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51.

When the coal is completely burnt in air, then the maximum temperature reached is called _________(a) calorific value of coal(b) gross calorific value(c) calorific intensity of coal(d) net calorific valueThe question was posed to me in class test.Enquiry is from Calorific Value topic in section Fuel Technologies of Applied Chemistry

Answer» RIGHT answer is (c) calorific intensity of coal

Explanation: Calorific VALUE of coal is defined as the amount of HEAT liberated during combustion of fuel COMPLETELY. Gross calorific value or HCV means the total heat liberated after combustion of fuel and products must be cooled. Net calorific value is the total heat liberated after combustion of fuel and products are allowed to escape. So, the maximum temperature REACHED is calorific intensity of coal.
52.

The coal sample contains=80%; H=4%; O=2%; N=12%; S=2%, the remainder is ash and then calculate the volume of air required for perfect combustion of 1kg of fuel assuming STP conditions.(a) weight of oxygen required=10.65kg; volume of the oxygen=8725l(b) weight of oxygen required=11.25kg; volume of the oxygen=8500l(c) weight of oxygen required=11.25; volume of the oxygen=8200l(d) weight of oxygen required=10.65kg; volume of the oxygen=8166.6lThis question was addressed to me in an interview for job.I would like to ask this question from Fuel Technologies Problems in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct option is (d) weight of oxygen required=10.65kg; volume of the oxygen=8166.6l

To elaborate: The total weight of oxygen required for combustion is calculated by TAKING EVERY component equation. It will be 2.45kg and then CALCULATE the volume of oxygen. At STP CONDITIONS 32g of oxygen occupies 22.4l volume. Calculate for 2450g and then FIND weight of oxygen required as we know 100kg of gas requires 23kg of oxygen.

53.

Olefins containing 2 to 4 carbon atoms are ______ at ordinary temperature.(a) solid(b) liquid(c) gaseous(d) semisolidThis question was addressed to me in an interview for job.The origin of the question is Classification of Crude Oil based on their Composition topic in chapter Fuel Technologies of Applied Chemistry

Answer»

The correct option is (c) gaseous

The best EXPLANATION: The olefins containing 2 to 4 carbons are very SMALL hydro carbons and they will be in gaseous state GENERALLY at room temperature.

54.

What is the general formula for Naphthenes?(a) CnH2n+2(b) CnH2n(c) CnH2n-6(d) CnH2n-2The question was posed to me in semester exam.The question is from Classification of Crude Oil based on their Composition topic in section Fuel Technologies of Applied Chemistry

Answer»

Right choice is (b) CNH2N

Explanation: The general formula for NAPHTHENES is CnH2n. The general formula for PARAFFINS CnH2n+2. The general formula for aromatics is CnH2n-6.

55.

Ultimate analysis of coal is also called as _________(a) quantitative analysis(b) elementary analysis(c) qualitative analysis(d) secondary analysisThe question was asked during an interview for a job.My query is from Analysis of Coal and Selection topic in section Fuel Technologies of Applied Chemistry

Answer»

The CORRECT ANSWER is (c) qualitative analysis

To elaborate: The ULTIMATE analysis of coal is called as qualitative analysis and the proximate analysis of coal is called as QUANTITATIVE analysis of coal.

56.

In proximate analysis, which of the following elements can be found?(a) % of moisture content(b) % of carbon(c) % of hydrogen(d) % of nitrogenThis question was posed to me in exam.This intriguing question originated from Analysis of Coal and Selection topic in division Fuel Technologies of Applied Chemistry

Answer»

Right answer is (a) % of moisture content

Explanation: The proximate analysis is ALSO called as quantitative analysis. It is used to FIND the % of moisture content, volatile MATTER, ash content and fixed carbon in COAL.

57.

The rate of combustion of a good fuel must be ________(a) Controllable(b) High(c) Low(d) Very highThe question was asked in semester exam.Question is taken from Characteristics of Good Fuel and its Advantages in section Fuel Technologies of Applied Chemistry

Answer»

Correct OPTION is (a) Controllable

The best I can explain: The RATE of the combustion of a good fuel must be controllable because if it is high or very high we cannot calculate the time taken by the fuel to BURN and if it is LOW also we cannot observe the time taken.

