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101.

A frog walking in a narrow lane takes `5` leaps forward and `3` leaps backward, then again `5` leaps forward and `3` leaps backward, and so on. Each leap is `1 m` long and requires `1 s`. Determine how long the frog takes to fall in a pit `13 m` away from the starting point.A. 35 sB. 36 sC. 37 sD. 38 s

Answer» Correct Answer - C
In each process of going forward and coming backward, it will take `8 s`, and he will move `2 m` in there `8 s`
Time taken to cover first `8 m : = (8)/(2) xx 8 = 32 s`
Now after convering `8 m`, when he taken five steps, he will fall into the pit. Time taken is `5 s`.
Total time `= 32 + 5 = 37 s`.
Discussion
102.

A particle has initial velocity `(3 hat i+ 4 hat j)` and has acceleration `(0.1 hat i+ 0.3 hat j)`. Its speed after `10 s` is.A. 7 unitB. `7 sqrt(2)` unitC. 8.5 unitD. 10 unit

Answer» Correct Answer - B
Using `vec v = vec u + vec a t`
`vec v =(3 hat i + 4 hat j)+(0.4 hat i + 0.3 hat j) xx 10`
`rArr vec v = 7 hat i+ 7 hat j`
hence speed `|v| = 7 sqrt(2)`.
Discussion