InterviewSolution
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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Simplify :`((25)^(3/2)x(243)^(3/5))/((16)^(5/4)x(8)^(4/3))` |
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Answer» `((25)^(3/2)x(243)^(3/5))/((16)^(5/4)x(8)^(4/3))` `((5^2)^(3/2)*(3^5)^(3/5))/((2^4)^(5/4)*(2^3)^(4/3))` `(5^3*3^3)/(2^5*2^4)` `(5^3*3^3)/2^9` `((5*3)/(2^3))^3` `(15/8)^3`. |
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| 2. |
Assuming that `x , y` are positive real numbers, simplify each of the following: (i)`sqrt(x^(-2)y^3)` (ii) `(x^(-2)doty^(-1/2))^2` (iii)`(sqrt(x^(-3)))^5` |
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Answer» 1)`(sqrt(x^(-2)y^3))^(1/2)` `=x^(-2/2)*y^(3/2)` `=y^(3/2)/x` `=(sqrty)^3/x` 2)`(x^(-2)*y^(-1/2))^2` `=(x^((-2)*2)*y^((-1/2)*(2)))` `=1/(ysqrtx^2)` 3)`(sqrtx^(-3))^5` `(x^(-3+2))^5` `x^(5-1)` `x^4`. |
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| 3. |
Show that :`(x^(a(b-c)))/(x^(b(a-c)))*(x^b)/(x^a))^c=1``((x^(a+b))^2(x^(b+c))(x^(c+a))^2)/((x^a x^b x^c)^4)=1` |
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Answer» `=(x^(a(b-c)))/(x^(b(a-c)))-:(x^b/x^a)^c` `=(x^(ab-ac)/x^(ab-bc))-:x^(bc)/x^(ac)` `=x^(ab-ac-(ab-bc))*x^(ac-bc)` `=x^(ab-ac-ab+bc+ac-bc)` `=x^0` `=1`. |
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