58.

To calculate the net calorific value, the products are _________(a) cooled(b) allowed to escape(c) heated(d) collectedThis question was addressed to me by my college professor while I was bunking the class.Question is taken from Calorific Value in portion Fuel Technologies of Applied Chemistry

Answer»

Right ANSWER is (b) allowed to escape

The explanation is: The products in FINDING NCV are allowed to escape as the hot gases has no chance of condensation. Cooled in HCV.

59.

The major advantage of a good fuel is _______(a) ease of transportation(b) production of more oxygen(c) production of more nitrogen(d) production of more vaporI got this question during a job interview.Query is from Characteristics of Good Fuel and its Advantages topic in section Fuel Technologies of Applied Chemistry

Answer»

The correct OPTION is (a) ease of transportation

The BEST I can explain: The good fuel can be transported easily. It is the MAIN ADVANTAGE of good fuel. It reduces the cost of transportation and makes it IDEAL.

60.

Calculate the GCV and NCV of a fuel from the following data. Volume of the fuel burnt at STP is 0.08m^2.Weight of the water used for cooling is 24kg.Temperature of inlet and outlet water is 25^oC. and 30^oC respectively. Weight of water obtained by steam condensation is 0.02kg.(a) 1234.50cal/g(b) 1353.25cal/g(c) 1225.50cl/g(d) 1335.25cal/gThe question was posed to me during a job interview.Asked question is from Fuel Technologies Problems topic in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct ANSWER is (B) 1353.25cal/g

Explanation: For calculating the GCV of the coal use the formula GCV=w (T2-T1)/V, where w=weight of water and v=volume of fuel burnt. Substitute the corresponding values and we know that NCV is GIVEN by NCV=GCV – [(M/V)587], M is the weight of the water obtained by steam.

61.

The boiling range of un-condensed gas is ___________(a) < 300C(b) < 400C(c) > 500C(d) < 200CThis question was addressed to me in an online interview.Query is from Mining of Petroleum topic in chapter Fuel Technologies of Applied Chemistry

Answer»

The CORRECT option is (a) < 300C

To explain: The boiling range of un-condensed gas must be very LOW that is less than 30^oC. As the GASES are un-condensed they are ready to condense and become steam. So, a small amount of heat is SUFFICIENT to boil them.

62.

Paraffins are obtained by ______ process from petroleum.(a) fractional distillation(b) sedimentation(c) filtration(d) fermentationThis question was posed to me during an internship interview.My question is based upon Classification of Crude Oil based on their Composition in division Fuel Technologies of Applied Chemistry

Answer» CORRECT option is (a) fractional distillation

Easiest explanation: Fractional distillation is the process in which the petroleum is refined and in this process at EVERY stage there will some bi-product and at a certain stage paraffins are OBTAINED in this process. Fermentation is used to produce the alcohol and filtration is the process of REMOVING impurities.
63.

The moisturizing the coal before introducing into furnace is called as _________(a) moisturizing(b) filtering(c) tempering(d) combustionThe question was asked by my college director while I was bunking the class.Question is taken from Analysis of Coal and Selection topic in section Fuel Technologies of Applied Chemistry

Answer» RIGHT option is (c) tempering

For EXPLANATION I would say: The PROCESS of moisturizing the coal is CALLED tempering. Combustion means complete burning. Filtering is the process to remove unwanted contents from the substance.
64.

