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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers. (i) `3/7` (ii) `5/8` (iii) `9/7` (iv) `6/5` (v) `12/7` (vi) `1/8` (vii) `1/11` |
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Answer» (i) Reciprocal of `3/7` is `7/3` which is an improper fraction. (ii)Reciprocal of `5/8` is `8/5` which is an improper fraction. (iii)Reciprocal of `9/7` is `7/9` which is a proper fraction. (iv)Reciprocal of `6/5` is `5/6` which is a proper fraction. (v)Reciprocal of `12/7` is `7/12` which is a proper fraction. (vi)Reciprocal of `1/8` is `8` which is a whole number. (vii)Reciprocal of `1/11` is `11` which is a whole number. |
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| 2. |
`7//9` is equivalent to `"______"`A. `14//18`B. `35//45`C. `56//72`D. All of these |
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Answer» Correct Answer - D `7/9 = 14/18 = 35/45 = 56/72` Hence the correct option is (d) . |
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| 3. |
Reduce `480//840` to its simplest form. |
| Answer» `480//840 = 2xx2xx2xx2xx2xx3xx5//2xx2xx2xx3xx5xx7=4//7` | |
| 4. |
If `3/4= k/12`, then `k` is `"______"`A. 3B. 4C. 6D. 9 |
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Answer» Correct Answer - D `3/4 = k/12 rArr (3(3))/(4(3)) = k/12 rArr k = 9` Hence the correct option is (d). |
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| 5. |
For the fractions given below : (a) Multiply and reduce the product to lowest form (if possible) (b) Tell whether the fraction obtained is proper or improper. (c) If the fraction obtained is improper then convert it into a mixed fraction. (i) `2/5 xx (5) 1/4` (ii) `(6) 2/5 xx 7/9` (iii) `3/2 xx (5) 1/3` (iv) `5/6 xx (2) 3/7` (v) `(3) 2/5 xx 4/7` (vi) `(2) 3/5 xx 3` (vii) `(2) 3/5 xx 3` (viii) `(3) 4/7 xx 3/5` |
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Answer» (i) `2/5xx 5 1/4 = 2/5 xx 21/4 = 21/10 = 2 1/10` (ii)`6 2/5xx7/9 = 32/5xx7/9 = 224/45 = 4 44/45` (iii)`3/2xx 5 1/3 = 3/2xx 16/3 = 8` (iv)`5/6xx2 3/7 = 5/6xx 17/7 = 85/42 = 2 1/42` (v)`3 2/5 xx 4/7 = 17/5 xx 4/7 = 68/35 = 1 33/35` (vi)`2 3/5 xx 3 = 13/5xx3 = 39/5 = 7 4/5` (vii)`2 3/5 xx 3 = 13/5xx3 = 39/5 = 7 4/5` (viii)` 3 4/7 xx 3/5 = 25/7xx3/5 = 15/7 = 2 1/7` |
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| 6. |
Reduce `1562//1846` and `924//1188` in lowest terms. |
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Answer» Correct Answer - (i) `11/13` , (ii) `7/9` (i) `1562/1846 = (11xx142)/(13xx142)=11/13` (ii) `924/1188 = (7xx132)/(9xx132) = 7/9` |
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| 7. |
The fraction `744//496` in its lowest terms is `"_____"`. |
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Answer» Correct Answer - `3/2` `744/496 = 3/2` |
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| 8. |
`6//7` is a/an `"_____"` (proper/improper) fraction. |
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Answer» Correct Answer - proper a proper fraction (Numerator `lt ` Denominator) |
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| 9. |
`5//5` is a/an `"_____"` (proper/improper) fraction. |
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Answer» Correct Answer - Improper an improper fraction |
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| 10. |
`120/25 = "______"`A. 0.048B. 4.8C. 48D. 4.08 |
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Answer» Correct Answer - b `120/25 = 120/25 xx 4/4 = (480)/(100) = 4.8` Hence the correct option is (b). |
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| 11. |
`4//3` is a/an `"_____"` (proper/improper) fraction. |
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Answer» Correct Answer - Improper an improper fraction (Numerator `gt` Denominator) |
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| 12. |
`2.3 + 4.4 + 6.9 = "______"` |
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Answer» Correct Answer - 13.6 `2.3+ 4.4 +6.9 = 13.6` |
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| 13. |
Match the Column A with Column B. |
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Answer» Correct Answer - (a) `rarr r`; (b) `rarr s`; (c ) `rarr p`; (d) `rarr q` (a) `1/2 = 6/12 rarr (r )` (b) `1/3 = 5/15 rarr (s)` (c ) `1/4 rarr (p)` (d) `3/4 rarr (q)` Therefore, the correct match is : `:. (a) rarr (r ) , (b ) rarr (s) , (c ) rarr (p), (d) rarr (q)` |
