6ab2 – b3) = 8a3 + 12a2b + 6ab2 + b3 – 8a3 + 12a2b – 6ab2 + b3 = 8a3 – 8a3 + 12a2b + 12a2b + 6ab2 – 6ab2 + b3 + b3 = 24a2b + 2b3 ii. (3r – 2k)3 + (3r + 2k)3 = [(3r)3 – 3(3r)2(2k) + 3(3r)(2k)2 – (2k)3] + [(3r)3 + 3(3r)2(2k) + 3(3r)(2k)2 + (2k)3] … [(a – b)3 = a3 – 3a2b + 3ab2 – b3, (a + b)3= a3 + 3a2b + 3ab2 + b3] = (27r3 – 54r2k + 36rk2 – 8k3) + (27r3 + 54r2k + 36rk2 + 8k3) = 27r3 – 54r3k + 36rk2 – 8k3 + 27r3 + 54r2k + 36rk2 + 8k3 = 27r3 + 27r3 – 54r2k + 54r2k + 36rk2 + 36rk2 – 8k3 + 8k3 = 54r3 + 72rk2 iii. (4a – 3)3 – (4a + 3)3 = [(4a)3 – 3(4a)2 (3) + 3(4a)(3)2 – (3)3] – [(4a)3 + 3(4a)2(3) + 3(4a)(3)2 + (3)3] … [(a – b)3 = a3 – 3a2b + 3ab2 – b3, (a + b)3 = a3 + 3a2b + 3ab2 + b3] = (64a3 – 144a2 + 108a – 27) – (64a3 + 144a2 + 108a + 27) = 64a3 – 144a2 + 108a – 27 – 64a3 -144a2 – 108a – 27 = 64a3 – 64a3 – 144a2 – 144a2 + 108a – 108a – 27 – 27 = -288a2 – 54 v. (5x – 7y)3 + (5x + 7y)3 = [(5x)3 – 3(5x)2(7y) + 3(5x)(7y)2 – (7y)3] + [(5x)3 + 3(5x)2 (7y) + 3(5x) (7y)2 +(7y)3] … [(a – b)3 = a3 – 3a2b + 3ab2 – b3, (a + b)3 = a3 + 3a2b + 3ab2 + b3] = (125x3 – 525x2y + 735xy2 – 343y3) + (125x3 + 525x2y + 735xy2 + 343y3) = 125x3 – 525x2y + 735xy2 – 343y3 + 125x3 + 525x2y + 735xy2 + 343y3 = 125x3 + 125x3 – 525x2y + 525x2y + 735xy2 + 735xy2 – 343y3 + 343y3 = 250x3 + 1470xy2 |
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| 5. |
Simplify:(7a – 6b + 5c)2 + (7a + 6b – 5c)2 |
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Answer» (7a – 6b + 5c)2 + (7a + 6b – 5c)2 = [(7a)2 + (- 6b)2 + (5c)2 + 2(7a) (-6b) + 2(-6b) (5c) + 2(7a) (5c)] + [(7a)2+ (6b)2 + (- 5c)2 + 2 (7a) (6b) + 2 (6b) (- 5c) + 2 (7a) (- 5c)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = 49a2 + 36b2 + 25c2 – 84ab – 60bc + 70ac + 49a2 + 36b2 + 25c2 + 84ab – 60bc – 70ac = 49a2 + 49a2 + 36b2 + 36b2 + 25c2 + 25c2 – 84ab + 84ab – 60bc – 60bc + 70ac – 70ac = 98a2 + 72b2 + 50c2 – 120bc |
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| 6. |
Simplify: i. (x – 2y + 3)2 + (x + 2y – 3)2ii. (3k – 4r – 2m)2 – (3k + 4r – 2m)2iii. (7a – 6b + 5c)2 + (7a + 6b – 5c)2 |
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Answer» i. (x – 2y + 3)2 + (x + 2y – 3)2 = [(x)2 + (- 2y)2 + (3)2 + 2 (x) (- 2y) + 2 (- 2y) (3) + 2 (x) (3)] + [(x)2 + (2y)2 + (- 3)2 + 2 (x) (2y) + 2 (2y) (- 3) + 2 (x) (- 3)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = x2 + 4y2 + 9 – 4xy – 12y + 6x + x2 + 4y2 + 9 + 4xy – 12y – 6x = x + x2 + 4y2 + 4y2 + 9 + 9 – 4xy + 4xy – 12y – 12y + 6x – 6x = 2x2 + 8y2 + 18 – 24y ii. (3k – 4r – 2m)2 – (3k + 4r – 2m)2 = [(3k)2 + (- 4r)2 + (- 2m)2 + 2 (3k) (- 4r) + 2 (- 4r) (- 2m) + 2 (3k) (- 2m)] – [(3k)2 + (4r)2 + (- 2m)2 + 2 (3k) (4r) + 2 (4r) (- 2m) + 2 (3k) (- 2m)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = (9k2 + 16r2 + 4m2 – 24kr + 16rm – 12km) – (9k2 + 16r2 + 4m2 + 24kr – 16rm – 12km) = 9k2 + 16r2 + 4m2 – 24kr + 16rm – 12km – 9k2 – 16r2 – 4m2 – 24kr + 16rm + 12km = 9k2 – 9k2 + 16r2 – 16r2 + 4m2 – 4m2 – 24kr – 24kr + 16rm + 16rm – 12km + 12km = 32rm – 48kr iii. (7a – 6b + 5c)2 + (7a + 6b – 5c)2 = [(7a)2 + (- 6b)2 + (5c)2 + 2(7a) (-6b) + 2(-6b) (5c) + 2(7a) (5c)] + [(7a)2 + (6b)2 + (- 5c)2 + 2 (7a) (6b) + 2 (6b) (- 5c) + 2 (7a) (- 5c)] … [(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac] = 49a2 + 36b2 + 25c2 – 84ab – 60bc + 70ac + 49a2 + 36b2 + 25c2 + 84ab – 60bc – 70ac = 49a2 + 49a2 + 36b2 + 36b2 + 25c2 + 25c2 – 84ab + 84ab – 60bc – 60bc + 70ac – 70ac = 98a2 + 72b2 + 50c2 – 120bc |
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| 7. |
Use the formulae to fill proper terms in the following boxes.1. (x + 2y)2 = x2 + ___ + 4y2 2. (2x – 5y)2 = __ – 20xy + __ 3. (101)2 = (100 + 1)2 = ___+ ___ + 12 = ___ 4. (98)2 = (100 – 2)2= 10000 – ___ + ___ = ___ 5. (5m + 3n) (5m – 3n) = ___ – ___ = ___ – __ |
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Answer» 1. (x + 2y)2 = x2 + 4xy + 4y2 2. (2x – 5y)2 = 4x2 – 20xy + 25y2 3. (101)2 = (100 + 1)2 = 10000+ 200 + 12 = 10201 4. (98)2 = (100 – 2)2= 10000 – 400 + 4 = 9604 5. (5m + 3n) (5m – 3n) = (5m)2 – (3n)2 = 25m2 – 9n2
(Use the formula a²-b²=(a+b)(a-b) Hope you clearly understood this, through the basics formula of alzebra) |
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| 8. |
Fill in the boxes with appropriate terms in the steps of expansion. (2p + 3m + 4n)2= (2p)2 + (3m)2 + __ + 2 × 2p × 3m + 2 × __ × 4n + 2 × 2p × __ = __ + 9m2 + __ + 12pm + __ + __ |
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Answer» (2p + 3m + 4n)2 = (2p)2 + (3m)2 + (4n)2 + 2 x 2p x 3m + 2 x 3m x 4n + 2 x 2p x 4n = 4p2 + 9m2 + 16n2 + 12pm + 24mn + 16pn |
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| 9. |
Use the above formulae to fill proper terms in the following boxes.1. (x + 2y)2 = x2 + ___ + 4y22. (2x – 5y)2 = __ – 20xy + __3. (101)2 = (100 + 1)2 = ___+ ___ + 12 = ___4. (98)2 = (100 – 2)2 = 10000 – ___ + ___ = ___5. (5m + 3n) (5m – 3n) = ___ – ___ = ___ - ___ |
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Answer» 1. (x + 2y)2 = x2 + 4xy + 4y2 2. (2x – 5y)2 = 4x2 – 20xy + 25y2 3. (101)2 = (100 + 1)2 = 10000 + 200 + 12 = 10201 4. (98)2 = (100 – 2)2 = 10000 – 400 + 4 = 9604 5. (5m + 3n) (5m – 3n) = (5m)2 – (3n)2 = 25m2 – 9n2 |
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