C=70%, O=10%, N=1%, S=5% and ash=4%.The NCV of the fuel was found to be 9210cal/g. percentage of hydrogen be x and HCV of the fuel be y.Find out y/x.(a) 747.7(b) 768(c) 777(d) 676.9I had been asked this question in an online quiz.This interesting question is from Dullong’s Formula topic in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct OPTION is (a) 747.7

For explanation I would SAY: Apply the dulong’s formula that is: HCV = 1/100[8080C + 34500(H-O/8) + 22400S], here the C, S, O, H are the percentages of carbon, sulphur, oxygen and hydrogen. So, substitute all the given values in the formula and calculate so that you will get HCV. As we don’t know the value of H, you will get HCV=[5336.75+345H]Cal/g. LET it be eauatin-1 and then we know that NCV = (GCV-0.09H*587), here 587cal/g is the latent heat of steam. NCV is given then you will get GCV=[9210+52.83H]Cal/g and let it be equation-2. So equate both the equations to get the value of H. you will get H=13.25% and let it be x and substitute in equation-1 to get the value of HCV=9908cal/g. Now let be y and divide y with x to get 747.7.

65.

If there is more oxygen content in fuel, then the calorific value of the fuel is _________(a) high(b) low(c) moderate(d) very highThis question was addressed to me in semester exam.My question is taken from Calorific Value in section Fuel Technologies of Applied Chemistry

Answer»

The correct CHOICE is (b) low

For explanation I would SAY: The oxygen content in fuel will reduce its ABILITY to burn and so that it cannot PRODUCE more amount of heat. So, the calorific value will be low.

66.

In liquid phase thermal cracking, the yield of petrol is ________(a) 50%-60%(b) 60%-70%(c) 70%-80%(d) 80%-90%The question was asked at a job interview.The origin of the question is Cracking and Knocking of Petroleum in section Fuel Technologies of Applied Chemistry

Answer»

Right option is (a) 50%-60%

EASIEST explanation: In LIQUID phase catalytic CRACKING, the yield of petrol is 50-60% with good octane rating of 65-70. Here, the cracked PRODUCTS are sent through fractionating where the products are SEPARATED.

67.

To find the % of volatile matter in coal, it must be heated in the crucible at ______ temperature.(a) 5261^0C(b) 3281^0C(c) 825^0C+10^0C(d) 925^0C+20^0CThis question was posed to me in an interview for job.This intriguing question comes from Analysis of Coal and Selection in section Fuel Technologies of Applied Chemistry

Answer»

Correct choice is (d) 925^0C+20^0C

For explanation: The moisture free COAL is taken into a silica CRUCIBLE and again it is heated at the temperature 925^0C+20^0C for 7 minutes then it is FIRST COOLED in air and late in a dessicator.

68.

Which of the following can be used as a preservative for wood?(a) solvent spirit(b) petroleum coke(c) tar(d) gasolineThis question was addressed to me during an interview for a job.This interesting question is from Mining of Petroleum topic in portion Fuel Technologies of Applied Chemistry

Answer»

Right ANSWER is (c) TAR

The explanation: Tar is used for preserving wood and the solvent spirit is MAINLY used for dry CLEANING and as motor fuel.

69.

For the generation of electricity, which source is used largely throughout the world?(a) coal(b) hydro power(c) wood(d) solar energyThis question was addressed to me at a job interview.I'm obligated to ask this question of Solid Fuels topic in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct ANSWER is (a) COAL

The explanation is: Coal is the most used resource to generate electricity. NEARLY 92% of the coal is used to produce electricity. The other resources like hydro POWER and solar energy are also used but in small amounts.

70.

To calculate HCV of the fuel, the products of combustion are cooled down to __________(a) 600F(b) 700F(c) 400F(d) 200FThe question was posed to me in an online interview.This is a very interesting question from Calorific Value topic in section Fuel Technologies of Applied Chemistry

Answer»

The correct OPTION is (a) 600F

For explanation: The products of combustion are COOLED down to 600F or 150C that is ROOM temperature. The hydrogen gas gets converted into steam.

71.

CO=40%, H2=12%, CO2=6%, CH2=2%, N2=50% are the components in the coal. What will be the composition of the dry flue gas, if the 50% excess air was used for burning 100m^3 of gas?(a) CO2=14.9%, N2=80%, O2=5.2%(b) CO2=12.2%, N2=70.8%, O2=6.5%(c) CO2=14.9%, N2=79.9%, O2=5.2%(d) CO2=13%, N2=77%, O2=75The question was asked in semester exam.My question comes from Fuel Technologies Problems in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct option is (c) CO2=14.9%, N2=79.9%, O2=5.2%

For explanation I would say: Form a table formulating the ACTUAL components in 100m^3, combination reactions and volume REQUIRED and % of dry GAS. Find total volume of gas. Later calculate the volume of oxygen in excess air by calculating the volume of dry products. Add the dry products combinations to GET the total products combination and then calculate the carbon dioxide, nitrogen and oxygen PERCENTAGES.

