Explore topic-wise InterviewSolutions in Current Affairs.

Insecticides: Insecticides are substances used to kill insects. Ex: Malathion, Pyrethrum.

C₂H₆O is an alcohol, i.e. ethanol C₂H₅OH 

Functional group is —OH.

The correct answer is D) Elephant

Journal: The organisms that are active mainly in the daytime. Ex: Cow, Sheep, Goat, Hen, Man

PestIcides: A pesticide Is a chemical or other substance that is used to kill or prevent pests. Ex: Glycol

The correct answer is A) Dog

Nocturnal: The organisms that are active mainly in the nighttime. Ex: Owl, Bat, Lizard.

Animals are divided into three types on the basis of their food. They are herbivores, carnivores and omnivores.

Different types of animals that live in our surroundings have their own food habits. (Way of taking in food and type of food taken)

Sucking, licking, pecking, chewing, peeling, swallowing are all the ways by which animals take in their food.

The correct answer is B) Bat

The reactive site is at a place where double bond is present.

Name of the compound is 2-pentene.

The Judges of the Supreme Court retire at the age of 65 years.

Public prosecutor is a person appointed by central / state govt, to represent cases on behalf of the state in criminal trials.

Climatic conditions for cultivation of citrus fruits are hot dry summers and mild rainy winters.

(b) The Abbot of Aberbrothok had placed the bell on a buoy on the rock. 

(a) The waves were so small that they did not move enough to ring the bell at the Inchcape Rock. 

(d) Ralph bent over from the boat. 

(c) There was a thick haze spread over the atmosphere. 

(e) Sir Ralph cursed himself in despair and in his frustration tore his hair.

The Abbot of Aberbrothok placed a bell on the Inchcape Rock because there were dangerous rocks near the coast which would wreck ships.

At the beginning of the poem the season is spring, the weather is mild and the sea-waters are calm. The waves pour softly over the Inchcape Bell. The Heavy Bell on a buoy would ring due to strong waves only in stormy weather.

When the Rover cut the Bell it was spring season. The mood was happy, light-hearted. He was up to mischief in a rash, jolly mood on a lovely spring day. He wanted to only trouble the Abbot.

After undoing the Abbot’s good work the Rover went away on his criminal voyages. But when he was returning the sea was stormy. Wild winds threw the ship off course. The mood is of confusion and fear because a thick fog covered them from the sun. The mood is of suspense, the sailors are lost.

By nightfall they did not still know where they were. They are really and metaphorically in the dark. They could hear the waves crashing yet they did not know which land was near. There is fear. There was no wild wind but the rough sea was pulling their ship along. They desperately wanted some clue to help them to know their location. The ship shattered onto the rocks as the Rover yelled and cursed. The dramatic end is violent and filled with despair.

Rutherford method.

1. To determine the diameter (d) of a planet or star, two diametrically opposite points of the planet are viewed from the same observatory.

2. If d is diameter of planet or star, angle subtended by it at any single point on the Earth is called angular diameter of planet.

3. Let angle α be angle between these two directions.

4. If distance between the Earth and planet or star (D) is known, α = \(\frac{d}{D}\)

5. This relation gives, d = α D 

Thus, diameter (d) of planet or star can be determined.

spectroscopic method using intensity ∝ radius² , i.e., I ∝ r²

We have, α = 200’’ 

= 2000 × 4.85 × 10^-6 rad. [∵ 1’’ = 4.85 × 10^-6 rad] 

And D= 1.5 × 10¹¹ 

Using d = αD, we get d = 2000 × 4.85 × 10^-6 × 1.5 × 10¹¹ 

= 2 × 4.85 × 1.5 × 10⁸ 

= 1.455 × 10⁹ m.

We have

r_PS = 0.38 AU 

Using r_PS = AU sin θ, 

or sin θ = \(\frac{r_{PS}}{AU}\)

= sin^-1 0.38 = 22^o3’ 

Now r_PE = AU cos θ 

∴ r_PE = (1.496 × 10¹¹ m) × cos 22^o3’ 

= 1.384 × 10¹¹ m

= 1.384 × 10⁸ km.

