Explore topic-wise InterviewSolutions in Current Affairs.

1. True 

2. False 

3. False 

4. True 

5. False

Alice saw a rabbit hurrying down a rabbit’s hole. She wanted to find out why the rabbit was in such a hurry. So she followed him.

Homelessness – Idealistic Solutions 

Student No. 1 : 

A permanent and sustainable end to homelessness requires four essential components.

1. Housing is the essential foundation to ending homelessness. 

2. Housing is essential, but it is not sufficient. Housing alone, without attention to health, behavioural health, employment and education will continue to result in instability and recurrent homelessness for many people.

Student No. 3 : 

Proposal that is both realistic and unconventional:

We can end the homelessness crisis by stabilizing people through shelter, moving them into permanent housing and implementing assistance programs to keep them in their housing. Only then we can reduce and eliminate homelessness in India.

This statement is True. 

Peer groups, family, neighbourhood, society, mass media are important agencies of socialisation. Generally, individuals do not opt consciously to become an ‘addict’. It is what they become over a period of time. Under the influence of several factors.

Peer pressure and social status – Friends in a group may knowingly or unknowingly pressurize others to adopt certain habits in order to ‘fit in’ which is common among students but it can also cut across other age categories e.g., the habit of smoking or ‘doing weed’ among friends.

Consuming narcotic drugs or imported brands of alcohol may be considered a fad in certain groups; non-conformity could lead to isolation or labelling. Thus, friends play important role in socialising addictive behaviour.

50 cm³ of saturated vapour is cooled 30° to 20°. The absolute humidity of saturated H₂O vapour 30 g/m³
Absolute humidity is the mass of water vapour present in a given volume at 30°C, it contains 30 g/m³
at 50 m³ it contains 30 × 50 = 1500 g
at 20°C it contains 16 × 50 = 800 g
Water condense = 1500 – 800 = 700 g.

Correct answer is 4.5°F

The correct answer is (C) 0.082

The correct answer is (C) 0.29

(B) longitudinal extension and lateral contraction.

Correct option is: (D) four times that of A.

Correct option is: (A) four times that of A

(A) \(\frac{1}{2}\)Mgl

elastic potential energy: \(\frac{1}{2}\) × F × L = \(\frac{1}{2}\)Mgl

The elastic potential energy gained by a wire during elongation b a stretching force is called as strain energy.

Let θ be the maximum angular deflection them

1/2mv² = mg (l - lcosθ)

and T - mg = mv²/l

T = mg + mv²/l

T/πr² = mg + 2 mg (l - lcosθ)

= 3mg - 2mg cosθ

For maximum value of θ, stress (=T/πr²) must be equal to breaking stress,

i.e., T/πr² = 7.85 x 10⁸

or, (3mg - 2mg cosθ)/(π x (10^-3)²) = 7.85 x 10⁸

or, cosθ = 0.2436 = cos 75.9°

or, θ = 75.9°

(C) more than two times its initial value

Given: F = 10 N, Strain energy = 1.1 × 10^-3 J,

To find: Extension (l)

Formula: W = \(\frac{1}{2}\) × F × l

Calculation:

From formula,

l = \(\frac{2\,W}{F}=\frac{2\times1.1\times10^{-3}}{10}\) = 2.2 × 10^-4 m.

The extension produced in the wire is 2.2 × 10^-4 m.

The alkali metals e.g., caesium, potassium and sodium emit photoelectrons even when visible radiation (light) is incident on them. Hence, they are most suitable as photosensitive surfaces.

Correct option is: (C) \(\frac{1}{2}\) × Y × (strain)²

Correct option :  (3)

Explanation :

From the relation eVs = hv - ω₀ 

it is clear that the value of stopping potential for a given metal depend upon ω₀ when a light of frequency v is incident on a metal surface.

Now ω₀ for sodium is 2.0 and ω₀ for aluminum is 4.2

The metal surface having lower value of work function will have a larger value of stopping potential. 

Let the breadth of a rectangular field = x m 

Length = (x + 26) m. 

Perimeter of a rectangular field 

= 2(l + b) = 400

l + b = 200 

x + 26 + x = 200 

2x = 200 – 26 = 174 

x = \(\frac{174}2\)

∴ x = 87 

∴ The length = x + 26 

= 87 + 26 

= 113 m 

Breadth = x = 87 m.