72.

The calorific value of the natural gas is?(a) 1200-1400kcal/m^3(b) 500-800kcal/m^3(c) 800-900Kcal/m^3(d) 12000-14000kcal/m^3I had been asked this question in final exam.I would like to ask this question from Power alcohols as Fuels topic in chapter Fuel Technologies of Applied Chemistry

Answer»

The CORRECT choice is (d) 12000-14000kcal/m^3

Explanation: 12000-14000kcal/m^3 is the calorific value of the natural GAS which is very HIGH value and PRODUCES a LOT of heat.

73.

Alcohol can absorb __________(a) traces of water(b) traces of impurities(c) traces of dust(d) traces of carbonI have been asked this question during a job interview.My doubt is from Power alcohols as Fuels topic in portion Fuel Technologies of Applied Chemistry

Answer»

The correct choice is (a) TRACES of WATER

For EXPLANATION: Alcohol has the power to ABSORB the traces of water present in PETROL as it dissolves in water.

74.

Olefins are slightly soluble in ___________(a) water(b) alcohol(c) kerosene(d) ethanolThis question was posed to me in an interview.Origin of the question is Classification of Crude Oil based on their Composition in portion Fuel Technologies of Applied Chemistry

Answer» CORRECT option is (a) WATER

The EXPLANATION is: Olefins are slightly soluble in water. The branching increases the SOLUBILITY of hydro CARBONS(Olefins).
75.

During metallurgical operations, n2 causes ___________(a) hardness to sample(b) softness to sample(c) moisture to sample(d) heat to sampleI got this question in semester exam.Asked question is from Analysis of Coal and Selection in portion Fuel Technologies of Applied Chemistry

Answer»

The correct ANSWER is (a) HARDNESS to sample

The explanation: During metallurgical processes, NITROGEN CAUSES hardness to the sample, but the presence of nitrogen does not affect the utility of the coal for great extent as it is present in small amounts.

76.

% of nitrogen can be determined by the process _________(a) dulong’s formula(b) orsat’s apparatus(c) kjeldahl’s method(d) fractional distillationI had been asked this question by my college director while I was bunking the class.My question is from Analysis of Coal and Selection in division Fuel Technologies of Applied Chemistry

Answer»

Correct ANSWER is (c) kjeldahl’s method

Best explanation: The dulong’s formula is used to find calorific VALUE of the coal. Orsat’s apparatus is used for analysis of the flue gas. Fractional DISTILLATION is used in purification of PETROLEUM. So, kjeldahl’s process is used for determination of nitrogen.

77.

The formation of coal is explained by ________(a) ex-situ theory(b) in-situ theory(c) molecular theory(d) nuclear theoryThe question was asked during a job interview.This interesting question is from Solid Fuels topic in section Fuel Technologies of Applied Chemistry

Answer»

The correct answer is (B) in-situ theory

For explanation: The in-situ theory explains the formation of COAL. It is ALSO explained by drift theory. ACCORDING to in-situ theory, the coal is FORMED only at the places where vegetation grew.

78.

What is the colour of the bio diesel?(a) orange(b) light yellow(c) dark orange(d) light brownThis question was posed to me in my homework.The doubt is from Power alcohols as Fuels in chapter Fuel Technologies of Applied Chemistry

Answer»

Right option is (b) LIGHT yellow

The BEST explanation: The BIO diesel is light yellow in colour. Most of the power ALCOHOLS are yellow in colour as they are hydrocarbons.

79.