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| 14. |
Divide `8.4` by 6. |
| Answer» `8.4 ÷ 6 = (84//10) ÷ 6 = (84//10)(1//6) = 84/6(1/10) = 14/10 = 1.4` | |
| 15. |
`1.608 divide 1.34 = "______"`A. `3.2`B. `2.2`C. `1.2`D. `4.2` |
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Answer» Correct Answer - C `(1.608)/(1.34) = 1.2` Hence the correct option is (c ). |
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| 16. |
`50.2 divide 1.255 = "_____"` |
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Answer» Correct Answer - 40 `(50.2)/(1.255)= (50200)/(1255) = 40` |
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| 17. |
Match the Column A with Column B. |
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Answer» Correct Answer - (a) `rarr p`; (b) `rarr r`; (c ) `rarr s`; (d) `rarr q` (a) `(1/2+1/3)` of `((3+2)/6) xx 6 = 5/6 xx 6 = 5` (b) `7/9` of `18 = ((2+1)/(6)) xx 18 = 9` (c ) `(1/4+ 1/3)` of `12 = ((3+4)/(12)) xx 12 = 7` (d) `(1/5 + 1/6)` of `30 ((6+5)/(30)) xx 30 = 11` (p) `(3/4 - 1/3)`of `12 = ((9-4)/(12)) xx 12 = 5` (q) `(5/2 - 2/3)` of `6 = ((15-4)/(6)) xx 6 = 11` ( r) `(5/4-1/2)` of `12 = ((5-2)/(4)) xx12 = 9` (s) `(3/4 - 1/6)` of `12 = ((9-2)/(12)) xx 12 = 7` Therefore, the correct match is : `(a) rarr (p), (b) rarr (r ) , (c) rarr (s) ,(d) rarr (q)` |
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| 18. |
Find the sum of `1.4` and `2.23`. |
| Answer» `1.4+2.23 = 3.63` | |
| 19. |
`37.23 divide 10 = "______"`A. `372.3`B. `3.723`C. `37.23`D. `0.3723` |
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Answer» Correct Answer - B `37.23 ÷ 10 = (37.23)/(10) = 3.723` Hencethe correct option is (b). |
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| 20. |
`0.00125 xx 200 = "_____"`. |
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Answer» Correct Answer - 0.25 `0.00125 xx 200 = 0.25` |
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| 21. |
`23.143 + 17.159 = "_____"`. |
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Answer» Correct Answer - `4.302` `23.143 + 17.159 = 40.302` |
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| 22. |
Sujith travels one-third of a distance. If the dis-tance is 12 km, then find the remaining distance that he would have travelled (in km).A. 2B. 4C. 6D. 8 |
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Answer» Correct Answer - D Required distance `= (2/3)` of `12` km `= 2/3 xx 12 = 8`km. Hence the correct option is `(d)`. |
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| 23. |
`36.121 -33.429 = "____"`. |
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Answer» Correct Answer - `2.692` `36.121 - 33.429 = 2.629` |
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| 24. |
`1/2 + 3/4 + 1/8 = "________"`.A. `1//2`B. `5//4`C. `9//8`D. `11//8` |
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Answer» Correct Answer - D `1/2 + 3/4 + 1/8 = ((1xx4)+(3xx2)+(1xx1))/(8)` `= (4+6+1)/(8) = 11/8` Hence, the correct option is (d). |
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| 25. |
Total strength of a class is 36 students. If three-fourth of the students is taking an examination from the class, then how many students are not taking the examination ?A. 9B. 12C. 24D. 27 |
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Answer» Correct Answer - A Required numbers of students `= (1/4) (36) = 9`. Hence the correct option is (a). |
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| 26. |
In a class of 40 students `1/5`of the total number of studetns like to study English, `2/5`of the total number like to study mathematics and the remaining students like to study Science. |
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Answer» Total number of students `= 40` Total number of students who like to study English ` = 1/5**40 = 8` Total number of students who like to study Maths` = 2/5**40 = 16` Fraction of total number of students who like to study Science` = 1-(1/5+2/5) = 1-3/5 = 2/5` |
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| 27. |
The side of an equilateral triangle is 3.5 cm. Find its perimeter |
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Answer» perimeter=3*side perimeter=3*3.5=10.5cm. |