Given details are,

Dimensions of box = 56cm × 0.4m × 0.25m

Dimensions of soap cake = 7cm × 5cm × 2.5cm

So,

Number of soap cakes that can be placed in box = volume of box / volume of soap cake

= (56 × 40 × 25) / (7 × 5 × 2.5)

= 640 soap cakes

Correct option is C) Diffusion

(a) (i) The least distance of distinct vision increases with age because of the increase in the minimum possible focal length of the eye lens or contraction of the eye ball. 

(ii) This defect can be corrected by placing a convex lens in front of the eye. 

(b) (i) Empathy : Helping and caring nature. 

(ii) Concern for his uncle.

(i) Reflecting telescope.

(ii) No chromatic aberration, mirrors are relatively lighter and cheaper compared to the lens.

(iii) First hand experience, inculcating a scientific temper, team work, enthusiasm, finding curiosity.

Thermal capacity of a body is the energy required to raise its temperature by 1°C. 

c = Q ∆T J/K or cal °C^-1 .

Heat is a form of energy which is inherent in anybody. It flows from a body at a higher temperature to a body at lower temperature.

Correct option is A) Concave

• When a spherical mirror breaks into smaller pieces, the radius of curvature and focal length does not change. 
• Hence, it will continue to behave like a spherical mirror only.

The mirror formula is \(\frac{1}{f}= \frac{1}{u}\,+\,\frac{1}{v}\)

f = focal length of mirror ; u = object distance ; v = image distance

 A) \(\cfrac{1}f\) = \(\cfrac{1}u\) + \(\cfrac{1}v\)

The answer is (b) Potato

• Potatoes are mainly propagated by vegetative methods (cloning).
• Potato tubers have nodes or eyes from which the new growth begins. 

The answer is Propagule

In horticulture, a propagule is any plant material used for the purpose of plant propagation.

B. Anabaena and Nostoe

The answer is (b) Shoot

• A flower is a modified shoot (stem bearing leaves). 
• In a typical flower the stem portion is condensed to form a compact receptacle called thalamus. 

Correct Answer is: B) Anabaena and Nostac

In some cases, the diastrophic partner is a cyanobacterium, such as Anabaena in coralloid roots of Cycads or Nostoc in stems of Gunnera.

Particularly interesting is the symbiosis between the cyanobacterium Anabaena azollae and the leaves of the aquatic fern Azolla.

• In angiosperms sexual reproduction necessarily involves meiosis and fertilization, ultimately resulting in seed formation.
• Whereas a method of formation of a new plant without involving meiosis and fertilization is called asexual reproduction. 
• In asexual reproduction, only mitotic divisions are involved and hence the offsprings are genetically similar to the parent plant. 
• In sexual reproduction, meiotic division results in variations and hence the offsprings show genetic variations.

• In a typical flower, there are four whorls, namely calyx, corolla, androecium and gynoecium. 
• Calyx and corolla form accessory whorls and androecium and gynoecium are called necessary whorls

• Agamospermy is a form of asexual reproduction in angiosperms in which seeds are formed without involving a fusion of gametes. 
• The embryo present in the seed is not formed from a diploid zygote but is formed from a diploid egg.

• During the practice of grafting the branch of a plant having desirable features is inserted into a rooted plant of the same or allied species. 
• The branch which is inserted is called scion and the rooted plants in which the branch is inserted and which provides the supply of water and minerals is called stock.

• Formation of a new individual from any vegetative part of the plant body is calledvegetative propagation. 
• Many plants produce a modified structure on their vegetative parts which
• when separated from the mother plant, established as an independent plant.\
• Such a method of multiplication is called vegetative reproduction.

Correct Answer is: B) Oxygen

Methanogens are methane producing bacteria and they are anaerobic organisms. Therefore, they do not produce or require Oxygen. The other options are gases which Methanogens produce.

d. Fungi plants exhibit more species diversity.