During refining the petroleum, in fractional distillation, what is the temperature in still?(a) 800^oC(b) 400^oC(c) 300^oC(d) 100^oCI have been asked this question in semester exam.I would like to ask this question from Mining of Petroleum in section Fuel Technologies of Applied Chemistry

Answer»

The CORRECT answer is (b) 400^oC

Easiest explanation: The CRUDE oil is distilled and later it is SENT into the pre-heater or else it can be HEATED with steam, inside the still the temperature is about 400^oC.

80.

Liquid paraffin is used as ________(a) Dye(b) Medical purposes(c) Inhibitor(d) CatalystThis question was posed to me in an interview for job.The query is from Classification of Crude Oil based on their Composition topic in section Fuel Technologies of Applied Chemistry

Answer» CORRECT CHOICE is (b) Medical purposes

Explanation: The liquid PARAFFINS are used for medical purposes. They are mainly used in ointments and gel TYPE medicines.Inhibitor MEANS negative catalyst.
81.

Paraffins are mostly used as _______(a) dye(b) lubricant(c) catalyst(d) coolentThis question was posed to me in unit test.Question is from Classification of Crude Oil based on their Composition topic in division Fuel Technologies of Applied Chemistry

Answer»

The correct choice is (b) lubricant

For explanation I would SAY: Paraffins are used as lubricant as it is having OILY NATURE. Coolent is the substance which is used to COOL down the system. In NUCLEAR reactor water is used as coolent. Aniline is the example of dye.

82.

One of the disadvantages of solid fuel is _________(a) clinker formation(b) moderate ignition temperature(c) storage(d) transportationThe question was asked in final exam.This intriguing question originated from Solid Fuels topic in portion Fuel Technologies of Applied Chemistry

Answer»

Correct option is (a) clinker formation

For explanation: The clinker formation is the MAIN disadvantage of SOLID fuels. They can be stored easily and transportation is also EASY and having the moderate ignition TEMPERATURE is also an ADVANTAGE as we can control the rate of combustion.

83.

Modification of the dulong’s formula can be done by considering the ___________(a) latent heat(b) heat(c) fuel state(d) liquid fuelsThe question was posed to me in an interview.I need to ask this question from Dullong’s Formula topic in section Fuel Technologies of Applied Chemistry

Answer»

Correct ANSWER is (a) latent heat

The explanation is: The modification of the formula is done by considering the latent heat. It may be of WATER or vapour or steam accordingly. It represents the heating value of the FUELS.

84.

While calculating HCV, if we need to apply the fuse wire, acid and cooling corrections then what is the formula for HCV?(a) HCV = [(W + w)(t2-t1 + cooling correction)-(acid correction + fuse correction)]/weight of fuel(b) HCV = [(W + w)(t2+t1 + cooling correction)-(acid correction + fuse correction)]/weight of fuel(c) HCV = [(W + w)(t2-t1 + acid correction)-(cooling correction + fuse correction)]/weight of fuel(d) HCV = [(W + w)(t2+t1 + acid correction)-(cooling correction + fuse correction)]/weight of fuelI have been asked this question in a national level competition.My doubt stems from Dullong’s Formula topic in division Fuel Technologies of Applied Chemistry

Answer»

The correct OPTION is (a) HCV = [(W + w)(t2-t1 + cooling correction)-(ACID correction + fuse correction)]/weight of fuel

The best explanation: The cooling correction must be added to the temperature difference because the heat loss is may be conduction, convection or radiation. The sum of acid and fuse corrections are subtracted because the heat PRODUCED by exothermic REACTIONS is already included in the change in temperature. So, it is to be subtracted to get HCV.

85.

Artificial fuels are mainly prepared from ________(a) petrol(b) peat(c) coal(d) natural gasI have been asked this question in final exam.I want to ask this question from Characteristics of Good Fuel and its Advantages in section Fuel Technologies of Applied Chemistry

Answer»

Right answer is (a) petrol

The BEST I can explain: ARTIFICIAL fuels are produced by man. PEAT, coal and natural gas are directly available from nature. Petrol is produced by a man using a FRACTIONAL distillation process.

86.