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| 28. |
A rectangular sheet of paper is `(12) 1/2 cm` long and `(10) 2/3 cm` wide. Find its perimeter. |
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Answer» The perimeter of the rectangular sheet can be given as, `P = 2**`(Sum of length and width) So, `P = 2**(12 1/2+ 10 2/3) = 2**(25/2+32/3) = 2**((75+64)/6)` `P = 139/3 = 46 1/3cm` |
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| 29. |
A car runs `16 km` using 1 litre of petrol. How much distance will it cover using `(2) 3/4` liters of petrol. |
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Answer» Distance covered by the car in 1 litre ` = 16km` Distance covered by the car in `2 3/4` litres ` = 16**2 3/4`km `= 16**11/4 = 44km` |
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| 30. |
Salil wants to put a picture in a frame. The picture is `(7) 3/5 cm` wide. To fit the frame the picture cannot be more than `(7) 3/10 cm` wide. How much should the picture be trimmed ? |
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Answer» Width of picture ` = 7 3/5cm = 38/5cm` Width of picture to fit the frame ` = 7 3/10 = 73/10cm` So, measure of picture that should be trimmed ` = 38/5-73/10 = (76-73)/10 = 3/10cm` |
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| 31. |
Michael finished colouring a picture in `7/12` hour. Vaibhav finished colouring the same picture in `3/4` hour. Who worked longer ? By what fraction was it longer ? |
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Answer» Michael=7/12 hours Vaibhav=3/4 hours Difference between them=`3/4-7/12=2/12=1/6` Vaibhav have done more work than Michael by 1/6 hours. |
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| 32. |
How much less is 28 km than 42.6 km? |
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Answer» We can find it by getting the difference between these two. Difference `= 42.6 - 28 = 14.6` km So, `28` km is `14.6` km less than `42.6` km. |
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| 33. |
By how much is the sum of `44.44` and `32.03` greater than their difference ? |
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Answer» Correct Answer - 64.06 `overset("Sum: "){:(44.44),(+32.03),(barul(76.47)):}" "overset("Difference:"){:(44.44),(-32.03),(barul(12.41)):}` `:.` Required quantity : `{:(76.47),(-12.41),(barul(64.06)):}` |
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| 34. |
A water bottleis `3/5` and `1/7` of the water is drawn. How much water is remaining in the bottle ?A. `16/35`B. `17/35`C. `8/17`D. `2/35` |
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Answer» Correct Answer - A Remaining water in the bottle `= 3/5 - 1/7` `= ((21-5))/(35) = 16/35` Hence, the correct option is (a). |
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| 35. |
How money glasses of water is required to fill one litre water bottle, if one glass of water is `25` mL. |
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Answer» Correct Answer - 40 Quantity of water in one glass`= 25` mL Required number of glasses `= 1000/25 = 40` |
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| 36. |
Vidya and pratap went from a picnic. their mother gave them a water bag that contained 5 litres of water. Vidya consumed `2/5` of the water. Pratap consumed the remaining water. (i) How much water did Vidya drink? (ii) What fraction of the total quantity of water did Pratap drink? |
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Answer» Total quantity of water in water bag ` = 5` litres Water consumed by Vidya in fraction `= 2/5` `:.` Water consumed by Vidya in litres ` = 5**2/5 = 2` litres Remaining water consumed by Pratap in fraction ` = 1-2/5 = 3/5` |
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| 37. |
Ram purchased 3 notebooks that each costs ₹ 20.75 and `4` pencil that each costs ₹4.25. Ram gave ₹ 100 to the shopkeeper. How much money should Ram get back from the shopkeeper ? |
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Answer» Correct Answer - ₹ 20.75 Cost of each note book `= 2.75` Cost of 3 note books `= 3xx 20.75 = ₹ 62.25` Costs of 4 pencils `= 4 xx 4.25 = 17` Total expenditure `= 62.25 + 17.00 = 79.25` Balance amount `= 100 - 79.25 = ₹20.75` |
