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1.	Convert the given fractions into like fractions.1/6, 4/9
Answer» Least common multiple of 6 and 9 is 18 So, make 18 as common denominator \(\frac{1}{6}=\frac{1\times3}{6\times3}\) = \(\frac{3}{18},\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}\) So, 3/18 and 8/18 are the required like fractions.

Convert the given fractions into like fractions.1/6, 4/9

Answer»

Least common multiple of 6 and 9 is 18

So, make 18 as common denominator

\(\frac{1}{6}=\frac{1\times3}{6\times3}\) = \(\frac{3}{18},\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}\)

So, 3/18 and 8/18 are the required like fractions.

Discussion

2.	Convert the given fractions into like fractions.3/8, 1/6
Answer» Least common multiple of 8 and 6 is 24 So, make 24 as common denominator \(\frac{3}{8}=\frac{3\times3}{8\times3}=\frac{9}{24},\) \(\frac{1}{6}=\frac{1\times4}{6\times4}=\frac{4}{24}\) So, \(\frac{9}{24},\frac{4}{24}\) are required like fractions.

Convert the given fractions into like fractions.3/8, 1/6

Answer»

Least common multiple of 8 and 6 is 24

So, make 24 as common denominator

\(\frac{3}{8}=\frac{3\times3}{8\times3}=\frac{9}{24},\) \(\frac{1}{6}=\frac{1\times4}{6\times4}=\frac{4}{24}\)

So, \(\frac{9}{24},\frac{4}{24}\) are required like fractions.

Discussion

3.	Convert the given fractions into like fractions.5/6, 4/5
Answer» Least common multiple of 6 and 5 is 30 So, make 30 as common denominator \(\frac{5}{6}=\frac{5\times5}{6\times5}=\frac{25}{30},\frac{4}{5}\) = \(\frac{4\times6}{5\times6}=\frac{24}{30}\) So, \(\frac{25}{30},\frac{24}{30}\) are required like fractions.

Convert the given fractions into like fractions.5/6, 4/5

Answer»

Least common multiple of 6 and 5 is 30

So, make 30 as common denominator

\(\frac{5}{6}=\frac{5\times5}{6\times5}=\frac{25}{30},\frac{4}{5}\) = \(\frac{4\times6}{5\times6}=\frac{24}{30}\)

So, \(\frac{25}{30},\frac{24}{30}\) are required like fractions.

Discussion

4.	Add the following:i. 3/15 + 4/15ii. 2/7 + 1/7 + 3/7iii. 2/10 + 4/10 + 3/10iv. 4/9 + 1/9
Answer» i. \(\frac{3}{15}+\frac{4}{15}=\frac{3+4}{15}=\frac{7}{15}\) ii. \(\frac{2}{7}+\frac{1}{7}+\frac{3}{7}=\frac{2+1+3}{7}=\frac{6}{7}\) iii. \(\frac{2}{10}+\frac{4}{10}+\frac{3}{10}=\frac{2+4+3}{10}=\frac{9}{10}\) iv. \(\frac{4}{9}+\frac{1}{9}=\frac{4+1}{9}=\frac{5}{9}\)

Add the following:i. 3/15 + 4/15ii. 2/7 + 1/7 + 3/7iii. 2/10 + 4/10 + 3/10iv. 4/9 + 1/9

Answer»

i. \(\frac{3}{15}+\frac{4}{15}=\frac{3+4}{15}=\frac{7}{15}\)

ii. \(\frac{2}{7}+\frac{1}{7}+\frac{3}{7}=\frac{2+1+3}{7}=\frac{6}{7}\)

iii. \(\frac{2}{10}+\frac{4}{10}+\frac{3}{10}=\frac{2+4+3}{10}=\frac{9}{10}\)

iv. \(\frac{4}{9}+\frac{1}{9}=\frac{4+1}{9}=\frac{5}{9}\)

Discussion

5.	The girls of Std V cleaned 3/4 of a field while the boys cleaned 1/4. What part of the field was cleaned altogether?
Answer» Girls cleaned + Boys cleaned \(\frac{3}{4}+\frac{1}{4}=\frac{3+1}{4}=\frac{4}{4}=1\) Full whole field cleaned altogether.

The girls of Std V cleaned 3/4 of a field while the boys cleaned 1/4. What part of the field was cleaned altogether?

Answer»

Girls cleaned + Boys cleaned

\(\frac{3}{4}+\frac{1}{4}=\frac{3+1}{4}=\frac{4}{4}=1\)

Full whole field cleaned altogether.

Discussion