The calorific value of LPG is _____________(a) 34800kcal/m^3(b) 84000kcal/m^3(c) 278000kcal/m^3(d) 29000kcal/m^3I had been asked this question by my college director while I was bunking the class.This is a very interesting question from Power alcohols as Fuels topic in section Fuel Technologies of Applied Chemistry

Answer» CORRECT ANSWER is (c) 278000kcal/m^3

The best I can explain: The CALORIFIC value of the LPG is more than that of the natural gas. It is about 278000kcal/m^3. So, it is more efficient than the natural gas.
87.

Main disadvantage of the power alcohol is _______(a) starting troubles(b) more cost(c) increases foreign currency(d) increases octane number of petrolThe question was posed to me in unit test.I need to ask this question from Power alcohols as Fuels in division Fuel Technologies of Applied Chemistry

Answer»

Right option is (a) starting troubles

Explanation: The MAIN disadvantages of the power ALCOHOLS are starting troubles due to the HIGH surface TENSION and ATOMIZATION.

88.

Pre-ignition of the fuel is seen in _________(a) petrol knocking(b) petrol cracking(c) diesel cracking(d) diesel knockingThis question was addressed to me in my homework.Origin of the question is Cracking and Knocking of Petroleum topic in section Fuel Technologies of Applied Chemistry

Answer»

The CORRECT OPTION is (a) PETROL knocking

For EXPLANATION I WOULD say: Petrol knocking is due to the pre-ignition of the fuel and in diesel knocking is because of ignition-lag of the fuel.

89.

Which of the following element has 100% anti knocking?(a) 2-methyl naphthalene(b) heptadecane(c) CH3-(-CH2-)14-CH3(d) 3-methyl naphthaleneThis question was posed to me in an online quiz.My query is from Cracking and Knocking of Petroleum in division Fuel Technologies of Applied Chemistry

Answer»

Right ANSWER is (c) CH3-(-CH2-)14-CH3

Explanation: CH3-(-CH2-)14-CH3 has the 100% anti knocking value. It is also CALLED as n-hexa decane. The lowest anti knocking value that is 0 is for the element 2-methyl naphthalene.

90.

What is the boiling range of diesel oil?(a) 120-180^oC(b) 180-250^oC(c) 320-400^oC(d) 250-320^oCThe question was posed to me in an interview for internship.My question is from Mining of Petroleum in chapter Fuel Technologies of Applied Chemistry

Answer»

Right option is (d) 250-320^oC

Easy explanation: Diesel oil’s BOILING POINT is 250-320^oC. So, in CRACKING the HIGH temperatures are APPLIED.

91.

Which of the following reactions indicates the Fischer-tropsch method?(a) nC+H(2n+2) → CnH(2n+2)(b) nC+H2n→ CnH2n(c) nCO+2nH2 → CnH2n+nH2O(d) nC+H(2n-1) → CnH(2n-1)I had been asked this question in homework.My doubt stems from Mining of Petroleum topic in chapter Fuel Technologies of Applied Chemistry

Answer»

Correct OPTION is (C) nCO+2nH2 → CnH2n+nH2O

The explanation is: The equation nCO+2nH2 → CnH2n+nH2O represents the Fischer-tropsch method, here the catalyst used is NI or CO. The other three reactions indicates the Bergius PROCESS or HYDROGENATION of coal.

92.

Which of the following fraction obtained on distillation used in dry cleaning?(a) petroleum ether(b) heavy oil(c) gas oil(d) naphthaI have been asked this question in homework.Asked question is from Mining of Petroleum in portion Fuel Technologies of Applied Chemistry

Answer»

Correct option is (d) naphtha

To elaborate: Naphtha is USED for dry cleaning. It is ALSO called as solvent spirit. HEAVY oil is mainly used in producing gasoline by cracking method.

93.

To remove sulphur compounds from petroleum, it is treated with __________(a) copper nitrate(b) copper oxide(c) magnesium chloride(d) sodium chlorideI had been asked this question during an internship interview.Question is from Mining of Petroleum topic in division Fuel Technologies of Applied Chemistry

Answer»

Correct choice is (b) copper oxide

For explanation I would say: The sulphur compounds can be removed by treating with copper oxide as the sulphur compounds are GET converted into the INSOLUBLE copper SULPHIDE.