Solution:

Let Hasan bought 2x m of trouser material and 3x m of the shirt material.

Per metre selling price(S.P) of the trouser material = ₹90+90×12/100

= 90 + 1.2× 9

= 90 + 10.8

=₹100.80

Per metre selling price(S.P) of trouser of shirt material

= ₹50+ 50× 10/100

= ₹ 50 + 5

=₹55

Given: total amount of sale= ₹ 36660

100.80 x (2x) + 55 x (3x) = ₹36660

201.60 x + 165x = 36660

366.60 x  = 36660

X= 36660/366.60

x = 100

Trouser material = 2x m = (2×100)m = 200m.

Hasan bought 200 m of trouser material.

There is a narrow rectangular plot, reserved for a school, in mahuli village. the length and breadth of the plot are in the ratio 11:4. 

let the common multiple be x 

the length will be 11x 

breadth = 4x 

Perimeter = 2( L + B ) 

=2(11x+4x) 
= 2*15x
=30x 

At the rate Rs 100 per meter 

30x * 100 = 3000x 
3000x= 75000 
3x=75 
x=25 

11x = 11*25 = 275m 
4x=4*25 = 100 m 

275m & 100m are the dimensions of the Plot

Let Sahil’s present age be x. Prakruthi’s present age is 6x, 15 years later Sahil age will be (x + 15) years and Prakruthi age will be (6x + 15) years. 

Given that Prakruthi age will be 3 times as old as Sahil. 

∴6x+15 = 3(x+15) 4 

6x+ 15 = 3x + 45 

6x – 3x = 45 – 15 

3x = 30 

x = \(\frac{30}{3}\)= 10 

Sahils age = x = 10 years Prakruthis age = 6x = 6 x 10 = 60 years

Alfred Wegener, a German meteorologist, put forward the idea of continental drift in 1912. He argued that millions of years ago, all the present-day continents were a single unit forming supercontinent named Pangea which was encircled by an ocean called Panthalassa. Wegener believed that over millions of years, the continental portions drifted over the ocean floor forming the present continents.

Some recent studies indicate that mostly all the continents on earth come together once in every 500 million years. It is believed that the most recent formation of Pangea was about 200 million years back, which means that we will have to wait for another 300 years for the next Pangea

New ocean floor is continuously being created as a result of magma that comes out through the divergent margins and solidification along the edges of the plates. This results in the phenomenon called seafloor spreading.

Fruit carving

Seafloor spreading: The mid-ocean ridges or ranges formed by lava rise up from the mantle. This fresh crust slowly pushes the plate away which is called seafloor spreading.

The thin layer of air that surrounds the earth is the atmosphere.

The solid crust or the hard top part of the earth which is made up of rocks and minerals and covered with a thick layer of soil is called the lithosphere.

Indian spices

Extrusive landforms: When a volcano is erupted some part of lava pours on the earth’s surface or pours out of fissures on the earth’s surface and forms rocks which are called extrusive landforms.

Intrusive landforms: When a volcano erupts some part of the lava may cool under the surface and become rocks. These are called intrusive landforms.

Second-order Landforms: Landforms like mountains, plains, and plateaus are called ‘second-order landforms’.

The primary divisions of the earth’s crust are oceans and continents. These are called first-order landforms.

First-order landforms: The primary division of the earth’s crust into oceans and continents.

The realm of life including bacteria is called the biosphere.

Lithosphere: The solid crust or the hard top part of the Earth.

Biosphere: The realm of life including bacteria.

Hydrosphere: The realm of water that comprises various sources of water and different types of water bodies like rivers, lakes, seas, and oceans, etc

Spices are included in a variety of food dishes for flavour.

a) water mass

b) land mass 

c) air mass 

d) life

Spices are used to flavour the food.

The correct answer is D) All the above

Mango : Fruit :: Potato : Stem

The correct answer is D) Leaf

Food is prepared by using one or more Ingredients

The correct answer is C) Ginger

Milk and meat are obtained from Animals

The correct answer is B) Cauliflower

The correct answer is A) Root