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| 38. |
Sameera purchased `3 frac{1}{2}` kg apples and `4 frac {3}{4}` kg oranges. What is the total weight of fruits purchased by her? |
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Answer» Weight of apples purchased by Sameera ` = 3 1/2` kg `= 7/2` kg Weight of oranges purchased by Sameera ` = 4 3/4` kg `= 19/4` kg `:.` Total weight of fruits purchased by Sameera ` = 7/2+19/4 = 33/4` kg `= 8 1/4` kg |
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| 39. |
The weight of a piece of gold is `0.2354` kg and the cost of gold is ₹ 2875.50` per gram. If `9.56` gm is separated for an ornament, then find the cost of remaining gold ?A. `646577.42`B. `646627.42`C. `646587.42`D. `649402.92` |
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Answer» Correct Answer - D Weight of gold piece of gold `= 0.2354 kg` `= 235.4` grams Weight of gold used for ornament `= 9.56` gm Remaining gold `= 235.4 - 9.56 = 225.84` gm Cost of remaining gold `= 225.84 xx2875.50` `= 649402.92` Hence, the correct option is (d). |
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| 40. |
Convert `24/25` into a decimal fraction. |
| Answer» `24/25 xx 4/4 = 96/100 = 0.96` | |
| 41. |
What should be added to the difference of `6.88` and `4.25` to get `5` ? |
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Answer» `6.88 - 4.25 = 2.63` To get 5, we need to get add `(5-2.63) = 2.37` |
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| 42. |
What should be added to the sum of `1//8` and `1//7` so that the sum is `5//14` ? |
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Answer» Correct Answer - `5/56` Given : `1/8+1/7=(7+8)/(56) = 15/56` The required fraction `= 5/14 - 15/56 = (20-15)/(56) = 5/56` `:. 5/56` should be added to the sum `7/8` and `1/9` to get `5/14`. |
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| 43. |
What should be added to `6.77` to get ? |
| Answer» `7.00 - 6.77 = 2.63` | |
| 44. |
Convert `0.425` into a fraction. |
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Answer» Correct Answer - `17/40` `0.425=425/1000=17/40` |
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| 45. |
What should be added to `1.834` so that the sum is `5` ? |
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Answer» Correct Answer - 3.166 `{:(5.000),(1.834),(barul(3.166)):}` `3.166` should be added to `1.834` to get 5. |
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| 46. |
Arrange `2/7, 4/5` and `3/4` in ascending order. |
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Answer» Correct Answer - `3/7 lt 3/4 lt 4/5` `2/7, 4/5` and `3/4`. LCM of 7,5 and 4 is 140. `2/7 = 2/7 xx 20/20 = 40/140, 4/5 =4/5 xx 28/28 = 112/140` `3/4 = 3/4 xx 25/25= 105/140` `40/140 lt 105/140 lt 112/140 rArr 2/7 lt 3/4 lt 4/5`. |
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| 47. |
Simplify : (i) `2/3 + 4/5` , (ii) `7/9 + 11/18` |
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Answer» Correct Answer - (i) `22/15` , (ii) `25/18` (i) `2/3 + 4/5 = (10+12)/(15) = 22/15` (ii) `7/9 + 11/18 = (14+11)/(18) = 25/18` |
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| 48. |
Simplify : `0.9+0.9xx0.9÷0.9-0.9+0.9÷0.9xx0.9` |
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Answer» Correct Answer - 1.8 `0.9+0.9xx0.9div0.9-0.9+0.9div0.9xx0.9` `= 9/10+9/10xx9/10 div 9/10 - 9/10 + 9/10 div 9/10 xx 9/10` `= 9/10 + 9/10 xx 1 - 9/10 +1 xx 9/10` `= 9/10 + 9/10 - 9/10 + 9/10` `= 18/10 = 1.8` |
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| 49. |
Simplify: `1/2 ÷ 4/3 xx 2/3 ÷ 1/2 + 3/4 - 5/2 + 2/3 xx 9/4 ÷ 2/3` |
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Answer» Correct Answer - 1 `1/2 ÷ 4/3 xx 2/3 ÷ 1/2 + 3/4 - 5/2 + 2/3 xx 9/4 ÷ 2/3` `= 1/2 xx 3/4 xx 2/3 xx 2 + 3/4 - 5/2 + 2/3 xx 9/4xx 3/2` `=1/2+3/4 - 5/2 +9/4 = 12/4 - 4/2= 1` |
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| 50. |
(i) Express 5 cm in metre and kilometre (ii) Express 35 mm in cm, m and km |
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Answer» We know, `10mm = 1cm` `100cm = 1m` `1000m = 1km` So, (i) `5cm = 5/100m = 0.05 m` `5cm = 5/100m = 0.05/1000km = 0.00005km` (ii)`35mm = 35/10cm = 3.5cm` `35mm = 35/1000m = 0.035m` `35mm = 35/1000m = 0.035/1000km = 0.000035km` |
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