94.

Which of the following is a synthetic fuel in gas form?(a) Natural gas(b) Producer gas(c) LPG(d) PetroleumI have been asked this question in an internship interview.My query is from Characteristics of Good Fuel and its Advantages topic in section Fuel Technologies of Applied Chemistry

Answer»

Right choice is (b) Producer gas

Easy explanation: The producer gas is a synthetic fuel in gas FORM WHEREAS, natural gas is a natural fuel in gas form. LPG and PETROLEUM are liquid FUELS.

95.

Which of the following releases less amount of carbon dioxide per unit of energy?(a) Coal(b) Oil(c) LPG(d) PetrolThis question was posed to me in quiz.My query is from Fuel Technologies Problems topic in section Fuel Technologies of Applied Chemistry

Answer»

The correct answer is (B) OIL

The explanation is: Oil releases very less amount of carbon dioxide when compared to COAL, LPG and PETROL but it also has very small calorific values when compared to those fuels and less efficient.

96.

Calculate the weight and volume of air required for the complete combustion of 2kg of carbon.(a) weight of air=5000g; volume of the air=17000l(b) weight of air=17000g; volume of the air=15000l(c) weight of air=5330g; volume of the air=17766.66l(d) weight of air=8220g; volume of the air=1555.45lI got this question in an online quiz.This intriguing question comes from Fuel Technologies Problems topic in division Fuel Technologies of Applied Chemistry

Answer»

The correct choice is (c) weight of air=5330g; volume of the air=17766.66l

Explanation: For calculation first the REACTION is C+O2 → CO2.For this equation, 12 kg of c requires 32kg of oxygen for combustion then FIND for 2kg of carbon dioxide. At NTP 1g MOLE of oxygen occupies 22.4l then calculates for the WEIGHTS of carbons that has calculated before then find volume of air by KNOWING that 100 parts of air contains 21 parts of oxygen.

97.

High % of moisture is undesirable because _________(a) increases the cost of transport(b) increases the cost of calorific value(c) increases the cost of efficiency(d) decreases the cost of storage costThe question was asked during an interview for a job.My question is from Analysis of Coal and Selection in division Fuel Technologies of Applied Chemistry

Answer»

Correct CHOICE is (a) increases the cost of transport

The BEST explanation: If there is more moisture content in the COAL then it is difficult to transport it because the moisture will CHANGE into steam.

98.

The calorific value of LPG is generally _______ than that of coal.(a) higher(b) lower(c) half(d) very lesserI got this question in a national level competition.Question is taken from Calorific Value topic in chapter Fuel Technologies of Applied Chemistry

Answer»

The correct choice is (a) higher

Best explanation: Generally, the CALORIFIC values of LIQUID FUELS are more than that of solid fuels. They produce more HEAT than liquid. So, the calorific value of LPG is more than that of COAL.

99.

Which of the following statements is correct?(a) 1k.Cal=2B.Th.U(b) 1B.Th.U=252Cal(c) 1k.Cal=100Cal(d) 1k.Cal=4C.H.UI have been asked this question during an interview for a job.This key question is from Calorific Value in division Fuel Technologies of Applied Chemistry

Answer»

Correct answer is (B) 1B.Th.U=252Cal

Best explanation: 1B.Th.U=252Cal is the correct ONE. 1k.Cal=2B.Th.U is WRONG because 1k.Cal=3.968B.Th.U=2.2 C.H.U. So 1k.Cal=4C.H.U is ALSO wrong. Kilo means 1000. So, 1k.Cal=1000Cal.

100.

Octane number is a rating of ___________(a) petrol knocking(b) diesel knocking(c) petrol cracking(d) diesel crackingThe question was posed to me in a national level competition.I want to ask this question from Cracking and Knocking of Petroleum in chapter Fuel Technologies of Applied Chemistry

Answer»

The CORRECT choice is (a) petrol KNOCKING

Easiest explanation: Octane number is the rating for petrol knocking and CETANE number is the rating for DIESEL knocking.